Hi I need the answer to this please

Answer:

E = 2.17 x 10⁻² V/m

Explanation:

First we will find out the current density by using the formula:

J = I/A

where.

J = Current Density = ?

I = Current = 5.5 A

A = Cross-Sectional Area = πr² = π(1.5 x 10⁻³ m)² = 7.068 x 10⁻⁶ m²

Therefore,

J = 5.5 A/7.068 x 10⁻⁶ m²

J = 0.778 x 10⁶ A/m²

Now, we calculate the magnitude of applied field:

E = ρJ

where,

E = Magnitude of applied field = ?

ρ = resistivity of Aluminum = 2.8 x 10⁻⁸ Ω.m

Therefore,

E = (2.8 x 10⁻⁸ Ω.m)(0.778 x 10⁶ A/m²)

E = 2.17 x 10⁻² V/m

Compute the block's weight:

w = m g = (20 kg) (9.8 m/s²) = 196 N

The net vertical force is 0, so the normal force has the same magnitude:

n + (-w) = 0   →   n = 196 N

The frictional force (mag. f ) is proportional to the normal force by a factor of µ = 0.20 such that

f = 0.20 (196 N) = 39.2 N ≈ 39 N

The force of kinetic friction acting on the block of mass 20 Kg having a coefficient of kinetic friction of 0.2 is 39.2 N

Mass (m) = 20 Kg

Acceleration due to gravity (g) = 9.8 m/s²

N = mg

N = 20 × 9.8

Coefficient of kinetic friction (µ) = 0.2

Normal reaction (N) = 196

F = µN

F = 0.2 × 196

Therefore, the force of kinetic friction acting on the block is 39.2 N

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Answer:3 N —->

Explanation:

In the case when  the forces act on the car as shown in the picture so here the net force should be 3N.

Since

A parachute in the back of the car is released to help slow down the car.

So here the net force should be

= 10 N - 7N

= 3 N

Hence, In the case when  the forces act on the car as shown in the picture so here the net force should be 3N.

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Answer:

if he were to land on concrete, he would most likely die and stop all momentum and for the water, he'd most likely live/die (mostly live) and slow momentum to a stop and rise up to the surface

Explanation:

that's the explanation now i gotta execute order 66

Answer:

Streamline the body of the rocket to reduce drag

Keep weight to a minimum

Use higher pressures

Use the right amount of water

Answer:

1.

A. Vf = 29.4 m/s

B. h = 44.1 m

2.

A. Vf = 24.5 m/s

B. h = 30.625 m

3.

A. Vf = 5.5 m/s

4.

A. t = 3.03 s

B. Vf = 29.7 m/s  

Explanation:

1.

A.

using 1st equation of motion:

Vf = Vi + gt

where,

Vf = Final Velocity = ?

Vi = Initial Velocity = 0 m/s (since, book starts from rest)

g = 9.8 m/s²

t = time = 3 s

Therefore,

Vf = 0 m/s + (9.8 m/s²)(3 s)

Vf = 29.4 m/s

B.

using 2nd equation of motion:

h = Vi t + (1/2)gt²

h = (0 m/s)(3 s) + (1/2)(9.8 m/s²)(3 s)²

h = 44.1 m

2.

A.

using 1st equation of motion:

Vf = Vi + gt

where,

Vf = Final Velocity = ?

Vi = Initial Velocity = 0 m/s (since, book starts from rest)

g = 9.8 m/s²

t = time = 2.5 s

Therefore,

Vf = 0 m/s + (9.8 m/s²)(2.5 s)

Vf = 24.5 m/s

B.

using 2nd equation of motion:

h = Vi t + (1/2)gt²

h = (0 m/s)(2.5 s) + (1/2)(9.8 m/s²)(2.5 s)²

h = 30.625 m

3.

A.

using 3rd equation of motion:

2gh = Vf² - Vi²

where,

Vf = Final Velocity = ?

Vi = Initial Velocity = 3 m/s

g = 9.8 m/s²

h = height = 2 m

Therefore,

2(9.8 m/s²)(2 m) = Vf² - (3 ms)²

Vf² = 39.2 m²/s² - 9 m²/s²

Vf = √30.2 m²/s²

Vf = 5.5 m/s

4.

A.

using 2nd equation of motion:

h = Vi t + (1/2)gt²

where,

h = height = 45 m

Vi = Initial Velocity = 0 m/s (since, photo copier was initially at rest)

t = time = ?

g = 9.8 m/s²

45 m = (0 m/s)(t) + (1/2)(9.8 m/s²)(t)²

t² = 2(45 m)/(9.8 m/s²)

t = √9.18 s²

t = 3.03 s

B.

using 1st equation of motion:

Vf = Vi + gt

Vf = 0 m/s + (9.8 m/s²)(3.03 s)

Vf = 29.7 m/s

Answer:

5

Explanation:

Answer:

5

Explanation:

Explanation:

so sorry

don't know but please mark me as brainliest please

Answer: If you want me to write them for you here they are

Explanation:

Net force causes  change in motion because  a net external force causes a change in motion; thus, we see that a net external force causes acceleration.

Not more likely to be Net force motion because if it doesnt say change then its gonna stay the same so Net force does cause change in a motion because  take for example if you are going to bounce a basketball its gonna change its position from one place to another thats how Net force causes Change in motion.  

Hope this helps :)

The properties of fluids are Density,Viscosity,Temperature, Pressure,Specific Volume,Specific Weight,Specific Gravity.

We are Given:

Mass of the block (m) = 500 grams or 0.5 Kg

Initial velocity of the block (u) = 0 m/s

Distance travelled by the block (s) = 8 m

Time taken to cover 8 m (t)= 2 seconds

Acceleration of the block (a) = a m/s²

Solving for the acceleration:

From the seconds equation of motion:

s = ut + 1/2* (at²)

replacing the variables

8 = (0)(2) + 1/2(a)(2)²

8 = 2a

a = 4 m/s²

Therefore, the acceleration of the block is 4 m/s²

The cart is pulled at a constant velocity, so it is in equilibrium. In particular, the net horizontal force is zero, and consists of only the pulling force and friction such that

p - f = 0

where p and f denote the magnitudes of the pulling force and friction.

So we have

p - 12 N = 0

p = 12 N

Answer:

280.6N

Explanation:

According to Newton's second law;

Force = mass * acceleration

Given

Mass = 280kg

velocity = 10m/s

Time = 10 secs

Acceleration = velocity?/Time

Force = mass * velocity/time

Force = 280 + (16-10/10)

Force = 280 + 0.6

Force = 280.6N

Hence the force exerted by the snowmobile to accelerate is 280.6N

Answer:168 N

Explanation:

Answer:

Dy = 49.01 [m]

Explanation:

The vertical component of the vector can be determined with the sine of the angle.

Dy = 92.5*sin(32)

Dy = 49.01 [m]

Answer:

(a) ω = 1.57 rad/s

(b) ac = 4.92 m/s²

(c) μs = 0.5

Explanation:

(a)

The angular speed of the merry go-round can be found as follows:

ω = 2πf

where,

ω = angular speed = ?

f = frequency = 0.25 rev/s

Therefore,

ω = (2π)(0.25 rev/s)

ω = 1.57 rad/s

(b)

The centripetal acceleration can be found as:

ac = v²/R

but,

v = Rω

Therefore,

ac = (Rω)²/R

ac = Rω²

therefore,

ac = (2 m)(1.57 rad/s)²

ac = 4.92 m/s²

(c)

In order to avoid slipping the centripetal force must not exceed the frictional force between shoes and floor:

Centripetal Force = Frictional Force

m*ac = μs*R = μs*W

m*ac = μs*mg

ac = μs*g

μs = ac/g

μs = (4.92 m/s²)/(9.8 m/s²)

μs = 0.5

Answer:

66.7s

Explanation:

Given parameters:

Distance between Mars and Earth  = 2 x 10¹⁰m

Unknown:

Time it takes for light to travel  = ?

Solution:

The speed of light is given as 3 x 10⁸m/s

 Now;

   Speed  = [tex]\frac{distance}{time}[/tex]  

    Time  = [tex]\frac{distance}{speed}[/tex]

Insert the parameters and solve;

   Time  = [tex]\frac{2 x 10^{10} }{3 x 10^{8} }[/tex]   = 66.7s

Answer: the velocity of water as it squirts horizontally from the needle is 4.09196 m/s

Explanation:

Given that;

inside diameter = 109μm

barrel diameter = 2.22 cm so r = 1.11 cm = 0.0111 m

force fair = 3.24 N

We know that the inside diameter is neglected; from the Bernoulli's equation

so

P_inside + 1/2pv²_inside + egy_inside = P_outside + 12pv²_outside + egy_outside

p_inside - p_outside = 1/2e_airv²outside = Fair / Abannel

Fair = 1/2painv²outside . Abannel

therefore

3.24 = 1/2(1000) v²outside (πr²)

3.24 = 1/2(1000) v²outside (π × (0.0111)²

3.24 = 0.1935 v²_outlet

v²_outlet = 3.24 / 0.1934

v²_outlet  = 16.7441

v_outlet = √16.7441

v_outlet  = 4.09196 m/s

Therefore the velocity of water as it squirts horizontally from the needle is 4.09196 m/s

Answer:

1.8m/s^2

Explanation:

Since the two ropes are going up, their combined force is 105+115=220N. With a gravitational force of 186N, the force of the two ropes pulling up the will be 220-186=34N.

Now we need the mass of the bucket itself in order to find the acceleration of the bucket (remember that F=ma and m is needed to find a). Since gravitational acceleration is 9.8m/s^2 and F=186N, 186/9.8=18.97959184 kg for the mass of the bucket.

Now that we have the mass of the bucket, we can find the acceleration of the bucket. Since F=34N from earlier, 34N/18.97959184kg=1.791397849m/s^2=1.8m/s^2 is the acceleration of the bucket.

Therefore, 1.8m/s^2 is the correct answer.

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Answer:

1.8

Explanation:

honestly i jus took the test

Answer:

6.64 Newtons

On the moon that 40 kg child would have a weight of 6.64 Newtons (kg multiplied by gravity) because the moon's gravity is 1/6th of the Earth's gravity. Your mass on any planet on the solar system (Jupiter, Venus, Earth, or anywhere else) is the same because the amount of matter in you does not change.

Explanation:

Answer:

The moment of inertia of this system is 68 kilogram-square meters.

Explanation:

We have two particles rotating about the z-axis, which is orthogonal to xy plane, the moment of inertia of the system ([tex]I_{z}[/tex]), measured in kilogram-square meters, is determined by the following formula:

[tex]I_{z} = \Sigma \limits_{i=1}^{2}m_{i}\cdot r_{i}[/tex] (1)

Where:

[tex]m_{i}[/tex] - Mass of the i-th particle, measured in kilograms.

[tex]r_{i}[/tex] - Distance of the i-th particle from axis of rotation, measured in meters.

By Pythagorean Theorem we calculate each distance:

[tex](x_{1}, y_{1}, z_{1}) = (4\,m, 0\,m,0\,m)[/tex]

[tex]r_{1}=\sqrt{(4\,m-0\,m)^{2}+(0\,m-0\,m)^{2}+(0\,m-0\,m)^{2}}[/tex]

[tex]r_{1} = 4\,m[/tex]

[tex](x_{2},y_{2}, z_{2}) = (0\,m, 3\,m, 0\,m)[/tex]

[tex]r_{2} = \sqrt{(0\,m-0\,m)^{2}+(3\,m-0\,m)^{2}+(0\,m-0\,m)^{2}}[/tex]

[tex]r_{2} = 3\,m[/tex]

If we know that [tex]m_{1} = 2\,kg[/tex], [tex]r_{1} = 4\,m[/tex], [tex]m_{2} = 4\,kg[/tex] and [tex]r_{2} = 3\,m[/tex], then the moment of inertia of the system is:

[tex]I_{z} = m_{1}\cdot r_{1}^{2}+m_{2}\cdot r_{2}^{2}[/tex] (1b)

[tex]I_{z} = (2\,kg)\cdot (4\,m)^{2}+(4\,kg)\cdot (3\,m)^{2}[/tex]

[tex]I_{z} = 68\,kg\cdot m^{2}[/tex]

The moment of inertia of this system is 68 kilogram-square meters.

Answer:

Explanation:

mass number is now 4 times less than the original value so alpha decay occur during alpha decay the mass number is decreased 4 times and atomic number decreased 2 times than the original value

Answer:

20 m

Explanation:

Area under the speed-time graph = Distance Traveled

Area under Graph 1/2(2)(20)

=20 m

Answer:

The speed of the projectile upon returning to its starting point is 50 m/s.

Explanation:

Given;

initial velocity of the projectile, u = 50 m/s

The velocity of the projectile is maximum before hitting the ground. As the object moves upward, the velocity reduces as it approaches the maximum height, at the maximum height the velocity becomes zero. Also, as the object moves downward, the velocity starts to increase and becomes maximum before hitting the ground.

Therefore, the speed of the projectile upon returning to its starting point is 50 m/s.

Answer:

group of answer choices

Explanation:

Answer:

Convection

Explanation:

The method of heat transfer that allows heat to rise via vertical transport of heated part of a fluid (gas or liquid) and replace the fluid upper layers is called "convection"

Answer:

Convection

Explanation:

Its Convection

Answer:

3.3m

Explanation:

Given parameters:

Frequency  = 90Mhz

Unknown:

Wavelength  = ?

Solution:

To find the wavelength, use the expression below;

  V  = f x wavelength

V is the speed of light = 3 x 10⁸m/s

f is the frequency

Now;

 Insert the parameters

     3 x 10⁸  = 90 x 10⁶ x wavelength

   Wavelength = [tex]\frac{3 x 10^{8} }{9 x 10^{7} }[/tex]   = 3.3m

Answer:

that's fusion

Explanation:

Answer:

the answer is fusion for this