Using test hypothesis and confidence interval concepts, it is found that a 95% confidence level should be used.
A confidence interval can be used to make a hypothesis test.For a significance level of [tex]\alpha[/tex], the confidence level is of [tex]1 - \alpha[/tex]In this problem, there is a significance level of 0.05, hence the confidence level is of 1 - 0.05 = 0.95 = 95%.
A similar problem, also involving a confidence interval and an hypothesis test, is given at https://brainly.com/question/14740644
vvorth 1 points
(01.02 MC)
Which of the following describes the correct process for solving the equation 2x - 4 = 20 and arrives at the correct solution?
O Add 4 to both sides, and then divide by 2. The solution is x = 12.
O Divide both sides by -4, and then subtract 2. The solution is x = -7.
O Subtract 4 from both sides, and then divide by 2. The solution is x = -12.
O Multiply both sides by -4, and then divide by 2. The solution is x = -40.
Hi there!
»»————- ★ ————-««
I believe your answer is:
"Add 4 to both sides, and then divide by 2. The solution is x = 12."
»»————- ★ ————-««
Here’s why:
⸻⸻⸻⸻
To solve for 'x', we would have to use inverse operations. We would first have to add four to both sides to undo the negative four. Addition is the opposite of subtraction. We would then divide by 2 to isolate 'x'. Division is the opposite of multiplication.⸻⸻⸻⸻
[tex]\boxed{\text{Solving for 'x'...}}\\\\2x - 4 = 20\\------------\\\rightarrow 2x - 4 + 4 = 20 + 4\\\\\rightarrow 2x = 24\\\\\rightarrow \frac{2x=24}{2}\\\\\rightarrow \boxed{x = 12}[/tex]
⸻⸻⸻⸻
»»————- ★ ————-««
Hope this helps you. I apologize if it’s incorrect.
A certain test preparation course is designed to help students improve their scores on the LSAT exam. A mock exam is given at the beginning and end of the course to determine the effectiveness of the course. The following measurements are the net change in 6 students' scores on the exam after completing the course: 6,16,19,12,15,14.
Using these data, construct a 90% confidence interval for the average net change in a student's score after completing the course. Assume the population is approximately normal. Find the critical value that should be used in constructing the confidence interval.
Answer:
The critical value is [tex]T_c = 2.5706[/tex].
The 90% confidence interval for the average net change in a student's score after completing the course is (9.04, 18.30).
Step-by-step explanation:
Before building the confidence interval, we need to find the sample mean and the sample standard deviation:
Sample mean:
[tex]\overline{x} = \frac{6+16+19+12+15+14}{6} = 13.67[/tex]
Sample standard deviation:
[tex]s = \sqrt{\frac{(6-13.67)^2+(16-13.67)^2+(19-13.67)^2+(12-13.67)^2+(15-13.67)^2+(14-13.67)^2}{5}} = 4.4121[/tex]
Confidence interval:
We have the standard deviation for the sample, so the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 6 - 1 = 5
90% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 5 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.9}{2} = 0.95[/tex]. So we have T = 2.5706, that is, the critical value is [tex]T_c = 2.5706[/tex]
The margin of error is:
[tex]M = T\frac{s}{\sqrt{n}} = 2.5706\frac{4.4121}{\sqrt{6}} = 4.63[/tex]
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 13.67 - 4.63 = 9.04.
The upper end of the interval is the sample mean added to M. So it is 13.67 + 4.63 = 18.30.
The 90% confidence interval for the average net change in a student's score after completing the course is (9.04, 18.30).
Please help me, by completing this proof!
Answer:
Step-by-step explanation:
Statement Reasons
1). Line PQ is an angle bisector of ∠MPN D). Given
2). ∠MPQ ≅ ∠NPQ A). Definition of angle bisector
3). m∠MPQ = m∠NPQ F). Definition of congruent
angles.
4). m∠MPQ + m∠NPQ = m∠MPN C). Angle addition postulate
5). m∠MPQ + m∠MPQ = m∠MPN G). Substitution property of
equality
6). 2(m∠MPQ) = m∠MPN B). Distributive property
7). m∠MPQ = [tex]\frac{1}{2}(m\angle MPN)[/tex] E). Division property of equality
If there are g girls and b-boys in a room, write an expression for the total number of children in the room.
Answer:
g+b
number of girls+number of boys
if i am incorrect forgive me plz
The expression for the total number of children in a room is g+ b.
What is an expression?
Expressions in math are mathematical statements that have a minimum of two terms containing numbers or variables, or both, connected by an operator in between.
What is addition?Addition is the process of finding the total, or sum, by combining two or more numbers or variables.
According to the given question
We have
Number of girls = g
And, number of boys = b
Therefore, the expression for the total number of children in room is given by
Total number of children = g + b
Hence, the expression for the total number of children in a room is g+ b.
Learn more about expression and addition here:
https://brainly.com/question/10386370
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Farmers in one state produced 417,938,650 bushels of corn one year. If the production of corn decreases by ten million bushels, how many bushels of corn will be produced?
A 417,938,650 bushels
B 417,938,640 bushels
C 417,928,650 bushels
D 407,938,650 bushels
Answer:
D
Step-by-step explanation:
417,938,650-10,000,000=407,938,650
Answer: D) 407,938,650 bushels
==========================================================
Explanation:
417,938,650 = 417 million, 938 thousand, 650
Focus on the "417 million" part only. Subtract 10 million from this, because of the key word "decrease". So we go from 417 to 417-10 = 407
Meaning we drop from 417 million to 407 million
The other parts remain the same
So "417 million, 938 thousand, 650" updates to "407 million, 938 thousand, 650"
Then we translate that somewhat wordy form into a pure number 407,938,650 which is choice D
In short, we just changed 417 to 407 and kept everything else the same.
Consider possible daily uses for the Pythagorean Theorem. For what types of careers would knowledge of this theorem be useful or necessary? For each career, include an example of a use for a2 + b2 = c2.
For engineering, it would be very useful to know Pythagorean theorem. You can use it to measure the tension in each ropes.
The sum of two numbers is -17. Their difference is 41. Find the numbers
Answer:
x = 12
y = -29
Step-by-step explanation:
Our given equations: x + y = -17 and x - y = 41
Solve for x and substitute.
x = -17 - y
(-17 - y) - y = 41
-17 - 2y = 41
2y = -58
y = -29
Solve for x using y
x + (-29) = -17
x = 12
What is the probability of flipping exactly 6 heads when you flip 6 coins? Please explain your answer and those who waste an answer space shall be reported. Also the best answer will get brainliest
Binomial probability states that the probability of x successes on n repeated trials in an experiment which has two possible outcomes can be obtained by
(nCx).(p^x)⋅((1−p)^(n−x))
Where success on an individual trial is represented by p.
In the given question, obtaining heads in a trial is the success whose probability is 1/2.
Probability of 6 heads with 6 trials = (6C6).((1/2)^6).((1/2)^(6–6))
= 1/(2^6)
= 1/64
[tex]\lim_{x\to \ 0} \frac{\sqrt{cos2x}-\sqrt[3]{cos3x} }{sinx^{2} }[/tex]
Answer:
[tex]\displaystyle \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)} = \frac{1}{2}[/tex]
General Formulas and Concepts:
Calculus
Limits
Limit Rule [Variable Direct Substitution]: [tex]\displaystyle \lim_{x \to c} x = c[/tex]
L'Hopital's Rule
Differentiation
DerivativesDerivative NotationBasic Power Rule:
f(x) = cxⁿ f’(x) = c·nxⁿ⁻¹Derivative Rule [Chain Rule]: [tex]\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)[/tex]
Step-by-step explanation:
We are given the limit:
[tex]\displaystyle \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)}[/tex]
When we directly plug in x = 0, we see that we would have an indeterminate form:
[tex]\displaystyle \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)} = \frac{0}{0}[/tex]
This tells us we need to use L'Hoptial's Rule. Let's differentiate the limit:
[tex]\displaystyle \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)} = \displaystyle \lim_{x \to 0} \frac{\frac{-sin(2x)}{\sqrt{cos(2x)}} + \frac{sin(3x)}{[cos(3x)]^{\frac{2}{3}}}}{2xcos(x^2)}[/tex]
Plugging in x = 0 again, we would get:
[tex]\displaystyle \lim_{x \to 0} \frac{\frac{-sin(2x)}{\sqrt{cos(2x)}} + \frac{sin(3x)}{[cos(3x)]^{\frac{2}{3}}}}{2xcos(x^2)} = \frac{0}{0}[/tex]
Since we reached another indeterminate form, let's apply L'Hoptial's Rule again:
[tex]\displaystyle \lim_{x \to 0} \frac{\frac{-sin(2x)}{\sqrt{cos(2x)}} + \frac{sin(3x)}{[cos(3x)]^{\frac{2}{3}}}}{2xcos(x^2)} = \lim_{x \to 0} \frac{\frac{-[cos^2(2x) + 1]}{[cos(2x)]^{\frac{2}{3}}} + \frac{cos^2(3x) + 2}{[cos(3x)]^{\frac{5}{3}}}}{2cos(x^2) - 4x^2sin(x^2)}[/tex]
Substitute in x = 0 once more:
[tex]\displaystyle \lim_{x \to 0} \frac{\frac{-[cos^2(2x) + 1]}{[cos(2x)]^{\frac{2}{3}}} + \frac{cos^2(3x) + 2}{[cos(3x)]^{\frac{5}{3}}}}{2cos(x^2) - 4x^2sin(x^2)} = \frac{1}{2}[/tex]
And we have our final answer.
Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Limits
find the missing side round to the nearest tenth brainly
Answer:
Sin43 = x/13
x= 13* sin43
x= 8.865
Answer:
8.9
Step-by-step explanation:
using sine rule
[tex] \frac{x}{sin \: 43} = \frac{13}{sin \: 90} [/tex]
cross multiply
x sin 90=13 sin 43
x=13 sin 43
x=8.9
if you can type 55 words in 20 seconds how much can you type in 1007 seconds
Answer:
[tex]55385[/tex]
words
Step-by-step explanation:
because
I) we have given 55 words
ii) we have given a time 20 seconds
iii) then we multiple 55 ×1007
iv) the answer will be 55385
Which expression is equivalent to
R^9/r^3?
Answer:
r^9/r^3 = r^9-3 = r^6
Step-by-step explanation:
Hi there!
»»————- ★ ————-««
I believe your answer is:
[tex]r^6[/tex]
»»————- ★ ————-««
Here’s why:
⸻⸻⸻⸻
[tex]\boxed{\text{Simplifying...}}\\\\\frac{r^9}{r^3} \\--------------\\\\\text{Recall the quotient rule:}} \frac{a^x}{a^y}=a^{x-y}\\\\\rightarrow \frac{r^9}{r^3}\\\\\rightarrow r^{9-3}\\\\\rightarrow \boxed{r^6}[/tex]
⸻⸻⸻⸻
»»————- ★ ————-««
Hope this helps you. I apologize if it’s incorrect.
If 1100 square centimeters of material is available to make a box with a square base and an open top, find the largest possible volume of the box. Round to two decimal places if necessary.
volume= a^2 * h
area= a^2+4ah
take the second equation, solve for h
4ah=1100-a^2
h=1100/4a -1/4 a now put that expression in volume equation for h.
YOu now have a volume expression as function of a.
take the derivative, set to zero, solve for a. Then put that value back into the volume equation, solve for Volume.
Cited from jiskha
Brian wants to buy the same
number of hats for 3 of his
friends. He has $57 dollars, and
each hat costs $5. What is the
greatest number of hats that
Brian buys for each friend?
Answer:each friend gets 3.
Step-by-step explanation:
Miya is picking up two friends to go the beach. She drives from her house to
pick up Drea, then she drives to pick up Francine, and then they go to the
beach to play volleyball. What is the total distance of the trip?
The grid below shows the coordinates of their houses on a map. All distances
are in miles.
Answer:
Option (C)
Step-by-step explanation:
Coordinates of the point representing the location of Miya → (1, 10)
Coordinates of the point representing the location of Drea → (13, 1)
Coordinates of the point representing the location of Francine → (16, 1)
Coordinates of the point representing the location of Beach → (19, 4)
Distance between Miya and Drea = [tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
= [tex]\sqrt{(13-1)^2+(1-10)^2}[/tex]
= [tex]\sqrt{144+81}[/tex]
= 15 miles
Distance between Drea and Francine = [tex]\sqrt{(16-13)^2+(1-1)^2}[/tex]
= 3 miles
Distance between Francine and Beach = [tex]\sqrt{(19-16)^2+(4-1)^2}[/tex]
= [tex]\sqrt{9+9}[/tex]
≈ 4.2 miles
Total distance between Miya and the beach = 15 + 3 + 4.2
= 22.2 miles
Option (C) is the answer.
Which graph is a function?
Answer:
B
Step-by-step explanation:
A function is a relation in which each input, x, has only one output, y.
There are two ways to determine if a relation is a function:
1. If each x-input has only one, unique y-output, then it's a function. If some x-inputs share the same y-outputs, it's not a function.
2. Vertical Line Test on Graphs:
To determine whether y is a function of x, when given a graph of relation, use the following criterion: if every vertical line you can draw goes though only 1 point, the relation can be a function. If you can draw a vertical line that goes though more than 1 point, the relation cannot be a function.
Since we're given a graph relation, let's test both of the answers out.
If I were to draw a vertical line in a specific place on the first graph, I'd be hitting more than one point in the coordinate plane.
If I were to draw a vertical line in a specific place on the second graph, I'd only be hitting one point in the coordinate plane.
Therefore, choice B is a function.
A physicist examines 10 water samples for iron concentration. The mean iron concentration for the sample data is 0.711 cc/cubic meter with a standard deviation of 0.0816. Determine the 90% confidence interval for the population mean iron concentration. Assume the population is approximately normal.
Step 1 of 2: Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places.
Step 2 of 2: Construct the 90% confidence interval. Round your answer to three decimal places. Lower endpoint? Upper endpoint?
Answer:
Poggers
Step-by-step explanation:
Find HG and HI.
A. HG = 11/ square root 3 and HI = 7 square root 3
B. HG= 11 square root 3/3 and HI= 7 square root 3/3
C. HG= 11 square root 3 and HI = 23 square root 3
D. HG= 11 square root 3/3 and HI = 22 square root 3/3
Answer: Choice D
HG= 11 square root 3/3 and HI = 22 square root 3/3
In other words, [tex]\text{HG} = \frac{11\sqrt{3}}{3} \ \text{ and } \ \text{HI} = \frac{22\sqrt{3}}{3}\\\\[/tex]
==========================================================
Explanation:
Let's say that x is the short leg and y is the long leg
For any 30-60-90 triangle, we have this connection: [tex]y = x\sqrt{3}[/tex]
The long leg y is exactly sqrt(3) times longer compared to the short leg x.
Let's solve for x and then plug in y = 11
[tex]y = x\sqrt{3}\\\\x = \frac{y}{\sqrt{3}}\\\\x = \frac{y*\sqrt{3}}{\sqrt{3}*\sqrt{3}}\\\\x = \frac{y\sqrt{3}}{3}\\\\x = \frac{11\sqrt{3}}{3}\\\\[/tex]
Side HG, the shorter leg, has an exact length of [tex]\text{HG} = \frac{11\sqrt{3}}{3}\\\\[/tex]
------------------
Once we know the short leg, we double that expression to get the length of the hypotenuse. Like before, this only applies to 30-60-90 triangles.
[tex]\text{hypotenuse} = 2*(\text{short leg})\\\\\text{HI} = 2*\text{HG}\\\\\text{HI} = 2*\frac{11\sqrt{3}}{3}\\\\\text{HI} = \frac{22\sqrt{3}}{3}\\\\[/tex]
------------------
Since [tex]\text{HG} = \frac{11\sqrt{3}}{3}\\\\[/tex] and [tex]\text{HI} = \frac{22\sqrt{3}}{3}\\\\[/tex], this shows that choice D is the final answer.
If g(x)=x+1/x-2 and h(x) = 4 – x, what is the value of (9*h)(-3)?
9514 1404 393
Answer:
(g·h)(-3) = 2.8
Step-by-step explanation:
Given:
g(x) = (x +1)/(x -2)
h(x) = 4 -x
Find:
(g·h)(x) = g(x) × h(x) for x = -3
Solution:
g(-3) = (-3+1)/(-3-2) = -2/-5 = 2/5
h(-3) = 4 -(-3) = 4 +3 = 7
Then the product is ...
g(-3)·h(-3) = (2/5)(7) = 14/5 = 2.8
(g·h)(-3) = 2.8
A cyclist rides his bike at a speed of 21miles per hour. What is this speed in miles per minute? How many miles will the cyclist travel in 10 minutes?
Answer:
.35 miles per minute
3.5 miles in 10 minutes
Step-by-step explanation:
21 ÷ 60= .35
.35 × 10 = 3.5
I need help on this 20 points
Answer:
4^15
Step-by-step explanation:
We know a^b^c = a^(b*c)
4^3^5
4^(3*5)
4^15
Help ASAP please !!
Option 4
Answered by Gauthmath must click thanks and mark brainliest
Your credit card has a balance of $3300 and an annual interest rate of 14%. You decided to pay off the balance over two years. If there are no further purchases charged to the card, you must pay $158.40 each month, and you will pay a total interest of $501.60. Assume you decided to pay off the balance over one year rather than two. How much more must you pay each month and how much less will you pay in total interest?
9514 1404 393
Answer:
$137.90 more each month$246.00 less total interestStep-by-step explanation:
The amortization formula is ...
A = P(r/12)/(1 -(1 +r/12)^(-12t))
for the monthly payment on principal P at annual rate r for t years. Here, we have P=3300, r = 0.14, and t=1, so the monthly payment is ...
A = $3300(0.14/12)/(1 -(1 +0.14/12)^-12) ≈ $296.30
The payment of $296.30 is ...
$295.30 -158.40 = $137.90 . . . more each month
The total amount paid is 12×$296.30 = $3555.60, so 255.60 in interest. This amount is ...
$501.60 -255.60 = $246.00 . . . less total interest
Three yellow balls, two red balls and five orange balls are placed in a bag. Mark draws a
ball out, and replaces it. He then picks another ball.
Draw a tree diagram to represent this information.
What is the probability that he gets at least one yellow ball?
Give your answer as a fraction in its simplest form
i think this could be the answer
(a+b)2= c+d
answer
answer
Answer:
a+b=c+d/2
i cant understand what answer you want
Solve this equation for x. Round your answer to the nearest hundredth.
1 = In(x + 7)
Answer:
[tex]\displaystyle x \approx -4.28[/tex]
General Formulas and Concepts:
Pre-Algebra
Equality PropertiesAlgebra II
Natural logarithms ln and Euler's number eStep-by-step explanation:
Step 1: Define
Identify
[tex]\displaystyle 1 = ln(x + 7)[/tex]
Step 2: Solve for x
[Equality Property] e both sides: [tex]\displaystyle e^1 = e^{ln(x + 7)}[/tex]Simplify: [tex]\displaystyle x + 7 = e[/tex][Equality Property] Isolate x: [tex]\displaystyle x = e - 7[/tex]Evaluate: [tex]\displaystyle x = -4.28172[/tex]e^1 = x+7
e - 7 = x
x = -4.28
The length side of xy is?
Answer:
10
Step-by-step explanation:
ok so you do 12/30 and u get a 0.4 ratio. boom multiply 0.4 by 25 and u get 10. so boom the length is 10
Answer:
XY=10
Step-by-step explanation:
Since they are similar the ratio between each sides should be the same.
Ratio is .4. Found by dividing 12/30.
Multiply .4 by 25= 10
P (6,0) under the translation (x-6, y-1)
Answer:
(0,-1)
Step-by-step explanation:
(6-6,0-1)
or, (0,-1)
Question 2
<
>
B 0.67/1
The measure of one angle of a right triangle is 0° more than the measure of the smallest angle.
Find the measures of all three angles, and separate your answers with commas.
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Answer:
45°, 45°, 90°
Step-by-step explanation:
If the difference of two angles is 0°, then they are congruent, and the triangle is isosceles.
The angle measures of the isosceles right triangle are 45°, 45°, 90°.
Answer anyone ? Tyia :)
