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a
b
c

Answer:

y(x)=6^(x)-3

Step-by-step explanation:

Let the exponential function be y(x) = ab^(x) but since the graph is translated 3 units down, y(x) = ab^(x)-3. Now, y(0)=-2=a*b^(0)-3. a=1. The equation is nearly complete but we need b, we can find it by using the point y(1)=3. y(x)=b^(x) - 3. y(1)=3=b-3, b=6. The equation of the function is y(x)=6^(x)-3

Answer:

I agree with the first one

Answer:

1a= 10

Step-by-step explanation:

[tex]f(g(1) = 3( - 2(1) + 7) - 5[/tex]

[tex] = 3(5) - 5 [/tex]

[tex]15 - 5 = 10[/tex]

Answer:

Step-by-step explanation:

f(x) = 3x - 5

g(x) = - 2x + 7

(a). f(g(1)) = 10

g(1) = - 2(1) + 7 = 5

f(5) = 3(5) - 5 = 10

(b). f(g( - 4)) = 40

g( - 4) = - 2( - 4) + 7 = 15

f(15) = 3(15) - 5 = 40

(c). g(f( - 2)) = 29

f( - 2) = 3( - 2) - 5 = - 11

g( - 11) = - 2( - 11 ) + 7 = 29

(d). g(f(3)) = - 1

f(3) = 3(3) - 5 = 4

g(4) = - 2(4) + 7 = - 1

Answer:

[tex]\displaystyle \left(\frac{-(m^{2}-1)\, x + 2\, m\, y - 2\, m \, c}{m^{2} + 1},\, \frac{(m^{2} - 1)\, y + 2\, m \, x + 2\, c}{m^{2} + 1}\right)[/tex].

Step-by-step explanation:

Consider the line that is perpendicular to [tex]y = m\, x + c[/tex] and goes through [tex](x,\, y)[/tex].

Both [tex](x,\, y)[/tex] and the reflection would be on this new line. Besides, the two points would be equidistant from the intersection of this new line and line [tex]y = m\, x + c[/tex].

Hence, if the vector between [tex](x,\, y)[/tex] and that intersection could be found, adding twice that vector to [tex](x,\, y)\![/tex] would yield the coordinates of the reflection.

Since this new line is perpendicular to line [tex]y = m\, x + c[/tex], the slope of this new line would be [tex](-1/m)[/tex].

Hence, [tex]\langle 1,\, -1/m\rangle[/tex] would be a direction vector of this new line.

[tex]\langle m,\, -1\rangle[/tex] (a constant multiple of [tex]\langle 1,\, -1/m\rangle[/tex] would also be a direction vector of this new line.)

Both [tex](x,\, y)[/tex] and the aforementioned intersection are on this new line. Hence, their position vectors would differ only by a constant multiple of a direction vector of this new line.

In other words, for some constant [tex]\lambda[/tex], [tex]\langle x,\, y \rangle + \lambda\, \langle m,\, -1 \rangle = \langle x + \lambda \, m,\, y - \lambda \rangle[/tex] would be the position vector of the reflection of [tex](x,\, y)[/tex] (the position vector of [tex](x,\, y)\![/tex] is [tex]\langle x,\, y \rangle[/tex].)

[tex]( x + \lambda \, m,\, y - \lambda )[/tex] would be the coordinates of the intersection between the new line and [tex]y = m\, x + c[/tex]. [tex]\lambda\, \langle m,\, -1 \rangle[/tex] would be the vector between [tex](x,\, y)[/tex] and that intersection.

Since that intersection is on the line [tex]y = m\, x + c[/tex], its coordinates should satisfy:

[tex]y - \lambda = m\, (x + \lambda \, m) + c[/tex].

Solve for [tex]\lambda[/tex]:

[tex]y - \lambda = m\, x + m^{2}\, \lambda + c[/tex].

[tex]\displaystyle \lambda = \frac{y - m\, x - c}{m^{2} + 1}[/tex].

Hence, the vector between the position of [tex](x,\, y)[/tex] and that of the intersection would be:

[tex]\begin{aligned} & \lambda\, \langle m,\, -1 \rangle \\= \; & \left\langle \frac{m\, (y - m\, x - c)}{m^{2} + 1},\, \frac{(-1)\, (y - m\, x - c)}{m^{2} + 1}\right\rangle \\ =\; &\left\langle \frac{-m^{2}\, x + m\, y - m\, c }{m^{2} + 1},\, \frac{-y + m\, x + c}{m^{2} + 1}\right\rangle \end{aligned}[/tex].

Add twice the amount of this vector to position of [tex](x,\, y)[/tex] to find the position of the reflection, [tex]\langle x,\, y \rangle + 2\, \lambda \,\langle m,\, -1 \rangle[/tex].

[tex]x[/tex]-coordinate of the reflection:

[tex]\begin{aligned} & x + 2\, \lambda\, m \\ = \; & x + \frac{-2\, m^{2}\, x + 2\, m \, y - 2\, m \, c}{m^{2} + 1} \\ =\; & \frac{-(m^{2} - 1) \, x + 2\, m \, y - 2\, m \, c}{m^{2} + 1}\end{aligned}[/tex].

[tex]y[/tex]-coordinate of the reflection:

[tex]\begin{aligned} & y + (-2\, \lambda)\\ = \; & y + \frac{- 2\, y + 2\, m\, x + 2\, c}{m^{2} + 1} \\ =\; & \frac{(m^{2} - 1) \, y + 2\, m \, x + 2\, m \, c}{m^{2} + 1}\end{aligned}[/tex].

Answer:

-7/8

Step-by-step explanation:

-5/8+x=-3/2

x= -3/2+5/8=-12/8+5/8= -7/8

Answer:

3/10

Step-by-step explanation:

1) 5/20+1/20= 6/20

2) Both 6 and 20 lowest number on dividing: 2

6 divide by 2= 3     20 divide by 2= 10

5/20+1/20

= 5+1/20

= 6/20

= 3/10

Answer:

Step-by-step explanation:

You've typed the equation incorrectly. 3^5x-1 = 3⁵x-1.

It needs to be typed as 3^(5x-1) = 7.

Answer:

0.85714285714286 x 100 = 85.7143%.

Step-by-step explanation:

Using basic proportionality theorem

[tex]\\ \sf\longmapsto \dfrac{x}{10}=\dfrac{42}{15}[/tex]

[tex]\\ \sf\longmapsto 15x=42(10)[/tex]

[tex]\\ \sf\longmapsto 15x=420[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{420}{15}[/tex]

[tex]\\ \sf\longmapsto x=28[/tex]

Answer:

-129

Step-by-step explanation:

2x+5=0

x=-5/2 [By the remainder theorem]

f(-5/2)=8(-5/2)^3+4(-5/2)^2+13(-5/2)+3

=-125+25-65/2+3

=-129.

Answer:

[tex]x=4[/tex]

Step-by-step explanation:

Solving for [tex]x[/tex], we get:

[tex]16=2(3x-6)+x[/tex]

[tex]16=2*3x+2(-6)+x[/tex] (Distributive Property of Multiplication)

[tex]16=6x-12+x[/tex] (Multiply distributed terms)

[tex]16=7x-12[/tex] (Combine like terms)

[tex]16+12=7x-12+12[/tex] (Add [tex]12[/tex] to both sides of the equation to isolate [tex]x[/tex])

[tex]28=7x[/tex] (Combine like terms / Simplify)

[tex]\frac{28}{7}=\frac{7x}{7}[/tex] (Divide both sides of the equation by [tex]7[/tex] to get rid of [tex]x[/tex]'s coefficient)

[tex]\bf x=4[/tex] (Simplify / Symmetric Property of Equality)

Hope this helps!

Step-by-step explanation:

[tex]16 = 2(3x - 6) + x \\ 16 = 6x - 12 + x \\ - 6x - x = - 12 - 16 \\ - 7x = - 12 - 16 \\ 7x = 12 + 16 \\ 7x = 28 \\ x = \frac{28}{7} \\ x = 4[/tex]

Answer:

x^3 + (9/5)x^2 -(42/5)x + (8/5)

Step-by-step explanation:

since 1/5, -4, and 2 are all zeroes, (x-1/5)(x+4)(x-2) must be a factor of p. if you distribute the statement, you get

Answer:

f(- 10) = 150

Step-by-step explanation:

f(- 10) with t = - 10 corresponds to t ≤ - 10 with f(t) = t² - 5t , then

f(- 10) = (- 10)² - 5(- 10) = 100 + 50 = 150

for t=-10

So

f(-10)

If the scale factor is 30, then all you have to do is multiply each measurement by the scale factor. In this case, 4 · 30 = 120.

Answer:

0.5 km/min and 1km

Step-by-step explanation:

30 km in an hour

30 km in 60 mins, 30/60 km in one minute so she cycle 0.5km/min. They will cover 1 km in 2 minutes

The first answer of the missing blank is 4/5.

The second answer of the missing blank is 2.

The third answer of the missing blank is 25.

*For all of these solutions, I will be using the common rules for logarithms.*

Solution for the first question:

Log9^4/5 must equal log9^4-log9^5, or it could also equal the more proper version, which is simplified: 2log9^2-log9^5.

Solution for the second question:

Log3^22 must equal log3^11+log3^2, if you break it down.

Solution for the third question:

Log9^25 must equal 2log9^5 because it will be like this when simplifying it:

log9^25=2log9^5

log9^5²=2log9^5

2log9^5=2log9^5

These are all of the step-by-step procedures for all three of these given questions. Anyways, I hope that this helped you!

Step-by-step explanation:

28000 ÷ 100

=280

280 × 5

=1400

Answer:

that is n standard notation mah frand

8.9 × 10^3 being scientific notation of " 8900 "

[tex]\huge\text{Hey there!}[/tex]

[tex]\large\textsf{8.9}\times\large\textsf{10}^\mathsf{3}\\\\\mathsf{10^3}\\\mathsf{= 10\times10\times10}\\\mathsf{= 100\times10}\\\mathsf{= \bf 1,000}\\\\\large\textsf{8.9}\times\large\textsf{1,000}\\\\\large\textsf{= \bf 8,900}\\\\\\\boxed{\boxed{\huge\text{Answer: \boxed{\underline{\underline{\bf 8,900}}}}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\boxed{\huge\text{}\boxed{\frak{Amphitrite1040:)}}}[/tex]

2 digits number = 10-99

Lets find the multiples of 2 and 7 both

Which are = 14, 28,42,56,70,84,98

Therefore there are 7 two digit multiples of both 2 and 7

Must click thanks and mark brainliest

9514 1404 393

Answer:

  7

Step-by-step explanation:

Those numbers are 14, 28, 42, 56, 70, 84, 98. There are 7 numbers that are multiples of 2 and 7 (multiples of 14).

Answer:

[tex]y = \sqrt{x - 5} + 7[/tex]

The median of a triangle divides it into two equal triangles of equal areas.

Must click thanks and mark brainliest

Answer:

240

Step-by-step explanation:

! means factorial or to multiply by the previous number down to one so 5!=5*4*3*2*1=120 120*2=240.

Answer:

345/5=69

Step-by-step explanation:

345/5=69

355/5=71

128Answer:

128

Step-by-step explanation:

vì 4+4=8

8+8=16

16+16=32

32+32=64

64+64=128

[tex]\\ \sf\longmapsto 5+(-3)(6x-5)[/tex]

[tex]\\ \sf\longmapsto 5-3(6x-5)[/tex]

[tex]\\ \sf\longmapsto 5-18x+15[/tex]

[tex]\\ \sf\longmapsto -18x+15+5[/tex]

[tex]\\ \sf \longmapsto -18x+20[/tex]

Option C is correct

None of the above

Answer:

18x + 20

Step-by-step explanation:

5 + (-3)(6x - 5)

Step 1. start by the parentheses (by multiplying (-3) by (6x - 5)

Answer: (-18x + 15)

Step 2. Add 5 to (-18x + 15)

Answer: (-18x + 20)

Thus, (-18x + 20) isn't a choice so None of the above

Answer:

It's option a. 36 + 6x^2 = 28x

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

Since LR=LA, RU=RA. 3m+21=6m, 3m=21, m=7

Answer:6348feet

Step-by-step explanation:

The table that represents a function in the options given is: Table A. (see image attached below).

Recall:

In the tables given, only the first table has exactly one y-value assigned or related to every x-value given.

Therefore, the table that represents a function in the options given is: Table A. (see image attached below).

Learn more about function table on:

https://brainly.com/question/3632175

Answer:

Graph A

Step-by-step explanation: