In order to use the energy stored in fat, the body breaks dow triglycerides into fatty acids, which individual cells burn for energy
You decide to focus on pickling cucumbers. The cucumbers that you have are all approximately 12 cm in length and 3 cm in diameter. If the diffusion coefficient for H+ ions in cucumbers is the same as in water, 7 x 10-5 cm2/sec, how long will it take for the protons to reach the center of the cucumbers? Enter your answer in minutes without including the units.
Answer:
0.0036
Explanation:
SEE THE ATTACHMENT BELOW FOR DETAILED EXPLANATION
moles of Fe in 3.13×1022 atoms of Fe
Answer: 0.05 moles
Explanation:
To convert from atoms to moles, you will need Avogadro's number.
Avogadro's number: 6.022×10²³atoms/moles
(3.13×10²²atoms)×(moles/6.022×10²³ atoms)=0.05 moles
The atoms would cancel out and we will be left with our moles.
(a) Give systematic names or the chemical formulas for the following. Remember, names must
be spelled correctly!
1.) [Ni(CO)2C2O4]
2.) K3[Fe(NCO)3(OCN)3]
3.) diammineaquahydroxoplatinum(II) ion
4.) Al[Co(CO3)2(CN)2]
5.) ethylenediaminedinitritozinc(II)
Answer:
[Ni(CO)2C2O4]- Dicarbonyloxalatonickel(0)
K3[Fe(NCO)3(OCN)3-potassiumtricyanatotriisocyanatoferrate II
diammineaquahydroxoplatinum(II) ion- [Pt(NH3)2(H2O)(OH)]^+
Al[Co(CO3)2(CN)2- Aluminiumdicarbonatodicyanocobalt III
ethylenediaminedinitritozinc(II)- Zn(en)(NO2)2
Explanation:
The international Union of Pure and applied chemistry published a set rules for the nomenclature of inorganic compounds in 1985. This set of rules have been consistently revised ever since.
The rules stipulate the order for naming positive ions, negative ions and neutral ligands and the allowed order of preference for naming. It also stipulates the proper endings for ligands which are positive ions, negative ions or neutral ligands as the case may be.
The compounds named above were named in accordance with the revised IUPAC nomenclature for inorganic compounds.
What is the chemical formula for a compound between Al and F? AlF AlF 3 AlF 2 Al 3F
Answer:
AlF3
Explanation:
Aluminum fluoride (AlF3) is an inorganic compound in which aluminum and fluoride has ionic bond between each other.
Aluminum ( atomic number - 13) has 3 valence electrons and can lose 3 electrons to get a stable configuration while fluorine (atomic number - 9) can gain one electron to make a stable configuration. So in order to attain a stable configuration one aluminum (Al) atom form ionic bond with three fluorine atoms and form AlF3.
Hence, the chemical formula between Al and F is AlF3.
Answer:
Explanation:
mmmmmmmmmmmmmh,mm
If 200 mL of 3M CaCO3 is diluted to 250 mL, what is the new molarity?
Answer: The new molarity is 2.4 M
Explanation:
According to the dilution law,
[tex]C_1V_1=C_2V_2[/tex]
where,
[tex]C_1[/tex] = concentration of pure solution = 3 M
[tex]V_1[/tex] = volume of pure solution = 200 ml
[tex]C_2[/tex] = concentration of diluted solution= ?
[tex]V_2[/tex] = volume of diluted solution= 250 ml
Putting in the values:
[tex]3M\times 200ml=M_2\times 250ml[/tex]
[tex]M_2=2.4M[/tex]
Thus the new molarity is 2.4 M
Calculate the empirical formula of a compound with the following
percentage composition: 31,8% K; 29,0% C1; 39,2% O
The empirical formula of ethane is CH. Its molar mass is 30 g.mol-
Answer:
The empirical formula for this compound is thus CH2.
Explanation:
please help me with this!
Answer:
mole fraction of Oxygen = mole of oxygen/ total mole
Explanation:
Atoms of the same element are alike because they must have the same number of
Answer:
They must have the same number of protons.
Explanation:
Protons determine the identity of an element. However, the neutrons can vary, resulting in different masses.
Answer:
Atoms of the same element can have different numbers of neutrons, however. Atoms of the same element (i.e., atoms with the same number of protons) with different numbers of neutrons are called isotopes. Most naturally occurring elements exist as isotopes.
Explanation:
A chemist performed a calibration method analysis to determine the concentration of vitamin c in a fruit sample. The standard vitamin c samples were prepared by mixing a complexing agent with the standard solution. The absorbance of the resulting solution was obtained. Once the absorbance of each standard solution was measured, he prepared the following calibration curve.y = 1.6421x -0.1113The unknown sample was prepared by taking 2.0 g of crushed fruit and extracting the concentrated juice. The extracted juice was added to 100.0 mL volumetric flask and the final volume was adjusted 100.0 mL with DI water. 10.0 mL of diluted fruit extra was pipetted into 50.0 mL volumetric flask and after adding 5.0 mL of complexing agent, the DI water was added until the final volume of the solution reaches 50.0 mL. This solution gave an absorbance of 0.461. I. Find the concentration of vitamin C in the original fruit sample. II. What is the total mass of vitamin C in the sample? III. Calculate the wt% of vitamin C in the fruit sample.
Answer:
I. 1.743mg/mL
II. 0.174g
III. 8.7 wt%
Explanation:
As absorbance is directly proportional to concentration. The calibration curve was:
Y = 1.6421X - 0.1113
Where Y is absorbance of sample and X its concentration in mg/mL
The diluted sample obtains an absorbance of 0.461, that means its concentration is:
0.461 = 1.6421X - 0.1113
0.3485mg/mL = X
I. The sample was diluted to 50.0mL from an aliquot of 10.0mL, thus, concentration in the original fruit sample was:
0.3485mg/mL × (50.0mL / 10.0mL) = 1.743mg/mL
II. The total mass of vitamin C in the sample (100.0mL) is:
100.0mL × (1.743mg/mL) = 174mg = 0.174g
III. As the fruit sample was of 2.0g, the wt% is:
0.174g / 2.0g = 8.7 wt%
How many molecules are in 0.3672 moles of LiBr?
Answer:
2.21×10²³molecules
Explanation:
Hello,
The question requires us to calculate the number of molecules present in a given number of mole.
Numbe of mole = 0.3672 moles
According to mole ratio concept, one mole of any substance is equal to Avogadro's number of particles, atoms or molecules. I.e,
1 mole = Avogadro's number
Avogadro's number = 6.022×10²³ atoms/molecules/particles or ions
1 mole = 6.022×10²³molecules
0.3672 mole = x molecules
x = 0.3672 × 6.022×10²³
X = 2.21×10²³molecules
Therefore, 0.3672moles of LiBr contains 2.21×10²³molecules
Tenormin, a member of the group of drugs known as beta-blockers, is used to treat high blood pressure and improve survival after a heart attack. It works by slowing down the heart to reduce its workload. Which atom in Tenormin is the most basic?
Answer:
Oxygen
Explanation:
In the compound tenormin, there are two highly electronegative atoms capable of accepting electrons; oxygen and nitrogen. Oxygen is more electronegative than nitrogen.
However, the oxygen atom in tenormin is bonded to carbon in a carbonyl bond. Recall that the carbonyl bond is polar and the direction of the dipole is towards the oxygen atom. Looking at the structure of tenormin, it is clear that the electron density of the bond tends towards the oxygen atom of the carbonyl group. Electron density is withdrawn from the adjacent nitrogen atom of the amine group via mesomeric and inductive mechanism towards the more electronegative oxygen atom.
On the other side of the structure, there are two oxygen atoms. These oxygen atoms are more electronegative than nitrogen thus they are more basic.
Hence the oxygen atom is the most basic atom in the compound tenormin.
Kate’s blood volume is 3.8L. Before treatment,if her blood glucose was 170 mg/dL, how many grams of glucose were in her blood?
Answer:
6.460 gm is the correct answer .
Explanation:
Given
Kate’s blood volume=[tex]3.8L[/tex]
blood glucose=[tex]170\ mg/dL[/tex]
As we know that
[tex]1\ dL= 10^{-1}\ litre[/tex]
The [tex]10^{-1}[/tex] includes the blood glucose of the [tex]170\ mg/dL,[/tex]
So [tex]3.8L.[/tex] of the Kate’s blood volume can be determined by
[tex]=\ \frac{170 * 3.8 }{10^{-1} }[/tex]
[tex]=170 * 38 \ mg[/tex]
[tex]=6460\ mg[/tex]
To convert into the gm we have divided by the 1000
[tex]6.460 \ gm[/tex]
Therefore the glucose in her blood=
[tex]6.460 \ gm[/tex]
Answer:
6.460 g
Explanation:
Glucose is a simple carbohydrate molecule which circulates in the blood along with other substances. The amount of glucose is measured to treat the medical conditions of patients which is measured as mg/dL.
1 liter of liquid contains 10 deciliters therefore 1 dL will have 0.1 liter or
1 dL= 10^-1 liter (0.1)
In the given question,
the total volume of blood = 3.8 L
1 dL of blood contains = 170 mg
3.8 L will have = (3.8 x 170)/0.1
=6460 mg
= 6.460 g
Thus, 6.460 g is the correct answer.
Amylose is a "polysaccharide" that plants use to store energy. It is made of repeating subunits of C6H10O5. If a particular amylose molecule has 2537 of these subunits, what is its molecular formula? What is its molar mass? What is the empirical formula of amylose?
Answer:
See exaplanation
Explanation:
For this question, we several sub-questions, lets start with the first one:
What is its molecular formula?
For this question we have to multiply the subunit by the number of subunits in the polysaccharide, so:
[tex](C_6H_1_0O_5)*2537=C_1_5_2_2_2H_2_5_3_7_0O_1_2_6_8_5[/tex]
What is its molar mass?
For this question, we have to find the molar mass of 1 subunit and then multiply by the number of subunits:
Atomic masses: C: 12 g/mol H: 1 g/mol O: 16 g/mol
Now we can multiply, the atomic masses by the number of atoms, so:
[tex](12*6)+(10*1)+(16*5)=~162~g/mol[/tex]
If we take into account the number of subunits:
[tex](162~g/mol)*2537=410994~g/mol[/tex]
What is the empirical formula of amylose?
In this case, we have to remember that the empirical formula is the smallest number of atoms. In other words, we have to simplify the formula. Therefore, the smallest formula is the subunit formula: [tex]C_6H_1_0O_5[/tex].
I hope it helps
How many moles of iron(III) sulfide,
Fe2S3, would be produced from the
complete reaction of 449 g iron(III)
bromide, FeBr3?
Answer:
0.76 mole of Fe2S3.
Explanation:
Step 1:
Determination of the number of mole in 449g iron(III)bromide, FeBr3. This is illustrated below:
Mass of FeBr3 = 449g
Molar mass of FeBr3 = 56 + (80x3) = 296g/mol
Mole of FeBr3 =..?
Mole = Mass /Molar Mass
Mole of FeBr3 = 449/296
Mole of FeBr3 = 1.52 moles
Step 2:
The balanced equation for the reaction. This is given below:
2FeBr3 + 3Na2S —> 6NaBr + Fe2S3
Step 3:
Determination of the number of mole of Fe2S3 produced from the reaction of 449g ( i.e 1.52 moles) of FeBr3. This is illustrated below:
From the balanced equation above,
2 moles of FeBr3 reacted to produce 1 mole of Fe2S3.
Therefore, 1.52 moles of FeBr3 will react to produce = (1.52 x 1)/2 = 0.76 mole of Fe2S3.
Therefore, 0.76 mole of Fe2S3 is produced from the reaction.
Answer: 0.76
Explanation:
The standard free energy change in physiological conditions (G') for the reaction catalyzed by malate dehydrogenase in the citric acid cycle malate + NAD+ oxaloacetate + NADH + H+ is ~+29 kJmol-1 Calculate the actual G' at 37C if Keq' is 1.02 × 10-5
Answer: The actual value of [tex]\Delta G[/tex] is -618 J/mol
Explanation:
Relation of ree energy change and equilibrium constant
[tex]\Delta G=\Delta G^0+2.303\times RT\times \log K_{eq}[/tex]
where,
[tex]\Delta G[/tex] = Free energy change
[tex]\Delta G^o[/tex] = standard free energy change = +29 kJ/mol =
R = universal gas constant
T = temperature = [tex]37^0C=(37+273)K=310K[/tex]
[tex]K_{eq}[/tex] = equilibrium constant = [tex]1.02\times 10^{-5}[/tex]
[tex]\Delta G=+29000J/mol+2.303\times 8.314J/Kmol\times 310K\times \log (1.02\times 10^{-5})[/tex]
[tex]\Delta G=29000J/mol-29619J/mol=-618J/mol[/tex]
The actual value of [tex]\Delta G[/tex] is -618 J/mol
Nitric oxide, NO, is made from the oxidation of NH3, and the reaction is represented by the equation: 4NH3 + 5O2 → 4NO + 6H2O What mass of O2 would be required to react completely with 6.87 g of NH3?
Answer:
16.16g of O2.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
4NH3 + 5O2 → 4NO + 6H2O
Next, we shall determine the mass of NH3 and O2 that reacted from the balanced equation. This is illustrated below:
Molar mass of NH3 = 14 + (3x1) = 17g/mol
Mass of NH3 from the balanced equation = 4 x 17 = 68g
Molar Mass of O2 = 16x2 = 32g/mol
Mass of O2 from the balanced equation = 5 x 32 = 160g.
From the balanced equation above,
68g of NH3 reacted with 160g of O2.
Now, we can calculate the mass of O2 that will be required to react completely with 6.87 g of NH3. This is illustrated below:
From the balanced equation above,
68g of NH3 reacted with 160g of O2
Therefore, 6.87g of NH3 will react with = (6.87 x 160)/68 = 16.16g of O2.
Therefore, 16.16g of O2 is needed for the reaction.
Mass of oxygen required for the reaction is 16.16 g.
The equation of the reaction is;
4NH3 + 5O2 → 4NO + 6H2O
Since Number of moles = Mass/molar mass
Molar mass of ammonia = 17 g mol
Number of moles of NH3 reacted = 6.87 g/17 g mol = 0.404 moles
From the reaction equation;
4 moles of ammonia reacts with 5 moles of oxygen
0.404 moles reacts with 0.404 moles × 5 moles/4 moles = 0.505 moles
Mass of oxygen = 0.505 moles × 32 g/mol = 16.16 g
Learn more: https://brainly.com/question/165414
Fe3O4(s) + CO(g) → FeO(s) + CO2(g) What coefficients will balance the equation? 3, 1, 1, 1 1, 1, 3, 1 3, 3, 1, 1 2, 2, 6, 4
Answer:
1, 1, 3, 1.
Explanation:
When balancing chemical equations, the amount of moles of each element on both sides of the equation should be equal.
Looking at the original equation, we can see that there are 3 mols of iron on the reactants side and 1 on the products. We can simply add a coefficient of '3' to 'FeO' to balance the iron.
For Oxygen, we can see 5 on the reactants side. However, since we already added a coefficient of '3' to 'FeO', this already balanced out the oxygen for us. We have 5 mols in the reactants, and 5 in the products.
Carbon is already balanced on both sides.
Therefore, the final formula is [tex]Fe_{3}O_{4} + CO -> 3FeO + CO_{2}[/tex], with coefficients of 1, 1, 3, and 1.
Answer:
B
Explanation:
Fe3O4(s) + CO(g) →FeO(s) + CO2(g)
Left side
Fe =3
O = 5
C = 1
Right side
Fe =1
O = 3
C = 1
Balance by finding common denominator
We'll make Fe 3 on the left side
Fe3O4(s) + CO(g) →3FeO(s) + CO2(g)
Left side
Fe =3
O = 5
C = 1
Right side
Fe =3
O = 5
C = 1
Convert the average temperatures for each collected data point given below from °C to K. Plot the average cell potentials E (y-axis) vs T (x-axis). The plot should be approximately linear. Add a trendline to find the best linear fit and write down the y-intercept and slope (b and m from the linear equation) for the trendline below.
Average Temperature in °C - Average Cell Potential (V)
15 - 0.465
18 - 0.467
21 - 0.468
24 - 4.69
27 - 0.471
30 - 0.472
33 - 0.474
Answer:
Explanation:
The equation of above line , y = 0.0005x+ 0.458
This can be compared with y = mx+c
Hence slope, m = 0.0005 and Y-intercept, c = 0.458
Or it can be plotted manually where straight line has to be drawn touching maximum number of data points. After drawing a straight linear line, we need to take any two points from the straight line and slope is calculated
Slope,
[tex]m = \frac{y_2-y_1}{x_2-x_1}[/tex]
and y -intercept is calculated using extraplotting backwards such that it touches the Y-axis. the point where straight line touches Y-axis is Y-intercept (c).
Plot the average cell potentials E (y-axis) vs T (x-axis). image attached
Which describes the correct procedure when converting a number from scientific notation to standard notation? If the power of 10 is positive, move the decimal point to the left. If the power of 10 is positive, move the decimal point to the right. If the number being converted is greater than 10, move the decimal point to the left. If the number being converted is greater than 10, move the decimal point to the right.
Answer:
option 2Explanation:
If the power of ten is positive, you move the decimal place to the right when converting a number from scientific to standard notation
For example:
5.6894 * 10^9
10^9 is 1 with 9 zeros
5.6894 * 1000000000
5689400000.
it moved right
If the power of 10 is positive, move the decimal point to the left.
If the power of 10 is positive, move the decimal point to the right.
If the number being converted is greater than 10, move the decimal point to the left.
If the number being converted is greater than 10, move the decimal point to the right.
This is option 2
The correct answer is if the power of 10 is positive, move the decimal point to the right.
What is scientific notation?A frequently-used floating-point system in which integers are expressed as products of a number between 1 and 10 multiplied by a power of 10.
Learn more about scientific notation here:-
https://brainly.com/question/2890945
#SPJ2
A solution consists of 0.27 M MgCl2 and 0.7 M CuCl2. Calculate the concentration of hydroxide ion needed to separate the metal ions. The Ksp of Mg(OH)2 is 6.3x10-10, and the Ksp of Cu(OH)2 is 2.2x10-20. Multiply your answer by 106 and enter that number to 2 decimal places.
Answer:
The concentration of hydroxide ion needed to precipitate Cu²⁺ whereas Mg²⁺ still in solution is 1.77x10⁻¹⁰
Explanation:
Based on the different Ksp of the hydroxides of the metal ions it is possible to precipitate 1 metal as hydroxide whereas the other still in solution.
Ksp of both hydroxides is:
Mg(OH)₂ ⇄ Mg²⁺ + 2OH⁻
Ksp = [Mg²⁺] [OH⁻]² = 6.3x10⁻¹⁰
Cu(OH)₂ ⇄ Cu²⁺ + 2OH⁻
Ksp = [Cu²⁺] [OH⁻]² = 2.2x10⁻²⁰
Replacing with the concentration of the metals:
[0.27] [OH⁻]² = 6.3x10⁻¹⁰
[OH⁻] = 4.83x10⁻⁵M
That means the precipitation of Mg²⁺ begins when [OH⁻] is 4.83x10⁻⁵M
[0.7] [OH⁻]² = 2.2x10⁻²⁰
[OH⁻] = 1.77x10⁻¹⁰
As the Cu²⁺ needs a low concentration of OH⁻ to begin precipitation,
the concentration of hydroxide ion needed to precipitate Cu²⁺ whereas Mg²⁺ still in solution is 1.77x10⁻¹⁰Aluminum metal reacts with sulfuric acid according to the equation:2Al(s) + 3H2SO4(aq) --> Al2(SO4)3(s) + 3H2(g)If 46 g of aluminum reacts with excess sulfuric acid, and 108 g of Al2(SO4)3 are collected, what is the percent yield for the reaction?
Answer:
Percentage yield = 38.37%
Explanation:
2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂
from the equation of reaction, 2 moles of Al reacts to produce 1 moles of Al₂(SO₄)₃
2 moles of Al contains = (2 × 27) = 54g of Al
1 mole of Al₂(SO₄)₃ contains (1 × 342.15) = 342.15g of Al₂(SO₄)₃
54g of Al produces 342.15g of Al₂(SO₄)₃,
46g of Al will produce x g of Al₂(SO₄)₃
Solve for x
X = (46 × 342.15) / 54
X = 15738.9 / 54
X = 281.46g
Theoretical yield of Al₂(SO₄)₃ = 281.46g
Percentage yield of a substance = (actual yield / theoretical yield) × 100
Actual yield = 108g
Theoretical yield = 281.46
% yield = (108 / 281.46) × 100
% yield = 0.3837 × 100
%yield = 38.37
The percentage yield of Al₂(SO₄)₃ is 38.37
Answer: Percentage yield = 38.37%
2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂ from the equation of reaction, 2 moles of Al reacts to produce 1 moles of Al₂(SO₄)₃ .
2 moles of Al contains = (2 × 27) = 54g of Al
1 mole of Al₂(SO₄)₃ contains (1 × 342.15) = 342.15g of Al₂(SO₄)₃
54g of Al produces 342.15g of Al₂(SO₄)₃,
46g of Al will produce x g of Al₂(SO₄)₃
Solve for x
X = (46 × 342.15) / 54
X = 15738.9 / 54
X = 281.46g
Theoretical yield of Al₂(SO₄)₃ = 281.46g
Percentage yield of a substance = (actual yield / theoretical yield) × 100
Actual yield = 108g
Theoretical yield = 281.46
% yield = (108 / 281.46) × 100
% yield = 0.3837 × 100
%yield = 38.37
The percentage yield of Al₂(SO₄)₃ is 38.37
1) How many kJ are absorbed when 45.2 g of water at 31.3 oC is heated to 76.9 oC? 2) Calculate the total heat released in kcal when 72.1 g water at 25.2 oC is cooled to 0 oC and freezes. 3) How many kilojoules are required to heat 55,500 mg of gold with specific heat = 0.129 J/g oC is heated from 24.6 oC to 123.4 oC? 4) Calculate the heat needed in kcal to change 45.6 g of water at 100 oC to change into steam.
Answer:
1. Q = 8.66 KJ
2. Q = 7.58 Kcal
3. Q = 0.71 KJ
4. Q = 24.31 Kcal
Explanation:
1. The quantity of heat absorbed can be determined by:
Q = mcΔθ
where: Q is the quantity of heat absorbed or released, m is the mass of the substance, c is the specific heat capacity of water = 4.2 j/g[tex]^{0}C[/tex] and Δθ is the change in temperature.
= 45.2 × 4.2 × (76.9 - 31.3)
= 8656.704
∴ Q = 8.66 KJ
The quantity of heat absorbed is 8.66 KJ.
2. Q = mcΔθ + mL
Where L is the latent heat of fusion of ice = 334 J.
= m(cΔθ + L)
= 72.1(4.2 × 25.2 + 334)
Q = 31712.464 J
= 7579.466 calories
The total heat released is 7.58 Kcal.
3. Q = mcΔθ
= 55.5 × 0.129 × (123.4 - 24.6)
= 707.3586
The quantity of heat required to increase the temperature of gold is 0.71 KJ.
4. Q = mL
Where: L is the specific latent heat of vaporization = 533 calories.
Q = 45.6 × 533
= 24304.8
The quantity of heat required to change water to steam is 24.31 Kcal.
1.09 grams of H2 to moles
Can the ph scale be utilized for all acids (Arrhenius, Bronsted-Lowery, and Lewis)? Explain reasoning.
Answer:
No, the pH scale can not be utilized for all types of acids known
Explanation:
The pH scale is a scale that shows the degree of acidity or alkalinity of a substance. The pH scale is graduated from 0-14. The pH scale is mostly applied to Arrhenius acids. Recall that in the Arrhenius definition, an acid produces hydrogen ion in solution while a base produces hydroxide ion in solution. Hence we could easily measure or calculate the pH and pOH of Arrhenius acids. Arrhenius acids apply mostly to acid-base discussion in Aqueous media.
Beyond aqueous media, we can still apply the Brownstead-Lowry and Lewis definitions for acid and base. Some of these substances to which we apply these other definitions of acid and base do not necessarily contain hydrogen or hydroxide ions hence the pH scale can not be utilized in discussing their acid-base properties, hence the answer.
In an oven, 7000 kg of limestone are heated to over 900ºC to give lime and carbon dioxide. Assuming all calcium carbonate reacts. How much lime do you get? What volume of CO2 is emitted into the atmosphere? Atomic weights: Ca: 40; C: 12; O: 16.
Answer:
3920kg of lime(CaO) 1568m^3 of CO2
Explanation:
I attached the explanation!
also for calculating the volume I assumed Standard Temperature and Pressure(STP).
The thyroid, parathyroid, and thymus are located in the
The adrenals, pancreas, testes, and ovaries are located in the
The pineal, hypothalamus, and pituitary are located in the
Answer:
The pineal, hypothalamus, and pituitary are located in the BRAIN
The thyroid, parathyroid, and thymus are located in the THROAT
The adrenals, pancreas, testes, and ovaries are located in the NEAR THE KIDNEY
Explanation:
The pineal, hypothalamus, and pituitary are located in the BRAIN
The thyroid, parathyroid, and thymus are located in the THROAT
The adrenals, pancreas, testes, and ovaries are located in the NEAR THE KIDNEY
Answer:
Throat
Abdomen
Brain
Explanation:
These are correct!
A liquid solvent is added to a flask containing an insoluble solid. The total volume of the solid and liquid together is 93.0 mL. The liquid solvent has a mass of 33.7 g and a density of 0.865 g/mL. Determine the mass of the solid given its density is 3.50 g/mL
Answer:
Mass of solid = 189.141 gram
Explanation:
Given:
Total volume = 93 ml
Mass of liquid = 33.7 gram
Density of liquid = 0.865 g/ml
Density of solid = 3.50 g/ml
Find:
Mass of solid = ?
Computation:
Volume of liquid = Mass of liquid / Density of liquid
Volume of liquid = 33.7 / 0.865
Volume of liquid = 38.9595 ml
Volume of solid = Total volume - Volume of liquid
Volume of solid = 93 - 38.9595
Volume of solid = 54.0405 ml
Mass of solid = Volume of solid × Density of solid
Mass of solid = 54.0405 ml × 3.50 g/ml
Mass of solid = 189.141 gram
three requirements to start a fire
what type of reaction is Cl2(g) + 2Kl(aq) arrow 2KCl(aq) + I2 (s)
2 MnO4−(aq) + 10 Cl−(aq) + 16 H+(aq) → 5 Cl2(g) + 2 Mn2+(aq) + 8 H2O(l) Oxidizing agent: Reducing agent:
Answer:
MnO4 is the oxidizing agent.
Cl is the reducing agent.
Explanation:
To know which is oxidizing agent and which is reducing agent, let us calculate the change in oxidation number of each element in the equation below:
2MnO4−(aq) + 10Cl−(aq) + 16H+(aq) → 5Cl2(g) + 2Mn2+(aq) + 8H2O(l)
Please note:
1. The oxidation state of oxygen is always –2 except in peroxide where it is –1
2. The oxidation state of Hydrogen is always +1 except in hydrides where it is –1
3. The oxidation state of chlorine is always –1
For Mn:
At left hand side
MnO4 = –1
Mn + 4O = –1
O = –2
Mn + (4 x –2) = –1
Mn – 8 = –1
Collect like terms
Mn = –1 + 8
Mn = +7
At the right hand side, Mn is +2.
The oxidation state of Mn changes from +7 to +2.
For Cl:
At the left hand side
Cl = –1
At the right hand side
Cl = 0
The oxidation state of Cl changes from – 1 to 0.
The oxidation state of O and H are unchanged.
Since the oxidation state of Mn changes from +7 to +2 i.e reduced, MnO4 is the oxidizing agent.
Since the oxidation state of Cl changes from – 1 to 0 i.e increase, Cl is the reducing agent.
