I NEED HELP PLEASE! Can someone help me with the last two red boxes please? The rest of the question is for reference. Thank you for your time!

I NEED HELP PLEASE! Can Someone Help Me With The Last Two Red Boxes Please? The Rest Of The Question

Answers

Answer 1

Answer:

I think you can go with:

The margin of error is equal to half the width of the entire confidence interval.

so  try .74 ± [tex]\frac{.032}{2}[/tex]  =   [ .724 , .756] as the confidence interval

Step-by-step explanation:


Related Questions

Write the solution for x+5≤8 x + 5 ≤ 8 in set notation

Answers

9514 1404 393

Answer:

  {x ∈ ℝ | x ≤ 3}

Step-by-step explanation:

Subtracting 5 from both sides, we see the solution is ...

  x ≤ 3

In set notation, this can be written ...

  {x ∈ | x ≤ 3}

You are skiing down a mountain with a vertical height of 1250 feet. The distance that you ski as you go from the top down to the base of the mountain is 3350 feet. Find the angle of elevation from the base to the tep of the mountain. Round your answer to a whole number as necessary. ​

Answers

Step-by-step explanation:

here is the answer to your question

At Dorcas's Hair Salon there are three hair stylists. 27% of the hair cuts are done by Martin, 30% are done by Jennifer, and 43% are done by Dorcas. Martin finds that when he does hair cuts, 6% of the customers are not satisfied. Jennifer finds that when she does hair cuts, 7% of the customers are not satisfied. Dorcas finds that when she does hair cuts, 3% of the customers are not satisfied. Suppose that a customer leaving the salon is selected at random. If the customer is not satisfied, what is the probability that their hair was done by Dorcas

Answers

Answer:

Dorcas's Hair Salon

If the customer is not satisfied, the probability that their hair was done by Dorcas is:

=  18.75%

Step-by-step explanation:

Number of hair stylists = 3

                                        Martin        Jennifer       Dorcas     Total

Percentage of haircuts

 done                               27%               30%            43%     100%

Percentage of dissatisfied

 customers                      6%                   7%               3%

Proportion of dissatisfied

 customers                    37.5% (6/16)    43.75% (7/16)   18.75% (3/16)

If the customer is not satisfied, the probability that their hair was done by Dorcas

=  18.75%

The isosceles triangle and rectangle have the same perimeter find the value of x

Answers

Answer:

x=15

Step-by-step explanation:

x+2+x+2+2x-2=9+8+9+8

2x+4=34

2x=30

x=15

I need to know the answer ASAP thank you

Answers

Answer:

Step-by-step explanation:

Find the value of term a14 in the sequence.

3, 1, –1, –3, –5, . . .

–23

–11

–9

–25

Answers

9514 1404 393

Answer:

  (a)  -23

Step-by-step explanation:

The sequence is arithmetic with first term 3 and common difference -2. Then the general term is ...

  an = a1 +d(n -1)

  an = 3 -2(n -1)

and the 14th term is ...

  a14 = 3 -2(14 -1) = 3 -2(13) = 3 -26

  a14 = -23

billy joe purchased a 60 gallon pool. at 1 pm he stared filling the pool at the rate of 3 gallons per hour. after 10 hours the horses started drinking the water at the rate of 1 gallon per hour. five hours after that he notices the animal and place a second hose in the pool which filled at the rate of 2 gallons per hour. at what time was the pool finally filled

Answers

Answer:

3*10=30 gallons after 10 hours

minus 1 gal/hr for 5 hours=25 gallons.

If the animals are still drinking, the pool is effectively filling at 1 gal/hr, 2-1, and it will take 35 more hours to fill.

If the animals aren't drinking, the pool will fill at 2 gal/hour and it will be full in 35/2 hours or 17.5 hours.

Step-by-step explanation:

The graph represents two complex numbers, z1 and z2, as solid line vectors. Which points represent their complex conjugates?

Answers

Point A represents the complex conjugate z₁ and point L represents the complex conjugate of z₂ respectively

The reason the above values of the points of the complex conjugate are correct is as follows:

Definition:

The complex conjugate of a complex number is a complex number that

having equal magnitude in the real and imaginary part as the complex

number to which it is a conjugate, but the imaginary part of the complex

conjugate has an opposite sign to the original complex number

Graphically, the complex conjugate is a reflection of the

original complex number across the x-axis because the transformation for

a reflection of the point (x, y) across the x-axis is given as follows;

Preimage (x, y) reflected across the x-axis give the image (x, -y)

In a complex number, x + y·i. we have;

x = The real part

y = The imaginary part

The reflection of z₁(1, -2) across the x-axis gives the point A(1, 2), while the

reflection of z₂(6, -7) across the x-axis gives the point L(6, 7)

To summarize;

Point A(1, 2) is the reflection and therefore represents the complex

conjugate of z₁(1, -2) and point L(6, 7) is the reflection and therefore

represents the complex conjugate of z₂(6, -7)

Learn more about complex numbers here;

https://brainly.com/question/20365080

Y=square root of x compare to y= - square root of x how they differ and why

Answers

Answer:

Simply because x=y2 doesn't imply that y=

x

.

The sum of two positive integers is 19 and the product is 48

Answers

Answer:

16 and 3

Step-by-step explanation:

Let x and y represent the positive integers. We know that

[tex]x + y = 19[/tex]

[tex]xy = 48[/tex]

Isolate the top equation for the x variable.

[tex]x = 19 - y[/tex]

Substitute into the second equation.

[tex](19 - y)y = 48[/tex]

[tex]19y - {y}^{2} = 48[/tex]

[tex] - {y}^{2} + 19y = 48[/tex]

[tex] - {y}^{2} + 19y - 48[/tex]

[tex](y - 16)(y - 3)[/tex]

So our values are

16 and 3.

a. The lengths of pregnancies in a small rural village are normally distributed with a mean of 266 days and a standard deviation of 14 days.
In what range would you expect to find the middle 98% of most pregnancies?
Between_____ and___ .
If you were to draw samples of size 35 from this population, in what range would you expect to find the middle 98% of most averages for the lengths of pregnancies in the sample?
Between_________ and __________.
b. Engineers must consider the breadths of male heads when designing helmets. The company researchers have determined that the population of potential clientele have head breadths that are normally distributed with a mean of 6.9-in and a standard deviation of 0.9-in.
In what range would you expect to find the middle 95% of most head breadths?
Between ____________and ___________.
If you were to draw samples of size 45 from this population, in what range would you expect to find the middle 95% of most averages for the breadths of male heads in the sample?
Between____ and____ .
c. The lengths of pregnancies in a small rural village are normally distributed with a mean of 265.3 days and a standard deviation of 15.2 days.
In what range would you expect to find the middle 50% of most pregnancies?
Between ____and____ .
d. The lengths of pregnancies in a small rural village are normally distributed with a mean of 265 days and a standard deviation of 16 days.
In what range would you expect to find the middle 68% of most pregnancies?
Between _________and ___________.
If you were to draw samples of size 44 from this population, in what range would you expect to find the middle 68% of most averages for the lengths of pregnancies in the sample?
Between_____ and_____ .

Answers

Step-by-step explanation:

a.

mean = 266

sd = 14

cumulative probability = 0.01 so the standard score = -2.33 and 2.33 to the right and left

we find X-upper and X-lower

X-lower = 266-2.33*14 = 233.38

X-upper = 266+2.33*14 = 298.62

Between 233.38 and 298.62

we have sample size = 35

X-lower = 266-2.33*14/√35 = 260.49

X-upper = 266+2.33*14/√35 = 271.5

Between 260.49 and 271.5

b. cumulative probaility = 0.25

standard score = 1.96 to the right and left

x-lower = 6.9-1.96x0.9 = 5.14

x-upper = 6.9+1.96x0.9 = 8.66

Between 5.14 and 8.66

if sample size = 45

x-lower = 6.9-1.96*0.9/√45 = 6.64

x-upper = 6.9+1.96*0.9/√45 = 7.2

Between 6.64 and 7.2

c. standard scores would have cut off value at 0.67 and -0,67

x-lower = 265.3-0.67x15.2 = 255.12

x-upper = 265.3+0.67x15.2 = 275.48

Between 255.12 and 275.48

d. we will have critical values at 1.00 and -1.00

X-lower = 265-1x16 = 249

x-upper = 265+1x16 = 281

Between 249 and 281

with sample size = 44

x-lower = 265-1x16/√44 = 262.59

x-upper = 265+1x16/√44 = 267.41

Between 262.59 and 267.41

Exhibit 10-7 In order to estimate the difference between the average hourly wages of employees of two branches of a department store, two independent random samples were selected and the following statistics were calculated. Downtown Store North Mall Store Sample size 25 20 Sample mean $9 $8 Sample standard deviation $2 $1 Refer to Exhibit 10-7. A 95% interval estimate for the difference between the two population means is _____. Selected Answer: b. .071 to 1.928

Answers

Answer:

[tex]E(x)=1[/tex]

Step-by-step explanation:

From the question we are told that:

Sample mean 1 [tex]\=x_1=$9[/tex]

Sample mean 1 [tex]\=x_2=$8[/tex]

Sample standard deviation 1 [tex]\sigma_1 = $2[/tex]

Sample standard deviation 1 [tex]\sigma_2 = $1[/tex]

Generally the equation for Point estimate is mathematically given by

[tex]E(x)=\=x_1-\=x_2[/tex]

[tex]E(x)=9-8[/tex]

[tex]E(x)=1[/tex]

a group of workers can plant 3/5 acres in 5/6 days. what is the unit rate per day?

Answers

Answer:

Workers can plant 0.72 acres per day.

Meena's family took a road trip to Niagara Falls. Meena slept through
the last 49% of the trip. If the total length of the trip was 500 miles, how many miles had they travelled when Meena fell asleep?

Answers

245 miles

49/100*500 i guess it's the answer

Answer: 255 miles

Explanation:

Total length of the trip = 500 miles

Then 49% = 49/100×500

= 245 miles

Therefore she slept for 245 miles

How many miles had they travelled when meena fell asleep

= 51%

= 51/100×500

= 255 miles

Or

500 - 245

= 255 miles

Answered by Gauthmath must click thanks and mark brainliest

When a constant force is applied to an object, the acceleration of the object varies inversely with its mass. When a certain constant force acts upon an object with mass 4 kg, the acceleration of the object is 13 m/s^2. When the same force acts upon another object, its acceleration is 2 m/s^2. What is the mass of this object?

Answers

Answer:

26 kg

Step-by-step explanation:

varies inversely :

y = k/x

acceleration = k/mass

13 = k/4

k= 52

---------------------

2 = k/mass

2 = 52/mass

mass = 26 kg

what expression is equivalent to (-7²-x-5)-(3x²+x)

Answers

Answer:

-3x² - 2x - 54

Step-by-step explanation:

(-7²-x-5)-(3x²+x)

-7² - x - 5 - 3x² - x

-49 - x - 5 - 3x² - x

-3x² - x - x - 49 - 5

-3x² - 2x - 54

Find the lengths of the other two sides of the isosceles right triangle

Answers

Answer:

h²=p²+b²

(7√2)²=x²+x²

(49×2)=2x²

2x²=49ײ

x²=49×2/2

x²=49

x=√49=7

x=7

OAmalOHopeO

The answer is 7 I’m quite sure

Plz help me i need this question solution

Answers

Answer:

your mom

Step-by-step explanation:

(B) An airline knows from experience that the distribution of the number of suitcases that get lost each week on a certain route is normal with μ (mean) = 15.5 and σ (standard deviation) = 3.6. What is the probability that during a given week the airline will lose between 11 and 19 suitcases?

Answers

Answer:

The correct answer is "0.7289".

Step-by-step explanation:

The given values are:

Mean,

[tex]\mu = 15.5[/tex]

Standard deviation,

[tex]\sigma = 3.6[/tex]

As we know,

⇒ [tex]z = \frac{(x - \mu)}{\sigma}[/tex]

The probability will be:

⇒ [tex]P(11< x< 19) = P(\frac{11-15.5}{3.6} <z<\frac{19-15.5}{3.6})[/tex]

                             [tex]=P(z< 0.9722)-P(z< -1.25)[/tex]

By using the z table, we get

                             [tex]=0.8345-0.1056[/tex]

                             [tex]=0.7289[/tex]

One card is randomly selected from a deck of cards. Find the odds against drawing a black 10.

The odds against drawing a black ten are ___:___.
​(Simplify your​ answers.)

Answers

Answer:

25/26 or 26/27 depending on free hands.

The first is if you don't use jokers/free cards

There is 13 cards in a single set, and a single 10 card.

Two sets are black and two sets a red.

Hearts, Spades, Clubs, and Diamonds

There is only 2 black tens out of 52 or 54 cards, so we can set it up as

50/52 or 52/54 which is simplified to

25/26 or 26/27 depending on free hands.

Step-by-step explanation:

Find the circumference of the circle.
10.1 in
Hint: C = xxd
x= 3.14




A.15.857 in
B.31.714 in
C.63.428 in
D.13.24 in

Answers

Step-by-step explanation:

c=3.14×3.14×10.1

=99.58196

A. Use the appropriate formula to determine the periodic deposit.
B. How much of the financial goal comes from deposits and how much comes from​ interest?
Periodic Deposit: $? at the end of each year
Rate: 7​% compounded annually
Time: 18 years
Financial Goal: ​$130,000

The periodic deposit is? $

Answers

Answer:

A. Periodic deposit:

The goal is to make $130,000 by depositing a set amount every year.

This set amount is an annuity. The $130,000 is therefore the future value of the annuity after 18 years.

Future value of annuity = Annuity * Future value of annuity factor, 7%, 18 years

130,000 = Annuity * 33.9990

Annuity = 130,000 / 33.9990

= $3,823.64

B. Sources of the financial goal.

Money from deposits = Periodic deposit * no. of years

= 3,823.64 * 18

= $68,825.52

Money from interest:

= Financial goal - Money from deposits

= 130,000 - 68,825.52

= $61,174.48

show that the line x-y+2=0 and the line joining the points (4,6) and (10,12) are parallel to each other

Answers

x-y+2=0

-y= -x-2

y=x+2

In order for the other line to be parallel, the slope has to be the same.

(12-6)/(10-4)= 6/6= 1

Both slopes are the same, meaning it is parallel.

Find the missing length indicated

Answers

Answer:

x = 15

Step-by-step explanation:

x = √{(25-16)×25}

x = √(9×25)

x = √225

x = 15

Answered by GAUTHMATH

Graph the function g(x) = 3^x + 3 and give its domain and range using interval notation.

Answers

When a function is plotted on a graph, the domain and the range of the function are the x-coordinate and the y-coordinate respectively.

The domain and the range of the given function are:

Domain: [tex](-\infty,\infty)[/tex]

Range: [tex](3,\infty)[/tex]

 The given function is:

[tex]g(x) = 3^x + 3[/tex]

First, we plot the graph of g(x)

To do this, we need to generate values for x and g(x). The table is generated as follows:

[tex]x = 0 \to g(0) = 3^0 + 3 = 4[/tex]

[tex]x = 1 \to g(1) = 3^1 + 3 = 6[/tex]

[tex]x = 2 \to g(2) = 3^2 + 3 = 12[/tex]

[tex]x = 3 \to g(3) = 3^3 + 3 = 30[/tex]

[tex]x = 4 \to g(4) = 3^4 + 3 = 84[/tex]

The generated values in tabular form are:

[tex]\begin{array}{cccccc}x & {0} & {1} & {2} & {3} & {4} \ \\ g(x) & {4} & {6} & {12} & {30} & {84} \ \end{array}[/tex]

Refer to the attached image for graph of g(x)

To determine the domain, we simply observe the x-axis.

The curve stretches through the x-axis, and there are no visible endpoints on the axis.  This means that the curve starts from [tex]-\infty[/tex] to [tex]+\infty[/tex]

Hence, the domain of the function is: [tex](-\infty,\infty)[/tex]

To determine the range, we simply observe the y-axis.

The curve of g(x) starts at y = 3 on the y-axis and the curve faces upward direction.  This means that the curve of g(x) is greater than 3 on the y-axis.

Hence, the range of the function is: [tex](3,\infty)[/tex]

Read more at:

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Function: [tex]g(x) = 3^{x} + 3[/tex]. Domain: [tex]Dom \{g(x)\} = \mathbb{R}[/tex], Range: [tex]Ran \{g(x) \} = (3, +\infty)[/tex], respectively.

In Function Theory, the domain of a function [tex]f(x)[/tex] represents the set of values of the independent variable ([tex]x[/tex]), whereas the range of the function is the set of values of the dependent variable.

The Domain of the Function represents the set of values of [tex]x[/tex] (horizontal axis), whereas the Range it is the set of values of [tex]y[/tex] (vertical axis). After analyzing the existence of Asymptotes, we complement with graphic approaches and conclude where domain and range (in Interval notation) are.

Analytically speaking, the domain of exponential functions is the set of all real numbers and the range of [tex]g(x)[/tex] is any number between [tex]\lim_{x \to -\infty} g(x)[/tex] and [tex]\lim_{x \to +\infty} g(x)[/tex]. In a nutshell, we get the following conclusions in interval notation:

Domain: [tex]Dom \{g(x)\} = (-\infty, +\infty)[/tex], Range: [tex]Ran \{g(x) \} = (3, +\infty)[/tex]

Lastly, we proceed to complement this analysis by graphing function with the help of a graphing tool.

According to the image, domain and range coincides with outcomes from analytical approaches.

a fair coin is flipped. if the flip results in a head, then a fruit is selected from a basket containing 8 apples, 2 bananas, and 6 cantaloups. if the flip results in a tail, then a fruit is selected from a basket containing 6 apples and 4 bananas. what is the probability that the flip resulted in tails, given that the fruit selexted is a banana g

Answers

Solution :

We have given two baskets :

[tex]$H_1$[/tex] : 8 apples + 2 bananas + 6 cantaloupes = 16 fruits

[tex]$H_2$[/tex] : 6 apples + 4 bananas = 10 fruits

A fair coin is made to flipped. If the [tex]\text{flip}[/tex] results is head, then the fruit is selected from a basket [tex]$H_1$[/tex].

If the flip results in tail, then the fruit is selected from the basket [tex]$H_2$[/tex].

Probability of head P(H) = [tex]1/2[/tex]

Probability of tail P(T) = [tex]1/2[/tex]

if given event is :

B = selected fruit is BANANA

We have to calculate : P(T|B)

Probability of banana if the flip results is head P(B|H) = [tex]$\frac{2}{16}$[/tex]

Probability of banana if the flip results is tail P(B|T) = [tex]$\frac{4}{10}$[/tex]

From the Bayes' theorem :

Probability of flip results is tail when selected fruit is BANANA.

[tex]$P(T|B) = \frac{P(B|T)\ P(T)}{P(B|T) \ P(T) + P(B|H)\ P(H)}$[/tex]

            [tex]$=\frac{\frac{4}{10} \times \frac{1}{2}} {\frac{4}{10} \times \frac{1}{2} + \frac{2}{16} \times \frac{1}{2}}$[/tex]

            [tex]$=\frac{\frac{1}{5}}{\frac{1}{5}+\frac{1}{16}}$[/tex]

            [tex]$=\frac{\frac{1}{5}}{\frac{21}{80}}$[/tex]

            [tex]$=\frac{16}{21}$[/tex]

∴  [tex]$P(\ T|B\ )=\frac{16}{21}$[/tex]

If the nominal rate of interest is 10% per annum and there is quarterly compounding, the effective rate of interest will be: a) 10% per annum b) 10.10 per annum c) 10.25%per annum d) 10.38% per annum​

Answers

9514 1404 393

Answer:

  d) 10.38%

Step-by-step explanation:

The multiplier for four quarters of quarterly compounding is ...

  (1 +10%/4)^4 = 1.025^4 = 1.103812890625

This is about 1 + 10.38%.

The effective rate of interest is about 10.38% per annum.

In the figure, ∆BAT ≅ ∆CAT. Which statement is not true by CPCTC? ∠BTA ≅ ∠CTA ∠BAT ≅ ∠CAT

Answers

Answer:

Both are true.

Step-by-step explanation:

100.331 divide 99.355​

Answers

Answer:

1.009823361

Step-by-step explanation:

Just divide like this:

[tex] \frac{100.331}{99.355} = 1.009853361[/tex]


Write an equation in slope-intercept form for the line with slope -3/2
and y-intercept 5.

Answers

Answer: y = -3/2x + 5

Step-by-step explanation:

Slope-intercept form: y = mx + b

m = slope = -3/2b = y-intercept = 5

y = -3/2x + 5

Answer:

y = -3/2x + 5 totally

Step-by-step explanation:

Other Questions
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