what is the voltmeter reading this time?
Answer: positive terminal
Explanation: A voltmeter reading is a process of measuring electic potentials in volts with voltmeter. A positive terminal is the terminal of a battery or other voltage source toward which electrons flow through the external circuit.
An ice skater has a moment of inertia of 5.0 kg.M^2 when her arms are outstretched , and at the time she is spinning at 3.0 rev/s . If she pulls in her arms and decreases her moment of inertia to 2.0 kg.M^2 , how fast will she be spinning
Answer:
The ice skater will spin at an angular speed of 7.5 revolutions per second.
Explanation:
From statement we notice that ice skater can be considered as a system, on which no external forces are exerted, such that Principle of Angular Momentum can be applied:
[tex]I_{1}\cdot \omega_{1} = I_{2}\cdot \omega_{2}[/tex] (Eq. 1)
Where:
[tex]I_{1}[/tex] - Moment of inertia of the ice skater when her arms are outstretched, measured in kilogram-square meters.
[tex]\omega_{1}[/tex] - Angular speed when arms are outstretched, measured in revolutions per second.
[tex]I_{2}[/tex] - Moment of inertial of the ice skater when her arms are pulled, measured in kilogram-square meters.
[tex]\omega_{2}[/tex] - Angular speed when arms are pulled, measured in revolutions per second.
If [tex]I_{1} = 5\,kg\cdot m^{2}[/tex], [tex]\omega_{1} = 3\,\frac{rev}{s}[/tex] and [tex]I_{2} = 2\,kg\cdot m^{2}[/tex], the angular speed when arms are pulled is:
[tex]\omega_{2} = \frac{I_{1}}{I_{2}} \cdot \omega_{1}[/tex]
[tex]\omega_{2} = \left(\frac{5\,kg\cdot m^{2}}{2\,kg\cdot m^{2}} \right)\cdot \left(3\,\frac{rev}{s} \right)[/tex]
[tex]\omega_{2} = 7.5\,\frac{rev}{s}[/tex]
The ice skater will spin at an angular speed of 7.5 revolutions per second.
PLEASE HELP!! ILL MARK BRAINLYEST!!
The atomic particles given off as a result of nuclear fission are _____ and _____.
beta
alpha
omega
gamma
Answer:
The atomic particles given off as a result of nuclear fission are alpha and beta.
Explanation:
A spring scale is used to exert a net force of 2.7 N on a cart.If the cart's mass is 0.64 kg,what is the cart's acceleration?
Answer:
4.2 m/s2
Explanation:
By using Newton's second law, the cart's acceleration is 4.2 m/[tex]s^{2}[/tex]
Given that a spring scale is used to exert a net force of 2.7 N on a cart.
If the cart's mass is 0.64 kg, then, we can use Newton's second law to solve the question.
F = ma
Force F = 2.7 N
Mass m = 0.64 kg
Acceleration a = ?
Substitute all the parameters into the formula
2.7 = 0.64a
a = 2.7/0.64
a = 4.2 m/[tex]s^{2}[/tex]
Therefore, the cart's acceleration is 4.2 m/[tex]s^{2}[/tex]
Learn more about force here: https://brainly.com/question/12970081
23) A ball was thrown straight up into the air at 50. m/s, how fast was it going 2.2 seconds later? (acceleration = g = -9.8 m/s2)
Answer:
-9.8m/s^2 x 2.2 = -21.56m/s^2 50m/s - 21.56m/s^2 = 28.44m/s
PLEASE HELP 25 POINTS !!!!!!!!!!!!!!!! Add the following numbers and round your answer to the correct number of significant figures:
90.0 + 80 =
Show both the unrounded and rounded answer.
Answer:
90.0 + 80 = 170
2 signifigant figures
1.70 x 10^2
HELP GIVING BRAINLIEST
Answer:
Ok let me figure this out
Explanation:
#9 asks what is the relationship between distance and force?
The relationships between the two are of the following: if you have distance you woulnt have force, and if there was no force then there is no distance, the 2 countereact each other and balance the scale
Please help!
A wooden block slides down a ramp that is 16 meters long in 4 seconds. What was the average speed of the wooden block?
A. 16 m/s
B. 20 m/s
C. 64 m/s
D. 4 m/s
When one resistor in a series is shorted, explain what would happen to the circuit's current, resistance, the voltage across the shorted component, and voltage across the other components
Answer:
A. The circuit's current drops. b. The circuit's resistance drops c. The voltage across it is zero d. The voltage remains the same.
Explanation:
a. What would happen to the circuit's current
Since the circuit is in series and one resistor is shorted, the current in the circuit would drop since it is a series circuit and one resistor has been shorted.
b. What would happen to the circuit's resistance
The resistance of the circuit drops by the value of the resistance shorted since it is a series circuit and the shorting cuts off this resistor from the circuit.
c. What would happen to the voltage across the shorted component
The voltage across the shorted component is zero because, since no current flows through it and we know that voltage V = IR and if I = 0, V = 0 × R = 0 V. So, the voltage across it is zero.
d. What would happen to the voltage across the other components
The voltage across the other components remains the same as the initial voltage because, the short transfers the current across the shorted component and makes the shorted component disappear from the circuit. The short thus makes it seem like the source voltage is directly connected to the other components across the shorted resistor. So, the new voltage across the other components is the initial voltage in the circuit before the short.
Please help anyone, I’ll give brainliest!
GREETINGS!
For Horizontal Distance formula is,
[tex]R = \frac{V_{o} ^2}{g} Sin2[/tex] θ
where,
R is range or horizontal distance
[tex]V_{o}[/tex] is initial velocity
g is acceleration due to gravity
θ is the angel it makes
so,
by putting the initial velocity and EACH ANGEL that is given in the data,
we will get range respectively,
for 31 degree = 565m
for 89 degrees= 22m
for 17 degrees = 357.88m
for 49 degrees = 633.77m
for 40 degrees = 630.27m
for 78 degrees = 260.3 m
SO FROM SHORTEST TO LONGEST IS,
89 degrees i.e. 22m , 78 degrees i.e. 260.3 m, 17 degrees i.e. 357.88m, 40 degrees i.e. 630.27m, 49 degrees i.e. 633.77m
I HOPE IT HELPS YOU :)
In a tug-of-war, one team pulls with a force of 150 Newtons.
How much force must the other team pull with if the tug-of-war rope is to be in a state of equilibrium?
A. O Newtons
B. 50 Newtons
C. 75 Newtons
D. 150 Newtons
E.
300 Newtons
As you move from a gas to the solid state forces of attraction do what?
Answer:
Gas – In a gas, particles are in continual straight-line motion. The kinetic energy of the molecule is greater than the attractive force between them, thus they are much farther apart and move freely of each other. In most cases, there are essentially no attractive forces between particles.
Explanation:
Answer:
The molecules of a gas move apart when they collide. The average kinetic energy of the particles in a liquid (or solid) is small enough that the forces of attraction between them is sufficient to hold the particles close together. The molecules in a liquid (or solid) do not move apart.
Explanation:
Gas – In a gas, particles are in continual straight-line motion. The kinetic energy of the molecule is greater than the attractive force between them, thus they are much farther apart and move freely of each other. In most cases, there are essentially no attractive forces between particles.
How long was Michael Jordan in the air when he jumped straight up with a speed of 4.5 m/s? I know the answer is 0.918 seconds, but I don't know how to get there.
Answer:
Explanation:
Using the equation of motion
v = u+gt
v is the final velocity
u si the initial velocity
g is the acceleration due to gravity
t is the time
Substitute
0 = 4.5-(9.8)t
-4.5 = -9.8t
t = 4.5/9.8
t = 0.459s
Why does a balloon when robbed on a wall sticks to the wall
Answer:
static electricity
Explanation:
A fullback is running down the football field in a straight line. He starts at the 0 yard line at 0 seconds. At 1 second, he is on the 10 yard line; at 2 seconds, he is on the 20 yard line; at 3 seconds, he is at the 30 yard line; at 4 seconds, he is on the 40 yard line. What is the players acceleration?
Answer:
10 yards per second
Explanation:
four reasons for launching a satellite into orbit around earth
In cold weather, exercise clothing should be made of a heavy material and be tight fitting to help prevent heat loss.
True
False
Answer:fda
afsd
ffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffff
whats another name 4 the pilgrims.
Answer:
piglets
Explanation:
more than 3
Answer :pedestrian walker.
Explanation:
A cross-country skier moves 36 meters eastward, then 44
meters westward, and finally 22 meters eastward.
For this motion, what is the distance moved?
Tap button at left to enter
Distance = 102
answer using our built-in
number pad.
What is the magnitude and direction of the
displacement?
Magnitude =
Tap button at left to enter
answer using our built-in
number pad
Dir'n =
(Tap field to change.)
Check Answers
Answer:
a) 102 meters
b) 14 meters
c) The direction is eastward.
Explanation:
Distance is said to be the length between two points. It is a scalar quantity.
a) The distance moved = 36 + 44 + 22
= 102 meters
b) Displacement is the distance moved in a specified direction.
Representing the distance moved with specific direction as a directed number, 36 meters eastward = +36, 44 meters westward = -44, and 22 meters eastward = +22
/Displacement/ = +36 -44 +22
= +58-44
= 14
The magnitude of the displacement is 14 meters.
c) The direction is eastward.
So that the magnitude of displacement and his direction is 14 meters eastward.
does using toothpast with baking soda make my teeth whiter than toothpaste without baking soda? What’s the independent variable and what’s the dependent variable. Also the constant?
Answer:
Yes using toothpaste and backing soda is whiting because Toothpaste by itself has whiting products in it which eat plaque off your enamel.
Explanation:
Unlike backing
soda it has an acid that cleans surfaces almost like bleach but safe enough to us on your teeth.
Don't use bleach on teeth it an kill you.
C. The driver is looking at her phone and has a total reaction time of 4.6 seconds as the car is moving at a constant speed of 11 m/s. If the driver slams on her brakes and slows down at a rate of -8.2 m/s2, what is the stopping distance for the car in this situation
Answer:
The stopping distance for the car when the driver slams on her brakes is 7.38 m.
Explanation:
The distance traveled for the car after stopping can be found using the following equation:
[tex] v_{f}^{2} = v_{0}^{2} + 2ad [/tex]
Where:
vf is the final speed = 0 (it stops)
v₀ is the initial speed = 11 m/s
a is the acceleration = -8.2 m/s²
d is the distance =?
When the driver slams on her brakes the distance traveled is:
[tex]d = -\frac{v_{0}^{2}}{2a} = -\frac{(11 m/s)^{2}}{2*(-8.2 m/s^{2})} = 7.38 m[/tex]
Therefore, the stopping distance for the car when the driver slams on her brakes is 7.38 m.
I hope it helps you!
If an object is moving at 4 m/s in the x-direction, and 2 m/s in the y-direction, what is the velocity of the object written in terms of standard basis vectors?
Answer:
V = 4i^ + 2j^
Explanation:
We are given;
Velocity in the x-direction; V_x = 4 m/s
Velocity in the y-direction; V_y = 2 m/s
Now, in terms of standard basis vectors, we normally write the resultant velocity as;
V = (V_x)i^ + (V_y)j^
Thus, the resultant velocity is;
V = 4i^ + 2j^
In a convection current, as the temperature of a fluid increases, what property of the fluid decreases?
density
energy
particle size
particle speed
Answer: Density
Explanation: When the fluids particles are heated, they move faster. As they move faster, the particles occupy more space, causing the density to decrease.
Answer:
A. Density
Explanation:
Describe a change caused by kinetic energy as well as a change that involves potential energy
Answer:
KE= energy associated with motion
PE= energy associated with position
KE example= throwing a ball (ball moving= KE), skateboarding
PE example= dropping a book (since the book is held above the ground, it has PE)(as it falls, PE is converted to KE)
A 0.6 kg basketball moving 7.2 m/s to the right collides with a 0.04 kg tennis ball moving 22 m/ s to the left. After the collision, the tennis ball is moving 32.7 m/s to the right. What is the velocity of the basketball after the collision?
Answer:
6.49m/sExplanation:
Given data
mass of basket ball m1=0.6kg
mass of tennis ball m2= 0.04kg
velocity of basket ball v1=7.2m/s
velocity of tennis ball v2=22m/s
velocity of basket ball v3=?
velocity of tennis ball v4=32.7m/s
we know that the expression for elastic collision is given as
m1v1+m2v2=m1v3+m2v4
substituting we have
0.6*7.2+0.04*22=0.6*x+0.04*32.7
4.32+0.88=0.6x+1.308
solving for x we have
3.892=0.6x
divide both side be 0.6 we have
x=3.892/0.6
x=6.49m/s
The velocity of the basketball after the collision is 6.49m/s
Answer:
3.6 m/s to the right
Explanation:
I gotchu
Question 12(Multiple Choice Worth 2 points) The photoelectric effect describes when light shines on a piece of metal, and the metal releases electrons. Which model of light behavior best helps explain this effect? Particle model Wave model Electromagnetic model Frequency model
Answer:
A. Particle model.
Explanation:
The photoelectric effect describes when light shines on a piece of metal, and the metal releases electrons. The model of light behavior which best helps to explain this effect is the particle model. According to Isaac Newton, he postulated that light consists of little (tiny) particles which typically travels in a straight line and from his experimental investigation he observed that white light comprises of a mixture of colors.
Sir Newton observed that, when light shines on a piece of metal, the metal releases electrons because the energy of the tiny light particles are greater than the binding energy of the electrons residing in the metal. This theory is known as the particle model of light.
Look on a periodic table. What element has the atomic number 6?
Answer:
Carbon (see below)
Explanation:
To identify an element on the period table, you can use its atomic number—or its number of protons.
The atomic number of an element is located in the upper left-hand corner of each square in the periodic table. Refer to IMAGE.A for more info.
If you look at the periodic table, you can spot carbon in the nonmetals.
Carbon's upper left-hand corner has a 6. Refer to IMAGE.B for more info.
A 2455 kg car was pushed by 77 kg student with a force of 720 N. What force does the car apply on the student?
a.0 N
b.-797 N
c.- 720 N
d.-3175 N
Answer:
C
Explanation:
Given that a 2455 kg car was pushed by 77 kg student with a force of 720 N.
According to Newton's third law of motion which state that in every action, there will be equal and opposite reaction.
The action on the car = 720 N
The reaction from the car = - 720 N
Therefore, the force the car will apply on the student will be -720N.
The correct answer is C
a rectangular block has amass of 60 kg and sides 2mx1mx3mx ij g=10m/s then what is the minimum pressure that is it can exert as it rest on a surface
A.100pa
B.200pa
C.50pa
D.300pa
==============================================
Explanation:
The largest face of this rectangular block is 2*3 = 6 square meters. You simply pick the two largest sides and multiply them to get the largest area.
Pressure is defined as the force divided by area. The larger the area gets, the smaller the pressure will be. This is because the pressure is spread out over more area to reduce the per square unit pressure amount.
The block is 60 kg and the acceleration of gravity is roughly 10 m/s^2
So the force pulling down on the block is roughly 60*10 = 600 newtons.
Now we can find the pressure
P = pressure = unknown
F = force = 600 N
A = area = 6 square m
P = F/A
P = (600 N)/(6 m^2)
P = 100 (N/m^2)
P = 100 pa
Where "pa" stands for the unit "pascals", which is one unit for pressure.
--------------
Note what happens when we make A as small as possible. That happens with the 1 by 2 side, so the area is A = 1*2 = 2, and we get
P = F/A = 600/2 = 300 pascals
Reducing A enlarges P. Consequently, minimizing A leads to maximizing P. So the max pressure occurs on the face that is 1 m by 2 m.
A student throws a baseball upwards at an angle of 60 degrees to the horizontal. The initial horizontal and vertical components are 12.50 m/s and 21.70 m/s, respectively At position C, the ball will have a horizontal velocity of -
Answer:
12.5 m/s
Explanation:
Given that,
The initial horizontal and vertical components are 12.50 m/s and 21.70 m/s, respectively.
We need to find the horizontal velocity of the ball at position C.
It is a case of projectile motion. We know that in case of projectile motion, the horizontal velocity of the projectile remains the same while vertical velocity varies. It can be very clear that the horizontal velocity at C is 12.5 m/s.
