Hello! Hello ! guys. or any genius of math. can you help me on this math problems. this question is out of my answer.

could you help me.
if your answer is correct there is a big changes to get brain list answer and 2 followers from my two accounts.

don't need to follow back. ​

Answer:

Yes

Step-by-step explanation:

Adding to both sides of the equation will keep both sides equal

Answer: Yes, it can.

Step-by-step explanation:

3π / 2π = 1.5

√20 / √5 = 2

I guess it can.

Answer:

you need to make a line by using the tools

[tex]\\ \rm\Rrightarrow 3.2\times 10^3[/tex]

[tex]\\ \rm\Rrightarrow 32\times 10^2[/tex]

[tex]\\ \rm\Rrightarrow 320\times 10^1[/tex]

[tex]\\ \rm\Rrightarrow 320(10)[/tex]

[tex]\\ \rm\Rrightarrow 3200[/tex]

Answer:

3200

Step-by-step explanation:

3.2·10^3

You move your decimal right three times. and you should get 3200.

3.2·10^3=3200

Answer:

Step-by-step explanation:

Answer:

D) 18

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable

Answer:

[tex]6 - x = - 12 \\ constants \: nearer \\ 6 + 12 = x \\ x = 18 \\ thank \: you[/tex]

Answer:

13 inches

Step-by-step explanation:

I have done a Little draw because I don't know how i can explain you this exuse me

Answer:

True.

Step-by-step explanation:

It fails the vertical line test. The vertical line test checks to see if any inputs (x values) have more than one output. In this case, they do.

Answer: Choice D)

The function has a range of all real numbers less than or equal to 2.

=======================================================

Explanation:

Let's go through the answer choices to see which are true, and which are false.

Answer:

option D

Step-by-step explanation:

THE FUNCTION HAS A RANGE OF ALL REAL NUMBERS LESS THAN OR EQUAL TO 2

Answer:

Answer:

36π inches which is 113.10 inches to the nearest hundredth

Step-by-step explanation:

The circumference = 12 * π

Rotating 3 times  the distance moved is 3 * 12π.

Answer:

VW=4

Step-by-step explanation:

UW=VW+UV

5x-5=(x)+(3x-1)

5x-5=4x-1

5x-4x=-1+5

x=4

VW=x= 4

I hope I helped you^_^

A general cosine function (we could also use a sine function) is written as:

y = A*cos(k*x + p) + M

We will find that the function of the graph is:

f(x) = 2*cos(2*x + 2.09) - 2

Let's return to the general function:

y = A*cos(k*x + p) + M

A is the amplitude, it defines the distance between the value of a maximum and the value of the minimum, such that A is exactly half of that difference.

Here we can see that the maximum is 0, and the minimum is -4

The differene is: 0 - (-4) = 4

Then:

A = 4/2 = 2

f(x) = 2*cos(k*x + p) + M.

M is the midline, this is, the horizontal line that cuts the graph in two halves. Here we can see that the midline is x = -2, then:

M = -2

f(x) = 2*cos(k*x + p) - 2

p is the phase shift.

In the graph, we can see that f(0) = -3, so we have:

f(0) = 2*cos(0 + p) - 2 = -3

      cos(p) = -1/2

             p = Acos(-1/2) = 2.09

Then we have:

f(x) = 2*cos(k*x + 2.09) - 2

Finally, k is related to the frequency of the function.

We can see that the function does a complete cycle at x = pi

This means that:

f(x) = f(x + pi)

Knowing that the period of a cosine function is 2*pi, then:

k*(x + pi) = k*x + 2*pi

k = 2

Then the equation of the graph is:

f(x) = 2*cos(2*x + 2.09) - 2

If you want to learn more, you can read:

https://brainly.com/question/24372261

Answer(s):

[tex]\displaystyle y = 2sin\:(2x + 1\frac{1}{4}\pi) - 2 \\ y = 2cos\:(2x - 1\frac{1}{4}\pi) - 2[/tex]

Step-by-step explanation:

[tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow -2 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-\frac{5}{8}\pi} \hookrightarrow \frac{-1\frac{1}{4}\pi}{2} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\pi} \hookrightarrow \frac{2}{2}\pi \\ Amplitude \hookrightarrow 2[/tex]

OR

[tex]\displaystyle y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow -2 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{\frac{5}{8}\pi} \hookrightarrow \frac{1\frac{1}{4}\pi}{2} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\pi} \hookrightarrow \frac{2}{2}\pi \\ Amplitude \hookrightarrow 2[/tex]

You will need the above information to help you interpret the graph. First off, keep in mind that although this looks EXACTLY like the cosine graph, if you plan on writing your equation as a function of sine, then by all means, go for it, but be careful and follow what is explained here. Now, as you can see, the photograph on the right displays the trigonometric graph of [tex]\displaystyle y = 2sin\:(2x - 1\frac{1}{4}\pi) - 2,[/tex] in which you need to replase “cosine” with “sine”, then figure out the appropriate C-term that will make the graph horisontally shift and map onto the cosine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the sine graph [photograph on the right] is shifted [tex]\displaystyle \frac{\pi}{4}\:unit[/tex] to the right, which means that in order to match the cosine graph [photograph on the left], we need to shift the graph BACKWARD [tex]\displaystyle \frac{\pi}{4}\:unit,[/tex] which means the C-term will be negative. Now, BEFORE we go any further, we must remember that this particular cosine graph [thank goodness it is a cosine graph we are working with] ALREADY has a horisontal shift and does not have a single crest oscıllαtıng about any endpoint on the y-axis. So, in this case we need to figure out how far the FIRST oscıllαtıng crest is from the origin, and that obviously would be [tex]\displaystyle \frac{5}{8}\pi\:units.[/tex] Though, sinse we want the sine equation of this graph, it must be “negative”; so, by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{-\frac{5}{8}\pi} = \frac{-1\frac{1}{4}\pi}{2},[/tex] in which the value of C is [tex]\displaystyle -1\frac{1}{4}\pi.[/tex] So, the sine equation of the cosine graph, accourding to the horisontal shift, is [tex]\displaystyle y = 2sin\:(2x + 1\frac{1}{4}\pi) - 2.[/tex] Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph hits [tex]\displaystyle [\frac{7}{8}\pi, -2],[/tex] from there to [tex]\displaystyle [-\frac{\pi}{8}, -2],[/tex] they are obviously [tex]\displaystyle \pi\:units[/tex] apart, telling you that the period of the graph is [tex]\displaystyle \pi.[/tex] Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = -2,[/tex] in which each crest is extended two units beyond the midline, hence, your amplitude. So, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

**As you can see, this is one of those moments where you will really need to be careful because if you notised, both equations have OPPOCITE horisontal shifts and C-values. Now, the ONLY TIME this occurs is when all crests in a SINUSOIDAL graph cycle half-way in between endpoints. Your best bet is to jot this down for when you see graphs like these in the future.

I am delighted to assist you at any time.

Answer:

f(4) =1

Step-by-step explanation:

f(1) = 10

f(n) = f(n − 1) – 3

Let n=2

f(2) = f(2 − 1) – 3 = 10-3 = 7

Let n =3

f(3) = f(3 − 1) – 3 = f(2) -3 = 7-3 = 4

Let n = 4

f(4) = f(4 − 1) – 3 = f(3) -3 = 4-3 = 1

Answer:

9

Step-by-step explanation:

f(4)=4(4-1)-3

f(4)=4(3)-3

f(4)=12-3

f(4)=9

Answer:

Equation B.

Step-by-step explanation:

Subtract 4 from both sides in the equation 11r+4=55. You will see that it is equivalent to equation B.

Answer:

you need to be more specific.

Step-by-step explanation:

Answer:

Below

Step-by-step explanation:

First I found the area of the portion that extends off (if that makes sense??)

It is a triangle, so use A = bh/2

A = (2)(6) / 2

   = 6 cm^2

Next I found the area of the rectangle using A = LW

A = (6)(3)

   = 18 cm^2

Total area = 18 + 6

                 = 24 cm^2

Hope this helps! Best of luck <3

Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

Top and bottom:

Front and back:

Left and right:

Total surface area:

Answer:

=280

Step-by-step explanation:

Step 1:

find the surface areas of both the figures

area of 1rst:

length = 2

width =4

height = 10

surface area formula = 2(wl+wh+hl)

= 136

area of second

length = 4

width =4

height = 7

surface area formula = 2(wl+wh+hl) =

2·(4·4+7·4+7·4)=144

144 + 136 = 280

Answer:

Answer for this is 62 * 2 = 126

Step-by-step explanation:

Answer:

14×9=126

Step-by-step explanation:

how do you explain it lol

The given expression can be written in factor form as 4a(2ab)

Given:

2³a²b to be expressed in factor form

To express the above given expression in factor form follow the steps below;

Finally, the given expression can be written in factor form as 4a(2ab)

To learn more about factorization, please visit: https://brainly.com/question/11909547

Answer:

2/5

Step-by-step explanation:

P(drive to school) = number of students that drive to school ÷ total number of students

P(drive to school) = 40/100

P(drive to school) = 2/5

Answer:

The probability would be:

(number of students drive to school)/(total number of selected students)

Therefore, the probability would be:

[tex]\frac{40}{100}=\frac{4}{10} =\frac{2}{5}[/tex]

Answer:

b = 19.6

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean theorem

a^2+b^2 = c^2  where a and b are the legs and c is the hypotenuse

20^2+ b^2 = 28^2  

400 + b^2 = 784

b^2 = 784-400

b^2 =384

Taking the square root of each side

sqrt( b^2) = sqrt(384)

b =19.59591794

To the nearest tenth

b = 19.6

Answer:

19.6

Step-by-step explanation:

It is a right triangle so use the pythagorean theorem; a^2 + b^2 = c^2

a=20

b=?

c=28 - c is the hypotenuse because it is across from the right angle

20^2 + b^2 = 28^2

400+ b^2 =784

b^2=384

b= 19.595917... or 19.6 (rounded to nearest tenth)

Answer:

-4 is the answer

Answer:

-4

Step-by-step explanation:

8+(-12)

+ x - = -

8-12

-4

Answer:

A) Sometimes

A ) Sometimes is the correct answer because b) always and c) never is not possible

it cannot be always measured 90 degrees

Answer:

The number of rare coins a coin collector owns is considered discrete data.

Answer:

Hi I'm going to answer the question is 0

Step-by-step explanation:

-2x(-8)(10x+1)=0

Multiply -2 times -8 is 16

16x(10x+1)=0

Use the distributive property to multiply 16x by 10x+1

[tex] {160}^{2} + 16 = 0 \\ [/tex]

Factor out x.

x(160x+16)=0

To find equation solutions, solve x=0 and 160x+16=0

x=0

x=

[tex] - \frac{1}{10} [/tex]

Answer:

Step-by-step explanation:

(7y+4)/(y+2)=-4/3

[tex]\dfrac{7y+4}{y+2}=\dfrac{-4}{3}\\\\[/tex]

Cross multiply,

(7y + 4) * 3 = -4*(y+ 2)

Use distributive property,

7y*3 + 4*3 = -4*y + 2*(-4)

21y + 12 = -4y - 8

Subtract 12 from both side

21y = -4y - 8 - 12

21y = -4y - 20

21y + 4y = -20

25y = -20

y = -20/25

[tex]y=\dfrac{-4}{5}[/tex]

[tex]\\ \sf\longmapsto \dfrac{7y+4}{y+2}=\dfrac{-4}{3}[/tex]

[tex]\\ \sf\longmapsto 3(7y+4)=-4(y+2)[/tex]

[tex]\\ \sf\longmapsto 21y+12=-4y-8[/tex]

[tex]\\ \sf\longmapsto 21y+4y=-8-12[/tex]

[tex]\\ \sf\longmapsto 25y=-20[/tex]

[tex]\\ \sf\longmapsto y=\dfrac{-20}{25}[/tex]

[tex]\\ \sf\longmapsto y=\dfrac{-4}{5}[/tex]