If we increase the driving frequency in a circuit with purely resistive load, how do the amplitudes VR and IR change?

Answer: Debbie exerts applied force on the first cart.

Explanation:

The first cart exert applied force on the second cart.

Answer:

Put some melted plastic over the print and let it harden

Explanation:

I think that's how the police do it

This question is incomplete, the complete question is;

Unpolarized light passes through two Polaroid sheets. The transmission axis of the second polarizing filter makes an angle of 34° with the axis of the first polarizer. What fraction of the original unpolarized light is transmitted through the second polarizing filter?

Answer: the fraction of the original unpolarized light transmitted through the second polarizing filter is 0.343

Explanation:

We know that when Unpolarized light passes through first polarizer, it's intensity will be reduced to half  i.e

I1 = I0/2

Now after that when light passes through 2nd polarizer, Intensity will be;

I2 = I1 × (cos A1)²  

but  I1 = I0/2

so

I2 = (I0/2) × (cos A1)²

I2/I0 = 0.5 × (cos A1)²

In the question we were given that; The transmission axis of the second polarizing filter makes an angle of 34° with the axis of the first polarizer

so A = 34°

so we substitute

I2/I0 = 0.5 × (cos 34)²

I2/I0 = 0.343

Therefore the fraction of the original unpolarized light transmitted through the second polarizing filter is 0.343

Answer:

D

Explanation:

The gravitational pull of the planet it orbits holds a moon in its orbit.

Answer:

ΔV = 2.04 x 10⁻⁶ m³ = 2.04 cm³

Explanation:

First we will find the initial volume of mercury by subtracting the volume of the steel ball from the interior volume of the brass shell:

V = Vs - Vb

where,

V = Initial Volume of Mercury  = ?

Vb = Volume of brass shell = 1.26 x 10⁻³ m³

Vs = Volume of Steel Ball = 0.63  x 10⁻³ m³

Therefore,

V = (1.26 x 10⁻³ m³) - (0.63 x 10⁻³ m³)

V = 0.63 x 10⁻³ m³

Now, we find the change in volume of mercury that will spill out due to increase in temperature:

ΔV = βVΔT

where,

ΔV = Amount of Mercury Spilled out = ?

β = Coefficient of Volumetric Expansion of mercury = 1.8 x 10⁻⁴ °C⁻¹

ΔT = Increase in temperature = 18 °C

Therefore,

ΔV = (1.8 x 10⁻⁴ °C⁻¹)(0.63 x 10⁻³ m³)(18 °C)

ΔV = 2.04 x 10⁻⁶ m³ = 2.04 cm³

The volume of mercury that spills out due to increase in temperature is [tex]2.04 \times 10^{-6} \ m^3[/tex].

The given parameters;

The volume of mercury in the given shell is calculated as;

[tex]V= V_1 - V_2\\\\V= 1.26 \times 10^{-3} \ - \ 0.63 \times 10^{-3} \\\\V = 6.3 \times 10^{-4} \ m^3[/tex]

The change in the volume of the mercury is calculated as follows;

[tex]\Delta V = \beta V \Delta t\\\\[/tex]

where;

[tex]\Delta V = (1.8 \times 10^{-4} ) \times (6.3\times 10^{-4}) \times 18\\\\\Delta V = 2.04 \times 10^{-6} \ m^3[/tex]

Thus, the volume of mercury that spills out due to increase in temperature is [tex]2.04 \times 10^{-6} \ m^3[/tex].

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Answer:

The correct option is A

Explanation:

For a substance to boil at 1415 °C shows the substance is an electrovalent/ionic substance (hence the elements are not the answer). Electrovalent/ionic substances are characterized by high melting and boiling points. Also, with a density of 3.13 g/cm³ (with a +/- 0.1 g/cm³), the correct answer is potassium iodide. This is because potassium iodide has a density of 3.12 g/cm³ (which is - 0.1 g/cm³). It should also be noted that pure potassium iodide boils at 1,330 °C, however the presence of impurities could increase the boiling point of the salt, thus an impure potassium iodide could have a density of 3.12 g/cm³ and a temperature around 1415 °C

"Potassium iodide" would it most likely be. A further explanation is provided below.

Given values are:

Density,

Boiling point,

Density can be change by,

Uncertainty in temperature,

We can take the value of density from:

We can take the value of temperature from:

After checking the ranges, we find "Potassium iodide" have density as well as temperature in our range.

Thus the above answer is right.

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Answer:

Option C. 0.36 m/s² to the left.

Explanation:

The following data were obtained from the question:

Mass of skateboarder = 65.2 Kg

Force in the right direction (Fᵣ) = 31.8 N

Force in the left direction (Fₗ) = 55.2 N

Acceleration of the skateboarder =.?

Next, we shall determine the net force acting on the skateboarder. This can be obtained as illustrated below:

Force in the right direction (Fᵣ) = 31.8 N

Force in the left direction (Fₗ) = 55.2 N

Net force (Fₙ) =?

Fₙ = Fₗ – Fᵣ

Fₙ = 55.2 – 31.8

Fₙ = 23.4 N to the left

Thus, the net force acting on the skateboarder is 23.4 N to the left.

Finally, we shall determine the acceleration of the skateboarder. This can be obtained as follow:

Mass of skateboarder = 65.2 Kg

Net force (Fₙ) = 23.4 N to the left

Acceleration (a) of the skateboarder =.?

Net force = mass × acceleration

23.4 N = 65.2 × a

Divide both side by 65.2

a = 23.4 / 65.2

a = 0.36 m/s² to the left.

Therefore, the acceleration of the skateboarder is 0.36 m/s² to the left.

Answer:

C. 0.36 [tex]m/s^{2}[/tex] to the left

Explanation:

you may want to google the answers cuz that is a lot

Answer:

T = 104.2 N

Explanation:

For this exercise we must define a coordinate system, the x axis is horizontal and the y axis is vertical, let's write the equilibrium equations on each axis

X axis

         T₁ₓ-T₂ₓ = 0

         T₁ₓ = T₂ₓ                           (1)

y axis  

         [tex]T_{1y}[/tex] + T_{2y} - W = 0

          T_{1y} + T_{21y} = W      (2)

Let's use trigonometry to find the decomposition of the stresses, they indicate that the angle between the two forces is 140º, but each force has an angle of 70º

           cos 70 = T₁ₓ / T₁

           T₁ₓ = T₁ cos 70

           sin 70 = [tex]T_{1y}[/tex] / T₁

           T_{1y} = T₁ sin 70

for tension 2 we have a similar equation

            T₂ₓ = T₂ cos 70

             T_{2y} = T₂ sin 70

From equation 1

        T₁ cos 70 = T₂ cos 70

        T₁ = T₂

therefore the two children apply the same force

From equation 2

        T sin 70 + T sin 70 = W

        2 T sin 70 = W

        T = W / 2sin 70

        T = 196 / (2 sin 70)

        T = 104.2 N

the two children have the same strength

Answer:

60 maybe

Explanation:

Answer:

1200 newton

and that's 4m/s² not 4 m/s

Answer:D) 7.0 A

Explanation:

The magnetic field strength at the center of a circular loop  is calculated using the formulae

B = μ₀I / 2R

where B = ,magnetic field strength= 1.1mT = 1.1 X 10^-3T

μ₀=  magnetic constant or the permeability of free space=4π X 10^-7 H/m

R = radius = 4.0mm =4.0 x 10^-3m

I= Current = ?

B=μ₀I / 2R

I = B2R /μ₀

I =   1.1 X 10^-3T X 2 X 4.0 x 10^-3m / 4π X 10^-7 H/m

I =7.00 A

Therefore magnitude of the current that flows through the wire is 7.0 A

Answer:

12.5

Explanation:

first, v=d/t

      v=25/2

      v=12.5

The final velocity of the ball is 44.6 m/s.

The given parameters;

The velocity of the ball increases as the ball moves downward and it will become maximum before the ball hits the ground.

This velocity is known as the final velocity of the ball.

The final velocity of the ball is calculated as follows;

v = u + gt

where;

v = 25 + 9.8(2)

v = 44.6 m/s

Thus, the final velocity of the ball is 44.6 m/s.

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Answer:

The balanced condition for Wheatstones bridge is  

Q

P

​  

=  

S

R

​  

as is obvious from the given values.

No, current flows through galvanometer is zero.

Now, P and R are in series, so

Resistance,R  

1

​  

=P+R

=10+15=25Ω

Similarly, Q and S are in series, so

Resistance R  

2

​  

=R+S

=20+30=50Ω

Net resistance of the network as R  

1

​  

 and R  

2

​  

 are in parallel

i=  

R

V

​  

=  

50

6×3

​  

=0.36 A.

Explanation:

Answer:

Its momentum is multiplied by a factor of 1.25

Explanation:

First, we calculate the initial velocity of the object:

With that velocity we can calculate the initial momentum of the object:

Then we calculate the velocity of the object once its kinetic energy has increased:

And calculate the second momentum of the object:

Finally we calculate the factor:

Answer: the minimum spacing that must be there between two objects on the earth's surface if they are to be resolved as distinct objects by this telescope 6.45 cm

Explanation:

Given that;

diameter of the mirror d = 1.7 m

height h = 180 km = 180 × 10³ m

wavelength λ = 500 nm = 5 × 10⁻⁹ m

Now Angular separation from the peak of the central maximum is expressed as;

sin∅= 1.22 λ / d

sin∅ = (1.22 × 5 × 10⁻⁹) / 1.7

 sin∅ = 3.588 × 10⁻⁷

we know that;

 sin∅  = object separation / distance from telescope

object separation =   sin∅ × distance from telescope

object separation = 3.588 × 10⁻⁷  × 180 × 10³

object separation =6.45 × 10⁻² m

then we convert to centimeter

object separation = 6.45 cm

Therefore the minimum spacing that must be there between two objects on the earth's surface if they are to be resolved as distinct objects by this telescope 6.45 cm

Answer:

I = - 0.135 kg m/s

Explanation:

The formula to calculate the impulse of delivered to the ball is:

I = Ft

where,

I = Impulse delivered to the ball by hole = ?

F = Force = ma (By Newton's Second Law)

t = time

Therefore,

I = mat

where,

m = mass of ball = 0.05 kg

a = acceleration of ball = (Vf - Vi)/t

Therefore,

I = m[(Vf - Vi)/t]t

I = m(Vf - Vi)

where,

Vf = Final velocity = - 1.3 m/s

Vi = Initial Velocity = 1.4 m/s

Therefore,

I = (0.05 kg)(- 1.3 m/s - 1.4 m/s)

I = - 0.135 kg m/s

Answer: D) All of the above

Explanation:

Answer:

The value is  [tex]C = 30729\ c[/tex]

Explanation:

From the question we are told that

  The power rating of the stove is  [tex]P = 4.4 KW = 4.4 *10^{3} \ W[/tex]

   The duration of its use everyday is [tex]t_1 = 70 \ minutes = 1.167 \ hours[/tex]    

    The rating of the light bulbs is [tex]P_2' = 150 W[/tex]

   The number is [tex]n = 7[/tex]

   The power rating of the total  bulb is  [tex]P_2 = 7 * 150 = 1050 \ W[/tex]

    The duration of its use everyday is  [tex]t_2 = 7 hours[/tex]

    The power rating of miscellaneous appliance [tex]P_3 = 1.8 \ KW = 1.8 *10^{3} \ W[/tex]

    The duration of its use everyday is [tex]t_3 = 1 hour[/tex]

     The power rating of hot water [tex]P = 4 KW = 4 *10^{3} \ W[/tex]

      The duration of its use everyday is [tex]t_4 = 120 \ minutes = 2 hours[/tex]

Generally the total electrical energy used in 1 month is mathematically represented as

    [tex]E = P_1 * t_1 * 30 + P_2 * t_2 * 30 + P_3 * t_3 * 30+ P_4 * t_4 * 30[/tex]

=>  [tex]E = 4.4*10^{3} * 1.167 * 30 + 1050 * 7 * 30 + 1.8 *1 * 30+ 4*10^{3} * 2 * 30[/tex]

=>  [tex]E = 614598 \ W \cdot h[/tex]

=>   [tex]E = 614.6 \ K W \cdot h[/tex]

Generally the monthly electricity  bill is mathematically represented as

    [tex]C = 614.6 * 50[/tex]

=> [tex]C = 30729\ c[/tex]

Answer: deposition

Explanation:

Try process of elimination. We know it's not boiling because that is basically water turning into gas. It's not condensation because it's not water which collects as droplets on a cold surface when humid air is in contact with it.

Answer:

deposition

Explanation:

Answer:

a the balloon becomes negatively charged

When a charge balloon brought closer to the wall, they will repel each other. Option C is correct.

Electric Charge:

It shows the degree at which the atom or object has less or more electron than proton.

An atom with extra electrons than proton has negative charge while atoms will less electron than proton has positive charge.

Opposite charge always attracts while similar charges repel each other. Since both wall and balloon are negatively charged.

Therefore, when a charge balloon brought closer to the wall, they will repel each other.

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Answer: A. -0.1 m/s

Explanation:

Answer:

The Answer is the first one, A. Or -0.1 m/s.

Explanation:

Answer:

Explanation:

Distance of barrier = 40 m

Distance covered during reaction time = .75 x 40 = 30 m .

distance covered during deceleration can be calculated as follows .

v² = u² - 2 a s

0 = 40² - 2 x 10 x s

s = 80 m

Total distance covered before coming to rest = 30 + 80 = 110 m

Distance of barrier = 40 m , so it will hit the barrier .

Answer:

The weight of the board is 200 N

Explanation:

Translational Equilibrium

An object is in translational equilibrium if the velocity of its translational motion is constant or if it's at rest.

The painter is standing on the single board scaffold, obviously at rest. This means the sum of all translational forces must be zero.

If the tensions of both ropes are T1 and T2, the weight of the painter is Wp, and the weight of the board is Wb, then:

T1 + T2 - Wp - Wb = 0

Both tensions go vertically up and both weights go vertically down.

Solving for Wb:

Wb = T1 + T2 - Wp

Wb = 550 N + 450 N - 800 N

Wb = 200 N

The weight of the board is 200 N

Answer:

dx = 2000 [m]

Explanation:

To solve this problem we must use the following equation of kinematics.

[tex]dx =v_{o}*t +\frac{1}{2} *a*t^{2}[/tex]

where:

dx =  distance [m]

Vo = initial velocity = 100 [m/s]

a = acceleration = 20 [m/s²]

t = time = 10 [s]

dx = 100*10 + 0.5*20*10²

dx = 2000 [m]

Note: the positive sign in the above equation means that the car is increasing its velocity.

Answer:

B???

Explanation:

guess

The shortest distance that the student could travel between home and school is approximately 539 meters.

Hence Option C) 539m is the correct answer.

Given the data in the question;

As illustrated in the image below,

We get a right angled triangle and the hypotonus "c" is the shortest distance from the student's house to her school.

Now, using  Pythagorean theorem:

[tex]a^2 + b^2 = c2[/tex]

We substitute our values into the expression and solve for "c"

[tex](500m)^2 + (200m)^2 = c^2\\\\250000m^2 + 40000m^2 = c^2\\\\c^2 = 290000m^2\\\\c = \sqrt{290000m^2}\\\\c = 539 m[/tex]

The shortest distance that the student could travel between home and school is approximately 539 meters.

Hence Option C) 539m is the correct answer.

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RLLY?

Explanation:

ALSO

MY DAD ALWAYS TELLS ME THAT IF YOUR FEET ARE COLD THAT YOU NEED TO PUT A HAT ON?!?!?!?!?!

Answer:

interphase

Explanation: