If path has 56 marbles and he gave Sandra 34 how many marbles will he have left?​

Answers

Answer 1

Answer:

22

Step-by-step explanation:

You just subtract them

56-34

= 22

Answer 2
56-34= 22
Therefore your answer is 22

Related Questions

Picking a card and spinning a spinner are independent events.

True
False

Answers

Answer:

True

Step-by-step explanation:

Both happened in different times and are seprate events

look at the image below

Answers

Answer:

272 yd²

Step-by-step explanation:

Surface area = base area + lateral area

= (10×10)+(8.6×10×2)

= 100+172

= 272 yd²

Subtract the integers. 22−​(−10​)​

Answers

Answer:

32

Step-by-step explanation:

Step 1: change 22 - ( -  10) into 22 + 10

Step 2: solve it like normal

Fewer and fewer customers have been coming into the restaurant, so Bill, the manager, decides to change the entire menu. After he does this, he finds out that people loved the food, but the service has been driving people away. This represents what kind of problem in the decision-making process? O a) Failure to develop enough options O b) Failure to correctly define the problem c) Failure to act on a decision O d) Failure to evaluate the decision

Answers

Answer:

failure to correctly define the problem

Step-by-step explanation:

He changes the menu without identify that the real problem was the service.

Find the shortest distance from A
to C
in the diagram below.

Answers

9514 1404 393

Answer:

  5√13 m

Step-by-step explanation:

The length of the space diagonal is the "Pythagorean sum" of the lengths of the edges of the cuboid.

  AC = √(8² +6² +15²) = √325 = √(13·25)

  AC = 5√13 . . . meters

__

AB is the hypotenuse of the right triangle with legs 6 and 8, so is 10 units. AC is the hypotenuse of right triangle ABC, so is ...

  AC = √(AB² +BC²) = √(10² +15²)

(20/2 + 4)/2

^^^ I NEED A EQUATION LIKE THAT BUT FOR IT TO EQUAL 16

Answers

Answer:

Here are a few examples.

(30/2 + 1)/2

(26/2 + 3)/2

(28/2 + 2)/2

A.60
B.40
C.24
D.20
Please help me on this

Answers

Answer:

The answer is 20

Step-by-step explanation:

3 times 2 is 6, and 120 divided by six is 20%.

8 millions =
how many hundred thousands

Answers

Answer:

100000

Step-by-step explanation:

100000x80=8m

solve the equation
0.09w+1.8

Answers

Step-by-step explanation:

0.09w + 1.8 = 0

0.09w = 0 - 1.8

0.09w = - 1.8

0.09w ÷ 0.09 = - 1.8/ 0.09

w = - 20

If K = (AB)/(A+B) , then B = ?

(a) (A)/(1−A)
(b) (AK)/(A−K)
(c) (AK)/(K−A)
(d) (A+K)/(A)
(e) (A−K)/(AK)

Answers

Lets do

[tex]\\ \sf\longmapsto K=\dfrac{AB}{A+B}[/tex]

[tex]\\ \sf\longmapsto \dfrac{1}{K}=\dfrac{A+B}{AB}[/tex]

[tex]\\ \sf\longmapsto \dfrac{1}{K}=\dfrac{1}{A}+\dfrac{1}{B}[/tex]

[tex]\\ \sf\longmapsto \dfrac{1}{B}=\dfrac{1}{K}-\dfrac{1}{A}[/tex]

[tex]\\ \sf\longmapsto \dfrac{1}{B}=\dfrac{K-A}{AK}[/tex]

[tex]\\ \sf\longmapsto B=\dfrac{AK}{K-A}[/tex]

Is u=−12 a solution of 8u−1=6u?

Answers

Answer:

No, -12 is not a solution.

Step-by-step explanation:

8u-1=6u

8(-12)-1=6(-12)

-96-1=-72

-97=-72

Untrue, to it’s not a solution

the factor of 12 are ...............​

Answers

Answer:

1, 2, 3, 4, 6, and 12

Step-by-step explanation:

Answer:

1,2,3,4,6,12

Step-by-step explanation:

because they divide the numbers without any remainder.

Paul bought a student discount card for the bus. The card allows him to buy daily bus passes for $1.70.
After one month, Paul bought 16 passes and spent a total of $35.20.
How much did he spend on the student discount card?

Answers

He spent $22.5 on the student discount card.

This question is solved using proportions.

The cost of each card is of $1.50.

Paul bought 15 passes, that is, 15 cards.

Considering that he bought 15 cards, each for $1.50, his spending was of:

He spent $22.5 on the student discount card.

While organizing the magazines at the doctor's office, Camille put 12 magazines in the first pile, 15 magazines in the second pile, 18 magazines in the third pile, 21 magazines in the fourth pile, and 24 magazines in the fifth pile. If this pattern continues, how many magazines will Camille put in the sixth pile?

Answers

Answer:

27

Step-by-step explanation:

since you are adding 3 to the pile each time, on the 6th pile you would have 27 because 24 + 3 = 27

area of a triangle 5cm base and 4 cm height

Answers

Answer:

1/2 base×height

1/2 .5×4

1/2.20

20 divided by 2 is 10

1/1×10

10cm2

ans

5404 buttons are produced by a factory in Jebel Ali in a week. If the factory produced same number of buttons every day of the week, buttons produced in a day is _________________​

Answers

We need to find the number of buttons the company produced per day

The company produced 772 buttons per day

Total bottons produced in a week = 5404

There are 7 days in a week

If the factory produced same number of buttons every day of the week

Then,

Buttons produced per day = Total bottons produced in a week / Total number of days in a week

= 5404 / 7

= 772 buttons

The company produced 772 buttons per day

Read more: https://brainly.com/question/24368335

Solve the system of equations.

6x−y=−14
2x−3y=6

whats the answer please C:

Answers

Answer:

Step-by-step explanation:

Which of the following factorizations is correct?

O x3 + 27 = (x - 3)(x2 + 3x – 9)

O x - 27 = (x - 3)(x2 + 3x +9)

O x3 - 27 = (x - 3)(x2 +9)

O x3 + 27 = (x - 3)(x2 - 9)

Answers

Answer:

first one is correct bro

The correct factorization of x³ - 27 is  (x - 3)(x² + 3x + 9).

What are the formulas for a³ + b³ and a³ - b³?

a³ + b³ = (a + b)(a² -ab + b²) and a³ - b³ = (a - b)(a² + ab + b²).

If we know the formula of these two we can conclude by observing that

the second option x³ - 27 = (x - 3)(x² + 3x +9) is correct.

As x³ - 27

= x³ - 3³.

= (x - 3)(x² + 3x + 9).

learn more about algebraic formulas here :

https://brainly.com/question/14583646

#SPJ2

If the prism has 3 layers, what would the volume of the
prism be in cubic centimeters?
OA) 4 cubic centimeters
OB) 8 cubic centimeters
OC) 12 cubic centimeters
OD) 16 cubic centimeters

Answers

Answer:

OD) 16 cubic centimeters

The sum of two numbers is 41. The larger number is 17 more than the smaller number. What are the numbers?
Larger number:
Smaller number:

Answers

Let x = the larger number
Let x - 17 = the smaller number
x + x + 17 = 41
2x + 17 = 41
2x = 58
x = 29
x - 17 = 29 - 17 = 12

Find the area of the figure

A =

Answers

Answer:

207 m

Step-by-step explanation:

17 x 6 = 102

15 + 6 = 21

5 x 21 = 105

105 + 102 = 207 m^2

Answer:

207m

Step-by-step explanation:

(17+5)*6=132

(15*5)=75

132+75=207

please solve asap thanks ​

Answers

Answer:

6x+36=180

6x=144

x=24

Step-by-step explanation:

this is the correct answer

X=24 That is the correct answer

For a particular​ event, 669 tickets were sold for a total of ​$4293. If students paid ​$5 per ticket and nonstudents paid ​$8 per​ ticket, how many student tickets were​ sold?

Answers

Answer:

353 tickets.

Step-by-step explanation:

Let's say that there are s student tickets and n nonstudent tickets.

s + n = 669

5s + 8n = 4293

Multiply -5 by the entire first equation to get...

-5s - 5n = -3345

Combine the two equations.

5s - 5s + 8n - 5n = 4293 - 3345

3n = 948

n = 316

Now, put the number of nonstudent tickets sold back into the first equation.

s + 316 = 669

s = 353 tickets.

Hope this helps!

What is 10,000,000 + 700,000,000 + 2,000,000 + 9,000 + 4 + 400,000 + 10,000 + 70 + 700 in standard form?

Answers

10,000,000+700,000,000+2,000,000+9,000+4+400,000+10,000+70+700=712419774

please mark this answer as brainlist

120 students, 41 for maths, 48 for chemistry, 42 for physics. 16 study both chemistry and maths, 14 study maths and physics, 18 study chemistry and physics, 9 study the three subjects, 1) how many of them study exactly one subject. 2) At least one subject. 3) None of the Subject

Answers

Answers:

number who study exactly one subject = 62number who study at least one subject = 92number who study none of the subjects = 28

The venn diagram is shown below.

========================================================

Explanation:

M = set of people studying math

C = set of people studying chemistry

P = set of people studying physics

Something like the notation n(C) refers to the count of items in set C, aka the number of people who study chemistry. Similar ideas apply to n(M) and n(P) to refer to the counts of math and physics respectively.

Something like n(C and M) is the number of people who study chemistry and math. Same idea applies to something like n(C and P) or n(M and P)

With all that in mind, we have these 7 facts

n(M) = 41 n(C) = 48 n(P) = 42 n(C and M) = 16 n(M and P) = 14 n(C and P) = 18 n(C and M and P) = 9

We'll start with fact 7. This value goes in the very center of the 3 overlapping circles of the venn diagram. Refer to the diagram below.

Since 9 people study all three subjects, and 16 study chemistry and math, this must mean 16-9 = 7 people study chemistry and math without physics involved. We'll write 7 in the region between circles C and M, but outside of circle P.

Since 9 people study all three subjects, and 14 study math and physics, we know that 14-9 = 5 people study only math and physics without chemistry. We'll write 5 in the region between circles M and P, but outside circle C.

Since 9 people study all three subjects, and 18 study chemistry and physics, we know that 18-9 = 9 people study only chemistry and physics without math. We'll write 9 in the region between circles C and P but outside circle M.

If you're lost, then refer the diagram below. So far, we have filled in the very center "9" and the closest three values surrounding it (the 7, 9 and 5).

-------------------------

Focus your attention on circle M for now. The values in this circle add to: 7+9+5 = 21

Since n(M) = 41, this must mean the missing value must be 20. This goes in circle M but outside the other two circles.

Note how 7+9+5+20 = 41 when we add everything in circle M. This circle is completely filled out. We'll follow a similar path for the other circles.

Move onto circle C. Adding everything in it so far gets us 9+9+7 = 25. We want to get to n(C) = 48 which means we need to have 48-25 = 23 in circle C but outside the other circles. Circle C is now done.

Lastly, focus on circle P. The values we found so far in this circle add to 9+9+5 = 23. The missing value must be 19 because 42-23 = 19, and n(P) = 42.

-------------------------

At this point, all three circles are filled out. The only thing missing is the number outside the circles, but inside the rectangle.

Add up everything in the circles: 23+7+20+9+9+5+19 = 92

This tells us that we have 92 people who studied at least one subject (i.e. one or more subjects). There are 120 people surveyed, meaning that 120-92 = 28 people study neither of these subjects. We write 28 outside the circles.

-------------------------

The venn diagram is done by this point. To address the questions, we'll just read from the diagram (and at most do an addition problem).

To find the number of people who study exactly one subject, we will add up the numbers that are in one circle but not in any other circle. Those values are: 23, 20, and 19. So 23+20+19 = 62 people study exactly one subject.

We already found the number of people who study at least one subject, and that was 92 people. This was when we added every number in the circles.

For the last question, we already found this value as well. This answer is 28 people which is found outside all three circles.

The venn diagram is shown below to visually summarize and organize all of the data. Hopefully it clears up any confusion you may have about the previous steps.

Total number of students who exactly one subject is 62

No of students who study at least one subject is 92

No of students who do not study any subject is 28

let us do this problem by set theory.

in the attached figure

three circles have been drawn representing the number of students studying maths, physics and chemistry.

from the diagram

1) Number of students who study exactly one subject=no of students who study maths + number of students who study chemistry+number of students who study physics- 2*[number of students who study both physics and chemistry-number of students who study both physics and maths-number of students who study both maths and chemistry ]+3*number of students who study all three subjects

from the attached figure,

2) Total number of students who exactly one subject = 20+19+23 = 62

3) No of students who study at least one subject will be the sum of each data in the attached figure i.e union of all three sets.

no of students who study at least one subject = 20+7+5+9+19+9+23=92

no of students who do not study any subject = total students- the union of all three sets.

no of students who do not study any subject = 120-92 = 28

therefore,

total number of students who exactly one subject is 62

no of students who study at least one subject is 92

no of students who do not study any subject is 28

to get more about set theory refer to the link,

https://brainly.com/question/13458417

Quadrilateral ABCD has vertices A(–1, –2), B(–1, 3), C(4, 3) and D(4, –2). It’s dilated by a factor of 2 with the center of dilation at the origin. What are the coordinates of the resulting quadrilateral A’B’C’D

Answers

9514 1404 393

Answer:

A'(-2, -4)B'(-2, 6)C'(8, 6)D'(8, -4)

Step-by-step explanation:

Dilation about the origin multiplies each coordinate value by the dilation factor.

  A' = 2A = 2(-1, -2) = (-2, -4)

  B' = 2B = 2(-1, 3) = (-2, 6)

 C' = 2C = 2(4, 3) = (8, 6)

  D' = 2D = 2(4, -2) = (8, -4)

what is the tan invers of 3i/-1-i​

Answers

z = 3i / (-1 - i )

z = 3i / (-1 - i ) × (-1 + i ) / (-1 + i )

z = (3i × (-1 + i )) / ((-1)² - i ²)

z = (-3i + 3i ²) / ((-1)² - i ²)

z = (-3 - 3i ) / (1 - (-1))

z = (-3 - 3i ) / 2

Note that this number lies in the third quadrant of the complex plane, where both Re(z) and Im(z) are negative. But arctan only returns angles between -π/2 and π/2. So we have

arg(z) = arctan((-3/2)/(-3/2)) - π

arg(z) = arctan(1) - π

arg(z) = π/4 - π

arg(z) = -3π/4

where I'm taking arg(z) to have a range of -π < arg(z) ≤ π.

How do I solve for y:
x²y² = 12/z²

Answers

Answer:

Y=Srt(12xs^2/z^2)

Step-by-step explanation:

Firstly

We multiply both sides with 1/x^2

We get

Y^2=12/z^2*1/x^2

Y^2=12x^2/z^2

Next: introduce a srt root

We have

Y=srt(12x^2/z^2)

If there are 43,560 square feet in an acre, and there are 7.5 gallons in a cubic foot, calculate gallons of irrigation water per square foot?​

Answers

The following information related to irrigation is as follows:

It is the water application that should be artificial via different sprays, pumps systems.It could be found from the groundwater via springs, surface water, etc

The gallons of irrigation water per square foot is [tex]326,700\ gallons\ per\ square\ foot[/tex]

For determining the gallons of irrigation water we have to multiply the square foot by the number of gallons in a cubic foot.

Given that,

There are 43,560 square feet in an acre i.e. 1 acre = 43,560.

And, there are 7.5 gallons in a cubic foot i.e. 1 cubic foot = 7.5 gallons.

So, the gallons of irrigation water per square foot is

[tex]= 43,560 \times 7.5\ gallons \\\\= 326,700\ gallons\ per\ square\ foot[/tex]

Therefore we can conclude that the gallons per square foot of irrigation water is [tex]326,700\ gallons\ per\ square\ foot[/tex]

Learn more about per square foot here: brainly.com/question/5991264

Answer:

326,700 gallons

Step-by-step explanation:

1 acre = 43,560 square feet

1 acre-foot of irrigation is an acre irrigated 1 foot deep with water.

Since thee are approximately 7.5 gallons in 1 cubic foot,

1 acre-foot of irrigation = 43,560 * 7.5 gallons

1 acre-foot = 326,700 gallons

This is the number of gallons in one acre-foot, not gallons per square foot.

10a+5(a-3)=15 I don’t know the answer I keep checking and it’s wrong

Answers

Answer:

[tex]10a + 5(a - 3) = 15 \\ 10a + 5a - 15 = 15 \\ 15a = 30 \\ a = \frac{30}{15} \\ a = 2 \\ 10 \times 2 + 5(2 - 3) = 15 \\ 20 + - 5 = 15 \\ 15 = 15 \\ lhs = rhs\\ thank \: you[/tex]

Answer: a = 2

Solve:

Given

10a + 5 (a - 3) = 15

Expand parentheses and apply the distributive property

10a + 5 · a - 5 · 3 = 15

10a + 5a - 15 = 15

Combine like terms

(10a + 5a) - 15 = 15

15a - 15 = 15

Add 15 on both sides

15a - 15 + 15 = 15 + 15

15a = 30

Divide 15 on both sides

15a / 15 = 30 / 15

[tex]\boxed{a=2}[/tex]

Check:

Left-hand side = 10a + 5 (a - 3)

Left-hand side = 10(2) + 5 (2 - 3)

Left-hand side = 20 + 5(-1)

Left-hand side = 20 - 5

Left-hand side = 15

Right-hand side = 15

15 = 15, therefore, [tex]\boxed{a=2}[/tex] would make the equation true.

Hope this helps!! :)

Please let me know if you have any questions

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