A(t)=P(1+r)t
A = accrued amount = what you are solving for
P = principle investment = $400
r = rate of growth = 5% = 0.05
t = time = 10 years
A(10) = 400(1.05)10 (use calculator to solve)
A(10) ≈ 4,200
Which choice shows 14 •(8 . 2) correctly rewritten using the associative property and then correctly simplified?
(14.8.2 = 112 · 2 = 224
(14.82) = 1, 148
14. (2. 8) = 14 · 16 = 224
14.2.8 = 28. 8 = 224
Step-by-step explanation:
=14×(8×2)
=14(16)
=224
What is word and expanded form of 5,901,452
She arrived at the car park at 2.15pm and leaves at 4.45pm on Thursday. how much does Diane pay for her car parking? Monday - Friday up to 2 hours £3.00 2-4 hours £4.50 5 hours + £5.50
Answer:
£4.50
Step-by-step explanation:
She is at the car park for 2 hours and 30 minutes.
It would be £4.50 because 2 hours and 30 minutes is between 2-4 hours.
It can't be £3.00 because it would be too little time (2 hours or less) and it wouldn't be £5.50 because she would be paying for more time than she was there for (5 hours or more).
Hope this helps :)
Solve for y 2y+1>-9/5y-6
Answer: All real numbers
Step-by-step explanation:
Let's find the critical points of the inequality.
2y2+1=
−9
5
y−6
2y2+1−(
−9
5
y−6)=
−9
5
y−6−(
−9
5
y−6)(Subtract (-9)/5y-6 from both sides)
2y2+
9
5
y+7=0
For this equation: a=2, b=1.8, c=7
2y2+1.8y+7=0
y=
−b±√b2−4ac
2a
(Use quadratic formula with a=2, b=1.8, c=7)
y=
−(1.8)±√(1.8)2−4(2)(7)
2(2)
y=
−1.8±√−52.76
4
Simplify this radical.
90
3/10
6/10
9/10
103
Need help please on this
Answer:
3[tex]\sqrt{10}[/tex]
Step-by-step explanation:
Assuming you mean [tex]\sqrt{90}[/tex]
Using the rule of radicals
[tex]\sqrt{a}[/tex] × [tex]\sqrt{b}[/tex] ⇔ [tex]\sqrt{ab}[/tex] , then
[tex]\sqrt{90}[/tex]
= [tex]\sqrt{9(10)}[/tex]
= [tex]\sqrt{9[/tex] × [tex]\sqrt{10}[/tex]
= 3[tex]\sqrt{10}[/tex]
Can someone help me find the standard deviation of this data set plssss
35
27
24
42
25
31
41
34
32
46
29
44
29
35
39
27
41
63
52
31
38
46
39
27
58
32
33
47
36
28
65
53
40
32
39
44
48
59
46
62
22
39
35
29
36
66
33
45
50
62
27
27
41
33
54
44
26
31
45
33
42
63
51
70
42
53
38
28
35
49
47
54
44
40
39
62
30
35
38
26
34
61
19
30
34
26
41
35
26
54
28
32
50
27
31
35
38
26
47
30
28
62
57
56
30
32
31
36
32
42
33
51
35
30
28
20
23
27
33
36
35
42
43
28
36
44
58
41
36
37
49
34
23
39
34
37
62
23
28
26
29
30
37
46
43
56
53
31
36
44
39
51
21
51
34
30
25
31
38
52
49
43
50
31
36
32
28
44
61
57
24
63
28
31
32
26
28
since it was too long, I just made this python code in order to solve for it:
from math import *
data = [35, 27, 24, 42, 25, 31, 41, 34, 32, 46, 29, 44, 29, 35, 39, 27, 41, 63, 52, 31, 38, 46, 39, 27, 58, 32, 33, 47, 36, 28, 65, 53, 40, 32, 39, 44, 48, 59, 46, 62, 22, 39, 35, 29, 36, 66, 33, 45, 50, 62, 27, 27, 41, 33, 54, 44, 26, 31, 45, 33, 42, 63, 51, 70, 42, 53, 38, 28, 35, 49, 47, 54, 44, 40, 39, 62, 30, 35, 38, 26, 34, 61, 19, 30, 34, 26, 41, 35, 26, 54, 28, 32, 50, 27, 31, 35, 38, 26, 47, 30, 28, 62, 57, 56, 30, 32, 31, 36, 32, 42, 33, 51, 35, 30, 28, 20, 23, 27, 33, 36, 35, 42, 43, 28, 36, 44, 58, 41, 36, 37, 49, 34, 23, 39, 34, 37, 62, 23, 28, 26, 29, 30, 37, 46, 43, 56, 53, 31, 36, 44, 39, 51, 21, 51, 34, 30, 25, 31, 38, 52, 49, 43, 50, 31, 36, 32, 28, 44, 61, 57, 24, 63, 28, 31, 32, 26, 28]
def stand_dev(list_n):
x = 0
sum_num = 0
for x in list_n:
sum_num += list_n[x]
sum_of_n = sum_num
mean = float(sum_of_n / len(list_n))
float(mean)
i = 0
e = 0.0
for i in list_n:
subtract_then_square = (list_n[i] - mean)**2
e += subtract_then_square
result1 = e
new_mean = result1 / len(list_n)
final_result = float(sqrt(new_mean))
return final_result
print(stand_dev(data))
basically, the first chunk of the code calculated the mean of the data. The second chunk would take all of the values from the data, subtract it from the mean, and then square it. I then took the sum of all the new values and average it to get the new mean, then square rooted the new mean to get the answer.
it should be ~= 11.713, but you can always check it by searching up a python compiler online and then insert in the data.
Answer:
I used MS excel and got the attached results.
Note the data is sorted and the data size is 177.
The answer I got is 11.31045226
The curve y=2x^3+ax^2+bx-30 has a stationary point when x=3. The curve passes through the point (4,2).
(A) Find the value of a and the value of b.
#secondderivative #stationarypoints
A stationary point at x = 3 means the derivative dy/dx = 0 at that point. Differentiating, we have
dy/dx = 6x ² + 2ax + b
and so when x = 3,
0 = 54 + 6a + b
or
6a + b = -54 … … … [eq1]
The curve passes through the point (4, 2), which is to say y = 2 when x = 4. So we also have
2 = 128 + 16a + 4b - 30
or
16a + 4b = -96
4a + b = -24 … … … [eq2]
Eliminate b by subtracting [eq2] from [eq1] and solve for a, then for b :
(6a + b) - (4a + b) = -54 - (-24)
2a = -30
a = -15 ===> b = 96
An initial deposit of $10000 is left in account for 5.5 years at 3.6% interest compounded continuously. What is the
final value of the account to the nearest dollar after the 5.5 years?
Answer:
11980
Step-by-step explanation:
This is simple interest.
We use the formula i=prt. Interest = price x rate x time
You just plug in your numbers, 10000 is your price, 5.5 years is the time, and 3.6% interest is rate.
Now our equation looks like this: i = 10000 x 5.5 x 0.036
(i converted the percent to a decimal)
So the interest is 1980, but the question asks for the final value, so we add the interest to the initial deposit, 1980 + 10000, and we get 11980 for our final value.
I apologize if my answer is wrong, but if it isn't I hope I helped :)
9514 1404 393
Answer:
$12,190
Step-by-step explanation:
The formula for the balance in an account where continuous compounding occurs is ...
A = Pe^(rt) . . . . where P is the principal invested at annual rate r for t years
A = $10,000e^(0.036·5.5) = $10,000e^0.198
A ≈ $12189.62 ≈ $12,190 . . . . rounded to the nearest dollar
which is the graph of the function fx=x^2+2x+3
Answer:
see below
Step-by-step explanation:
fx=x^2+2x+3
This is a parabola that opens upward
f(x) = (x^2 +2x)+3
= (x^2+2x+1) +3-1
= (x+1)^2 +2
This is in vertex form y =a(x-h)^2 +h where the vertex is (h,k)
This has a vertex as (-1,2)
And has a y intercept at (0,3)
this does not cross the x axis
Help me solve please
(3a^4b/2b^3)^3
cube all the terms:
3^3 = 27
b^3
(a^4)^3 = a^(4*3) = a^12
2^3 = 8
(b^3)^3 = b^3*3 = b^9
27a^12b^3 / 8b^9
Divide the b terms to get the final answer:
27a^12 / 8b^6
look at the image below
Answer:
16
Step-by-step explanation:
volume= Length x width x height
Answer:
Volume: [tex]1/3\times Area\; of\; base\;\times height[/tex]
[tex]= 1/3\times2\times 2\times 4[/tex]
[tex]=16/3\; ft^{3}[/tex]
[tex]=5.3\; ft^{3}[/tex]
OAmalOHopeO
Jane and her two friends will rent an apartment for S550 a month, but Jane will pay double what each friend does because she will have her own bedroom.
How much will Jane pay a month?
Answer:
$275 a month
Step-by-step explanation:
Let x represent how much each friend is paying.
The amount Jane pays can be represented by 2x, since she is paying double than her friends.
Add together these terms and set them equal to 550. Then, solve for x:
x + x + 2x = 550
4x = 550
x = 137.5
So, each friend is paying $137.50. Double this to find how much Jane is paying:
137.5(2)
= 275
So, Jane is paying $275 a month
4) What is the perimeter of a square with side length Of 3 squared
Answer:
36
Step-by-step explanation:
3² = 9.
So, the perimeter is 9(4) = 36
HELP ASAP!!!!
Lydia is creating floral centerpieces for a friend's wedding. She is trying to decide the amount of tulips and peonies she should include in the centerpieces. The table below shows the number of flowers she plans to use in each centerpiece. The total number of flowers used for each centerpiece should be no more than 21 flowers.
Flower Type Number
Sweet Pea 8
Hyacinth 2
Tulip t
Gardenia 3
Peony p
First, select the inequality that can be used to represent the number of peonies, p, and tulips, t, Lydia can use in each centerpiece. Then, select possible combinations of peonies and tulips that could be in a centerpiece to satisfy the inequality.
answers
13 - (t + p) ≤ 21
13 + p + t ≥ 21
3 tulips and 9 peonies
2 tulips and 3 peonies
13 + t + p ≤ 21
6 tulips and 4 peonies
5 tulips and 3 peonies
21 - p + t ≥ 13
9514 1404 393
Answer:
13 + t + p ≤ 215 tulips and 3 peonies2 tulips and 3 peoniesStep-by-step explanation:
"No more than 21" means "less than or equal to 21." The total of flowers Lydia has listed is ...
8 + 2 + t + 3 + p = 13 +p +t
Lydia wants this less than or equal to 21, so the appropriate inequality is ...
13 +p +t ≤ 21
__
Subtracting 13 from both sides gives us a relation that helps us better see the possible values of p and t.
p +t ≤ 8
Then suitable numbers of peonies and tulips will numbers that total 8 or less. Of the choices listed, ones that match that requirement are ...
2 tulips and 3 peonies
5 tulips and 3 peonies
Savannah used 2 quarts of paint on a summer project. She still had 5.
quarts of paint left when she was finished. How much paint did Savannah
have at first?
la cloud
Answer:
7 quarts
Step-by-step explanation:
total paint = paint used + paint left
total paint = 2 +5
total paint 7
e/22 = 6/15, What does e equal? Please answer with work!
Answer:
e = 44/5 = 8.800
Step-by-step explanation:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
e/22-(6/15)=0
Step by step solution :
STEP
1
:
2
Simplify —
5
Equation at the end of step
1
:
e 2
—— - — = 0
22 5
STEP
2
:
e
Simplify ——
22
Equation at the end of step
2
:
e 2
—— - — = 0
22 5
STEP
3
:
Calculating the Least Common Multiple :
3.1 Find the Least Common Multiple
The left denominator is : 22
The right denominator is : 5
Number of times each prime factor
appears in the factorization of:
Prime
Factor Left
Denominator Right
Denominator L.C.M = Max
{Left,Right}
2 1 0 1
11 1 0 1
5 0 1 1
Product of all
Prime Factors 22 5 110
Least Common Multiple:
110
Calculating Multipliers :
3.2 Calculate multipliers for the two fractions
Denote the Least Common Multiple by L.C.M
Denote the Left Multiplier by Left_M
Denote the Right Multiplier by Right_M
Denote the Left Deniminator by L_Deno
Denote the Right Multiplier by R_Deno
Left_M = L.C.M / L_Deno = 5
Right_M = L.C.M / R_Deno = 22
Making Equivalent Fractions :
3.3 Rewrite the two fractions into equivalent fractions
Two fractions are called equivalent if they have the same numeric value.
For example : 1/2 and 2/4 are equivalent, y/(y+1)2 and (y2+y)/(y+1)3 are equivalent as well.
To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.
L. Mult. • L. Num. e • 5
—————————————————— = —————
L.C.M 110
R. Mult. • R. Num. 2 • 22
—————————————————— = ——————
L.C.M 110
Adding fractions that have a common denominator :
3.4 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
e • 5 - (2 • 22) 5e - 44
———————————————— = ———————
110 110
Equation at the end of step
3
:
5e - 44
——————— = 0
110
STEP
4
:
When a fraction equals zero :
4.1 When a fraction equals zero ...
Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.
Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.
Here's how:
5e-44
————— • 110 = 0 • 110
110
Now, on the left hand side, the 110 cancels out the denominator, while, on the right hand side, zero times anything is still zero.
The equation now takes the shape :
5e-44 = 0
Solving a Single Variable Equation:
4.2 Solve : 5e-44 = 0
Add 44 to both sides of the equation :
5e = 44
Divide both sides of the equation by 5:
e = 44/5 = 8.800
One solution was found :
e = 44/5 = 8.800
Answer:
e =44/5
Step-by-step explanation:
e 6
----- = --------
22 15
Using cross products
e * 15 = 6 *22
15e = 132
Divide by 15
15e/15 = 132/15
e =44/5
QUESTION 5 - 1 POINT
An investment of $32,000 is worth $38,302 after being compounded monthly at 3%. How many years was the investment
for? (Round to the nearest whole year).
9514 1404 393
Answer:
6
Step-by-step explanation:
The compound interest formula tells you the future value of principal P invested at annual rate r compounded n times per year for t years is ...
A = P(1 +r/n)^(nt)
Solving for t, we get ...
t = log(A/P)/(n·log(1 +r/n))
Using the given values, we find t to be ...
t = log(38302/32000)/(12·log(1 +0.03/12)) ≈ 5.9997
The investment was for 6 years.
Apply Simpson's rule to approximate the value of integration 1 to 4 e^x In x dx with n = 3.
[tex]Here, h=41,0.25,y=1+x21
[/tex]
[tex]x y101.020.25 0.9413 0.250.94140.750.64510.5
[/tex]
[tex]By Simpson's Rule:
[/tex]
[tex]∫011+x2dx=4×31
[/tex]
[tex][(1+0.5)+4(0.941+0.941+0.64)+2(0.8)]
[/tex]
[tex]=121[9.424]=0.785
[/tex]
-p/3-8=3 what is the variable
Answer:
-33
Step-by-step explanation:
-p/3-8=3
or,(-p-24)/3=3
or,(-p-24)=9
or,-p=33
Therefore, p=-33
NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW. Ch. 15 part 1a
How can a matrix be used to solve a system of equations. Demonstrate by solving the following system. Show your work.
We are given the equations:
x - 3y = 2
3x - 4y = 0
writing the system as matrices
[tex]\left[\begin{array}{ccc}1&-3\\3&-4\end{array}\right][/tex][tex]\left[\begin{array}{ccc}x\\y\end{array}\right][/tex] = [tex]\left[\begin{array}{ccc}2\\0\\\end{array}\right][/tex]
which is in the form:
AX = B
solving for X(the matrix holding the variables), we get:
X = (A⁻¹)B
Finding A⁻¹:
now, to do this, we need to find the inverse of A
[tex]\left[\begin{array}{ccc}w&x\\y&z\end{array}\right]^{-1} = \frac{1}{wz-xy}\left[\begin{array}{ccc}z&-x\\-y&w\end{array}\right][/tex]
using this formula to find the inverse of matrix A:
[tex]A^{-1} = \frac{1}{(1*-4)-(-3*3)}\left[\begin{array}{ccc}-4&3\\-3&1\end{array}\right][/tex]
[tex]A^{-1} = \frac{1}{5}\left[\begin{array}{ccc}-4&3\\-3&1\end{array}\right][/tex]
Matrix X:
We know that:
X = A⁻¹B
[tex]X = \frac{1}{5}\left[\begin{array}{ccc}-4&3\\-3&1\end{array}\right] * \left[\begin{array}{ccc}2\\0\end{array}\right][/tex]
[tex]X = \frac{1}{5}\left[\begin{array}{ccc}-8\\-6\end{array}\right][/tex]
since matrix X is just a matrix with the variables
[tex]\left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}\frac{-8}{5}\\\frac{-6}{5}\end{array}\right][/tex]
x = -8/5
y = -6/5
Solve the equation for y. Identify the slope and y- intercept. Then graph the equation. 2y-3x=10
Answer:
y=3/2x+5
The slope is 3/2 and the y-intercept is 5
Step-by-step explanation:
Solving for y will give us the slope and y-intercept
Isolate y
2y/2=10+3x/2
y=5+3/2x
The slope is 3/2 and the y-intercept is 5
Graph it by graphing (0,5) and using the slope (up 3 over 2) to put other points
Instructions: The polygons in each pair are similar. Find the
missing side length.
Answer:
missing side length is 12
Step-by-step explanation:
similar means that all correlating pairs of sides have the same ratio (old side length) / (new side length).
so, when we know the ratio of one pair, we can apply it to any other side to calculate the correlating side.
we see, when we go from small to large, that we have the ratio 32/40 = 4/5.
so, multiplying the larger side by this, we get the shorter side.
15 × 4/5 = 3 × 4 = 12
the proportion part in your picture is a bit confusing :
yes,
x/15 = 32/40 = 32/40
I don't know, why this last expression was repeated.
x/15 = 32/40
x = 15×32/40 = 15×4/5 = 3×4 = 12
as you see we get of course the same result doing it that way.
Which one
Dndns sjsjsjsj
Answer:
Step-by-step explanation:
It's the first / top most option. This is because n < -3 means the variable n is less than 3. It's also the open circle because the less than symbol is not underlined. Hope this helps!
To make sky blue Sam uses two drops of blue paint for every eight drops of white paint. He wants to
make a large amount of sky blue paint. If he uses sixteen drops of blue, how many drops of white will he
need?
Answer:
64
Step-by-step explanation:
The Ratio of Blue to White drops is 2:8
16*4=64,... 16:64 Have a nice day!
what principle will amount to Rs. 4000 in 20 yrs at 2.5%?
Answer:
3200Step-by-step explanation:
Consider principle =Rs.P, Time (T)=4 years
Consider principle =Rs.P, Time (T)=4 yearsRate =6
Consider principle =Rs.P, Time (T)=4 yearsRate =6 4
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 =
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 4
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest =
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R =
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P×
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 4
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 =
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P =
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 4
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P =
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 4
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P =4000
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P =40005P=4×4000
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P =40005P=4×4000P=Rs.3200
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P =40005P=4×4000P=Rs.3200Therefore, Principle =Rs.3200
joe went to to the store and spent a total of $37 .84. if paid with a $50 then how much change did he get back?
Answer:
$ 12.16
Step-by-step explanation:
Spent = $ 37.84
Paid = $ 50
Change = $50 - $37.84
Change = $ 12.16
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807Peace!Answer:
$12.16
Step-by-step explanation:
You must subtract his total from his payment. $50-$37.84=$12.16
Complete the equation describing how x
and y are related.
х у
y = [ ? ]x
-2
-1
0
1
2
3
-6
-3
0
3
6
9
Enter the answer that
belongs in [?]
Answer:
y=3x
Step-by-step explanation:
-6/-2=3, -3/-1=3, 3/1=3. 6/2=3
How do we find the second and the third derivative of this equation? Please help!
Answer:
[tex]\frac{7}{2\sqrt{2} }[/tex]
Step-by-step explanation:
substitute 2 in for x. the square root of 2 is already in radical form
Please help me to find this answer
Answer:
37
Step-by-step explanation:
Tan(B) = 6/8
B= arctan(3/4)=37
What number x gives maximum value for c(12,x)?
Answer:
i will say methods try yourself:
How to Determine Maximum Value
How to Determine Maximum ValueIf your equation is in the form ax2 + bx + c, you can find the maximum by using the equation:
How to Determine Maximum ValueIf your equation is in the form ax2 + bx + c, you can find the maximum by using the equation:max = c - (b2 / 4a).
How to Determine Maximum ValueIf your equation is in the form ax2 + bx + c, you can find the maximum by using the equation:max = c - (b2 / 4a).The first step is to determine whether your equation gives a maximum or minimum. ...
How to Determine Maximum ValueIf your equation is in the form ax2 + bx + c, you can find the maximum by using the equation:max = c - (b2 / 4a).The first step is to determine whether your equation gives a maximum or minimum. ...-x2 + 4x - 2.
How to Determine Maximum ValueIf your equation is in the form ax2 + bx + c, you can find the maximum by using the equation:max = c - (b2 / 4a).The first step is to determine whether your equation gives a maximum or minimum. ...-x2 + 4x - 2.Since the term with the x2 is negative, you know there will be a maximum point.
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