(I'm so confused please help)
Suppose M is the midpoint of XY. If XM = 2x + 11 and MY = 5x - 16, find the value of X.
A) x = -4
B) x = 4
C) x = -9
D) x = 9
E) x = 2

My math:
2x + 11 = 5x + 16
(-5x and -11 from both sides)
-3x=5
(divide -3 on each side)
x=-5/3
But it isn't an option, so I don't know.

Answer:

Solution given:

[tex]\sqrt{6-15x} =5x+d[/tex]......(1)

d=?

and

x=-2

Substituting value of x in equation 1.

[tex]\sqrt{6-15*-2} =5*-2+d[/tex].

Solve the like terms

[tex]\sqrt{6+30} =-10+d[/tex].

solve the like terms

[tex]\sqrt{36} =-10+d[/tex].

we have square root of 36 is 6.

6=-10+d

d=16

the value of constant term is 16.

The value of d for the expression [tex]\sqrt{6-15x} = 5x+d[/tex] is 16.

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication and division.

The value of 'd' is calculated as,

[tex]\sqrt{6-15x} = 5x+d[/tex]

Put the value of x =-2,

[tex]\sqrt{6-(15\times -2)}=(5\times -2)+d[/tex]

√36 = -10 + d

6 = -10 + d

d = 16

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Answer:

13 sports books and 10 unknown books is 23 books

Step-by-step explanation:

we already know scott read 23 books total, we also know that he read 10 mystery books.

subtracting 10 unknown books from 23 total books, we get 13 sports books as your answer

Answer:

Im not sure what is in the algebra 1 module 4 but for algebra 1 you should study how to graph equations, solve system of equations with substitution and elimination. those topics, at least for e, have been a little tricky

Step-by-step explanation:

Answer:

Three more than twice a number is equal to four less than the number. find the number.

Answer:

#1

The cost to produce 500 helmets:

#5

The break-even point is the price when profit is zero:

#6

There will be a profit as the selling price is greater than the break even point:

Find cost of x=500 helmets

Break even point

So

There is profit as its less than 18

Answer:

[tex]y=\displaystyle\frac{3}{2}x-3[/tex]

Step-by-step explanation:

Hi there!

Slope-intercept form: [tex]y=mx+b[/tex] where m is the slope and b is the y-intercept (the value of y when x=0)

We're given:

⇒ x-intercept = 2

⇒ y-intercept = -3

1) Determine the slope (m)

[tex]m=\displaystyle\frac{y_2-y_1}{x_2-x_1}[/tex] where two points that fall on the line are [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]

Given the x- and y-intercepts, we can rewrite them as points:

x-intercept = 2

⇒ (2,0)

y-intercept = -3

⇒ (0,-3)

Plug these points into the equation:

[tex]m=\displaystyle\frac{0-(-3)}{2-0}\\\\m=\displaystyle\frac{0+3}{2}\\\\m=\displaystyle\frac{3}{2}[/tex]

Therefore, the slope of the line is [tex]\displaystyle\frac{3}{2}[/tex]. Plug this into [tex]y=mx+b[/tex]:

[tex]y=\displaystyle\frac{3}{2}x+b[/tex]

2) Plug in the y-intercept (b)

[tex]y=\displaystyle\frac{3}{2}x+b[/tex]

We're given the y-intercept: -3. Plug this into [tex]y=\displaystyle\frac{3}{2}x+b[/tex]:

[tex]y=\displaystyle\frac{3}{2}x+(-3)\\\\y=\displaystyle\frac{3}{2}x-3[/tex]

I hope this helps!

Answer:

-4

Step-by-step explanation:

The average rate of change of the interval [a,b] is (f(b)−f(a)) / (b−a)

Replacing a=−5, b=4, f(x)=−x^2−5x+12.

 (f(b)−f(a))/(b−a) =12−5x4− 4^2 − (12−5 x(−5)−(−5)^2)/ (4−(−5))= −4.

Answer:

considering it was simple interest,

We have the formula:

I = PRT ÷ 100

where,

for the first part of the question,

Thus, I = (2160 × 20 × 4)÷ 100

I = Rs. 1728

Now, for the second part,

T = 100×I÷PR

T = 100 × 1728÷(1800 × 12)

T = 8 Years

Answer:

133.33

Step-by-step explanation:

Answer:

133 1/3 or 133.33

Step-by-step explanation:

So first let's turn 15% into a decimal. For me personally, its less intimidating that way.

15%=0.15

now, let's say the number we are trying to find is x.

A trick I use for these questions is to look at the words. "Of" is used when something is multiplied. "Is" is used for equal signs. So if 20 is 0.15 of x, our formula is easy to figure out!

20=0.15x

x=133.33333...

x=133 1/3

Answer:

A) both functions are linear

B) f(x) = 7446.4x + 178713.6 and f(x) = 11000x + 179000

C) House 2 will value $106894.4 more than house 1.

Step-by-step explanation:

A) Value Increase from year 1 to year 2:

House 1: 193,606.40 - 186,160 = 7446.4

House 2: 201,000 - 190,000 = 11000

Value Increase from year 2 to year 3:

House 1: 201,350.66 - 193,606.40 = 7744.26

House 2: 212,000 - 201,000 = 11000

This means that a constant increament in x variable gives a constant increament in both houses vales. Then, both functions are linear.

B) The slope is the same as the value increment from one year to the next one.

slope (m) of House 1: 7446.4

slope (m) of House 2: 11000

General formula of a line:

f(x) = mx+b

Replacing with a known point:

House 1

186,160 = 7446.4(1) + b

b = 186,160 - 7446.4 = 178713.6

equation: f(x) = 7446.4x + 178713.6

House 2

190,000 = 11000(1) + b

b = 190,000 - 11000 = 179000

equation: f(x) = 11000x + 179000

C) Replacing x = 30 into each equaiton:

Value of House 1 after 30 years

f(x) = 7446.4(30) + 178713.6 = 402105.6

Value of House 2 after 30 years

f(30) = 11000(30) + 179000 = 509000

Then, house 2 will value 509000 - 402105.6 = $106894.4 more than house 1.

Answer:

$525

x+ y = 975

x - 75 = y

x + x - 75 = 975

2x = 1050

x = $525

Step-by-step explanation:

Answer:

Below!

Step-by-step explanation:

Let x represent the cost of the bench

The cost of the garden table can be represented by this equation:

      x + 75

x + (x + 75) = 975

2x + 75 = 975

2x = 900

Divide both sides by 2

x = 450

The bench costs $450

The garden table costs 450 + 75 = $525

Hope this helps! Best of luck <3

I would really appreciate brainliest if possible :)

Answer:

A 6.09

Step-by-step explanation:

Answer:

x=2,y=2

Step-by-step explanation:

3y-1 = 5

or, 3y = 5+1

or, y = 6/3

y = 2

2x+1 = 3y-1

or, 2x = 3×2-1-1

or, 2x = 4

or, x = 2

[tex]\\ \sf\longmapsto \left[{2x+1\atop 2x+x}\:\:\:{3y-1\atop 3}\right]=\left[{3y-1\atop 4}\:\:\;{5\atop 3}\right][/tex]

[tex]\\ \sf\longmapsto 3y-1=5[/tex]

[tex]\\ \sf\longmapsto 3y=5+1[/tex]

[tex]\\ \sf\longmapsto 3y=6[/tex]

[tex]\\ \sf\longmapsto y=2[/tex]

Put the value in 1st one

[tex]\\ \sf\longmapsto 2x+1=3y-1[/tex]

[tex]\\ \sf\longmapsto 2x+1=3(2)-1[/tex]

[tex]\\ \sf\longmapsto 2x+1=6-1[/tex]

[tex]\\ \sf\longmapsto 2x+1=5[/tex]

[tex]\\ \sf\longmapsto 2x=5-1[/tex]

[tex]\\ \sf\longmapsto 2x=4[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{4}{2}[/tex]

[tex]\\ \sf\longmapsto x=2[/tex]

Analyzing the text, we find that the function is decreasing over the following intervals: (0, 1)

-------------------------

Going from maximum to minimum, meaning that between them the function decreases, thus, the first interval it is decreasing is between (0,1).

Going up, increases.

-------------------------

Thus, the function decreases over the following interval: (0, 1)

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Answer:

Step-by-step explanation:

In the coordinate given, x = 3 and y = b. If we plug those into the given equation, we can solve for b:

y = 2x + 9 ---> b = 2(3) + 9 so

b = 6 + 9 and

b = 15

Answer:

b = 15

Step-by-step explanation:

y = 2x+9

Let x = 3 and y=b

b = 2(3)+9

b = 6+9

b = 15

Answer:

540°

Step-by-step explanation:

90 revolutions = 360°×90 = 32400°

32400° in 60 sec or 1 min

so, in 1 sec 32400/60 = 540°

Answer:

540°

Step-by-step explanation:  

90 revolutions = 360°×90 = 32400°  

=> 32400° in 60 sec or 1 min  

=> In 1 sec,

=> 32400/60 = 540°

Answer:

Step-by-step explanation:

A horizontal line is only concerned with the y value. The equation is y = 10 because that is the point that the line must go through.

The x value does not matter as long as the y value is given as 10. The domain is any real value. The range is 10

Answer: x= 42.3

Step-by-step explanation:

Sqrt a^2 + b^2 - (2ab)(cos 100)

Sqrt 25^2 + 30^2 - (2)(25)(30)(cos 100)

42.3

Answer:

C

Step-by-step explanation:

The actual dimensions of the check out area is 25 m by 35 m.

An equation is an expression that shows the relationship between two or more numbers and variables.

An independent variable is a variable that does not depend on other variables while a dependent variable is a variable that depends on other variables.

Given the scale of:

1 cm = 5 m, hence:

Length = 5 cm = 5 cm * 5 m per cm = 25 m

Width = 7 cm = 7 cm * 5 m per cm = 35 m

The actual dimensions of the check out area is 25 m by 35 m.

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Answer:

The answer for no 2 is x = 3+y or y+3

Answer:

2pi*r(r+h)

Step-by-step explanation:

SEE IMAGE FOR SOLUTION

HAVE A GREAT DAY

Answer:

x = 7/2

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

cos theta = adj side / hypotenuse

cos 45 = x / 7 sqrt(2) /2

7 sqrt(2)/2 cos 45 = x

7 sqrt(2)/2 (1/ sqrt(2))= x

7/2 = x

Answer is: B

Step-by-step explanation: correct answer is B

b  

2

−a  

2

Given, acotθ+bcscθ=p

           bcotθ+acscθ=q

⇒p  

2

−q  

2

=(p−q)(p+q)

                   =[acotθ+bcscθ−bcotθ−acscθ][acotθ+bcscθ+bcotθ+acscθ]

                   =[cotθ(a−b)−cscθ(a−b)][cotθ(a+b)+cscθ(a+b)]

                   =(a−b)(cotθ−cscθ)(a+b)(cotθ+cscθ)

                   =(a  

2

−b  

2

)(cot  

2

θ−csc  

2

θ)

                   =(−1)(a  

2

−b  

2

)[∵csc  

2

θ−cot  

2

θ=1]

                   =(b  

2

−a  

2

)

[tex]\\ \sf\longmapsto \left[{3a+b\atop a-b}\:\:\:{3c-d\atop a+b+d}\right]=\left[{3\atop 5}\:\:\;{6\atop 2d-1}\right][/tex]

Now constructing equations

[tex]\\ \sf\longmapsto 3a+b=3\dots(1)[/tex]

[tex]\\ \sf\longmapsto a-b=5\dots(2)[/tex]

[tex]\\ \sf\longmapsto 3c-d=6\dots(3)[/tex]

[tex]\\ \sf\longmapsto a+b+d=2d-1\dots(4)[/tex]

Adding eq(1) and (2)

[tex]\\ \sf\longmapsto 4a=8[/tex]

[tex]\\ \sf\longmapsto a=\dfrac{8}{4}[/tex]

[tex]\\ \bf\longmapsto a=2[/tex]

Put the value in eq(2)

[tex]\\ \sf\longmapsto a-b=5[/tex]

[tex]\\ \sf\longmapsto b=a-5[/tex]

[tex]\\ \sf\longmapsto b=2-5[/tex]

[tex]\\ \bf\longmapsto b=-3[/tex]

put the values in eq(4)

[tex]\\ \sf\longmapsto a+b+d=2d-1[/tex]

[tex]\\ \sf\longmapsto 2+(-3)+d=2d-1[/tex]

[tex]\\ \sf\longmapsto d-1=2d-1[/tex]

[tex]\\ \sf\longmapsto d-2d=-1+1[/tex]

[tex]\\ \sf\longmapsto -d=0[/tex]

[tex]\\ \bf\longmapsto d=0[/tex]

Put the value in eq(3)

[tex]\\ \sf\longmapsto 3c-d=6[/tex]

[tex]\\ \sf\longmapsto 3c-0=6[/tex]

[tex]\\ \sf\longmapsto 3c=6+0[/tex]

[tex]\\ \sf\longmapsto 3c=6[/tex]

[tex]\\ \sf\longmapsto c=\dfrac{6}{3}[/tex]

[tex]\\ \sf\longmapsto c=2[/tex]

By some properties of logarithms, rewrite the equation as

[tex]2\log(a-2b) = \log(a) + \log(b) \\\\ \log(a-2b)^2 = \log(ab)[/tex]

so that

(a - 2b)² = ab

Expand the left side:

a ² - 4ab + 4b ² = ab

Rearrange terms to get a quadratic equation in a/b :

a ² - 5ab + 4b ² = 0

b must be greater than 0, otherwise log(b) doesn't exist, and the same goes for a. So we can divide by b ² to get

a ²/b ² - 5a/b + 4 = 0

Factorize and solve for a/b :

(a/b - 4) (a/b - 1) = 0

==>   a/b = 4   or   a/b = 1

However, if a/b = 1, then a = b makes a - 2b = -b. But we must have b > 0, so we omit the second solution and end up with

a/b = 4

Answer:

bro what is the diagonal of second square.

Answer:

25/81 is already in the simplest form. It can be written as 0.308642 in decimal form (rounded to 6 decimal places).

Answer:

It is a rational number.

Step-by-step explanation:

A rational number is a number that repeats with the same number, or terminates. An irrational number is a number that repeats, but not with a constant number, like pi for example. 3.739 terminates at the end, so it is a rational number.

Hope this helps :)

Answer:

[tex]\boxed{x^2=-8y}[/tex]

Step-by-step explanation:

[tex](a,b)\ is \ the\ focus\\y=k\ is \ the\ directrice\\\\Formula\ to\ use:\ y=\dfrac{(x-a)^2}{2(b-k)} +\dfrac{b+k}{2} \\\\Here: \ a=0,\ b=-2, \ k=2\\\\y=\dfrac{(x-0)^2}{2(-2-2)} +\dfrac{-2+2}{2} \\\\so\ y=-\dfrac{x^2}{8} \\\\or\ x^2=-8y[/tex]

The equation which represents the parabola is x^2 = 8y, the correct option is C.

If a quadratic equation is written in the form

y=a(x-h)^2 + k

then it is called to be in vertex form. It is called so because when you plot this equation's graph, you will see vertex point(peak point) is on (h,k)

First of all, i used this vertex formula thing since it is visible that there are quadratic functions. Otherwise, you had to use calculus to get critical points, then second derivative of functions to find the character of critical points as minima or maxima or saddle etc to get the location of vertex point.

This point (h,k) is called the vertex of the parabola that quadratic equation represents.

We are given that;

Focus of parabola= (0,–2)

Now,

The vertex is halfway between the focus and the directrix on a line perpendicular to them. Since the focus is at (0,-2) and the directrix is y = 2, we can find that:

The vertex is at (0,0), because it has an x-coordinate of 0 (same as the focus) and a y-coordinate of 0 (the average of -2 and 2).

p is equal to 2, because it is half of the distance between -2 and 2.

Now we can plug in these values into the formula:

(x - 0)^2 = 4(2)(y - 0)

Simplifying, we get:

x^2 = 8y

Therefore, the equation of the parabola will be x^2 = 8y.

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