Given circle C with diameter AB
, find the value of x.

A circle with three chords. Point C is in the center, point D is a 2 o clock, point B is at 3 o clock, and point A is at 9 o clock. Segment AB is passing through C. Segment BD and AD do not pass through C. Angle ABD is labeled 70 degrees. Angle DAB is labeled x.

Enter your answer in the box.

Answers

Answer 1

The value of x is 70 degrees.

To find the value of x, we can use the properties of angles in a circle.

In the given circle, we have a diameter AB passing through the center of the circle, labeled as point C. Point D is located at 2 o'clock, point B at 3 o'clock, and point A at 9 o'clock.

We are given that angle ABD is labeled as 70 degrees. Since angle ABD is an angle formed by a chord (AB) and a tangent (BD), we can apply the property that the measure of an angle formed by a tangent and a chord is equal to half the measure of the intercepted arc.

In this case, angle ABD intercepts the arc AB. Since AB is a diameter, it subtends a 180-degree arc. Therefore, the measure of angle ABD is equal to half the measure of the intercepted arc AB, which is 180 degrees divided by 2, resulting in 90 degrees.

Now, let's focus on angle DAB, labeled as x. Since angle DAB and angle ABD are vertical angles (angles formed by the intersection of two lines), they have the same measure. Therefore, x is also equal to 70 degrees.

In conclusion, the value of x is 70 degrees.

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Related Questions

Activity
You have also set up a card game in which a player picks a card from a standard deck of 52 cards. The player wins if these two events occur together: E1, in which the card drawn is a black card, and E2, in which the card drawn is a numbered card, 2 through 10.

Question 1
What is the probability of getting a black card and a numbered card? Calculate the probabilities P(E1) and P(E2) as fractions.

Answers

The probability of getting a black card and a numbered card is 9/26.

To calculate the probability of getting a black card (E1), we need to determine the number of black cards in a standard deck of 52 cards.

There are 26 black cards in total, which consist of 13 spades (black) and 13 clubs (black).

Therefore, the probability of drawing a black card (P(E1)) is:

P(E1) = Number of favorable outcomes / Total number of possible outcomes

P(E1) = 26 / 52

Simplifying this fraction, we get:

P(E1) = 1/2

So the probability of drawing a black card is 1/2.

To calculate the probability of drawing a numbered card (E2), we need to determine the number of numbered cards (2 through 10) in a standard deck.

Each suit (spades, hearts, diamonds, clubs) contains one card for each numbered value from 2 to 10, totaling 9 numbered cards per suit.

Therefore, the probability of drawing a numbered card (P(E2)) is:

P(E2) = Number of favorable outcomes / Total number of possible outcomes

P(E2) = 36 / 52

Simplifying this fraction, we get:

P(E2) = 9/13

So the probability of drawing a numbered card is 9/13.

To calculate the probability of both events occurring together (getting a black card and a numbered card), we multiply the individual probabilities:

P(E1 ∩ E2) = P(E1) × P(E2)

P(E1 ∩ E2) = (1/2) × (9/13)

Simplifying this fraction, we get:

P(E1 ∩ E2) = 9/26

Therefore, the probability of getting a black card and a numbered card is 9/26.

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A number is thrice the other number and their sum is 80. (i) Express the above statements in the form of linear equations. (ii) Find the numbers.​

Answers

So, let us call our numbers a and b.

Statement 1:
a is thrice to b or: a = 3*b

Statememt 2:
Their (a’s and b’s) sum is 80: a+b =80

Together we have the two linear equations:
a=3b
a+b=80

Solving them can be done by using the fact that a is equal to 3b and plugging this into the second equation:

3b + b = 80


Now 3 apples plus 1 apple is 4 apples, right? So 3b + b = 4b !

4b = 80

No we divide by 4 and get the result for b:

b = 20

Now how do we find a? Well we know that a = 3b. So we just plug the solution for b into this equation:

a = 3 * 20 = 60.

That means the two numbers were 20 and 60

What number must you add to complete the square x2+4x=15

Answers

Answer: 19

Step-by-step explanation:

x^2+4x-15=0. To complete the square, it needs to be (x+2)^2, which is x^2+4x+4. Thus, you need to add 19.

50 pts. Compute the requested operating costs as indicated, based on the preceding table and the following information.


Car: six-cylinder compact

Year driven: second

Miles driven: 14,000


The insurance cost for second year is $

.


If the answer is right, (I will check it,) then I will post a question and give you more points. just get on my prophile, and keep reloading on my "questions' page. 100 extra points.


DONT FLAG. I NEED HELP WITH THIS PROBLEM AND I"M TRYING TO GET A REAL ANSWER.

Answers

From the table , the insurance cost for the second year based on the prescription given is : $1329

Using the prescription table, the six cylinder compact , second year car with a mileage of 14000 falls in the mid table category with the 13000 mileage label .

The operating cost in insurance for the second year is therefore $1329.

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hich linear function has the steepest slope?
y = negative 8 x + 5
y minus 9 = negative 2 (x + 1)
y = 7 x minus 3
y + 2 = 6 (x + 10)

Answers

The function with the steepest slope is [tex]y = 7x - 3[/tex].

The correct answer is C.

The linear function with the steepest slope is the one with the highest absolute value for the coefficient of x.

Let's compare the coefficients of x in each of the given functions:

[tex]y = -8x + 5[/tex]

Slope: -8

[tex]y - 9 = -2(x + 1)[/tex]

Simplifying, we get [tex]y - 9 = -2x - 2[/tex]

Rearranging, we have [tex]y = -2x + 7[/tex]

Slope: -2

[tex]y = 7x - 3[/tex]

Slope: 7

[tex]y + 2 = 6(x + 10)[/tex]

Simplifying, we get [tex]y + 2 = 6x + 60[/tex]

Rearranging, we have [tex]y = 6x + 58[/tex]

Slope: 6

Therefore, the steepest slope is the [tex]y = 7x - 3[/tex].

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A round wading pool has a diameter of 115cm and is 25cm deep. A hose is filling the pool at a rate of 34,000cm^3 per minute.

Answers

Therefore, it will take approximately 7.67 minutes to fill the wading pool completely.

The round wading pool has a diameter of 115 cm and a depth of 25 cm. To find the volume of the pool, we can use the formula for the volume of a cylinder, which is

V = πr^2h.

Since the pool is round, the radius (r) is half the diameter, which is

115 cm / 2 = 57.5 cm.

Plugging in the values, we have

V = π(57.5 cm)^2 * 25 cm ≈ 260,979 cm^3.

The hose is filling the pool at a rate of 34,000 cm^3 per minute.

To determine how long it will take to fill the pool, we divide the volume of the pool by the rate of filling:

260,979 cm^3 / 34,000 cm^3/min ≈ 7.67 minutes.

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A photo has a side length 4 inches and 6 inches in length .After the enlargement the length becomes 5 more inches what is the length of the photo

Answers

Therefore, the length of the photo after the enlargement is 9 inches.

The initial length of the photo is given as 4 inches. After the enlargement, the length becomes 5 more inches. To find the final length, we can add 5 inches to the initial length.

Initial length of the photo: 4 inches

Additional length after enlargement: 5 inches

Final length = Initial length + Additional length

Final length = 4 inches + 5 inches

Final length = 9 inches

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Factorize q2-4 completely

Answers

The completely factorized form of the expression q² - 4 is (q + 2)(q - 2).

What is the factored form of the expression?

Given the expression in the question:

q² - 4

To factorize the expression q² - 4 completely, we can use the formula for the difference of squares.

The difference of squares formula states that :

a² - b² can be factored as (a + b)(a - b).

Given that:

q² - 4

Replace 4 with 2²
q² - 2²

From this expression, let a = x and b = 2

a² - b² =  (a + b)(a - b)

q² - 2² = (q + 2)(q - 2)

Therefore, the factored form is (q + 2)(q - 2).

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PLEASE HELP URGANT I WILL GIVE BRAINLIST

Answers

Answer:74

Step-by-step explanation:

DCB arc's degree is equal to 2*<DAB so,

arc DCB=106*2=212 degrees

cicle is 360 degrees total, so,

360-212=148 degrees

and it is arc DAB which is arc for <DCB and same rule applies here:

arc DAB=2*<DCB

<DCB=DAB/2=148/2=74

Read the problem and decide whether it has too much or too little
information.
On Saturday at the Boxerville Carnival, 800 people attended. On Sunday, 650
people attended. On Monday, 250 people attended. On Tuesday, 350 people
attended. How many people attended the Boxerville Carnival on the
weekend?

Answers

The problem provides the attendance numbers for four specific days of the Boxerville Carnival: Saturday (800 people), Sunday (650 people), Monday (250 people), and Tuesday (350 people). The question asks for the total number of people who attended the carnival on the weekend.

Given that the information about Saturday and Sunday attendance is provided, we have enough information to determine the total number of people who attended the carnival on the weekend. We can simply add the attendance numbers for Saturday and Sunday:

800 + 650 = 1450 people.

Therefore, the problem has sufficient information to calculate the total attendance on the weekend. It is not excessive or lacking in detail, allowing us to accurately find the desired answer.

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Pam likes to practice dancing while preparing for a math tournament. She spends 80 minutes every day practicing dance and math. To help her concentrate better, she dances for 20 minutes longer than she works on math.

Part A: Write a pair of linear equations to show the relationship between the number of minutes Pam practices math every day (x) and the number of minutes she dances every day (y). (5 points)

Part B: How much time does Pam spend practicing math every day? Show your work. (3 points)

Part C: Is it possible for Pam to have spent 60 minutes practicing dance if she practices for a total of exactly 80 minutes and dances for 20 minutes longer than she works on her math? Explain your reasoning. (2 points)

Answers

Let the time spent practicing math be x minutes. Since Pam spends 20 minutes longer practicing dance than math, she spends (x + 20) minutes practicing dance. Therefore, the total time spent practicing math and dance is

:x + (x + 20) = 2x + 20

Since she spends 80 minutes every day practicing math and dance, we can create an equation as follows:2x + 20 = 80To find the value of x, we need to solve the equation

.2x + 20 = 80

Subtract 20 from both sides of the equation

:2x = 60

Divide both sides by

2:x = 30

Therefore, Pam spends 30 minutes practicing math every day.Part B: Pam spends 30 minutes practicing math every day. To find the total time she spends practicing dance, we can use the fact that she spends 20 minutes longer practicing dance than math. Therefore, she spends:

30 + 20 = 50 minutes

practicing dance every day.Part C: It is not possible for Pam to have spent 60 minutes practicing dance if she practices for a total of exactly 80 minutes and dances for 20 minutes longer than she works on her math. If Pam spends 30 minutes practicing math every day, then she spends 50 minutes practicing dance. Therefore, the total time she spends practicing math and dance is

:30 + 50 = 80

Since the total time spent practicing math and dance is exactly 80 minutes, it is not possible for Pam to have spent 60 minutes practicing dance.

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Who is correct and why?
Selena is incorrect because she should have substituted the values for the variables first, and then simplifed.
Selena is correct because she simplified correctly and then evaluated correctly after substituting the values for the variables.
Drake is incorrect because he should have simplified first, before substituting the values for the variables.
Drake is correct because he substituted the values for the variables first, and simplified correctly.

Answers

Selena and Drake both are correct.

Selena: According to the statement, Selena is said to have not substituted the values for the variables first and then simplified.If she did not follow the correct order of operations, it's possible that she made an error.Drake: According to the statement, Drake is said to have substituted the values for the variables first and then simplified. This order seems to align with the correct order of operations, but without further details, it is not possible to determine if he made any mistakes during the process.

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Simplify this expression:2x + 3 – (5 – 6x).

Answers

Answer:

8x - 2

Step-by-step explanation:

2x + 3 - (5 - 6x) ← distribute parenthesis by - 1

= 2x + 3 - 5 + 6x ← collect like terms

= (2x + 6x) + (3 - 5)

= 8x + (- 2)

= 8x - 2

What is the value of y?
150%
O A. 85
O B. 65
O C. 75
OD. 55
95°

Answers

Hello!

angle1 = (360° - 2 * 150°)/2 = 30°

angle2 = (360° - 2 * 95°)/2 = 85°

y° = 180° - (30° + 85°) = 65°

The correct answer is 65°
The answer yo your question is B

Let's roll two dice and find the probability of rolling a certain sum. Is this a simple or compound event?
Two dice - Red and Blue

Recall that a simple event has one and only one outcome of interest. In this example, we are rolling two dice, but we are only interested in one outcome, the sum of the two dice. This is a simple event.
What is the probability of:
Rolling a sum of 1?
Rolling a sum of 3?
Rolling a sum of 12?
Rolling a sum of 7?
Since we are rolling a pair of dice and looking for the sum, the sample space is a little more complicated than rolling one die. The chart below will help us determine the possible outcomes. The top row indicates the numbers on the sides of the blue die and the first column represents the number on the sides of the red die. The white area indicates the sum of the numbers in the row and column.
# Rolled 1 2 3 4 5 6
1 1+1=2
1
+
1
=
2
1+2=3
1
+
2
=
3
1+3=4
1
+
3
=
4
1+4=5
1
+
4
=
5
1+5=6
1
+
5
=
6
1+6=7
1
+
6
=
7
2 2+1=3
2
+
1
=
3
2+2=4
2
+
2
=
4
2+3=5
2
+
3
=
5
2+4=6
2
+
4
=
6
2+5=7
2
+
5
=
7
2+6=8
2
+
6
=
8
3 3+1=4
3
+
1
=
4
3+2=5
3
+
2
=
5
3+3=6
3
+
3
=
6
3+4=7
3
+
4
=
7
3+5=8
3
+
5
=
8
3+6=9
3
+
6
=
9
4 4+1=5
4
+
1
=
5
4+2=6
4
+
2
=
6
4+3=7
4
+
3
=
7
4+4=8
4
+
4
=
8
4+5=9
4
+
5
=
9
4+6=10
4
+
6
=
10
5 5+1=6
5
+
1
=
6
5+2=7
5
+
2
=
7
5+3=8
5
+
3
=
8
5+4=9
5
+
4
=
9
5+5=10
5
+
5
=
10
5+6=11
5
+
6
=
11
6 6+1=7
6
+
1
=
7
6+2=8
6
+
2
=
8
6+3=9
6
+
3
=
9
6+4=10
6
+
4
=
10
6+5=11
6
+
5
=
11
6+6=12
6
+
6
=
12
How many outcomes are in the sample space? Answer

Answers

Answer:

the answer to your question how many outcomes is really gonn adepend on you you slove you problem but my amswer is gonna be 7.

sum of 2 number is 34,678 if one of the number is 30,020 what is the other number​

Answers

The other number is 4, 658

How to determine the value

Algebraic expressions are described as expressions that are made up of terms, variables, constants and factors.

These algebraic expressions are also made up of arithmetic operations such as;

AdditionMultiplicationDivisionBracketParenthesesSubtraction

From the information given, we have that;

sum of 2 number is 34,678

If one of the number is x and the other is 30, 020

Then, we have that;

x + 30,020 =34, 678

collect the like terms, we have;

x = 34, 678 - 30, 020

x = 4, 658

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A 12 oz box of sugar costs $3.10 and a 36 oz box of sugar costs $7.90. Which box of sugar is the better buy?

Answers

Answer: 36 oz box

Step-by-step explanation:

3.1/12=0.258333

7.9/360.291444

Thus, the 36 oz box is the better buy

PLEASE HELP TODAY I WILL GIVE BRAINLIST

Answers

Answer: Triangle C only

Step-by-step explanation: using the formula to find out if the triangle are right angle (a^2+b^2=c^2) the legs are supposed to equal to the hypotenuse. A and B arentaren't equal to the hypotenuse

Sketch an angle 0 in standard position such that 0 has the least possible positive measure, and the point (-2,√3) is
on the terminal side of 0. Then find the values of the six trigonometric functions for the angle. Rationalize denominators
if applicable.

Answers

The trigonometric functions for the angle with the least possible positive measure and the point (-2, √3) on the terminal side are:

sin(0) = √3/2

cos(0) = -1/2

tan(0) = -√3

csc(0) = 2/√3

sec(0) = -2

cot(0) = -1/√3

To sketch an angle in standard position, we start by placing the initial side along the positive x-axis. Since we want the angle with the least possible positive measure, we choose the smallest positive angle, which is 0 degrees or 0 radians.

Next, we plot the point (-2, √3) on the terminal side of the angle. This point lies in the third quadrant of the coordinate plane. We draw a line segment from the origin to this point, representing the terminal side of the angle.

To find the values of the trigonometric functions, we can use the coordinates of the point (-2, √3) to determine the side lengths of a right triangle. The x-coordinate (-2) represents the length of the adjacent side, and the y-coordinate (√3) represents the length of the opposite side. The hypotenuse can be found using the Pythagorean theorem.

Using the values of the sides, we can calculate the trigonometric functions:

sin(0) = opposite/hypotenuse = √3/2

cos(0) = adjacent/hypotenuse = -1/2

tan(0) = opposite/adjacent = -√3

csc(0) = 1/sin(0) = 2/√3

sec(0) = 1/cos(0) = -2

cot(0) = 1/tan(0) = -1/√3

The trigonometric functions for the angle with the least possible positive measure and the point (-2, √3) on the terminal side are:

sin(0) = √3/2

cos(0) = -1/2

tan(0) = -√3

csc(0) = 2/√3

sec(0) = -2

cot(0) = -1/√3

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Functions of Random Variables

Answers

The statement for the function of random variable "The density of Y can be found by differentiating the CDF of Y" is false.

Why is the statement on deafferenting random variable false?

The density of a random variable can be found by differentiating its CDF, but only if the random variable is continuous. The random variable X in this case is discrete, so its density cannot be found by differentiating its CDF.

The CDF of a discrete random variable is a step function, which means that it has a jump discontinuity at each point where the value of the random variable changes.

The derivative of a step function is a Dirac delta function, which is a mathematical object that represents a point mass at a specific value. The density of a discrete random variable is the sum of the Dirac delta functions at each point where the value of the random variable changes.

In this case, the CDF of Y is a step function, so its derivative is a Dirac delta function. The density of Y is the sum of the Dirac delta functions at each point where the value of Y changes. However, the value of Y can only change at integer values, so the density of Y is a discrete function, not a continuous function.

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Given that ABCD is a rhombus, what is the value of x?
B
(4x-25)
A
OA. 29
B. 23
C. 46
D. 38
OE. 45
O F. Cannot be determined

Answers

The value of x in the rhombus ABCD is determined as 23.

option B.

What is the value of x?

The value of x is calculated by applying the following formula as shown below.

the diagonals of a rhombus intersects at 90 degrees;

the complementary angle of  (4x - 25) = 90 - (4x - 25)

90 - (4x - 25) = x (alternate angles are equal)

90 - 4x + 25 = x

115 = 4x + x

115 = 5x

divide both sides of the equation by 5 to obtain the value of x;

5x = 115

x = 115 / 5

x = 23

Thus, the value of x in the rhombus ABCD is determined as 23.

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Assume that you buy a 49,000 VNĐ milk tea cup everyday, 30 days per month. As 12 months interest rate - 6.3% quoted by Vietcombank, how much money do you have after 10 years if you invest monthly after saving your money?

Answers

Answer:

To calculate the future value of your monthly investments after saving your money, i can use the formula for the future value of an ordinary annuity:

FV = P * ((1 + r)^n - 1) / r

Where:

FV = Future Value

P = Monthly investment amount

r = Monthly interest rate

n = Number of months

Given:

Monthly investment amount (P) = 49,000 VNĐ

Monthly interest rate (r) = 6.3% / 12 = 0.00525

Number of months (n) = 10 years * 12 months/year = 120 months

Plugging in these values, i can calculate the future value:

FV = 49,000 * ((1 + 0.00525)^120 - 1) / 0.00525

Calculating this expression, the future value is approximately 7,565,000 VNĐ.

Therefore, after 10 years of investing 49,000 VNĐ per month and earning an interest rate of 6.3% per year, you would have approximately 7,565,000 VNĐ.

64 players started how many left after 3 rounds

Answers

Answer: 8

Step-by-step explanation:

I do not understand the question. But if my interpretation is correct, then:

If there are 64 players and 3 rounds, 32 will get out in the first round. 16 will get out in the second, and 8 will get out on the third. Thus, the answer is 64-(32+16+8) or just simply 8.

what is the slope of AB? if the slope of BC is -1/2

Answers

The slope of AB is given by:(0 - (-1/2x - 5/2)) / (0 - x)= 1/2

Given that the slope of BC is -1/2. We need to find the slope of AB.

Slope of a line can be defined as the ratio of the change in y-coordinate to the change in x-coordinate between any two distinct points on the line.

Let us consider the coordinates of point B as (x, y)Coordinates of point C can be obtained by moving 3 units to the right from point B.

Therefore, coordinates of point C are (x+3, y+1).Since the slope of BC is -1/2, we can say that:(y+1 - y) / (x+3 - x) = -1/2y + 1 = -1/2(x + 3)y = -1/2x - 5/2Therefore, the coordinates of point B are (x, -1/2x - 5/2).

Point A lies on the x-axis. Therefore, its y-coordinate is zero. Therefore, the slope of AB is given by:(0 - (-1/2x - 5/2)) / (0 - x)= 1/2

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Please hurry need help, Answer choices-
A.9
B.-2
C.11
D.3

Answers

The numerical value of x in angle ABD is 9 as angle ABC is divided into two equal halves.

What is the numerical value of x?

An angle bisector divided an angle into two equal halves.

From the diagram:

Line BD divides angle ABC into two equal halves.

Angle ABD = ( 3x - 7 ) degrees

Angle DBC = 20 degrees

Since angle ABD and DBC are equal haves;

Angle ABD = Angle DBC

Plug in the values:

( 3x - 7 ) = 20

Solve for x:

3x - 7 = 20

Add 7 to both sides:

3x - 7 + 7 = 20 + 7

3x = 27

x = 27/3

x = 9

Therefore, the value of x is 9.

Option A)9 is the correct answer.

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find the front and side elevation

Answers

The sketch of the front elevation and the side elevation of the prism are added as an attachment

How to draw the front elevation and the side elevation of the prism

From the question, we have the following parameters that can be used in our computation:

The prism

Using the figure as a guide, we understand that:

The front elevation is a rectangle of 2m by 0.5m

While the side elevation is a rectangle merged with a trapezoid

Next, we draw the elevations (see attachment)

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M Question 2 Unit 7 Chapter 10 %
https://ezto.mheducation.com/ext/map/index.html?
Account for 63859...Pay your trash bills...
Unit 7 Chapter 10 Quiz
2
Imported from inte...
Wait time
Inspection time
Process time
Seved
New folder
Imported from inte....
17 days
13 days
23 days
22 days
12 days
Navern Corporation manufactures and sells custom home elevators. From the time an order is
placed until the time the elevator is installed in the customer's home averages 87 days. This 87
days is spent as follows:
Help
Move time
Queue time
What is Navern's manufacturing cycle efficiency (MCE) for its elevators?
Seve & Exit
Su

Answers

Navern's manufacturing cycle efficiency (MCE) for its elevators is: 41.4%

How to solve the manufacturing cycle efficiency

The formula for obtaining the manufacturing cycle efficiency is value-added time divided by the production cycle time * 100. In the data given, the process and inspection times qualify as a value-added time

Process time = 23 days

Inspection time = 13 days

Value added time = 23 + 13 = 36days

The production cycle time = Move time + process time + queue time + inspection time + wait time

= 22 + 12 + 23 + 13 + 17 days

= 87 days

So, the manufacturing efficiency time = 36/87 * 100

= 41.4%

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A data set consists of 3 numbers, a
, b
, and c
. Write an algebraic expression, in terms of a
, b
, and c
, to represent the mean of the new set of numbers obtained by

Answers

The universal set for sets A, B, and C is {0, 1, 2, 3, 4, 5, 6, 8}.

The universal set is the set that contains all the elements under consideration. In this case, we have three sets: A, B, and C. To determine the universal set for all three sets, we need to identify the set that includes all the unique elements from each of the individual sets.

Set A contains the elements {1, 3, 5}, Set B contains the elements {2, 4, 6}, and Set C contains the elements {0, 2, 4, 6, 8}. To form the universal set, we need to combine all these elements without any repetition.

By observing the elements in Sets A, B, and C, we can see that the universal set would be the set that includes all the unique elements from these sets. Therefore, the universal set for all three sets is the set that contains {0, 1, 2, 3, 4, 5, 6, 8}.

This means that any element that is present in at least one of the sets A, B, or C is included in the universal set. It covers all the possible elements that can be found in these sets.

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Question

If set A = {1, 3, 5}, B = {2, 4, 6} and C = {0, 2, 4, 6, 8}. Then write the universal set for all three sets.

harm, Inc. is a pharmaceutical company with 100 million shares ag at $10/share and debt outstanding of $ 250 million. The firm has ered beta of 1.00 and a pre-tax cost of debt of 4.5%. The risk-free s 3.5%, the marginal tax rate is 40% and the equity risk premium o. A. What is the cost of equity capital? B. What is the after-tax cost of debt? C. What is the WACC? ow assume that the firm plans to borrow $ 500 million and buy back ock. If this will triple the default spread on the debt (both new and xisting), estimate the new cost of capital for the firm after the ecapitalization. D. What is the cost of equity after restructuring? E. What is after-tax cost of debt after restructuring? F. What is the WACC after restructuring? Now assume that the firm does buy back stock with the $ 500 million and pays$ 11/share. G. Estimate the value (price) per share for the remaining shareholders in the company. (You can assume no growth in perpetuity).

Answers

The following are the solutions to the given problem:A. Cost of Equity Capital:Given,Beta of the firm = 1.00Risk-Free Rate (Rf) = 3.5%Equity Risk Premium = 6%Cost of Equity (Re) = Rf + Beta*(Equity Risk Premium)Re = 3.5% + 1.00(6%)Re = 9.5%B. After-Tax Cost of Debt:Given,

Pre-tax cost of debt = 4.5%Tax rate = 40%

After-tax cost of debt (Rd) = Pre-tax cost of debt x (1 - Tax Rate)Rd = 4.5% x (1 - 0.40)Rd = 2.7%C. Weighted Average Cost of Capital (WACC):Given,

Weightage of Equity (We) = 100 million shares / 100 million shares + 250 million of debtWe = 28.57%Weightage of Debt (Wd) = 250 million of debt / 100 million shares + 250 million of debt

Wd = 71.43%WACC = (We x Re) + (Wd x Rd)WACC = (28.57% x 9.5%) + (71.43% x 2.7%)WACC = 3.91%D. Cost of Equity after Restructuring:Given,New Default Spread = 3 x Old Default SpreadOld Default Spread = 2.7% - 3.5%Old Default Spread = -0.8%New Default Spread = 3 x -0.8%

New Default Spread = -2.4%New After-tax Cost of Debt (Rd) = 2.7% + (-2.4%)Rd = 0.3%New Weightage of Debt (Wd) = 750 million of debt / 100 million shares + 750 million of debt

Wd = 88.24%New Weightage of Equity (We) = 100 million shares / 100 million shares + 750 million of debtWe = 11.76%New Cost of Equity (Re) = 9.5%Re = 9.5%New WACC

= (We x Re) + (Wd x Rd)New WACC = (11.76% x 9.5%) + (88.24% x 0.3%)New WACC = 0.53%E. After-tax Cost of Debt after Restructuring:Given,

New After-tax Cost of Debt (Rd) = 0.3%F. WACC after Restructuring:New WACC = 0.53%G. Value (Price) per Share for the Remaining Shareholders in the Company:Given,

New Shares = 500 million / $11 per share = 45,454,545 shares New Equity Shares = 100 million shares + 45,454,545 shares = 145,454,545 shares Value of Equity = 145,454,545

shares x $11 per shareValue of Equity = $1,600,000,000Value per Share for the Remaining Shareholders in the Company = $1,600,000,000 / 100 million sharesValue per Share for the Remaining Shareholders in the Company = $16.00 per share.

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The base of the mountain is 6,500 feet above sea level and AB measures 230 feet across. Given that the measurements for QAP is 20° and QBP is 35°, how far above sea level is peak P ? Express your answer to the nearest foot.

Height above sea level:

Answers

Answer:

6610

Step-by-step explanation:

We have tan(X) = opposite/ adjacent

tan(QBP) = PQ/BQ

tan(35) = PQ/BQ    ---eq(1)

tan(QAP) = PQ/AQ

tan(20) = [tex]\frac{PQ}{AB +BQ}[/tex]

[tex]=\frac{1}{\frac{AB+BQ}{PQ} } \\\\=\frac{1}{\frac{AB}{PQ} +\frac{BQ}{PQ} } \\\\= \frac{1}{\frac{230}{PQ} + tan(35)} \;\;\;(from\;eq(1))\\\\= \frac{1}{\frac{230 + PQ tan(35)}{PQ} } \\\\= \frac{PQ}{230+PQ tan(35)}[/tex]

230*tan(20) + PQ*tan(20)*tan(35) = PQ

⇒ 230 tan(20) = PQ - PQ*tan(20)*tan(35)

⇒ 230 tan(20) = PQ[1 - tan(20)*tan(35)]

[tex]PQ = \frac{230 tan(20)}{1 - tan(20)tan(35)}[/tex]

[tex]= \frac{230*0.36}{1 - 0.36*0.7}\\\\= \frac{82.8}{1-0.25} \\\\=\frac{82.8}{0.75} \\\\= 110.4[/tex]

PQ = 110.4

≈110

Height above sea level = 6500 + PQ

6500 + 110

= 6610

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