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Answer:
10
Step-by-step explanation:
The sum of terms of an arithmetic series is ...
Sn = (2a +d(n -1))·n/2 = (2an +dn^2 -dn)/2
For the series with first term 2 and common difference 3, the sum is 155 for n terms, where ...
155 = (3n^2 +n(2·2 -3))/2
Multiplying by 2, we have ...
3n^2 +n -310 = 0 . . . . . arranged in standard form
Using the quadratic formula, the positive solution is ...
n = (-1 +√(1 -4(3)(-310)))/(2(3)) = (-1 +√3721)/6 = (61 -1)/6 = 10
10 terms of the series will have a sum of 155.
Step-by-step explanation:
[tex]\displaystyle \ \Large \boldsymbol{} S_n=\frac{2a_1+d(n-1)}{2} \cdot n =155 \\\\ \frac{4+3(n-1)}{2} \cdot n =155 \\\\\\ 4n+3n^2-3n=310 \\\\ 3n^2+n-310=0 \\\\D=1+3720=3721=61^2\\\\n_1=\frac{61-1}{6} =\boxed{10} \\\\\\n_2=\frac{-61-1}{3} \ \ \o[/tex]
Help me pls ASAP I WILL GIVE BRAINLIEST
-3 = -e/75
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Answer:
e = 225
Step-by-step explanation:
To eliminate the coefficient of e, multiply both sides of the equation by its reciprocal. The reciprocal of -1/75 is -75.
(-75)(-3) = (-75)(-e/75)
225 = e
Let f(x) =
[tex] \sqrt[3]{11x - 3 \:} determine \: {f}^{ - 1} (x)[/tex]? here
Step-by-step explanation:
Set up f(x).
[tex] \sqrt[3]{11x - 3} = f(x)[/tex]
Replace f(x) with y
[tex] \sqrt[3]{11x - 3} = y[/tex]
Swap x and y
[tex] \sqrt[3]{11y - 3} = x[/tex]
Solve for y
Cube both sides
[tex]11y - 3 = {x}^{3} [/tex]
Add 3 to both sides
[tex]11y = {x}^{3} + 3[/tex]
Divide both sides by 11
[tex]y = \frac{x {}^{3} + 3 }{11} [/tex]
so
[tex]f {}^{ - 1} (x )= \frac{ {x}^{3} + 3}{11} [/tex]
The strength of a school Increased from 400 to 500 find the Increase percent.
Answer:
25
Step-by-step explanation:
I'm sorry but I rlly don't rember how I did it because I did this question on a quiz and the teacher said this was that answer but not how to get it.
What is the value of x that makes l1||l2?
A. 15
B. 25
C. 18
D. 29
Answer:
x = 29
Step-by-step explanation:
The angles are corresponding angles and corresponding angles are equal when the lines are parallel
3x+17 = 4x-12
Subtract 3x from each side
3x+17-3x = 4x-12-3x
17 = x-12
Add 12 to each side
17+12 = x-12+12
29 =x
Answer:
D. 29
Step-by-step explanation:
If you plug in 29 in the missing values for L1 and L2, you get
L1 = 3(29) + 17 = 104
L2 = 4(29) - 12 = 104
I know I am correct because since both L1 and L2 are parallel and T in cutting them, I know that they are both going to be the same degrees, 104.
So, your answer would be D. 29
Hope the helps! :)
Using the Factor Theorem, which of the polynomial functions has the zeros 2, radical 3 , and negative radical 3 ? f (x) = x3 – 2x2 – 3x + 6, f (x)= x3 – 2x2 + 3x + 6, f (x) = x3 + 2x2 – 3x + 6, f (x) = x3 + 2x2 – 3x – 6
To solve this question, we use the factor theorem, and using it, the polynomial function is:
[tex]f(x) = x^3 - 2x^2 - 3x + 6[/tex]
------------------------------
The factor theorem means that if k is a root of f(x), f(k) = 0.
Thus, applying the factor theorem for this question, we have to choose the function for which: [tex]f(2) = 0, f(\sqrt{3}) = 0, f(-\sqrt{3}) = 0[/tex]
------------------------------
Function 1:
[tex]f(x) = x^3 - 2x^2 - 3x + 6[/tex]
Testing the values:
[tex]f(2) = 2^3 - 2(2)^2 - 3(2) + 6 = 8 - 8 - 6 + 6 = 0[/tex]
[tex]f(\sqrt{3}) = \sqrt{3^3} - 2(\sqrt{3})^2 - 3\sqrt{3} + 6 = \sqrt{3^2\times3} - 6 - 3\sqrt{3} + 6 = 3\sqrt{3} - 3\sqrt{3} = 0[/tex]
[tex]f(-\sqrt{3}) = -\sqrt{3^3} - 2(-\sqrt{3})^2 - 3(-\sqrt{3}) + 6 = -\sqrt{3^2\times3} - 6 + 3\sqrt{3} + 6 = -3\sqrt{3} + 3\sqrt{3} = 0[/tex]
Thus, since all three conditions are satisfied, [tex]f(x) = x^3 - 2x^2 - 3x + 6[/tex] is the polynomial function.
A similar question is given at https://brainly.com/question/11378552
Question 12
A leaking pond loses 16 gallons of water in 5 hours. How many gallons of water will it lose in 41 hours?
Answer:
131.2 gallons
Step-by-step explanation:
1)16/5= 3.2 gallons - of water are lost in 1 hour;
2)3.2*41=131.2 gallons
a team's stadium has a capacity of 86,047. The fan base is notorious for selling out of tickets every game. If every game sells out this year, how many tickets are sold in their 12 game regular season play?
Answer:
1,032,564 tickets
Step-by-step explanation:
Find how many tickets they sell in total by multiplying the capacity of the stadium by the number of games in the season:
86,047(12)
= 1,032,564
So, if every game sells out, 1,032,564 tickets will be sold.
Find the equation of the line: with a slope of -1/2 through (4,5)
Answer:
y=-1/2x+3
Step-by-step explanation:
y=mx+c
5=-1/2*4+c
5=-2+c
c=5-2
c=3
y=-1/2x+3
what is 4 and 5???????
Answer:
586 cm^3 and 486 in^2
Step-by-step explanation:
4) The volume of the triangular prims is (1/2)*(a*c*h) = 0.5*(8*9*16)=586 cm^3
5) Wrapping paper needed is equal to the surface area of the cube, 6s^2=486 in^2
find value of x and YZ if Y is between X and Z
XY=2x+1, YZ =6x, and XZ=81
Answer:
10
Step-by-step explanation:
Applying the segment addition theorem, the value of x = 10
YZ = 60
What is the Segment Addition Theorem?The segment addition theorem states that if a point, C, lies between two endpoints of a segment, A and B, then: AC + CB = AB.
Given:
XY = 2x+1
YZ = 6x
XZ = 81
Thus:
XY + YZ = XZ (segment addition theorem)
2x + 1 + 6x = 81
Find x
8x = 81 - 1
8x = 80
x = 10
Find YZ:
YZ = 6x
Plug in the value of x
YZ = 6(10)
YZ = 60
Therefore, applying the segment addition theorem, the value of x = 10
YZ = 60
Learn more about the segment addition theorem on:
https://brainly.com/question/1397818
There are 200 ounces in 6 liters. How many milliliter (ml) are in 6 liters? (How to do in dimensional analysis?)
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Answer:
6000 mL
Step-by-step explanation:
The prefix "milli-" is an SI standard prefix meaning 1/1000. So, 1 mL = (1/1000)L.
When doing dimension changes, you always want to use scale factors that have a value of 1, which is to say the numerator is equal to the denominator. For converting liters to milliliters, the scale factor you want will have mL in the numerator and L in the denominator:
(1 mL)/(1/1000 L) or (1000 mL)/(1 L)
To do your conversion, multiply your liter volume by this factor.
[tex](6\text{ L})\times\dfrac{1000\text{ mL}}{1\text{ L}}=\dfrac{6\times1000\text{ mL$\cdot$L}}{1\text{ L}}=6000\text{ mL}[/tex]
6 liters is 6000 milliliters.
__
You will notice that the dimensions "L" cancel, which is the point of the exercise.
_____
Additional comment
6 L is closer to 202.884 fluid ounces. The conversion factor is ...
[tex]\dfrac{128\text{ fl oz}}{231\text{ in}^3}\times\dfrac{1\text{ in}^3}{(0.254\text{ dm})^3}\times\dfrac{1\text{ dm}^3}{1\text{ L}}=\dfrac{128\text{ fl oz}}{3.785411784\text{ L}}\quad\text{exactly}[/tex]
[tex]log(x) * log(2)[/tex]
Why can't this problem be solved?
Answer:
Because it is not an equation.
Step-by-step explanation:
[tex] log(x) \times log(2) \\ = log(x + 2) [/tex]
can someone help? i can’t figure this out; i’ll give brainliest:))
What we need to memorize when finding the slope is this formula:
[tex] \displaystyle \large{m = \frac{y_2 - y_1}{x_2 - x_1} }[/tex]
m here represents the slope. I hope this does not confuse you with line m.
The problem here is that we do not have any given points, but we have a way.
If we notice on the graph, the graph contains or passes through (2,-1) and (-2,1). We can use these points to find the slope. So let these be the following:
[tex] \displaystyle \large{(x_1,y_1) = (2 ,- 1)} \\ \displaystyle \large{(x_2,y_2) = ( - 2 ,1)} [/tex]
Then we substitute these points in the formula.
[tex] \displaystyle \large{m = \frac{ 1 - ( - 1)}{ - 2 - 2} }[/tex]
negative × negative = positive.
[tex] \displaystyle \large{m = \frac{ 1 + 1}{ - 2 - 2} } \\ \displaystyle \large{m = \frac{ 2}{ - 4} } \longrightarrow \boxed{m = - \frac{1}{2} }[/tex]
Since m represents the slope. Therefore, the slope of line m is -1/2
I need help please. Thank you
Answer:
0.0009765625
Step-by-step explanation:
This is what i got its probally incorrect
express 6.25 as a fraction and find the square root as a decimal
Answer:
There are several ways to find this. For example:
√
6.25
=
√
6
+
1
4
=
√
25
4
=
√
25
√
4
=
5
2
=
2.5
√
6.25
=
√
625
100
=
√
625
√
100
=
25
10
=
2.5
which is larger 1 1/2 or 1 15/16
Hi there!
»»————- ★ ————-««
I believe your answer is:
1 (15/16)
»»————- ★ ————-««
Here’s why:
⸻⸻⸻⸻
[tex]\boxed{\text{Converting the Fractions...}}\\\\\rightarrow \frac{1}{2}=\frac{1*8}{2*8}= \boxed{\frac{8}{16}}\\\\\text{We would only compare the fractions because we have the same whole number.}\\\\\frac{8}{16} <\frac{15}{16}\\\\\text{Therefore:}\\\\\boxed{1\frac{15}{16} >1\frac{1}{2}}[/tex]
⸻⸻⸻⸻
»»————- ★ ————-««
Hope this helps you. I apologize if it’s incorrect.
I really need help on this been trying for ages
Answer:
cos F = adjacent/hypotenuse
= 15/28
plzz help me asap i need help picture below
Which line has a slope of -?
line d
line b
line a
line c
NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW!!! PLEASE answer thoroughly. Chapter 9 part 2
4. How can you determine the maximum number of solutions for a polynomial? How are these counted on the graph?
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Answer:
a) the degree of the polynomial
b) count the x-intercepts, with attention to multiplicity
Step-by-step explanation:
The Fundamental Theorem of Algebra tells you the number of zeros of a polynomial is equal to the degree of the polynomial. That is, for some polynomial p(x), the number of solutions to p(x)=0 will be the degree of p.
__
On a graph, a real zero of the polynomial will be an x-intercept. The "multiplicity" of a zero is the degree of the factor giving rise to that zero. When the multiplicity is even, the graph does not cross the x-axis at the x-intercept. The greater the multiplicity, the "flatter" the graph is at the x-intercept.
If all solutions (zeros) are distinct, then the number of real solutions can be found by counting the number of x-intercepts of the graph.
_____
By way of illustration, the attached graph is of a 6th-degree polynomial with 6 real zeros. From left to right, they are -1 (multiplicity 1), 1 (multiplicity 2), 4 (multiplicity 3). The higher multiplicities are intended to show the flattening that occurs at the x-intercept, and the fact that the graph does not cross the x-axis where the multiplicity is even.
Three blocks are shown. Which statement is correct?
A. Block A has the greatest density
B. Block B has the greatest density
C. The density of Block A is equal to the density of Block B
D. The density of Block B is equal to the density of Block C
Answer:
Block A has greatest density because it also the biggest.
Step-by-step explanation:
If you like my answer than please mark me brainliest thanks
NEED HELP ASAP
David is shopping for new tires for his 4-wheel-drive truck. In addition to the price of the tires, there is a 10% sales tax plus a state-mandated $60 fee for disposing of his old tires. If David has determined that he will spend less than $578.10 total, then what is the price range he can spend on the tire set?
Select one:
a.
Less than $471
b.
At least 475
c.
$471 or more
d.
Less than 476
Answer:
a. Less than $471
Step-by-step explanation:
The total price must be less than $578.10.
Let the price of the 4 tires = x.
He pays 10% tax on x. That means he pays x + 10%x = 1.1x including tax.
Then he pays the $60 fee.
He pays a total of 1.1x + 60
That must be less than $578.10
1.1x + 60 < 578.10
Subtract 60 rom both sides.
1.1x < 518.1
Divide both sides by 1.1
x < 471
Answer: a. Less than $471
-3(y-5)+6y-2 simplify using distributive property and then combine like terms ANOTHER ONE PLEASE
Answer:
3y+13
Step-by-step explanation:
-3(y-5)+6y-2
Distribute
-3y +15 +6y-2
Combine like terms
-3y+6y +15-2
3y +13
[tex]\bf \large{\purple{ \implies}} \tt \: - 3(y - 5) \: + \: 6y \: - \: 2[/tex]
[tex]\bf \large{\purple{ \implies}} \tt \: - 3y \: + \: 15 \: + \: 6y \: - 2[/tex]
[tex]\bf \large{\purple{ \implies}} \tt \: - 3y \: + \: 6y \: + \: 15 \: - \: 2[/tex]
[tex]\bf \large{\purple{ \implies}} \tt \: 3y \: + \: 13[/tex]
there are 3 blouse and 2 pieces cloths for sale in the market. how many possible sets are there?
Answer:
Each item could be included in a set or not included. That gives 2^5 = 32 ways to choose sets, including 1 set with no items, 5 sets of 1 item, 10 sets of 2 items, 10 sets of 3 items, 5 sets of 4 items, and 1 set of 5 items.
Find the second partial derivatives of the following functions
a) z = 3x^2 − 4xy + 15y^2
b) z = 4xe^y
c) z = 6xln(y)
(a) z = 3x ² - 4xy + 15y ²
has first-order partial derivatives
∂z/∂x = 6x - 4y
∂z/∂y = -4x + 30y
and thus second-order partial derivatives
∂²z/∂x ² = 6
∂²z/∂x∂y = -4
∂²z/∂y∂x = -4
∂²z/∂y ² = 30
where ∂²z/∂x∂y = ∂/∂x [∂z/∂y] and ∂²z/∂y∂x = ∂/∂y [∂z/∂x].
(b) z = 4x eʸ
∂z/∂x = 4eʸ
∂z/∂y = 4x eʸ
∂²z/∂x ² = 0
∂²z/∂x∂y = 4eʸ
∂²z/∂y∂x = 4eʸ
∂²z/∂y ² = 4x eʸ
(c) z = 6x ln(y)
∂z/∂x = 6 ln(y)
∂z/∂y = 6x/y
∂²z/∂x ² = 0
∂²z/∂x∂y = 6/y
∂²z/∂y∂x = 6/y
∂²z/∂y ² = -6x/y ²
apter 3 If a driver uses of a tank of gas every day, what fraction of a tank will he use in a) 3 days? b) 1 week? 21
You need to re copy and paste it, I can’t see the full possible answers/question.
X < -3 graph line
How do you graph
X < -3
Is it A,B,C,D ?
Answer:
Option B
Step-by-step explanation:
x<-3 means the values of x will be less than -3, do the dot will be blank and towards the left side of -3
-4x+3x+2x+x=17
x-4x+3x+2x=13
2x+x-4x+3x=9
3x+2x+x-4x=1
Answer:
x= 8,5
x=0
X= 2
x= -2
Step-by-step explanation:
Use the diagram to answer the question below.
Name a point not on line AC
Answer:
It can be the point E or the point D
Solve: 5 + n > 2
Just let me know because I am stuck and need to know the answer for this test please let me know thank you ❤️
[tex]\\ \sf\longmapsto 5+n>2[/tex]
We have to find n Take 5 to right side sign will be changed[tex]\\ \sf\longmapsto n>2-5[/tex]
Simplify[tex]\\ \sf\longmapsto n>-3[/tex]
A general wishes to draw up his 7500 soldiers in the form of a square. After arranging, he found out that some of them are left out. How many soldiers were left out ?
If you want to form a square of 7500 soldiers, the side of the square must be [tex]\sqrt{7500}\approx86.6[/tex] soliders.
But since you cannot have 0.6 solider, the general needs to find the closest perfect square to the number 7500 which is less than 7500.
That number is 7396 which when square rooted gives 86 soliders on the side.
Subtract 7396 from 7500 and get how many soliders were left out,
[tex]7500-7396=\boxed{104}[/tex]
Hope this helps :)
