Answer:
The answer is 3 m/s²Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
[tex]a = \frac{f}{m} \\ [/tex]
where
f is the force
m is the mass
From the question we have
[tex]a = \frac{12}{4} \\ [/tex]
We have the final answer as
3 m/s²Hope this helps you
In a single process, a system does 125 J of work on its surroundings while 75 J of heat is added to the system. What is the internal energy change for the system
Answer:
-50JExplanation:
What is the first law of thermodynamics?
"The first law of thermodynamics state that energy is conserved"
the expression bellow is the Change in internal energy of a system
Change in internal energy of a system
= heat put into the system - work done by the system on its surroundings,
or
ΔU = ΔQ - ΔW.
given data
Work done=125J
Heat= 75J
change=?
Substituting we have
ΔU = 75- 125
ΔU = -50J
"ΔQ is positive if heat flows into the system, negative if it flows out of the system.
ΔW is positive if the system does work on its surroundings and it is negative if work is done on the system. "
Write the electric field strength EE in all three regions as a function of rr: for r>r2r>r2, r1
Answer:
Explanation:
See attachment
I NEED HELP ASAP! PLS! <3
Answer:
a = - 1 [m/s²]
Explanation:
To solve this problem we must use the following equation of kinematics.
[tex]v_{f} = v_{o} +(a*t)[/tex]
where:
Vf = final velocity = 0 (velocity at 10 seconds)
Vo = initial velocity = 4 [m/s]
a = desacceleration [m/s²]
t = time = 4 [s]
From the graph, we can deduce that between the second 10 and the second 6 there are (10-6) = 4 seconds difference.
In the second 6, the velocity is 4 [m/s]
0 = 4 + (a*4)
4*a = -4
a = - 1 [m/s²]
Which type of power plant uses the energy of moving water in nature to
generate electricity?
A. Radiant power
B. Natural gas
C. Coal
D. Hydroelectric
Answer:
D
Explanation:
Answer:
Hydroelectric power plants
Explanation:
This is because hydropower is a form of renewable energy that uses water stored in dams, rivers to create electricity
How far will a motorcycle that accelerates at 1.28 m/s2 travel as its velocity increases from 10.0 m/s to 20.0 m/s?
Answer:
117
Explanation:
A dairy farmer notices that a circular water trough near the barn has become rusty and now has a hole near the base. The hole is 0.29 m below the level of the water that is in the tank. If the top of the trough is open to the atmosphere, what is the speed of the water as it leaves the hole
Answer:
2.385 m/s
Explanation:
Here there is a transformation of potential energy of the water at the top to Kinectic energy at the hole
This can be expressed as
Potential energy= Kinect energy
mgh= 1/2m v²
Where m= mass of water
h= Lenght below the level of the water that is in the tank.
v= the speed of the water as it leaves the hole
g= acceleration due to gravity= 9.81m/s
Here there is 'm' at both sides which can cancelled beach other out.
Then we have
gh= ¹/₂v²
making v² subject of the formular
v²=gh/(¹/₂)
v=√(2gh)
V=√2g h
V= √(2×9.81×0.29)
V=2.385 m/s
Therefore, the speed of the water as it leaves the hole is 2.385 m/s
The line segment joining the mid point of any side with the opssosite vertex is called?
last question, PLEASE help
An athlete wants your shoe company to make his/her new basketball shoe. He is known for his speed down the court and doesn't want his shoes to have any pattern on the outsole, the bottom of the shoe, because he thinks it would slow him down. How would you convince this athlete that a pattern is needed because friction is important in his game?
Answer:
my answer is in explanation below
Explanation:
You would convince him by saying the pattern adds elevation to the shoe therefore causing more friction.
(If it's wrong, I am sorry, I'm not in college)
(If it's right, can I get that brainliest?)
A string under a tension of 53.9 N is used to whirl a rock in a horizontal circle of radius 2.59 m at a speed of 21.8 m/s. The string is pulled in and the speed of the rock increases. When the string is 1.23 m long and the speed of the rock is 54.8 m/s, the string breaks. What is the breaking strength (in newtons) of the string
Answer:
The breaking strength of the string is 717.19 N
Explanation:
Given;
initial tension on the string, T₁ = 53.9 N
initial radius of the string, r₁ = 2.59 m
initial speed of the rock, v₁ = 21.8 m/s
final radius of the string, r₂ = 1.23 m
final speed of the rock, v₂ = 54.8 m/s
the final tension on the string = breaking strength, T₂ = ?
Apply centripetal force equation due to inward motion;
[tex]T= \frac{mv^2}{r}\\\\Tr = mv^2\\\\m =\frac{Tr}{v^2}\\\\ \frac{T_1r_1}{v_1^2} = \frac{T_2r_2}{v_2^2}\\\\T_2 = \frac{T_1r_1v_2^2}{r_2v_1^2}\\\\ T_2 = \frac{(53.9)(2.59)(54.8)^2}{(1.23)(21.8)^2}\\\\ T_2 = 717.19 \ N[/tex]
Therefore, the breaking strength of the string is 717.19 N
A physicist is creating a computational model of a falling person before and after opening a parachute. What boundary conditions would be important here?
the air resistance encountered as the person falls
the speed at which the person falls
the change in kinetic and potential energy
the location where potential energy is zero
Answer:
Air resistance
Explanation:
Air resistance encountered as the person falls
Answer:
the location where potential energy is zero
Explanation:
A hopper jumps straight up to a height of 0.45 m. With what velocity will it return to the table?
Answer:
3 m/s
Explanation:
We can solve with kinematics or with energy.
Using kinematics, and taking down to be positive, we're given:
Δy = 0.45 m
v₀ = 0 m/s
a = 10 m/s²
Find: v
v² = v₀² + 2aΔy
v² = (0 m/s)² + 2 (10 m/s²) (0.45 m)
v = 3 m/s
Or, we can use energy.
PE = KE
mgh = ½ mv²
v = √(2gh)
v = √(2 × 10 m/s² × 0.45 m)
v = 3 m/s
An asteroid floating in space attracts a skyscraper on Earth’s with gravitational force of 12
newtons from a given distance. If the distance between the two objects is reduced to half, what is the
changed force of attraction between them?
a. 3 Newtons
b. 24 Newtons
c. 48 Newtons
d. 144 Newtons
Answer:
Explanation:
it is C
A big dog B and a small dog S are pulling horizontally in opposite directions on a large bone. The bone’s mass is mmm, the big dog’s leftward force magnitude is F_BF
B
F, start subscript, B, end subscript and the small dog’s rightward force magnitude is F_SF
S
F, start subscript, S, end subscript. The bone accelerates to the right along the table with no friction.
The correct expression for the mass m of the bone is m=Fs-Fb/a.
What is force?The force is defined as the shear stress or pressure applied per unit area.
A big dog B and a small dog S are pulling horizontally in opposite directions on a large bone. The bone’s mass is m, the big dog’s leftward force magnitude is Fb and the small dog’s rightward force magnitude is Fs. The bone accelerates to the right along the table with no friction.
Across the bottom is green grass. In the center, there is a brown table with a large bone on top. To the left is a black outline of a large dog facing rightwards that is pulling leftwards on the bone. To the right is a black outline of a small dog facing leftwards that is pulling rightwards on the bone. The small dog stands on a grey box. Across the bottom is green grass.
Two dogs pulling on a large bone. Big dog and small dog images courtesy of pixabay. Consider rightward as the positive direction.
The net force acting on bone will be
F = Fs -Fb
From the Newton's second law of motion, Force = mass x acceleration
F = ma
m = F/a
m = Fs-Fb/a
Thus, correct expression for the mass m of the bone is m=Fs-Fb/a.
Learn more about force.
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Find the magnitude of the Sun's gravitational force on the Earth when the Earth is at perihelion and at aphelion. The perihelion and aphelion distances are 1.48 ✕ 1011 m and 1.52 ✕ 1011 m, respectively.
Answer:
Explanation:
Force F = GMm / R²
mass of the sun M = 1.99 x 10³⁰ kg
mass of the earth = 5.97 x 10²⁴ kg
value of G = 6.67 x 10⁻¹¹
for perihelion point R = 1.48 x 10¹¹ m
Force = 6.67 x 10⁻¹¹ x 1.99 x 10³⁰ x 5.97 x 10²⁴ / ( 1.48 x 10¹¹ )²
= 36.17 x 10²¹ N
for aphelion point R = 1.52 x 10¹¹ m
Force = 6.67 x 10⁻¹¹ x 1.99 x 10³⁰ x 5.97 x 10²⁴ / ( 1.52 x 10¹¹ )²
= 34.29 x 10²¹ N
What is an advantage of using nuclear power over natural gas to generate
electricity?
A. Nuclear power produces no waste.
B. Nuclear power does not contribute to climate change.
C. Nuclear power produces greenhouse gases.
D. Nuclear power is free.
Answer:b
Explanation:
I got the answer right
The main advantage of using nuclear power over natural gas to generate the electricity that nuclear power does not contribute to climate change, therefore the correct answer is option B.
What is a nuclear power plant ?It is a particular kind of power plant where electricity is produced using a nuclear reactor that may use nuclear fusion or nuclear fission .
When a radioactive substance undergoes a nuclear reaction, a tremendous quantity of energy is produced .
As given in the problem , we have to find out what is an advantage of using nuclear power over natural gas to generate electricity .
Option B is the proper response , since employing nuclear power instead of natural gas to produce electricity has the advantage of not causing the climate change .
To learn more about Nuclear power plants here , refer to the link given below ;
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A ball is thrown straight downward with a speed of 0.50 meter per second from a height of 4.0 meters. What is the speed of the ball 0.70 second after it is released? [Neglect friction.]
Answer:
The speed of the ball is 7.36 m/s
Explanation:
Constant Acceleration Motion
It happens when the velocity of an object changes by an equal amount in every equal period of time.
Being a the constant acceleration, vo the initial speed, vf the final speed, and t the time, the following relation applies:
[tex]v_f=v_o+at[/tex]
Since the situation corresponds to a vertical motion, the acceleration is g=9.8 m/s^2.
The ball is thrown downward at vo=0.5 m/s. Its speed at t=0.7 seconds is
[tex]v_f=0.5+9.8\cdot 0.7[/tex]
[tex]v_f=7.36\ m/s[/tex]
The speed of the ball is 7.36 m/s
Note: There is no use of the height it was released from
An object is moving with an initial velocity of 20 m/s. If it is decelerating at 5 m/s2 how far does it travel before it stops
Answer:
The object travels a distance of 40 meters before it stops.
Explanation:
A body moves with constant acceleration motion or uniformly accelerated rectilinear motion (u.a.r.m) when the trajectory of the mobile is a straight line and its speed varies the same amount in each unit of time.
Torricelli's equation relates the speed to the space traveled by the body in u.a.r.m. To calculate the velocity of a body as a function of space, the expression is used:
[tex]v^{2} =v0^{2} +2*a*d[/tex]
Where :
v: final velocity (m/s) v0: initial velocity (m/s) a: acceleration (m/s²) d: space traveled by the body (m)In this case:
v: 0 m/s because the object stopsv0: 20 m/sa: - 5 m/s² because the object is deceleratingd: ?Replacing:
[tex](0\frac{m}{s} )^{2} =(20 \frac{m}{s} )^{2} +2*(-5\frac{m}{s^{2} }) *d[/tex]
Solving:
[tex]0\frac{m^{2} }{s^{2} } =400 \frac{m^{2} }{s^{2} } -10\frac{m}{s^{2} } *d[/tex]
[tex]0\frac{m^{2} }{s^{2} } -400 \frac{m^{2} }{s^{2} } = -10\frac{m}{s^{2} } *d[/tex]
[tex]-400 \frac{m^{2} }{s^{2} } = -10\frac{m}{s^{2} } *d[/tex]
[tex]\frac{ -400 \frac{m^{2} }{s^{2} }}{ -10\frac{m}{s^{2} }} = d[/tex]
40 m= d
The object travels a distance of 40 meters before it stops.
Dangerous substances in an ecosystem that are harmful to its organisms are:
A sediments. B scavengers. C pollutants. D overpopulation.
Answer:
C pollutants
Explanation:
Pollutants are dangerous substances in the ecosystem that are harmful to its organisms. They are contaminants and effluents that leads to pollution in the environment.
There are different types of pollutants. Most of them are introduced into the environment by anthropogenic activities. Also, some natural events also introduce these pollutants into the environment. These materials pose huge health risks to living organisms. They can render the environment unfit for life.Answer:
c
Explanation:
A water slide is constructed so that swimmers, starting from rest at the top of the slide, leave the end of the slide traveling horizontally. As the drawing shows, one person hits the water 5.00 m from the end of the slide in a time of 0.378 s after leaving the slide. Ignore friction and air resistance, find the height H in the drawing.
Answer:
9.63 m
Explanation:
We know that
Δx = vt.
Therefore, v = Δx / t
v = 5 / 0.378
v = 13.23 m/s
h = ½gt, so that
h = ½ * 9.8 * 0.378²
h = 4.9 * 0.1429
h = 0.7 m
Finally, using the law of conservation of energy, we know that
½mv² = mg(H - h)
½v² = g(H - h)
½v²/g = H - h, substituting the values and solving, we have
(½ * 13.23²) / 9.8 = H - 0.7
(½ * 175) / 9.8 = H - 0.7
87.5 / 9.8 = H - 0.7
8.93 = H - 0.7
H = 8.93 + 0.7
H = 9.63 m
The mass of the moon is about 1/81 the mass of the earth and its radius is 1/4
that of the earth. The
acceleration due to gravity at the earth's surface is 9.8 m/s2. What is the acceleration due to gravity on the moon's surface?
9.8 m/s2
2.8 m/s2
1.9 m/s2
3.0 m/s2
what is compressibility?
Hi! Compressibility is the capacity of something to be flattened or reduced in size by pressure. I hope this helps you! Good luck and have a great day. ❤️
A 0.414 kg object is at rest at the origin of a coordinate system. A 2.08 N force in the positive x direction acts on the object for 1.57 s. What is the velocity at the end of this interval
Answer:
The value is [tex]v = 7.89 \ m/s[/tex]
Explanation:
From the question we are told that
The mass of the object is [tex]m = 0.414 \ kg[/tex]
The force is [tex]F = 2.08 \ N[/tex]
The time taken is [tex]t = 1.57 \ s[/tex]
Generally the force acting on the object according to Newton's second law is
[tex]F = \frac{ m (v -u )}{t}[/tex]
=> [tex]v = \frac{F * t}{m} + u[/tex]
Here u is the initial velocity with value 0 m/s since the object was initially at rest
[tex]v = \frac{2.08 * .57}{0.414 } + 0[/tex]
[tex]v = 7.89 \ m/s[/tex]
Which of the following is correct about a motion diagram?
a. A group of images for different objects found in one place at the same time
b. A series of images that show the position of a moving object at equal time intervals
c. A series of images that show the position of a moving object at unequal time intervals
d. Collection of photos taken by a person while moving around different places
Answer:
d. collection of photos taken by a person while moving around different places
Answer:
Moving object at equal time intervals
a 45 kg girl is bouncing on a trampoline. during a certain interval after she leaves t he surface of the trampoline, her kinetic energy decreases to 220 J from 420 J. how high does she rise during this interval neglect air resistance
Answer: Height = 0.45m
Explanation:
According to the conservation of energy, When there are no interactions outside a system ie neglecting air resistance,The change in kinetic energy is equal to the change in potential energy in a closed system.
Therefore the kinetic energy decrease, the potential energy increases, and decreases for increase in Kinetic energy
an is represented by the formulae
ΔKinetic energy + ΔPotential energy = 0
ΔKinetic energy = -ΔPotential energy ( where negative sign represent decrease as kinetic energy increases.
ΔK.E=ΔP.E
420J- 220J= mgh
mass = 45kg
g =gravitational acceleration =9.8 m/s^2
200J = 45 X 9.8 X h
h = 200/45 x 9.8 /= 0.45m
Which type of muscle helps the body move?
a
Cardiac
b
Smooth
c
Skeletal
d
None of the Above
Answer:
Cccccccc GIVE BRAINLYEST PLEASE
Answer: It´s c-skeletal
Explanation:
Consider a car with a mass of 1250 kg moving at a constant speed of (22.0 A) m/s in a circular off ramp with a radius of (65.0 +B) m. What does the coefficient of static friction have to be for the car to just maintain its motion of ramp? Give your answer to 3 significant figures.
A=7
B=2
Answer:
Explanation:
weight of the car mg = m g
frictional force acting on the car = μ mg where μ is coefficient of friction
= m μ g
This force provides centripetal force , hence
m μ g = m v² / R
μ = v² / rg
= 22 x 22 / 65 x 9.8
= .759
A hockey puck is sitting stationary on a frozen pond. A player slaps the puck, accelerating it from rest to 45 m/s in 0.03 s. What is the average force on the hockey puck while it is in contact with the stick
Answer:
F = 240 N
Explanation:
Let the mass of the puck, m = 160 g = 0.16 kg
Initial speed, u = 0 (at rest)
Final speed, v = 5 m/s
Time, t = 0.03 s
We need to find the average force on the hockey puck while it is in contact with the stick. Force is given by the formula as follows :
F = ma, a is acceleration
[tex]F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{0.16\times (45-0)}{0.03}\\\\F=240\ N[/tex]
So, the average force is 240 N.
A 0.150-kg baseball traveling in a horizontal direction with a speed of 21.0 m/s hits a bat and is popped straight up with a speed of 15.0 m/s. If the bat was in contact with the ball for 51.0 ms, what was the average force of the bat on the ball
Answer:
17.65N
Explanation:
We know that the relationship for the impulse and momentum is given as
Ft=mv
given data
mass m=0.15kg
t= 51ms= 26.5/1000= 0.051seconds
velocity v1= 21m/s
Velocity v2=15m/s
substituting in the expression we have
Ft=m(v1-v2)
make F subject of formula we have
F=m(v1-v2) /t
F=0.15(21-15)/0.051
F=0.15*6/0.051
F=0.9/0.051
F=17.65N
This question involves the concepts of momentum and impulse.
The average force of the bat on ball is "17.65 N".
What is the average force?According to Impulse Equation the change in momentum is equal to the product of applied force and time of contact. Mathematically:
[tex]\Delta P=F\Delta t\\\\F=\frac{m\Delta v}{\Delta t}[/tex]
where,
F = Average force = ?m = mass of baseball = 0.15 kgΔv = change in speed = 21 m/s - 15 m/s = 6 m/sΔt = time of contact = 51 ms = 0.051 sTherefore,
[tex]F=\frac{(0.15\ kg)(6\ m/s)}{0.051\ s}[/tex]
F = 17.65 N
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The tendency of an object to resist change in its motion is known as
a. mass
b. inertia
c. force
d. balance
A 100 kg mass, initially at rest, is blown apart into a 60 kg piece and a 40 kg piece. After the blast, the two masses are moving apart with a relative velocity of 60 m/s. The speed of the 60 kg mass is
Answer:
Explanation:
According to law of conservation of momentum
(m1+m2)v = m1u1+m2u2
Let m1 and m2 be the masses
u1 and u2 be their respective velocities
v is the velocity of combined objects
Given
m1 =60kg
m2 = 40kg
v =0 m/s
u2 - u1 = 60 ............ 1
0 = 60u1 + 40u2 = 0 .......... 2
From 1: u2 = 60+u1
Substitute into 2:
60u1 + 40(60+u1) = 0
60u1 +2400 +40u1 = 0
100u1 = -2400
u1 = -2400/100
u1 = -24m/s
Hence the speed of the 60 kg mass is 24m/s (in the negative direction)
