if an object weighs 550 n and the area is 1 cube​

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Answer 1
12 km is the answer thank me later

Related Questions

Need help with this one! Thank you xoxo!

Answers

Answer:

it's electron attraction

The answer is Electron Attraction

A 10 n force is applied horizontally on a box to move it 10 m across a frictionless surface. How much work was done to move the box?

Answers

Given from question
Force = 10 N
Displacement = 10 m
Work done = ?
We know that
Work done = force X displacement
So 10 X 10
100
Work done = 100J answer

Answer:

[tex]\boxed {\boxed {\sf 100 \ J}}[/tex]

Explanation:

We are asked to calculate the work done to move a box.

Work is the product of force and distance or displacement.

[tex]W= F*d[/tex]

A 10 Newton force is applied horizontally on the box. Since the surface is frictionless, there is no force of friction, and the net force is 10 Newtons. The force moves the box 10 meters.

F= 10  N d= 10 m

Substitute the values into the formula.

[tex]W= 10 \ N * 10 \ m[/tex]

Multiply.

[tex]W= 100 \ N*m[/tex]

Let's convert the units. 1 Newton meter is equal to 1 Joule, therefore our answer of 100 Newton meters is equal to 100 Joules.

[tex]W= 100 \ J[/tex]

100 Joules of work was done to move the box.

The angle of the resultant vector is equal to
the inverse tangent of the quotient of the x-component divided by the y-component of the resultant vector
the inverse cosine of the quotient of the y-component divided by the x-component of the resultant vector.
the inverse cosine of the quotient of the x-component divided by the y-component of the resultant vector.
the inverse tangent of the quotient of the y-component divided by the x-component of the resultant vector.

Answers

The angle of the resultant vector is equal to the inverse tangent of the quotient of the y-component divided by the x-component of the resultant vector.

To find the angle of a resultant vector, the vector must be resolved into y-component and x-component.

The y-component of a vector is the product of the magnitude of the vector and the sine of the angle of the vector to the horizontal. The x-component of a vector is the product of the magnitude of the vector and the cosine of the angle of the vector to the horizontal.

The angle of this resultant vector is also known as the direction of the vector.

Mathematically, the direction of a resultant vector is given as;

[tex]\theta = tan^{-1} (\frac{R_y}{R_x} )\\\\where;\\\\\theta \ is \ the \ direction \ of \ the \ resultant \ vetcor\\\\R_y \ is \ the \ magnitude \ of \ the\ vector \ resolved \ in \ y - direction\\\\R_x \ is \ the \ magnitude \ of \ the\ vector \ resolved \ in \ x - direction[/tex]

Therefore, the angle of the resultant vector is equal to the inverse tangent of the quotient of the y-component divided by the x-component of the resultant vector.

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What is tensor quantity?
Is Inertia a tensor? give reason​

Answers

Answer:

A tensor is a quantity, for example a stress or a strain, which has magnitude, direction, and a plane in which it acts. Stress and strain are both tensor quantities. ... A tensor is a quantity, for example a stress or a strain, which has magnitude, direction, and a plane in which it acts.

Inertia Tensor. where I = the inertia tensor. The angular momentum of a rigid body rotating about an axis passing through the origin of the local reference frame is in fact the product of the inertia tensor of the object and the angular velocity. ... As shown in [7], the inertia tensor is symmetric.

Explanation:

Hope dis help

Large cockroaches can run as fast as 1.50 m/s in short bursts. Suppose you turn on the light in a cheap motel and
see one scurrying directly away from you at a constant 1.50 m/s. If you start 0.90 m behind the cockroach with
an initial speed of 0.80 m/s toward it, what minimum constant acceleration would you need to catch up with it
when it has traveled 1.20 m, just short of safety onder a counter?

Answers

Answer:

The time that you need to use 1.2/1.5 because this is how long it took the cockroach to travel the 1.2 meters to the counter. That is therefore how long you have to catch up to it.

Explanation:

Consider newtonian mechanics here.

Dynamic equation is

The time we have to use 1.2/1.5 this how long it took the cockroach to travel the 1.2 meters to the counter.

we'll consider newtonian mechanics here.

so the dynamic equations is S = ut + 0.5at^2

we know u=0.8

S=1.2+0.9

t=1.2/1.5

find a.

The question is in the photo.​

Answers

Answer:

heyaa thereeee

see temperature is rising in interval of

0 to 4 minutes

8 to 10 minutes

but 8 to 10 is NOT in options

so answer is option a) 0 to 4 minutes

:))))

A diffraction grating has 6000 lines per centimeter ruled on it. What is the angular separation (in degrees) between the second and the third orders on the same side of the central bright fringe when the grating is illuminated with a beam of light of wavelength 500 nm

Answers

Explanation:

Hope it Will help he hsuejwoamxgehanwpalasmbwfwfqoqlmdbehendalmZbgevzuxwllw. yeh we pabdvddxhspapalw. X

The angular separation (in degrees) between the second and the third orders on the same side of the central bright fringe if the wavelength is 500 nm and A diffraction grating has 6000 lines per centimeter ruled on it, is  27.29°.

What is diffraction?

Waves spreading outward around obstructions are known as diffraction. Sound, electromagnetic radiation like light, X-rays, and gamma rays, as well as very small moving particles like atoms, neutrons, and electrons that exhibit wavelike qualities all exhibit diffraction.

Given:

The number of lines = 6000 per cm,

The Wavelength, λ = 500 nm = 500 × 10 ⁻⁹ m

Calculate the diffraction grating,

[tex]d = 1 / no\ of\ lines[/tex]

d = 10⁻² / 6000 m,

Calculate the second-order maxima angle and third-order maxima angle by the formula given below,

[tex]dsin\theta_1 = n_1 \lambda[/tex]

[tex]sin\theta_1 = n_1\lambda / d[/tex]

[tex]\theta _1 = sin^{-1}[2\times 500\times 10 ^{-9}/10^{-2}\times 6000][/tex]

θ₁ = sin⁻¹(0.6)

θ₁ = 36.87°

Similarly, for θ₂,

θ₂ = sin⁻¹(3 × 500 × 10 ⁻⁹ / 10⁻² × 6000)

θ₂ = sin⁻¹(0.9)

θ₂ = 64.16°

Calculate the separation as follows,

θ₂ - θ₁ = 64.16° - 36.87°

θ₂ - θ₁ =  27.29°

Therefore, the angular separation (in degrees) between the second and the third orders on the same side of the central bright fringe if the wavelength is 500 nm and A diffraction grating has 6000 lines per centimeter ruled on it, is  27.29°.

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Select the correct answer.
What is abstraction?
OA. the concept that software architecture can be separated into modules and that each module can be examined independently
OB. the process of containing information within a module, preventing any crossover or access to Irrelevant information
OC. the process of splitting a program both horizontally and vertically
OD. the process of cutting down irrelevant information so only the information that is useful for a particular purpose remains
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4:

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Answer:

OD. The process of cutting down irrelevant information so only the information that is useful for particular purpose remains

Abstraction is the process of cutting down irrelevant information so only the information that is useful for a particular purpose remains.

What is abstraction?

Abstraction is the practice of removing anything from a set of core features by eliminating or deleting attributes.

One of the three core ideas of object-oriented programming is abstraction order to decrease complexity and maximize efficiency, a programmer uses abstraction to conceal all but the important facts about an object.

Abstraction is the process of cutting down irrelevant information so only the information that is useful for a particular purpose remains.

Hence option D is correct.

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Consider a concave mirror that has a focal length f. In terms of f, determine the object distances that will produce a magnification of

A. -2
B. -3
C. -4

Answers

We have that the magnification of each focal length is given respectively as

A) has [tex]u=3\frac{f}{2}[/tex]

B) has [tex]u=4\frac{f}{3}[/tex]

C) has  [tex]u=5\frac{f}{4}[/tex]

From the question we are told that:

Focal Length F

Generally, the equation for Magnification is mathematically given by

[tex]M=\frac{-v}{u}[/tex]

Therefore

[tex]v=2u[/tex]

For A

[tex]M=-2[/tex]

Therefore

[tex]\frac{1}{f}=\frac{1}{u}+\frac{1}{v}[/tex]

[tex]\frac{1}{f}=\frac{1}{u}+\frac{1}{2u}[/tex]

Therefore

[tex]u=3\frac{f}{2}[/tex]

For B

[tex]M=-3[/tex]

Therefore

[tex]v=3u[/tex]

Where

[tex]\frac{1}{f}=\frac{1}{u}+\frac{1}{v}[/tex]

[tex]\frac{1}{f}=\frac{1}{u}+\frac{1}{3u}[/tex]

Therefore

[tex]u=4\frac{f}{3}[/tex]

For C

[tex]M=-4[/tex]

Therefore

[tex]v=4u[/tex]

Therefore

[tex]\frac{1}{f}=\frac{1}{u}+\frac{1}{v}[/tex]

[tex]\frac{1}{f}=\frac{1}{u}+\frac{1}{4u}[/tex]

Therefore

[tex]u=5\frac{f}{4}[/tex]

Conclusion

From the calculations above we can rightly say that the magnifications of the values above are

A has [tex]u=3\frac{f}{2}[/tex]

B has [tex]u=4\frac{f}{3}[/tex]

C has  [tex]u=5\frac{f}{4}[/tex]

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Earth’s Moon has a diameter of 3,474 km and orbits at an average distance of 384,000 km. At that distance it subtends and angle just slightly larger than half a degree in Earth’s sky. Pluto’s moon Charon has a diameter of 1,186 km and orbits at a distance of 19,600 km from the dwarf planet. Compare the appearance of Charon in Pluto’s skies with the Moon in Earth’s skies. Describe where in the sky Charon would appear as seen from various locations on Pluto.

Answers

The result of the comparison of the appearance of Charon on Pluto and   times the Moon from Earth is that; Charon as seen from Pluto appears approximately 7 times larger than the Moon

Charon is directly overhead from the side of Pluto locked to the side of Charon

Charon appears at the horizon from the poles of the axis of rotation of Jupiter around Charon

The reason for arriving at the above solutions is as follows:

The given dimensions and distance from the Earth of the Moon are;

The diameter of the Moon, d = 3,474 km

The average distance of the Moon from the Earth, R = 384,000 km

Required:

The comparison between Charon's appearance in Pluto and the Moon's appearance on Earth Earth

Solution:

The distance of the Moon's travels in an orbit, C = 2·π·R

∴ C = 2 × π × 384,000 km

The angle subtended by the Moon, θ = d/C × 360°

∴ θ = 3,474/(2 × π × 384,000) × 360° ≈ 0.518°

Pluto's moon Charon, has the following parameters;

The diameter of the Charon, d₂ = 1,186 km

The average distance of the Charon from Pluto, R₂ = 19,600 km

Therefore, the distance of the Moon's travels in an orbit, C₂ = 2·π·R₂

∴ C₂ = 2 × π × 19,600 km

The angle subtended by the Moon, θ₂ = d₂/C₂ × 360°

∴ θ₂ = 1,186/(2 × π × 19,900) × 360° ≈ 3.415°

The angle subtended by Charon in Pluto's sky ≈ 3.415°

Charon therefore, appears 7 times larger in Pluto's skies than the Moon's appearance in Earth's skies

Required:

The appearance of Charon as seen from different locations on Pluto

Solution:  

Charon is gravitationally locked to Pluto, therefore, the same side of Pluto is faced with the same side of Charon

Therefore;

Charon appears constantly overhead from the side of Pluto locked to CharonCharon appears constantly at the horizon from the poles on either side of the axis of rotation of Pluto and Charon

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Which state of matter has properties that are responsible for your smelling
the perfume of someone across the room?
A. Gas
B. Solid
C. Liquid
D. Plasma

Answers

this answer should be gas

Answer:

Gas

Explanation:

Solid particles cannot travel far, since they are mostly attracted together.

Liquid Particles cannot travel far either, although they can flow, but they flow with respect with gravity.

Plasma... is a very hot material, it's probably cooler than the sun but it's way warmer than your average boiling water.

So which leaves gas, since we know that the properties of gases are :

Gas particles can freely travel

Gas particles are spread out

These enables it to flow around the room, and this has something to do with diffusion, but i believe it's out of topic.

So, the answer's gas!

HOPE THIS ANSWER HELPED :)

What happens when a ray of light enters a glass slab ?​

Answers

Explanation:

then the

speed decreases

Answer:

It gets refracted,

Explanation:

Because i did a couple different searches.

Yeast are tiny fungi to make products like bread, other kinds of dough, beer, and wine. They do this by digesting sugar. A byproduct of this is the release of carbon dioxide gas which makes bread so light and fluffy. We can observe yeast through experimentation by putting them in a closed container with sugar with a ballon on top to trap any carbon dioxide released. What is a quantitative observation that could be made in this experiment?

Answers

Answer:

Compare the volume  (weight) of CO2  gas produced to the weights of sugar and yeast that were used to produce the CO2. Ideally, both the yeast and sugar would be entirely consumed.

Identify 2 different ways that data can be displayed or represented.​

Answers

Answer:

tables, charts and graphs

Explanation:

why do we go to hospital​

Answers

Answer:

bcz we want to have fun there lolol

Answer:

for emergency, treatment, medicines,etc.....

A fan is turned off, and its angular speed decreases from 10.0 rad/s to 6.3 rad/s in 5.0 s. What is the magnitude of the angular acceleration of the fan?
A) 0.37 rad/s2
B) 11.6 rad/s2
C) 0.74 rad/s2
D) 0.86 rad/s2
E) 1.16 rad/s2

Answers

Answer:

chk photo

Explanation:

A train starts from rest (at position zero) and moves with constant acceleration. On the first observation, its velocity is 20m/s and 80seconds later the velocity became 60m/s. At 80s calculate the position, average velocity, and the constant acceleration over the interval.(7-points)

Answers

The value of the acceleration is a = 0.5 m/s². The position at 80 s is x = 3200 m and finally the average velocity is v = 40 m/s.

Acceleration:

We can use the fallowing kinematic equation to get the acceleration at 80 s.

[tex]a=\frac{v_{f}-v_{i}}{t}[/tex]            

Where:

v(i) is the initial velocity (20 m/s)v(f) is the final velocity (60 m/s)t is the interval (80 s)

The, we have:

[tex]\vec{a}=\frac{60-20}{80}[/tex]

[tex]\vec{a}=0.5\: m/s^{2}[/tex]

Position:

Knowing the acceleration we can find the position using the falling equation.

[tex]\vec{x}=v_{i}t+0.5at^{2}[/tex]

[tex]\vec{x}=20*80+0.5*0.5*80^{2}[/tex]

[tex]\vec{x}=3200 m[/tex]

Average velocity:

The definition of the average velocity is:

[tex]\vec{v}=\frac{\Delta x}{t}[/tex]

[tex]\vec{v}=\frac{x_{f}-x_{i}}{t}[/tex]

[tex]\vec{v}=\frac{3200-0}{80}[/tex]

[tex]\vec{v}=40\: m/s[/tex]

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Length of spring is 8cm when mass is 4kg is hang on it its become 16cm what is its spring constant?

Answers

Answer:

constant is 500 N/m

Explanation:

Extension, e = (16 - 8) = 8 cm

Force, F = (4 × 10) = 40 N

from hooke's law:

[tex]F = kx \\ 40 = (k \times 0.08) \\ k = \frac{40}{0.08} \\ \\ k = 500 \: newton \: per \: metre[/tex]

Magnetic fields exist

A. Near a magnet
B. Farther away from a magnet
C. Within a magnet
D. All of the above

Answers

Answer:

Magnetic fields exist near a magnet, farther away from a magnet, and within a magnet.

So, the answer is D. All of the above.

Let me know if this helps!

Which sequence shows the chain of energy transfers that create surface currents on the ocean?

Answers

Answer:

The correct answer is A. The sun is the energy source of the surface currents in the ocean

The energy transfer starts from solar energy , then wind energy and finally wind energy is the cause of surface current .

What is surface current ?

Surface currents are currents that are located in the upper feet of the ocean , they are simply how water moves from one place to another . Pattern of surface current are determined by wind direction .

Surface currents are formed by global wind system that are fueled by energy from the sun . Because of heating effect of sun , the earth's atmosphere gets warmed up . As we know , warm air is lighter then cool air , it rises up and create low pressure near the equator because of this wind causes surface currents the ocean .

hence , The energy transfer starts from solar energy , then wind energy and finally wind energy is the cause of surface current .

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Calculate the kinetic energy of a mass 2kg moving with a velocity of 0.1m/s

Answers

ANSWER-:

1/2 mv²

K.E = 1/2 mv²

K.E = 0.01 J.

Hence, the kinetic energy of a body is 0.01 Joule.

!! HOPE ITS HELP U !!

1/2mv^2
1/2(2)(0.1)^2
= 0.01 J

In part A of the lab we see that the magnetic field of a long straight wire __. a. increases with distance in a linear relationship b. increases with distance in a non-linear relationship c. decreases with distance in an inverse (1/r) relationship d. decreases with distance in an inverse-square (1/r2) relationship

Answers

Explanation:

a long straight wire __. a. increases with distance in a linear relationship b. increases with distance in a non-linear relationship c. decreases with distance in an inverse (1/r) relationship d. decreases with distance in an inverse-square (1/r2) relationship

In part A of the lab, we see the magnetic field of a long straight wire decreases with distance in an inverse (1/r) relationship, therefore the correct option is C.

What is a magnetic field?

A magnetic field could be understood as an area around a magnet, magnetic material, or an electric charge in which magnetic force is exerted. The SI unit of the magnetic field is tesla.

For a  long straight wire carrying the current, the relation with the distance as given below

B = μI/(2πr)

where B is the magnetic field

μ is the permeability of the free space

r is the distance from the wire

As we can see from the above relation

the magnetic field of a long straight wire decreases with distance in an inverse (1/r) relationship, therefore the correct answer is option C.

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The timing device in an automobile’s intermittent wiper system is based on an RC time constant and utilizes a 0.500 micro F capacitor and a variable resistor. Over what range must R be made to vary to achieve time constants from 2.00 to 15.0 s?

Answers

Answer:

check 2 photos for answer

check 2 photos for answer

a baseball is given an initial velocity with magnitude v at the angle beta above the surface of an incline which in turn inclined at angle teta above horizontal calculate the distance measured along incline from the launch point to where the baseball strike the incline


Answers

Explanation:

The maximum height of an object, given the initial launch angle and initial velocity is found with:h=v2isin2θi2g h = v i 2 sin 2 ⁡ θ i 2 g .

what is used to measure the amount of sunshine ​

Answers

Answer:

Campbell-Stokes sunshine recorders or modern sunshine sensors.

Explanation:

Answer:

modern sunshine sensorssunshine recordersCampbell-Stokes

tìm thời điểm vật đạt tốc độ 25\pi cm/s lần thứ 2021

Answers

Answer:

una ufx vek cintos kavres millianto

Explanation:

vekas moriqn5o siveria il a ola ola micanese ma n8 aou ko sevyaera

a bullet is dropped from the same height when another bullet is fired horizontally they will hit the ground

Answers

Answer:

simultaneously

Time taken to reach the ground depends on the vertical component of velocity, not horizontal component of velocity.

A mass is tired to spring and begins vibration periodically the distance between it's lowest position is 48cm what is the Amplitude of the vibration

Answers

Answer:

The amplitude of vibration of the spring is "24 cm"

The periodic vibrating body's motion follows a sinusoidal path. This sinusoidal path is illustrated in the attached picture.

From the picture, it can be clearly seen that the amplitude of the periodic vibration motion is the distance from its mean position to the highest point.

Since the distance of both the highest and the lowest points from the mean position is the same. Therefore, the distance between the lowest and the highest point must be equal to two times the amplitude of the wave.

Amplitude = 24 cm

Between which two points of a concave mirror should an object be placed to obtain a magnificati of -3​

Answers

Answer:

When object is placed between the focus (F) and pole (P) of a concave mirror, magnified and erect image of the object is formed on the back of the mirror.

When object is placed between the centre of curvature and the principal focus of a concave mirror, magnified and inverted image is formed in front of the mirror.

Explanation:

why nuclear fusion difficult to be carried out in a laboratort​

Answers

Answer:

Nuclear fusion reactions in the laboratory have been extraordinarily difficult to achieve. Extremely high temperatures (in the millions of degrees) are required. The neutrons released during the fusion reactions can interact with atoms in the reactor and convert them to radioactive materials.

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