Answer:
13/9l or 1 4/9 l
Step-by-step explanation:
Answer:
quantity of alcohol = l liters
we need to make a solution of having 45% alcohol by adding water.
45% alcohol means whatever id the total quantity of solution there is 45% alcohol.
Let the total quantity of solution be x.(
then
quantity of alcohol in terms of x = 45% of x = 45/100 x
but we know that quantity of alcohol = l liters
45/100 x = l
x = 100/45 l
Thus, total quantity of solution is 100/45 l,
but in it, there are l liters of alcohol.
to find the quantity of water we need to subtract the quantity of alcohol from the total quantity of solution
quantity of water in the solution = 100l/45 - l = (100l - 45l)/45 = 65l/45
quantity of water in the solution = 13/9l = 1 4/9 l -------->answer.
Thus, 1 4/9 liters of water needs to be added to l liters of alcohol to make a solution of 45% alcohol.
PLEASE MARK THIS AS BRAINLIST
What are the possible degrees for the polynomial function?
Answer: Option 1
Degrees of 6 or greater
Answered by Gauthmath must click thanks and mark brainliest
A 230 pound man, a 140 pound woman, a 750 pound crate of equipment, an 80 pound bag of concrete. What percent of the total weight was concrete?
What percent of the total weight was human?
A hose is left running for 240 minutes to 2 significant figures. The amount of water coming out of the hose each minute is 2.1 litres to 2 significant figures. Calculate the lower and upper bounds of the total amount of water that comes out of the hose.
Answer:
Hello,
Step-by-step explanation:
Let say t the time the hose is left running
235 ≤ t < 245 (in min)
Let say d the amount of water coming out of the hose each minute
2.05 ≤ d < 2.15 (why d : débit in french)
235*2.05 ≤ t*d < 245*2.15
481.75 ≤ t*d < 526.75 (litres)
Answer:
Lower bound: [tex]495\; \rm L[/tex] (inclusive.)
Upper bound: [tex]505\; \rm L[/tex] (exclusive.)
Step-by-step explanation:
The amount of water from the hose is the product of time and the rate at which water comes out.
When multiplying two numbers, the product would have as many significant figures as the less accurate factor.
In this example, both factors are accurate to two significant figures. Hence, the product would also be accurate to two significant figures. That is:
[tex]240 \times 2.1 = 5.0 \times 10^{2}\; \rm L[/tex] ([tex]500\; \rm L[/tex] with only two significant figures.)
Let [tex]x[/tex] denote the amount of water in liters. For [tex]x\![/tex] to round to [tex]5.0 \times 10^{2}\; \rm L[/tex] only two significant figures are kept, [tex]495 \le x < 505[/tex]. That gives a bound on the quantity of water from the hose.
The number N(t) of supermarkets throughout the country that are using a computerized checkout system is described by the initial-value problem
dN/dt = N(1 − 0.0008N), N(0) = 1.
Required:
Predict how many supermarkets are expected to adopt the new procedure over a long period of time?
Answer:
1250 supermarkets
Step-by-step explanation:
Given
[tex]\frac{dN}{dt} = N(1 - 0.0008N)[/tex]
[tex]N(0) = 1[/tex]
Required
Number of supermarkets over a long period of time
To do this, we simply set
[tex]\frac{dN}{dt} = 0[/tex]
So, we have:
[tex]N(1 - 0.0008N) = 0[/tex]
Split
[tex]N = 0\ or\ 1 - 0.0008N = 0[/tex]
Solve: [tex]1 - 0.0008N = 0[/tex]
Collect like terms
[tex]0.0008N = 1[/tex]
Make N the subject
[tex]N = \frac{1}{0.0008}[/tex]
[tex]N = 1250[/tex]
So:
[tex]\lim_{t \to \infty} N(t) = 1250[/tex]
find the sum of the given infinite geometric series. NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW
Answer:
320/3
Step-by-step explanation:
First find the common ratio
20/80 = 1/4
The sum of an infinite geometric series
sum = a1/ (1-r) where a1 is the first term and r is the common ratio
=80/ ( 1-1/4)
= 80/(3/4)
= 80 *4/3
= 320/3
A silo is built in the shape of a cylinder with a cone for a roof. If the height of the
cylinder is 5 m, the radius is 2.8 m and the slant height of the cone is 6,6 m,
determine the amount of material needed to create the rounded sides and conical
roof, Round to the nearest tenth of a cubic m.
9514 1404 393
Answer:
146.0 m²
Step-by-step explanation:
The lateral areas of the cylinder and cone are given by the formulas ...
A = πrs . . . . cone area; radius r, slant height s
A = 2πrh . . . . cylinder area; radius r, height h
__
The total area lateral area of the silo is ...
A = π(2.8 m)(6.6 m) +2π(2.8 m)(5 m) = π(2.8 m)(6.6 m +2(5 m)) = 46.48π m²
A ≈ 146.0 m² . . . area of sides and roof of silo
_____
Additional comment
The answer is requested in cubic meters. Area has units of square meters. There is nothing in this problem statement that seems to be requesting a volume, which is what would have units of cubic meters.
Which graph represents the function h(x)=x+0.5
Answer:
The correct graph of h(x) will be number 3 (c).
Step-by-step explanation:
We have the function h(x) = |x| + 0.5
On putting x=0, in the function h(x), we get,
h(0) = |0| + 0.5
h(0)=0 + 0.5
h(0)=0.5
Thus, the point (0,0.5) lie on the graph of h(x).
The graph that represents the function h(x) is graph (c)
How to determine the graph?The equation is given as:
h(x) = |x| + 0.5
The above equation is an absolute value function
An absolute value function is represented as:
h(x) = a|x + h| + k
Where:
Vertex = (h,k)
By comparing h(x) = a|x + h| + k and h(x) = |x| + 0.5, we have:
h = 0 and k = 0.5
So, the vertex is (0,0.5)
The graph that has a vertex of (0,0.5) is graph (c)
Hence, the graph that represents the function h(x) is graph (c)
Read more about absolute value function at:
https://brainly.com/question/3381225
Suppose that there are two internet service providers in Kabwe, Eyeconnect and Topconnect.
Currently, Eyeconnect has 180 000 customers and Topconnect has 120 000 customers.
Assume that, every year, 10% of the customer base of Eyeconnect switches to Topconnect
and 5% of the customer base of Topconnect switches to Eyeconnect. For the purposes of this
question, suppose no customer leaves a company without switching to the other one and no
company attracts customers that are not leaving the other (that is, the only changes in
customer base come from switching between the two companies).
a. Find the number of customers of Eyeconnect and Topconnect after one year.
b. Find the number of customers of Eyeconnect after many years.
Answer:
a. 168000 for Eyeconnect, 132000 for Topconnect
b. 100,000
Step-by-step explanation:
a.
Because the change in customers are only due to leaving companies, we can say that, after one year, Eyeconnect loses 10% of its customers to Topconnect and Topconnect loses 5% of its customers to Eyeconnect. This represents all changes in customers.
First, we can calculate how much Eyeconnect loses, which is 10% of 180,000 = 0.1 * 180,000 = 18,000 . They then have 180,000 - 18,000 = 162,000 employees
Next, Topconnect loses 120,000 * 5% = 120,000 * 0.05 = 6,000. They then have 120,000-6,000 = 114,000 employees
We can then add the customer amounts. Note that we are subtracting both sides before adding as both companies gain and lose customers simultaneously.
We can then add how much one company lost to the other company's customers.
Eyeconnect gains 6,000 customers, so they then have 162,000 + 6,000 = 168000 employees. Topconnect gains 18,000 customers so they then have 114,000 + 18,000 = 132,000 employees
b.
After many years, the number of customers Eyeconnect has will be less than the number of customers that Topconnect has. One way to find the end amount of customers that Eyeconnect has is to figure out when the customer bases even out, or when Eyeconnect loses the same amount of customers as Topconnect so the customer base stays the exact same. We know that no customers leave or join the companies except to leave/join the other, so the total amount of customers between the two companies stays the exact same. The amount of customers is 180,000 + 120,000 = 300,000. Therefore, at the end amount,
Eyeconnect customers (E) + Topconnect customers (T) =300,000
Furthermore, if the amount of customers that leave Eyeconnect is the same that leaves Topconnect, we can say
E * 0.1 = T * 0.05
divide both sides by 0.05 to isolate the T
E * 0.1 / 0.05 = T
2 * E = T
plug that into the first equation
E + 2 * E = 300,000
3 * E = 300,000
divide both sides by 3 to isolate E
E = 100,000 after many years
Can someone please help
Answer:
-2 <× <35
i hop i helped you sold the question
= 10 + 3
=13
Example 6
If f(x) = 2x + 1, g(x) = 3x - 2 and fg(x) = 5, find the value of x,
Answer:
f(x) = 2x + 1, g(x) = 3x - 2 and fg(x) = 5
Step-by-step explanation:
Naomi invested $3,425 in an account that
pays 3% simple interest. what was the total
balance of the account after 15 years?
Answer:
$4,966.25
Step-by-step explanation:
3 x 15 = 45
After 15 years, Naomi would have earned a total of 45% interest rate.
3,425 x 1.45 = 4,966.25
Don't use .45 as the multiplier
3,425 x .45 = 1,541.25 <- incorrect
Remy drinks 2/1/4 cups of water every 1/4/5 hours.
How many cups of water does he drink in 1 hour?
Answer:
1¼ cups
Step-by-step explanation:
2¼ ÷ 1/4/5 =
9/4 ÷ 9/5 =
9/4 x 5/9 =
5/4 = 1¼
Write an equation that represents the line.
Use exact numbers.
Answer: y=2/3X- 4/3
Step-by-step explanation:
Slope = (4-2)/(4-1)=2/3
Y-2=2/3(x-1)
Y-2=2/3x-2/3
Y=2/3X-2/3+2
Y=2/3X-4/3
6 times the sum of 5 and K
Answer:
6(5+k)
Step-by-step explanation:
The sum of 5 and k
5+k
6 times the sum
6(5+k)
Teacher gives 2 questions to a class of 50 student. 30 students correctly answer ther first question, 25 students correctly answer the second question, 7 wongly answer both question, there are _ students correctly answer both question
Answer:
43
Step-by-step explanation:
only 7 out of the 50 got both wrong
Answer:
Step-by-step explanation:
Write the options so they are homogeneous in content. • Use answers given in previous open-ended exams to provide realistic distractors. 2. Use a Question ...
A researcher records the repair cost for 27 randomly selected refrigerators. A sample mean of $60.52 and standard deviation of $23.29 are subsequently computed. Determine the 90% confidence interval for the mean repair cost for the refrigerators. Assume the population is approximately normal. Step 1 of 2 : Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places.
Answer:
The critical value is [tex]T_c = 1.7056[/tex]
The 90% confidence interval for the mean repair cost for the refrigerators is ($52.875, $68.165).
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 27 - 1 = 26
90% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 26 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.9}{2} = 0.95[/tex]. So we have T = 1.7056, which means that the critical value is [tex]T_c = 1.7056[/tex]
The margin of error is:
[tex]M = T\frac{s}{\sqrt{n}} = 1.7056\frac{23.29}{\sqrt{27}} = 7.645[/tex]
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 60.52 - 7.645 = $52.875.
The upper end of the interval is the sample mean added to M. So it is 60.52 + 7.645 = $68.165.
The 90% confidence interval for the mean repair cost for the refrigerators is ($52.875, $68.165).
You plan to charge $1 for each time a student plays, and the payout for a win is $5. According to your calculations, the probability of a win is .05. What is your expected value for this game? The expected value
Answer:
- $0.75Step-by-step explanation:
For each game played the chance of winning is 0.05 and losing is 0.95.
If the student wins, they get $5 -$1 = $4, but they lose $1.
Expected value is:
4*0.05 - 1*0.95 = -0.75It means you will make $0.75 per average game.
Answer:
21.8
Step-by-step explanation:
Step 1
This is a problem on finding the mean of continuous grouped data. We first find the midpoint of each interval. For example, the first interval or class is 0 - 10. The mid-point of this class will be (0 + 10)/2 = 5.
fullscreen
Step 2
We now calculate the product of mid-point and frequency for each class. Here, the number of athletes in each class is the frequency of that class. For example, for the first class 0 – 10, its frequency is 3.
fullscreen
Step 3
We can now use the formula to calculate mean. Note that t...
What is a placement form from the school mean
Answer:
Placements are basically extended internships or work experience assignments
Step-by-step explanation:
The height of a triangle is 2 times the base. The area is 4 square inches. Find the base.
The base of the triangle is
inches.
Answer:
2 Inches
Step-by-step explanation:
Area of a triangle = (1/2)* Base * Hight
lets consider the base of the triangle is X inches,
then, Hight of the triangle is 2X
Then the Area of the Angle is = (1/2)*X*2X
4 = x^{2}
X = 2
Ten samples were taken from a plating bath used in an electronics manufacturing process, and the bath pH was determined. The sample pH value are 7.91, 7.85, 6.82, 8.01, 7.46, 6.95, 7.05, 7.35, 7.25, 7.42. Manufacturing engineering believes that pH has a median value of 7.0. Do the sample data indicate that this statement is correct
Answer:
There is no sufficient evidence to support the claim.
Step-by-step explanation:
Given the data:
7.91, 7.85, 6.82, 8.01, 7.46, 6.95, 7.05, 7.35, 7.25, 7.42
Sample size, n = 10
The sample mean, xbar = ΣX/ n = 74.07 / 10 = 7.407
The sample standard deviation, s = 0.41158 ( from calculator)
The hypothesis :
H0 : μ = 7
H0 : μ ≠ 7
The test statistic :
(xbar - μ) ÷ (s/√(n))
(7.047 - 7) ÷ (0.41158/√(10))
0.047 / 0.1301530
Test statistic = 0.361
Testing the hypothesis at α = 0.05
The Pvalue ;
df = n - 1 ; 10 - 1 = 9
Two tailed test
Pvalue(0.361, 9) = 0.7263
Since the Pvalue > α ; we fail to reject the Null and conclude that there isn't sufficient evidence to support the claim.
Walnut High Schools Enrollment is exactly five times as large as the enrollment at walmut junior high the total enrollment for the two schools is 852 what is the enrollment at each school
Answer:
142
Step-by-step explanation:
If the enrollment is five times as big, then that is six different things. So, take 852 and divide it by 6 to get 142. Or in other words:
852÷6=142
142x6=856
I hope this helps. Cheers^^
In an episode of the old school version of the game show Family Feud, 43 out of a random sample of 100 people said they pick their noses at red lights. Find a 95% confidence interval of the proportion of all people who pick their noses at red lights. Be sure to interpret your answer
Answer:
[tex]P_{95\%}=(0.333,0.527)[/tex]
Step-by-step explanation:
From the question we are told that:
Sample size [tex]n=100[/tex]
Selected sample [tex]x=43[/tex]
Confidence Interval [tex]CI=95\%[/tex]
Significance Level [tex]\alpha=0.05[/tex]
Probability of picking nose is
[tex]P=\frac{x}{n}[/tex]
[tex]P=\frac{43}{100}[/tex]
[tex]P=0.43[/tex]
Generally the equation for standard error is mathematically given by
[tex]S.E=\sqrt{p*(1-p)}{n}[/tex]
[tex]S.E=\sqrt{0.4*(1-0.57)}{100}[/tex]
[tex]S.E=0.0495[/tex]
Therefore
The proportions 95\% interval is
[tex]P_{95\%}=[P-1.96x SE(P),P+1.96*SE(P)][/tex]
[tex]P_{95\%}=(0.43-1.96*0.0495,0.43+1.96*0.045)[/tex]
[tex]P_{95\%}=(0.333,0.527)[/tex]
Determine the critical values for the confidence interval for the population standard deviation from the given values. Round your answers to three decimal places.
n = 12 and c = 0.9.
Answer:
The answer is "[tex]\chi^2_{L} = 4.575 \ and\ \chi^2_{U}= 19.675[/tex]"
Step-by-step explanation:
[tex]n=12\\\\\ c= 0.9[/tex]
Calculating the level of significance [tex](\alpha) = 1 -c[/tex]
[tex]=1-0.9\\\\=0.1[/tex]
Calculating the degrees of freedom:
[tex]df=n-1=12-1=11[/tex]
Calculating the critical value:
Applying the Chi-Square table, the critical values for the two-tailed test with a degree of freedom (11) for the significance level of [tex]\alpha = 0.1[/tex]:
[tex]\chi^2_{L} = 4.575 \\\\\chi^2_{U}= 19.675[/tex]
Find the length of the arc. Round your answer to the nearest tenth
Answer:
12.6 mi
Step-by-step explanation:
Arc length = 2πr (Θ/360)
2π(12) (60/360)
= 12.6 mi
Answered by g a u t h m a t h
Solve the equation below:
5x – 11 = 19
x = 4
x = 6
x = 4.4
x = 1.6
pls answer i need help today
Answer:
x=6
Step-by-step explanation:
5x - 11 = 19
5x = 30
x = 6
20characters
5x = 19+11 5x = 30 x = 30/5 x = 6
please help me with this
please mark this answer as brainlist
I'm not sure how to do this
Answer:
1 and 5 sevenths of a bag
Step-by-step explanation:
2/7 males half to it takes 4/7 to make a full one multiply 4 by 3 and you get 12/7 so that makes 1 and 5/7
Find the sequence of this term
41,40,48,38 35,--....,...
Answer:
hxvkgyjdh ht yshysfhyys is not working properly configured form and the kids will not work with a little over again. thank you
The polygons in each pair are similar. Find the missing side length.
Let missing side be x
If both polygons are similar
[tex]\\ \sf\longmapsto \dfrac{3}{4}=\dfrac{18}{x}[/tex]
[tex]\\ \sf\longmapsto 3x=4(18)[/tex]
[tex]\\ \sf\longmapsto 3x=72[/tex]
[tex]\\ \sf\longmapsto x=\dfrac{72}{3}[/tex]
[tex]\\ \sf\longmapsto x=24[/tex]
A sample of 4 different calculators is randomly selected from a group containing 14 that are defective and 34 that have no defects. What is the probability that at least one of the 4 calculators in the sample is defective
Answer:
The answer is "0.7616".
Step-by-step explanation:
Using formula:
[tex]\text{P( at least one de-fective) = 1 - P( all calculators work )}[/tex]
[tex]= 1-(\frac{34}{48}\times \frac{33}{47}\times \frac{32}{46}\times \frac{31}{45})\\\\= 1-(\frac{34}{1}\times \frac{11}{47}\times \frac{1}{23}\times \frac{31}{45})\\\\=1-(\frac{11594}{48647})\\\\=\frac{48647-11594}{48647}\\\\=\frac{37051}{48647}\approx 0.7616[/tex]
