If you have 0.341 m3 of water at 25.0 ∘C in an insulated container and add 0.127 m3 of water at 95.0 ∘C, what is the final temperature f of the mixture? Use 1000 kg/m3 as the density of water at any temperature.
Answer:
[tex]T_F=44.0\°C[/tex]
Explanation:
Hello!
In this case, since this calorimetry problem is about the mixing of two volumes of water, we can infer that the heat lost by the hot water is gained by the cold water so we can write:
[tex]Q_{W,hot}=-Q_{W,cold}[/tex]
Which in terms of mass, specific heat and temperature change is:
[tex]m_{W,hot}C_{W,hot}(T_F-T_{W,hot})=-m_{W,cold}C_{W,cold}(T_F-T_{W,cold})[/tex]
Clearly, the specific heat is the same for both waters and the masses, considering the given densities are:
[tex]m_{W,cold}=0.341m^3*\frac{1000kg}{1m^3} =341kg\\\\m_{W,hot}=0.127m^3*\frac{1000kg}{1m^3} =127kg\\[/tex]
Thus, we can solve for the the final temperature as shown below:
[tex]T_F=\frac{m_{W,hot}T_{W,hot}+m_{W,cold}T_{W,cold}}{m_{W,hot}+m_{W,cold}}[/tex]
And by plugging in the values we obtain:
[tex]T_F=\frac{341kg*25.0\°C+127kg*95.0\°C}{341kg+127kg}\\\\T_F=44.0\°C[/tex]
Best regards!
The final temperature of the mixture of hot and cold water at the given masses is 44 ⁰C.
The given parameters;
volume of the cold water, V = 0.341 m³ initial temperature of the wave, = 25⁰Cvolume of water added hot water, = 0.127 m³final temperature of water, = 95⁰ CThe mass of the cold water and the hot water are calculated as follows;
[tex]mass = density \times volume\\\\m_{cold} = 1000 \times 0.341 = 341 \ kg\\\\m_{hot} = 1000 \times 0.127 = 127 \ kg[/tex]
Apply the principle of conservation of energy to determine the final temperature of the mixture;
heat lost by the hot water = heat absorbed by the cold water
[tex]341 \times 4200 \times (t - 25) = 127 \times 4200 \times (95 - t)[/tex]
where;
t is the final temperature of the mixture[tex]341(t- 25) = 127(95-t)\\\\341t - 8525 =12065 - 127t\\\\468t = 20590\\\\t = \frac{20590}{468} \\\\t = 44 \ ^0C[/tex]
Thus, the final temperature of the mixture of hot and cold water at the given masses is 44 ⁰C.
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Explanation:
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what is the isotope formed during radioactive decay
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Explanation:
9.78 cm equals how many
mm
Answer:
97.8
Explanation:
Incorrect
Question 8
0/5 pts
(03.03 MC)
The diagram below represents a convection cell. The arrows
indicate the direction of air flow:
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A
map shows the physical properties or characteristics of a region.
highway
topographical
population
computer
compound
Answer:
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Answer:Electrical
Explanation:because its above the earth's surface
Answer:
Chemical O
Explanation:
A sample of gas contains 0.1200 mol of NH3(g) and 0.1500 mol of O2(g) and occupies a volume of 13.0 L. The following reaction takes place: 4NH3(g) + 5O2(g)4NO(g) + 6H2O(g) Calculate the volume of the sample after the reaction takes place, assuming that the temperature and the pressure remain constant.
Answer:
14.44 Liters
Explanation:
4NH3(g) + 5O2(g) -----> 4NO(g) + 6H2O(g)
From the equation of the reaction, the mole ratio of NH3 to NO2 = 1:1
Therefore 0.12 moles of NH# produces 0.12 moles of NO
Also from the equation of reaction, mole ratio of NH3 to H20 is 4:6
Therefore, 0.12 moles of NH3 will produce 0.12 * 6/ 4 moles of H2O =0 0.18 moles of H2O
Total moles of gases produced = 0.30 mole
From Avogadro's law:
v1/n1 = v2/n2
v1 = 13.0 L
n1 = 0.12 + 0.15= 0.27 moles
v2 = ? =
n2 = 0.30
V2 = v1n2/n1
v2 = 13.0 * 0.30/0.27
V2 = 14.44 Liters
How did Altair begin
Answer:
Altaïr is an ancestor (on the maternal side) of Desmond Miles, a modern-day assassin. He was trained in the Masyaf Castle in Syria by Al Mualim, his guardian since childhood.
Explanation:
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A. distillation of a mixture
B. filtration of pure substance
C. evaporated of a mixture
D. sorting of a pure substance
Answer:
A. distillation of a mixture
Explanation:
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Answer:
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Explanation:
Thermal expansion happens when
Answer:
the size of an object changes with a change in temperature.
Explanation:
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Answer:
I'd say it's the first option, A study that follows people for an extended period of time to see if they develop a disease or condition.
Explanation:
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A. HCl and NaOH
B. NaCl and H20
C. Na and CI
D. H and cl
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What is Reactant ?
The substance(s) to the left of the arrow in a chemical equation are called reactants.
A reactant is a substance that is present at the start of a chemical reaction.
In the given case, HCI and NaOH are the reactants, they both react to form the products, which are NaCl and H₂0.
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starting materials for a chemical reaction,
H2O + S03 - ?
Which compound is likely produced by the chemical reaction?
A. HF
B. H2CO3
C. H2SO4
D. CO2
SUBMIT
Answer:
C. H₂SO₄
Explanation:
Given expression:
H₂O + SO₃ → H₂SO₄
In the chemical reaction, the product and the reactant have the same species.
Chemical reactions obeys the law of conservation of matter.
This way, atoms combine with one another to give a desired product. The products will contain a mix of the reactants.
Fluorine is not part of the reactantsCarbon is not part of the reactantsCarbon is not part of the reactants.Answer:
cccccccccc
Explanation:
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Answer:
I think it is c
Explanation:
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False
True
Answer:
False
Explanation:
That would still be very unsafe
Answer:
False
Explanation:
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3. A solution is neutral if it has more hydronium ions than hydroxide ions.
a. True
b. False
Answer:
false
Explanation:
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B. It is just like regular oxygen
C. It protects us from UV light
D. It is a layer within another layer in our
atmosphere
Answer:
B
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Answer:
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Explanation:
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in order to produce an electric current in a coil of wire , a magnet field through the coil must be
Answer:
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Explanation:
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Answer:
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Explanation:
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Answer:
a. 0.20 M HF and 0.10 M NaOH.
c. 0.10 M HF and 0.10 M NaF
d. 0.10 M HCl and 0.20 M NaF.
Explanation:
A buffer solution consists of a weak acid and its conjugate base, or of a weak base and its conjugate acid.
In this case, HF is the weak acid and F⁻ is its conjugate base.
Let's go case-by-case:
a. 0.20 M HF and 0.10 M NaOH.
Some -but not all- HF will react and produce F⁻, leaving a buffer solution.b. 0.10 M HF and 0.10 M NaOH.
All HF will react, not a buffer solution.c. 0.10 M HF and 0.10 M NaF.
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A 30.0 mL sample of 0.200 M Ba(OH)2 is titrated with 0.100 M HCl.
a) Determine the pH of the solution before the addition of HCl.
b) Determine the pH of the solution after the addition of 25.0 mL HCl.
Answer:
what's the question? is it A
A 30.0 ml sample of 0.200 M Ba(OH)2 is titrated with 0.100 M HCl. teh pH will be:
a) The pH of the solution before the addition of HCl is 13.301.
b) The pH of the solution after the addition of 25.0 mL HCl is 13.494.
What is pH?pH is potential hydrogen. It is the measurement of the acidity and basicity of any solution.
a)
[tex]\rm Ba(OH)_2 = Ba_2+ + 2OH^-Ba(OH)_2[/tex]
Given, [OH¯] = 0.200 M
pOH = -log 0.200 = 0.699
pH = 14.000 - pOH = 14.000 - 0.699 = 13.301
b)
Now 25 ml HCl is added
0.025 × 0.100 = 0.0025
Moles of OH = 0.02 × 0.0025 = 0.0005
Remaining OH = 0.0025 – 0.0005 = 0.00245
Now calculate the pH
0.055 is divided by 0.200 = 0.275
pOH = -log 0.275 = 0.5606
pH = 14.000 - 0.5606 = 13.4394
Thus, a) 13.301.
b) 13.4394.
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