Help pls ?? I really don’t know what to do

Answer:

m=-2 c=3

Step-by-step explanation:

y=mx+c

rearrange

-mx-c+y=0

original

y=2x-3

Answer:

as per ur ques if we take x as number then we get algebraic expression as

2x - 4

brainliest?

Answer:

A can with capacity 44 litres

Step-by-step explanation:

If you like my answer than please mark me brainliest thanks

Answer:

[tex]\sqrt[3]{a^2}[/tex]

Step-by-step explanation:

a ^ 2/3

The top is the power and the bottom is the root

[tex]\sqrt[3]{a^2}[/tex]

Answer:

No, because 6² + 8² ≠ 12²

Step-by-step explanation:

In a right angled triangle,

Perpendicular² + Base² = Hypotenuse² (pythagoras theorem)

But in the given triangle; 6² + 8² ≠ 12²

36 + 64 ≠ 144

100 ≠ 144

Perpendicular² + base² ≠ hypotenuse²

Thus the given triangle is not right angled.

Answer:

1. x = -4 + y (answer for the equation −x+y=4)

2. parabola with vertex  at (h, k) = (-1/2, -49/4), and focal length at |p| = 1/4

Step-by-step explanation:

Answer:

x = 9.4m

Hope this helps...Have a good day!!

Answer:

f(0) = 0.25 = 1/4

f(x) = f(x-1) × 2/3

Step-by-step explanation:

a0 = 0.25×(2/3)⁰ = 0.25×1 = 0.25 = 1/4

a1 = 0.25×(2/3)¹ = 0.25×(2/3) = 1/4 × 2/3 = 2/12 = 1/6 =

= a0 × 2/3

a2 = 0.25×(2/3)² = 0.25×(4/9) = 1/4 × 4/9 = 4/36 = 1/9 =

= a1 × 2/3

=>

an = an-1 × 2/3, n >= 1

but what about negative x ?

is a0 = a-1 × 2/3 ?

[tex]a - 1 = 0.25 \times {(2 \div 3)}^{ - 1} [/tex]

so, yes, a0 = a-1 × (2/3)

and a-1 = a-2 × (2/3)

...

Answer:

[tex](x+1)^2+(y+4)^2=9\\[/tex]

Step-by-step explanation:

The general format for the equation of a circle is the following:

[tex](x-h)^2+(y-k)^2=a^2\\[/tex]

Where [tex](h,k)[/tex] is the center of the circle and ([tex]a[/tex]) is the circle's radius. Please note, that the circle ([tex](x-h)^2+(y-k)^2=a^2\\[/tex]) has a center that is (h) units to the right of the origin, and (k) units above the origin.

The given circle has a center at [tex](-1,-4)[/tex], moreover, its radius is (3) units. Therefore, one must substitute these points into the equation of a circle and simplify to find its equation:

[tex](x-h)^2+(y-k)^2=a^2\\[/tex]

[tex](x-(-1))^2+(y-(-4))^2=(3)^2\\[/tex]

[tex](x+1)^2+(y+4)^2=9\\[/tex]

Answer:

Step-by-step explanation: Let's first determine the center of the circle

which is represented by the red dot and it has the coordinates (-1, -4).

The radius of the circle is a segment that joins the center of the

circle to a point on the circle and all radii of a circle are congruent.

The radius of the circle shown here is 3.

Now, the equation of a circle is (x - h)² + (y - k)² = r² where

(h, k) is the center of the circle and r is the radius.

Now we plug all our given information into the formula.

So we have [x - (-1)]² + [y - (-4)]² = (3)².

Notice that I changed the parentheses in the formula to brackets

so that we wouldn't be dealing with too many sets of parentheses.

Changing the brackets back to parentheses,

our equation is (x + 1)² + (y + 4)² = 9.

Answer:

the third option=C -2,3

Step-by-step explanation:

solve simultaneously

Answer:

(-2,3)

Step-by-step explanation:

The solution to the system is where the two lines cross

x= -2

y = 3

(-2,3)

Answer:

D because even though the flat fee is 150 paying 5$ a hour it will cost less

Answer:

187 sweets

Step-by-step explanation:

8 units - 6 units = 2 units

2 units = 22 sweets

1 unit = 22 sweets ÷ 2

= 11 sweets

Total amount of sweets = 11 sweets × (6 units + 3 units + 8 units) = 11 sweets × 17 = 187 sweets

Answer:

sin(theta)=-2/3 and cos(theta)=-sqrt(5)/3

Step-by-step explanation:

First of all, as the theta is in 3rd quadrant, all the other ratios will be negative. Second tan(theta)=P/B. So, 2=P and B=sqrt(5), H=sqrt(P^2+H^2)=sqrt(4+5)=3. sin(theta) will be P/H=-2/3 and cos(theta) will be B/H=-sqrt(5)/3

Answer:

hendoebhdjdbdjjsjsnsnns

jskebeuejbeiwnwvgwvshcc

Answer:

x=9

x=-9

Step-by-step explanation:

The x intercept or roots are x values that makes the f(x) equal 0. So in order words, to find the x intercept. Set the equation equal 0.

[tex] {x}^{2} - 81 = 0[/tex]

We can approach this problem 2 ways

Way 1: Differnece of Squares

Recall that

[tex]a {}^{2} - {b}^{2} = (a + b)(a - b)[/tex]

Since x^2 and 81 are both perfect squares and 81 is negative, we can say that

[tex](x + 9)(x - 9) = 0[/tex]

Set each equation to zero

[tex]x = 9[/tex]

[tex]x = - 9[/tex]

Way 2: Take square root of both sides

[tex] {x}^{2} - 81 = 0[/tex]

[tex] {x}^{2} = 81[/tex]

Next step, take square root of both sides. Square root produce negative and positive solutions so

[tex]x = 9[/tex]

or

[tex]x = - 9[/tex]

Answer:

48

Step-by-step explanation:

(204-x)/2=78

or, 204-x=156

or, x=204-156

or, x=48

Answer:

(6) the letter n : intersection which means the number you will find at the first bracket and has the same number at the other bracket

Answer:

5*sqrt(3)+sqrt(6)

Step-by-step explanation:

sqrt(3)*(5+sqrt(2))=5*sqrt(3)+sqrt(6)

Answer:

(5 x sqrt(3)) + sqrt(6)

Brainliest, please! (Almost an Ace!)

Step-by-step explanation:

Distribute the sqrt(3) through and get:

(5 x sqrt(3)) + (sqrt(3) x sqrt(2))

Next, we simplify.

(5 x sqrt(3)) + sqrt(6)

Answer:

3/5

Step-by-step explanation:

cos X = Adjacent/Hypotenuse

cos X = 30/50

= 3/5

Answer:

Answer 3/5

Step-by-step explanation:

cos(X)=XY/XZ=30/50=3/5

Answer:

the picture is not coming clearly !!!

Answer:

Step-by-step explanation:

I can't give you either B or D, but I can calculate the answer.

2^5

=====

(2^5)(3^5)  

The 2^5s cancel out.

1

===

3^5

Another answer could be 3^-5

or

0.004115

1hr=60min

[tex]\\ \sf\longmapsto \dfrac{3}{5}\;of\;60min[/tex]

[tex]\\ \sf\longmapsto \dfrac{3}{5}\times 60[/tex]

[tex]\\ \sf\longmapsto \dfrac{180}{5}[/tex]

[tex]\\ \sf\longmapsto 36min[/tex]

Answer:

t=r/(sq)

Step-by-step explanation:

r=sqt

=> r/(sq)=t

Answer:

T= r/(sq)

Step-by-step explanation:

r= sqt

=r/(sq) =t

Step-by-step explanation:

figure for the triangle with ab

Answer:

1/6 = 0.16 = 16%

restate the question: 16% of 20.5 is what? multiply: 20.5*.16 = 3.28 now, to find the weight of the object on the moon, subtract 16% from 20.5. 16% of 20.5 is 3.28 20.5-3.28 = 17.22 = 17 22/100 = 17 11/50

the weight of the object is 17 11/50 pounds on the moon.

Answer:  C. a set of input values

The domain is the set of allowed x values, aka input values.

With fairly many domain problems, one thing to look out for are things like potential division by zero issues. For example, if you had the function f(x) = 2/(x-3), then we want to avoid the denominator x-3 from being zero. Because x = 3 makes x-3 equal to zero, this means we must kick x = 3 out of the domain; however, any other real number will work. This example function therefore has the domain of any real number but 3.

Square roots are another thing that often comes up with domain problems. One example could be g(x) = sqrt(x+5). We'd want the x+5 to never be negative. Solving [tex]x+5 \ge 0[/tex] leads to [tex]x \ge -5[/tex] to tell us what set of input x values we can plug in: namely anything -5 or larger.

Other types of domain problems can occur, but those two types are most common in my experience.

Answer:

26.8

Step-by-step explanation:

2×√(18²-12²)

= 26.8328157..

= 26.8 (rounded to the nearest tenth)

Answer:

26.8

Step-by-step explanation:

We can use the Pythagorean theorem

a^2+b^2 = c^2

where a and b are the legs and c is the hypotenuse

12^2+ b^2 = 18^2

144+b^2 = 324

b^2 = 324-144

b^2 = 180

Taking the square root of each side

sqrt(b^2) = sqrt(180)

b = 13.41640

We know b = 1/2x

2b =x

2(13.41640) =x

26.83281573 =x

26.8

First we have to find angle D

As it is a quadrilateral

[tex]\\ \sf\longmapsto <A+<B+<C+<D=360[/tex]

[tex]\\ \sf\longmapsto 45+50+35+<D=360[/tex]

[tex]\\ \sf\longmapsto 130+<D=360[/tex]

[tex]\\ \sf\longmapsto <D=360-130[/tex]

[tex]\\ \sf\longmapsto <D=230°[/tex]

Now

[tex]\\ \sf\longmapsto <D+x=360[/tex]

[tex]\\ \sf\longmapsto x+230=360[/tex]

[tex]\\ \sf\longmapsto x=360-230[/tex]

[tex]\\ \sf\longmapsto x=130°[/tex]

Answer:

x = 130

Step-by-step explanation:

Sum of all the angle of quadrilateral = 360°

50 + 45 + 35 + ∠ADC = 360

                130 + ∠ADC = 360

                         ∠ADC = 360 - 130

                         ∠ADC = 230

x = Reflex ∠ADC

  = 360 - 230

  = 130

Answer:

f (-3)

since -3 is between-4 and -2 for every value of x y is 2