If a drug has a concentration of 8.22 mg per 3.039 mL, how many mL are needed to give 7.469 gram of the drug? Round to 1 decimal.​

Answer:

it is 23

Step-by-step explanation:

first divide

then add

then subtract

Answer:

23

Step-by-step explanation:

Follow PEMDAS

16 ÷ 2 = 8

8 + 20 = 28

28 - 5 = 23

Answer:

Discrete

Discrete data represent items that can be counted; they take on possible values that can be listed out. The list of possible values may be fixed (also called finite); or it may go from 0, 1, 2, on to infinity (making it countably infinite).

Answer:

see explanation

Step-by-step explanation:

Using the Sine rule in all 3 questions

(1)

[tex]\frac{a}{sinA}[/tex] = [tex]\frac{b}{sinB}[/tex] , substitute values , firstly calculating ∠ B

[ ∠ B = 180° - (78 + 49)° = 180° - 127° = 53° ]

[tex]\frac{a}{sin78}[/tex] = [tex]\frac{18}{sin53}[/tex] ( cross- multiply )

a sin53° = 18 sin78° ( divide both sides by sin53° )

a = [tex]\frac{18sin78}{sin53}[/tex] ≈ 22.0 ( to the nearest tenth )

(3)

[tex]\frac{c}{sinC}[/tex] = [tex]\frac{a}{sinA}[/tex] , substitute values

[tex]\frac{35}{sinC}[/tex] = [tex]\frac{45}{sin134}[/tex] ( cross- multiply )

45 sinC = 35 sin134° ( divide both sides by 35 )

sinC = [tex]\frac{35sin134}{45}[/tex] , then

∠ C = [tex]sin^{-1}[/tex] ( [tex]\frac{35sin134}{45}[/tex] ) ≈ 34.0° ( to the nearest tenth )

(5)

Calculate the measure of ∠ B

∠ B = 180° - (38 + 92)° = 180° - 130° = 50°

[tex]\frac{a}{sinA}[/tex] = [tex]\frac{b}{sinB}[/tex] , substitute values

[tex]\frac{BC}{sin38}[/tex] = [tex]\frac{10}{sin50}[/tex] ( cross- multiply )

BC sin50° = 10 sin38° ( divide both sides by sin50° )

BC = [tex]\frac{10sin38}{sin50}[/tex] ≈ 8.0 ( to the nearest tenth )

Answer:

49.09°

Step-by-step explanation:

c = circumference = 2×π×r

= 2× 22/7 ×7 = 44 ft

θ = 6/c × 360°

= 6/44 × 360° = 49.09°

Answer:

Step-by-step explanation:

Number of attendees the first day = x.

Solve the following equation for x:

Answer:

i) 410 cm³

ii) 48 min

Step-by-step explanation:

we start with 250 cm³.

and then we fill in 20 cm³ per minute.

i)

after 30 minutes we have

250 + 8×20 = 250 + 160 = 410 cm³

ii)

how long (how many minutes) does it take to reach 1210 cm³ in the tank ?

well, first we subtract the start amount (250).

and then we see how often 20 cm³ will "fit" into the remainder. and then we know how many minutes the water has to run.

1210 - 250 = 960 cm³

so, the incoming water needs to reach 960 cm³ to have a total of 1210 cm³.

and

960 cm³ / (20 cm³ / min) = 960 cm³ min / 20 cm³ =

= 960 min / 20 = 48 min

Answer:

It's How much did you spend at the movies today?

Step-by-step explanation:

The question can the manager asks "How much did you spend at the movies today?". Then the correct option is C.

A discrete quantitative parameter has a clear mathematical explanation but could only take certain integer values (instead of every value in intervals).

The manager of a movie theater is standing outside the theater complex one evening.

He will be asking the moviegoers questions.

Then the questions can the manager ask that will result in discrete quantitative data will be

How much did you spend at the movies today?

The question can the manager asks "How much did you spend at the movies today?"

Then the correct option is C.

More about the discrete quantitative data link is given below.

https://brainly.com/question/12831013

#SPJ2

Answer:

assuming youre asking for line of symmetry, it's a line that cuts a shape exactly in half.  

for example, a square has 4 lines of symmetry

First, I'll make f(x) = sin(px) + cos(px) because this expression shows up quite a lot, and such a substitution makes life a bit easier for us.

Let's apply the first derivative of this f(x) function.

[tex]f(x) = \sin(px)+\cos(px)\\\\f'(x) = \frac{d}{dx}[f(x)]\\\\f'(x) = \frac{d}{dx}[\sin(px)+\cos(px)]\\\\f'(x) = \frac{d}{dx}[\sin(px)]+\frac{d}{dx}[\cos(px)]\\\\f'(x) = p\cos(px)-p\sin(px)\\\\ f'(x) = p(\cos(px)-\sin(px))\\\\[/tex]

Now apply the derivative to that to get the second derivative

[tex]f''(x) = \frac{d}{dx}[f'(x)]\\\\f''(x) = \frac{d}{dx}[p(\cos(px)-\sin(px))]\\\\ f''(x) = p*\left(\frac{d}{dx}[\cos(px)]-\frac{d}{dx}[\sin(px)]\right)\\\\ f''(x) = p*\left(-p\sin(px)-p\cos(px)\right)\\\\ f''(x) = -p^2*\left(\sin(px)+\cos(px)\right)\\\\ f''(x) = -p^2*f(x)\\\\[/tex]

We can see that f '' (x) is just a scalar multiple of f(x). That multiple of course being -p^2.

Keep in mind that we haven't actually found dy/dx yet, or its second derivative counterpart either.

-----------------------------------

Let's compute dy/dx. We'll use f(x) as defined earlier.

[tex]y = \ln\left(\sin(px)+\cos(px)\right)\\\\y = \ln\left(f(x)\right)\\\\\frac{dy}{dx} = \frac{d}{dx}\left[y\right]\\\\\frac{dy}{dx} = \frac{d}{dx}\left[\ln\left(f(x)\right)\right]\\\\\frac{dy}{dx} = \frac{1}{f(x)}*\frac{d}{dx}\left[f(x)\right]\\\\\frac{dy}{dx} = \frac{f'(x)}{f(x)}\\\\[/tex]

Use the chain rule here.

There's no need to plug in the expressions f(x) or f ' (x) as you'll see in the last section below.

Now use the quotient rule to find the second derivative of y

[tex]\frac{d^2y}{dx^2} = \frac{d}{dx}\left[\frac{dy}{dx}\right]\\\\\frac{d^2y}{dx^2} = \frac{d}{dx}\left[\frac{f'(x)}{f(x)}\right]\\\\\frac{d^2y}{dx^2} = \frac{f''(x)*f(x)-f'(x)*f'(x)}{(f(x))^2}\\\\\frac{d^2y}{dx^2} = \frac{f''(x)*f(x)-(f'(x))^2}{(f(x))^2}\\\\[/tex]

If you need a refresher on the quotient rule, then

[tex]\frac{d}{dx}\left[\frac{P}{Q}\right] = \frac{P'*Q - P*Q'}{Q^2}\\\\[/tex]

where P and Q are functions of x.

-----------------------------------

This then means

[tex]\frac{d^2y}{dx^2} + \left(\frac{dy}{dx}\right)^2 + p^2\\\\\frac{f''(x)*f(x)-(f'(x))^2}{(f(x))^2} + \left(\frac{f'(x)}{f(x)}\right)^2 + p^2\\\\\frac{f''(x)*f(x)-(f'(x))^2}{(f(x))^2} +\frac{(f'(x))^2}{(f(x))^2} + p^2\\\\\frac{f''(x)*f(x)-(f'(x))^2+(f'(x))^2}{(f(x))^2} + p^2\\\\\frac{f''(x)*f(x)}{(f(x))^2} + p^2\\\\[/tex]

Note the cancellation of -(f ' (x))^2 with (f ' (x))^2

------------------------------------

Let's then replace f '' (x) with -p^2*f(x)

This allows us to form  ( f(x) )^2 in the numerator to cancel out with the denominator.

[tex]\frac{f''(x)*f(x)}{(f(x))^2} + p^2\\\\\frac{-p^2*f(x)*f(x)}{(f(x))^2} + p^2\\\\\frac{-p^2*(f(x))^2}{(f(x))^2} + p^2\\\\-p^2 + p^2\\\\0\\\\[/tex]

So this concludes the proof that [tex]\frac{d^2y}{dx^2} + \left(\frac{dy}{dx}\right)^2 + p^2 = 0\\\\[/tex] when [tex]y = \ln\left(\sin(px)+\cos(px)\right)\\\\[/tex]

Side note: This is an example of showing that the given y function is a solution to the given second order linear differential equation.

Answer:

You dind't include the answer choices but it should look something like

[tex]50000(.8)^t[/tex]

Answer:

86

Step-by-step explanation:

First, we should use the rule of:

B: bracket

O: of

D: division

M: multiplication

A: addition

S: subtraction

so, before adding we should multiply

or;36+50

or;86 ans.

Answer:

b

Step-by-step explanation:

the graph gets translated 5 units above its parent graph of y = x

Answer:

6

Step-by-step explanation:

Given :

Sample size, n = 36

Sample variance, s² = 1296

The estimated standard error can be obtained using the relation :

Standard Error, S. E = standard deviation / √n

Standard deviation, s = √1296 = 36

S.E = 36/√36

S.E = 36/6

S.E = 6

Hence, estimated standard error = 6

Area of parallelogram = b × h

Base = x + 7

Height = x + 3

ATQ

Area = (x + 7) ( x + 3)

x² + 3x + 7x + 21

x² + 10x + 21

Answered by Gauthmath must click thanks and mark brainliest

Answer:

Step-by-step explanation:

B; So this is a transformation problem from the parent function of f(x)=|x| so the function is is moved 3 units down giving it the -3 at the end and is moved to the right 7 units so it would be x-7

Answer:

4

Step-by-step explanation:

24 = 2^3 x 3

100 = 2^2 x 5^2

HCF = 2^2 = 4

Im sorry I don't know the answer to the question

Answer:

C. rotation 180º about the origin

Step-by-step explanation:

Given

Quadrilaterals GWVY and G'W'V'Y'

Required

Describe the transformation rule

Pick points Y and Y'

[tex]Y = (5,-4)[/tex]

[tex]Y' = (-5,4)[/tex]

The above obeys the following rule:

[tex](x,y) \to (-x,-y)[/tex]

When a point is rotated by 180 degrees, the rule is:

[tex](x,y) \to (-x,-y)[/tex]

Hence, (c) is correct

Answer:

(3,-2)

Step-by-step explanation:

-5/3x + 3 = 1/3x - 3

-5/3x = 1/3x - 6

-2x = -6

x = 3

y = -5/3(3) + 3

y = -5 + 3

y = -2

Step-by-step explanation:

70 + 45 = 115

180 - 115 = 65

angle c = 65

use sohcahtoa

cos angle = adjacent

hypotenuse

cos 65 = 2.5

b

b cos 65 = 2.5

use the calc for further answers

hope that helped

9514 1404 393

Answer:

  (a) (-∞, -8), (-5, -2), (2, 5)

  (b) -8, -2, 5

  (c) negative

  (d) 6

Step-by-step explanation:

(a) The function is increasing on intervals where the graph slopes upward left-to-right. Those are (-∞, -8), (-5, -2), and (2, 5).

__

(b) The local maxima are at the right end of each interval on which the function is increasing: -8, -2, 5.

__

(c) The function opens downward (∩), so has a negative leading coefficient.

__

(d) There are three local maxima and two local minima (left end of an increasing interval), so a total o 5 turning points. The degree of the polynomial is at least one more than this: 6.

Answer:

$14.40

Step-by-step explanation:

my way of doing things:

15/100=0.15=1%of total amount

0.15 x 6=0.9= the 6% which is the tax

0.15 x 10 = 1.5=the coupon

Take the coupon amount $1.50 minus the tax amount $0.90 =$0.60. Because the coupon amount is greater than the tax the 60 cents gets taken away from the original 15 dollars leaving Mr. Longely only having to pay $14.40.

Answer:

21

Step-by-step explanation:

Answer:

m = 6

c = 0

General Formulas and Concepts:

Algebra I

Slope-Intercept Form: y = mx + c

Step-by-step explanation:

Step 1: Define

y = 6x

↓ Compare to Slope-Intercept Form

Slope m = 6

y-intercept c = 0

9514 1404 393

Answer:

Step-by-step explanation:

The base length is the length of the horizontal line segment KN. That length is the difference of the x-coordinates: 3x -0 = 3x.

The height is the difference of the y-coordinate of point M and the y-coordinate of horizontal segment KN. That difference is 2y -0 = 2y.

The area is half the product of base and height:

  A = (1/2)bh

  A = 1/2(3x)(2y) = 3xy

In ΔKMN, the length of the base is 3x and the height is 2y. So an expression for the area of ΔKMN is 3xy.

__

In ΔKLM, the length of the base is 3x and the height is 2y. So an expression for the area of ΔKLM is 3xy.

Answer:

4=x y=325

Step-by-step explanation:

60x + 20 = 65x

group the variables

20=5x

because you subtracted 60x from both

4=x

because you divided 5 from both

now substitute 5 for x

65×5 is 325

y=325

Answer:

x = 74.74 m

Step-by-step explanation:

you need simple trigonometry to solve it

cosine of an angle is the ratio of the adjacent side to the hypotenuse

cos(42.2) is about 0.74

so X / Hypotenuse = 0.74

we know hypotenuse is 101 m

X / 101 = 0.74

x = 74.74 m

hope this helped!

We need not consider a whole triangle but just point B.

Before reflection we know that [tex]B(5,9)[/tex].

Reflecting B over [tex]y=1[/tex] is relatively easy. First because its a reflection over the horizontal line the only coordinates that will change are y coordinates, while x coordinate will not change so half of the reflection is already done for us,

[tex]B(5,a)[/tex]

Now to what has changed, well currently the distance between 9 and 1 on the y axis is 8 up. But because we are reflecting the a must now be 8 down from 1 which means [tex]1 - 8 = -7[/tex] so our point is now [tex]\boxed{B(5,-7)}[/tex].

Hope this helps :)

9514 1404 393

Answer:

  (5, -7)

Step-by-step explanation:

Reflection across the line y = c is accomplished by the transformation ...

  (x, y) ⇒ (x, 2c -y)

For c=1 and point B, we have ...

  B(5, 9) ⇒ B'(5, 2·1 -9) = B'(5, -7)

The image of point B is (5, -7).

Step-by-step explanation:

Forty three thousand one hundred and six

Answer:

Forty three AND one hundred six thousandths

Step-by-step explanation:

If there is a comma ( , ) between the two numbers, you are correct.  

If there is a period / dot ( . ) between them, and you need to read the place values, you must read the numbers to the right of the . as decimals.  Those are the "th" numbers.  1 is in the tenths place, 0 in the hundredths place and the 6 in the thousandths place.  

If you are simply reading out the digit names, without assigning their value, you might say "forty three POINT one hundred six"  or "forty three DOT one hundred six" or "forty three DECIMAL one hundred six".