help me I m stuck on this question

Answer:

First Kepler law states that Each planet describes an ellipsoidal motion about the sun as its single focus.

Second Kepler law states that An imaginary line joining a planet to the Sun sweeps out equal areas in equal time intervals.

Third Kepler law states that The squares of period of revolution of the planet around the sun are proportional to the cubes of mean distance between the planet and the sun.

Weightlessness is the condition where the body has zero gravity ( its acceleration is equal to the acceleration due to gravity )

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Kepler's law states that the Sun serves as the planet's center of gravity while they travel in elliptical orbits.

Each planet describes an ellipsoidal motion around the sun as its sole focus, according to the first Kepler law.

According to the second Kepler law, an imaginary line between a planet and the Sun sweeps out equivalent areas at equivalent times.

According to the third Kepler law, the squares of a planet's period of revolution around the sun are proportional to the cubes of the planet's mean distance from the sun.

When the body is weightless, there is no gravitational pull on it ( its acceleration is equal to the acceleration due to gravity).

Therefore, the Sun serves as the planet's center of gravity while they travel in elliptical orbits, which is described by Kepler's law.

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Answer:

the speed of the block at the given position is 21.33 m/s.

Explanation:

Given;

spring constant, k = 3500 N/m

mass of the block, m = 4 kg

extension of the spring, x = 0.2 m

initial velocity of the block, u = 0

displacement of the block, d =1.3 m

The force applied to the block by the spring is calculated as;

F = ma = kx

where;

a is the acceleration of the block

[tex]a = \frac{kx}{m} \\\\a = \frac{(3500) \times (0.2)}{4} \\\\a = 175 \ m/s^2[/tex]

The final velocity of the block at 1.3 m is calculated as;

v² = u² + 2ad

v² = 0 + 2ad

v² = 2ad

v = √2ad

v = √(2 x 175 x 1.3)

v = 21.33 m/s

Therefore, the speed of the block at the given position is 21.33 m/s.

The speed of the block at a height of 1.3 m above the starting position is 21.33 m/s

To solve this question, we'll begin by calculating the acceleration of the block.

F = Ke

Also,

F = ma

Thus,

ma = Ke

Divide both side by m

a = Ke / m

a = (3500 × 0.2) / 4

a = 175 m/s²

v² = u² + 2as

v² = 0² + (2 × 175 × 1.3)

v² = 455

Take the square root of both side

v = √455

v = 21.33 m/s

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Explanation:

a) D_t = 500m*10laps

D_t = 5000m or 5km

b)

I) v = d/t

v = 500m/50s

v = 10m/s

ii) 10m/s = 5000m/t

t = 5000m/10m/s

t = (500s)*(1min/60s)

t = 8'20" or 8 mins and 20 sec

c) v_f = v_0 + a*t

v_f-v_0 = a*t

a = (v_f-v_0)/t

a = (12m/s-8m/s)/2s

a = (4m/s)/2s

a = 2m/s²

Part(a),

The distance travelled by the cyclist is 5 km.

Part(b),

(i) The average speed is 10 m/s

(ii) The time taken to cover 10 laps is 8 minutes and 20 seconds.

Part(c),

The acceleration is 2 m/s²

Speed is defined as the ratio of the time distance travelled by the body to the time taken by the body to cover the distance. Speed is the ratio of the distance travelled by time. The unit of speed in miles per hour.

a) The distance will be calculated as

D = 500m*10laps

D = 5000m or 5km

b) The average speed is calculated as,

I) v = d/t

v = 500m/the 50s

v = 10m/s

The time will be calculated as,

ii) 10m/s = 5000m/t

t = 5000m/10m/s

t = (500s)*(1min/60s)

t = 8'20" or 8 mins and 20 sec

The acceleration is calculated as,

c) vf = v0 + at

vf-v0 = at

a = (vf-v0)/t

a = (12m/s-8m/s)/2s

a = (4m/s)/2s

a = 2m/s²

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B will have the greater force

Fc=MV2 /R=Fm

The A particle has less centipetal force and larger radius so larger curve

Answer:

Yes.

Explanation:

Instantaneous velocity is a vector quantity and thus can be negative.

Unlike, Instantaneous speed which is found by taking the absolute value of the magnitude of instantaneous velocity, and thus always positive.

Check attached photo

Check attached photo

I believe the correct answer is a

The true statement is that, at resonance, current is in phase with the driving voltage.

Resonance occurs in an RLC circuit at the point when the inductive reactance is equal to the capacitive reactance. At the point of resonance, the voltage across the inductor  and capacitor are equal.

It should noted that, at resonance, the current is in phase with the driving voltage. This is the true statement in the list.

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Answer:

Acceleration=12.5/3m/s^2=4.17m/s^2

Explanation:

Initial velocity u = 45 km/h = 12.5 m/s; Final velocity v = 0 m/s; time t = 3 s, acceleration a.

[a=v-u/t] : a=0-12.5/3=-12/3m/s^2

(Retaradation=-(-12.5/3)=12.5/3.

According to definition of general chemistry matter is any substance which has atleast a mass and occupies a volume.

Matter is of three types

We are being given that:

A pictorial view showing the diagrammatic representation of the information given in the question is being attached in the image below.

From the attached image below, the potential difference across the conducting element of the length (dx) moving with the velocity (v) appears to be perpendicular to the magnetic field (B).

The magnitude of the potential difference induced between the center of the blade in relation to either of its ends can be determined by using the derived formula from Faraday's law of induction which can be expressed as:

[tex]\mathsf{E = B\times l\times v}[/tex]

where;

From the diagram, Let consider the length of the conducting element (dx) at a distance of length (x) from the center O.

Then, the velocity (v) = ωx

The potential difference across it can now be expressed as:

[tex]\mathsf{dE = B*(dx)*(\omega x)}[/tex]

For us to determine the potential difference, we need to carry out the integral form from center point O to L/2.

∴

[tex]\mathsf{E = \int ^{L/2}_{0}* B (\omega x ) *(dx)}[/tex]

[tex]\mathsf{E = B (\omega ) \times \Big[ \dfrac{x^2}{2}\Big]^{L/2}_{0}}[/tex]

[tex]\mathsf{E = B (\omega ) * \Big[ \dfrac{L^2}{8}\Big]}[/tex]

Recall that,

[tex]\mathsf{E = (4\times 10^{-3}) * (17) \Big[ \dfrac{(1.5)^2}{8}\Big]}[/tex]

[tex]\mathsf{E = 19.13 mV}[/tex]

Thus, we can now conclude that the magnitude of the potential difference as a result of the rotation caused by the metal blade from the center to either of its ends is 19.13 mV.

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Answer:

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Answer:

B has greater potential

Explanation:

We know;

Potential Energy (PE) = mgh

where, m=mass of body

g=acceleration due to gravity

h=height of body

From the formula,

PE is directly proportional to the mass of the body

so the body with greater mass has greater potential.

Answer:

Very TRUE

Option A is legit

Answer:

contact force because they were pushing it and it moved

Answer:

Every dielectric medium will have a dielectric (strength) constant.

For space / vacuum it is 1. For rest of the dielectric media, it is greater than 1. The capacitance of a capacitor filled with a material of dielectric constant k, is given by the relation:

C = k . C0 (where C0 is the capacitance with space / vacuum as the dielectric material in that capacitor which means no dielectric between the plates)

So, it clearly states that the higher the dielectric constant, the more the capacitance i.e. it is directly proportional to the dielectric strength.

Dielectric constant varies with temperature.

Explanation:

plz mark me as a brainliest

Answer:

1.84 hours

I hope it's helps you

Answer:

photo

Explanation:

Answer:

PlROCA

Explanation:

Hi,

The valves in the heart open and close to move blood in between heart chambers.

Answer:

d) one direction

We have that the  energy (in calories) is transferred to the water as heat,to the bowl and  the original temperature of the cylinder  is mathematically given as

Energy

Generally the equation for the   is mathematically given as

(a)

The heat transferred to the H20

Qw= CwMwdT+Lvms

Qw=((220g)(100°C-20.0T)+(539 caVg)(5.00 g)

Qw=20.3 kcal .

(b)

The heat transferred to the bowl is

Qb= CbmbdT

Q= (0.0923 cal/gC)(150g)(100°C-20.0°C)

Q= 1.11 kcal

(c)  

original temperature of the cylinder

-Qw- Qb = CcMc(T2-T1)

[tex]T1=\frac{Qw+Qm}{CcMc}+T2[/tex]

T1=873C

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Photons — particles of light — stream toward the smooth pane of glass and bounce off it. The image of everything in front of the mirror is reflected backward, retracing the path it traveled to get there. Nothing is switching left to right or up-down. Instead, it's being inverted front to back.

When an object is placed in front of the convex mirror, the image is formed behind the mirror.  The height of the image is 1.5 cm. The image is upright.

Convex mirror is the spherical type of mirror. It has positive focal length. It forms the images by the virtual meeting of the rays coming from the object.

By the lens maker formula,

1/f = 1/u +1/v

where image distance is v, the object distance is 30 cm and the focal length of mirror, f = Radius of curvature /2

f = 20/2 = 10 cm

Substitute the values, we get the image distance as

1/10 = 1/-30 +1/v

v = 7.5 cm (on right of lens)

From the definition,

m = -image distance /object distance = image height / object height

-(7.5) /30 = hi / 6

hi = 1.5 cm

Thus, the height of the image is 1.5 cm. The image is upright.

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The value of n in the relationship between F₁ and F₂, (F₂ = n·F₁), is n = 2

The reason for the above value is as follows;

The given parameters of the first pair of books are;

The masses of the books = m₁, and m₂

The distance between the two m₁ and m₂ = r

The gravitational force between the masses = F₁

The given parameters of the second pair of books are;

The masses of the books second pair = 2·m₁, and 4·m₂

The distance between the two masses in second pair = 2·r

The gravitational force between the masses in second pair = F₂

The relationship between the two forces is F₂ = n·F₁

The required parameter;

The value of n in F₂ = n·F₁

According to Newton's law of universal gravitation, we have;

[tex]\mathbf{F = G \times \dfrac{m_1 \times m_2}{r^2}}[/tex]

Therefore, we get;

[tex]F_1 = G \times \dfrac{m_1 \times m_2}{r^2}[/tex]

[tex]F_2 = G \times \dfrac{2\cdot m_1 \times 4 \cdot m_2}{(2 \cdot r)^2} = G \times \dfrac{8 \times m_1 \times m_2}{4 \times r^2} = 2 \times G \times \dfrac{ m_1 \times m_2}{r^2} = 2 \times F_1[/tex]

Therefore;

F₂ = 2·F₁

The value of n in F₂ = n·F₁ is n = 2

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Answer:

as it 8s based upon to fundamental units distance and Time

Answer:

english

Explanation:

Answer:

intensity

Explanation:

b. example, The sun is very bright and intense. and sounds can be very loud.

Answer:

There will be a phase change at the 1-1.38 interface and no phase change at the 1.38-1.33 interface.

At a thickness of lambda / 4       (y/4) one should get constructive interference for the reflected light.

y = 4 * 99.8 * 10E-9 m = 400 nm (about)  = 4 * 10E-7 m

The color of this light will be violet or blue

Answer:

check photo for solve

Explanation:

Answer:

a. True

Explanation:

It's commonly used in the bain bridge diagram determining positive rays

Answer:

Lever => [tex]d_{e} = d_{r}[/tex]

Pulley => G = M x n (gravitational acceleration)

Wheel and axle => M.A = Radius of the wheel/radius of the axle = R/r

Inclined plane => It can be divided into two components: Fi = Fg * sinθ - parallel to inclined plane. Fn = Fg * cosθ - perpendicular one.