How should the following reaction be classified?
CaCo3 → CaO + CO2
A. combustion
B. decomposition
C. single displacement
D. synthesis
E. double displacement

Answer: Least Common Multiplier of a6m, 0.003 moles 0.01elamos

Steps 6m, 0.003 moles

Compute an expression comprised of Factors that appear either in a6m or 0.003 moles

= 0.018elamos

Explanation:

Taking into account the definition of molarity,  0.005 liters of a 6.0 M solution of acetic acid contain 0.0030 moles​.

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

[tex]molarity=\frac{number of moles}{volume} [/tex]

Molarity is expressed in units [tex]\frac{moles}{liters} [/tex].

In this case, you have a 6.0 M solution of acetic acid that contain 0.0030 moles​. Replacing in the definition of molarity:

[tex]0.6\frac{moles}{liters} =\frac{0.0030 moles}{volume} [/tex]

Solving:

0.6 [tex]\frac{moles}{liters} [/tex]× volume= 0.0030 moles

volume= 0.0030 moles ÷0.6 [tex]\frac{moles}{liters} [/tex]

volume=0.005 liters

Finally, 0.005 liters of a 6.0 M solution of acetic acid contain 0.0030 moles​.

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Answer:

I think the w/w% of this question is 10.

The w/w% of a solution that contains 10 grams of solute and 100 grams of solvent is 9.09%

Mass percentage is another name of w/w % or weight /weight % .

To determine the weight/weight % of a solution :

we divide the mass of solute by mass of the solution (solute and solvent together) and multiply by 100 to obtain per cent.

[tex]\dfrac{w}{w} \; \%\; =\;\rm\dfrac{mass \;of\; solute}{mass\; of \; solute\;+\;mass\;of\;solvent} \times 100[/tex]

It is given that , mass of solute = 10 grams and mass of solvent = 100 grams

So,

[tex]\dfrac{w}{w} \; \%\; =\;\rm\dfrac{10}{10+100} \times 100[/tex]

[tex]\dfrac{w}{w} \; \%\; =\;\rm\dfrac{10}{110} \times 100\\\\\dfrac{w}{w} \; \%\; =\;\rm\dfrac{100}{11}\\\\\dfrac{w}{w} \; \%\; =\; 9.09 \;\%[/tex]

The w/w% of a solution that contains 10 grams of solute and 100 grams of solvent is 9.09% .

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150000 J

Chemistry

Thermodynamics

Specific Heat Formula: q = mcΔT

Math

Pre-Algebra

Order of Operations: BPEMDAS

Step 1: Define

Identify variables

[Given] m = 225 g

[Given] c = 4.184 J/g °C

[Given] ΔT = 133 °C - -26.8 °C = 159.8 °C

[Solve] q

Step 2: Solve for q

Step 3: Check

Follow sig fig rules and round. We are given 3 sig figs.

150436 J ≈ 150000 J

Topic: AP Chemistry

Unit: Thermodynamics

Book: Pearson AP Chemistry

Answer:

the correct answer is option C

Answer:

The correct answer is A

Explanation:

Endothermic is a reaction of which heat is provided to break down the reacted molecules

Answer:

the one that has more power to it

Answer: A

Explanation:

The structure that corresponds to the name. 2, 2, 3-tribromopentane is the first one. option A is correct.

In 2, 2, 3-tribromopentane structure the organic compound consists of 5 charbon chains which all are attached with a single bond to each other and there are 2 bromines attached at the second number of carbon and the last one is attached at the third number of carbon.

Five carbons in the organic compound which all are bounded with a single bond with each other are named pentane and bromine is a functional group attached to the second and third carbon.

This system of the naming of organic compounds was introduced by the international union of pure and applied chemistry. this organic compound is also named based on this system of IUPAC culture.

Therefore, option A is correct.

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Answer:

1.95 M

Explanation:

Molarity is a measure of the molar concentration of a substance (solution). In relation to the volume, it is calculated using the formula as follows;

C1V1 = C2V2

Where;

C1 = initial concentration (M)

C2 = final concentration (M)

V1 = initial volume (L)

V2 = final volume (L)

According to the provided information in this question;

C1 = 14.38 M

C2 = ?

V1 = 1.28 L

V2 = 9.45 L

Using C1V1 = C2V2

14.38 × 1.28 = C2 × 9.45

18.4064 = 9.45 C2

C2 = 18.4064 ÷ 9.45

C2= 1.95 M

Answer:

Freezing point of solution = -2.740C

Explanation:

The solution is attached herewith

The normal freezing point of an aqueous solution of C₁₂H₂₂O₁₁ is -1.26°C

The freezing point depression can be calculated using the formula:

ΔTf = i* Kf*m ; where

The molality of the aqueous solution of C₁₂H₂₂O₁₁ is first determined using the formula:

The mass of water is unknown but is determined from the mass of the solute and solution from the formula:

mass of solute = number of moles * molar mass

moles of solute in 1 L solution = 0.7439 moles

molar mass of solute, C₁₂H₂₂O₁₁ = 342.0 g/mol

mass of solute = 0.7439 moles * 342.0 g

mass of solute = 254.41 g

mass of solution = density * volume

volume of solution = 1 L = 1000 mL

mass of solution = 1.35g/ml * 1000 mL

mass of solution = 1350 g

Therefore, mass of solvent (water) = 1350 g - 254.41 g

mass of solvent (water) = 1095.59 g

mass of solvent (water) in kg = 1095.59 g * 1 kg/ 1000 g

mass of solvent (water) in kg = 1.0956Kg

Thus, molality of solution = 0.7439 moles / 1.0956 Kg

molality of solution = 0.679 mol/kg

The freezing point depression, ΔTf, is then determined using the formula: ΔTf = i* Kf*m

Since C₁₂H₂₂O₁₁ is a non-electrolyte; i for C₁₂H₂₂O₁₁ = 1

Kf of water = 1.86 kg/mole

m = 0.679 mol/kg

ΔTf = 1 * 1.86 * 0.679

ΔTf = 1.26 °C

Therefore, freezing point depression, ΔTf = 1.26 °C

normal freezing point of solution = freezing point of water - freezing point depression

normal freezing point of solution = 0.0°C - 1.26°C

normal freezing point of solution = -1.26°C

Therefore, the normal freezing point of an aqueous solution of C₁₂H₂₂O₁₁ is -1.26°C

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Answer:

The answer is below

Explanation:

Ketone is a class of organic compounds which has a carbonyl group such that the carbon atom is covalently bonded to an oxygen atom, while the remaining two bonds are to other carbon atoms or hydrocarbon radicals.

Ketones are highly reactive hydrocarbons, they can be gotten from the oxidization of secondary alcohols. Ketone are used for medicinal applications.

The third option is the ketone

it’s the the last 2 choices

Sodium hydroxide, also known as lye and caustic soda, is an inorganic compound with the formula NaOH. It is a white solid ionic compound consisting of sodium cations Na + and hydroxide anions OH −

Answer:

6.50M

Explanation:

Molarity, M, is an unit of concentration widely used in analytical chemistry. Is defined as the ratio between the moles of solute (In this case, 5.46 moles) and liters of solution. To solve this question we must find the volume of the solution in liters in to find the molarity of the solution, as follows:

Liters solution:

840mL * (1L / 1000mL) = 0.840L

Molarity:

5.46moles / 0.840L

Answer:

the food goes to your stomache.

Answer: The new temperature of container is 123 K.

Explanation:

Given: [tex]P_{1}[/tex] = 795 mm Hg,     [tex]T_{1}[/tex] = 273 K

[tex]P_{2}[/tex] = 358 mm Hg,          [tex]T_{2}[/tex] = ?

Formula used to calculate the new temperature is as follows.

[tex]\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}[/tex]

Substitute the values into above formula as follows.

[tex]\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}\\\frac{795 mm Hg}{273 K} = \frac{358 mm Hg}{T_{2}}\\T_{2} = 123 K[/tex]

Thus, we can conclude that the new temperature of container is 123 K.

Answer:

C Region

Explanation:

C Region contains all the liquids as 0 °C is the freezing point of water (Crystals of water are formed leaving it no more in the liquid state) and 100 °C is the boiling point (The water boils leaving it no more in the liquid state).

Hence, All liquids are contained in the C region.

[tex]\rule[225]{225}{2}[/tex]

Hope this helped!

it is held every 4-5 years

Answer:

C Condensation of water vapor

Explanation:

One of the components of the atmosphere is water vapour. Water vapour is always present in air.

This water vapour may combine with particles of dust and smoke and condense around them to form clouds.

As more water vapour condenses and coalesces, the clouds become thicker and precipitation eventually follows.

Answer:

Explanation:

The balanced chemical equation between

SrO + 2HCl → H2O + SrCl2

I think that the answer is protons

When an electrolyte dissolves in water, the resulting solution conducts an electric current.

Question :—

1. Calculate the mass percent of salt in salt water if 1 gram of salt is dissolved into 99 grams of water. Show the steps in your calculation.

Answer :—

Mas of common salt (solute)=1 g

Mas of common salt (solute)=1 Mass of water (soluted) =99 g

Mas of common salt (solute)=1 gMass of water (soluted) =99 gmass of solution =1+99 = 100

gconcentration of solution= mass of solution (M mass of solute) ×100 [tex] = > \frac{1}{100} \times 100[/tex]

=> 1% [/tex]Hence, the concentration of the solution is 1%

The  mass percent of salt in salt water if 1 gram of salt is dissolved into 99 grams of water is 1%.

The way of expressing a concentration is mass percent. Moreover, it describes the component in a particular mixture. The solution composition can be understood in a mass percentage. It shows the mass of solute present in a given mass of solution. The quantity of solute is expressed in mass or by moles.

The mass percent may be a way of expressing a degree. Moreover, it describes the component during a particular mixture. The solution composition is often described in mass percentage. It shows the mass of solute present during a given mass of solution. The number of solutes is expressed in mass or by moles.

Percentage of mass = (solute’s mass ÷ mass of solution) x 100%, substitution of values gives 1/100×100=1%.

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We are given:

Volume of gas = 3.8 L

Pressure = 460 mmHg

Temperature = 77°c = (77+273)K = 350K

Converting the pressure to atm:

Pressure(in atm)  = Pressure(in mmHg) / 760

Pressure = 460/760 = 0.6 atm

Finding the number of moles:

using the ideal gas equation:

PV = nRT                                         [where R is the universal gas constant]

replacing the given values in this equation

(0.6)(3.8) = n(0.082)(350)

n = (0.6*3.8)/(0.082*350)

n = 0.08 moles

Answer:

Sand has a melting point of 1550

Salt has a melting point of 1474

Copper Chloride has a melting point of 928.4

Sugar has a melting point of 366.8

Based on this information I am sure you can determine sugar has the lowest melting point

Answer:

B) Co2 cuz in the diagram I see two similar atoms it might be of (oxygen) and the one atom of (carbon)

Answer:

See Explanation

Explanation:

The equation of the reaction is;

C7H16(g) + 11O2(g) ---->7CO2(g) + 8H2O(g)

1a) Number of moles in 228 g of H2O = 228 g/18 g/mol = 12.67 moles

From the reaction equation;

11 moles of O2 yields 8 moles of H2O

x moles of O2 yields 12.67 moles of H2O

x = 11 * 12.67/8

x = 17.4 moles of O2

Since 1 mole of O2 occupies 22.4 L

17.4 moles of O2 occupies 17.4 moles * 22.4 L/1 mole = 389.76 L

1b) Molar mass of C7H16 = 100 g/mol

Number of moles in 300 g of C7H16 = 300 g/100g/mol = 3 moles

1 mole of C7H16 yields 7 moles of CO2

3 moles of C7H16 yields 3 * 7/1 = 21 moles of CO2

If 1 mole of CO2 occupies 22.4 L

21 moles of CO2 occupies 21 moles * 22.4 L/1 mole = 470.4 L of CO2

2) Number of moles in 202 L of H2 is obtained by;

1 mole of H2 occupies 22.4 L

x moles of  H2 occupies 202 L

x = 1 mole * 202 L/22.4 L =  9 moles of H2

From the reaction equation;

3 moles of H2 yields 2 moles of PH3

9 moles of H2 will yield 9 * 2/3 = 6 moles of PH3

Mass of 6 moles of PH3 = 6 moles of PH3 * 34 g/mol = 204 g of PH3

Answer:

100 m of KCL

Explanation:

This is because it is a more reactive metal and higher in the electro reactivity series which lead us to believe that it will take a longer time to heat along with the fact that it is lower in the periodic table and is a metal

i) diffusion, concentration differences in gas and fluid disappears when particles of sugar are evenly spread in solution

ii)  Heating the solution, mixing the solution

b)  Distillation, solution is heated until water is vaporized and water vapour condenses in another part of apparatus.

Sugar is separated from water by evaporation of the sugar solution to dryness.

i) The process of that causes the sugar to spread throughout the water is called solvation.  Solvation simply refers to the interaction of a solute and a solvent.

ii) To make the sugar to dissolve quicker;

b)To obtain pure water from sugar, the sugar is evaporated to dryness. This is done by heating the sugar in a set up as shown in the image attached.

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