Answer:
x=300
Step-by-step explanation:
STEPS FOR SOLVING LINEAR EQUATION
−150=−0.5x
Divide both sides by −0.5.
−0.5
−150
=x
Expand
−0.5
−150
by multiplying both numerator and the denominator by 10.
−5
−1500
=x
Divide −1500 by −5 to get 300.
300=x
Swap sides so that all variable terms are on the left hand side.
x=300
Hope this helped!
hi guys good afternoon
in two or more complete sentences, describe how to graph the following equation. in your description, include the slope and both the x- and y-intercepts of the line. y=2
Answer:
Slope: 0
x-intercept: there isnt one
y-intercept: 2
Step-by-step explanation:
the easiest way to look at this is to put it in the form y=mx+b where m is the slope and b is the y intercept. when we just think about what y=2 would look like, we can imagine a straight horizontal line at y=2. No matter what x value you choose, y will always equal 2. We know the slope (m) of any horizontal line is zero because there is no rise and zero divided by anything is going to be zero. we also know if y is always equal to 2 the y intercept will be 2. this would give us y=0x+2. to find the x intercept we just need to set y equal to zero in this equation. this gives us 0=0x+2 or 0=2 which can never be true, therefore there will be no x intercept.
*insert shrek script*
...................................
When -2(x − 4) + 1 = 7 is solved, the result is:
Answer:
1
Step-by-step explanation:
-2(x-4)+1=7
First Distribute the -2.
-2x+8+1=7
Subtract the 8 and 1 from the whole equation.
-2x=-2
Divide both sides of the equation by -2.
x=1
I hope this helps!
Answer:
x = 1
Step-by-step explanation:
-2(x − 4) + 1 = 7
-2x + 8 + 1 = 7
-2x + 9 = 7
-2x = -2
x = 1
Ginkgo for Dementia The herb ginkgo biloba is commonly used as a treatment to prevent dementia. In a study of the effectiveness of
this treatment, 1545 elderly subjects were given ginkgo and 1524 elderly subjects were given a placebo. Among those in the ginkgo
treatment group, 246 later developed dementia, and among those in the placebo group, 277 later developed dementia. We want to
use a 0.01 significance level to test the claim that ginkgo is effective in preventing dementia. Test the claim using a hypothesis test.
Given test Statistic z = -1.66
Write Hypothesis and Critical Value, do you Support or reject the claim.
Answer:
i) 2.58
ii) We reject the claim
Step-by-step explanation:
The number of subjects in the ginkgo treatment group, n₁ = 1,545
The number of subjects in the placebo group, n₂ = 1,524
The number that developed dementia in the ginkgo group = 246
The number that developed dementia in the placebo group = 277
The proportion that developed dementia in the ginkgo group, [tex]\hat{p}_1[/tex] = 246/1,545 = 82/515
The proportion that developed dementia in the placebo group, [tex]\hat{p}_2[/tex] = 277/1,524
The null hypothesis is H₀; [tex]\hat{p}_1[/tex] = [tex]\hat{p}_2[/tex]
The alternative hypothesis is Hₐ; [tex]\hat{p}_1[/tex] ≠ [tex]\hat{p}_2[/tex]
The z-test statistic is given as follows;
[tex]Z=\dfrac{\hat{p}_1-\hat{p}_2}{\sqrt{\hat{p} \cdot (1-\hat{p}) \cdot \left (\dfrac{1}{n_{1}}+\dfrac{1}{n_{2}} \right )}}[/tex]
Therefore, we get;
[tex]Z=\dfrac{\dfrac{82}{515} -\dfrac{277}{1,524} }{\sqrt{\left (\dfrac{\dfrac{82}{515} \times \left(1 - \dfrac{82}{515} \right) }{1,545}+\dfrac{\dfrac{277}{1,524} \times \left (1 - \dfrac{277}{1,524} \right)}{1,524} \right )}} \approx -1.66[/tex]
From the the p-value at z ≈ -1.66 is p = 0.04846.
i) The z-Critical at 0.01 significant level is 2.58
ii) Given that the p-value, 0.04846, is larger than the significant level, 0.01, the p-value is not significant, and we fail to reject the null hypothesis
There is sufficient statistical evidence to suggest that there is no difference in the proportion of the subject on the ginkgo treatment and the proportion of the subject on the placebo treatment that have dementia, we therefore reject the claim that the herb ginkgo biloba is effective for the treatment of dementia.
a senior one student has reported in her class and has settled at her desk the math teacher has asked her to explain how she can access her seat
Answer:
she can sit
Step-by-step explanation:
Integral of 1 /x+ sq.root x^2-1
I'm assuming the integral is
[tex]\displaystyle \int \frac{\mathrm dx}{x+\sqrt{x^2-1}}[/tex]
Rationalize the denominator:
[tex]\dfrac1{x+\sqrt{x^2-1}} \times \dfrac{x-\sqrt{x^2-1}}{x-\sqrt{x^2-1}} = \dfrac{x-\sqrt{x^2-1}}{x^2-\left(\sqrt{x^2-1}\right)^2} = x-\sqrt{x^2-1}[/tex]
Then the integral is
[tex]\displaystyle \int\left(x-\sqrt{x^2-1}\right)\,\mathrm dx = \dfrac12x^2 - \int\sqrt{x^2-1}\,\mathrm dx[/tex]
For the remaining integral, substitute x = sec(t ) and dx = sec(t ) tan(t ) dt. Then over an appropriate domain, we have
[tex]\displaystyle\int\sqrt{x^2-1}\,\mathrm dx = \int\sec(t)\tan(t)\sqrt{\sec^2(t)-1}\,\mathrm dt = \int\sec(t)\tan^2(t)\,\mathrm dt[/tex]
Integrate by parts, taking
u = tan(t ) ==> du = sec²(t ) dt
dv = sec(t ) tan(t ) dt ==> v = sec(t )
Then
[tex]\displaystyle\int\sec(t)\tan^2(t)\,\mathrm dt = \sec(t)\tan(t) - \int\sec^3(t)\,\mathrm dt[/tex]
Now for *this* remaining integral, integrate by parts again, taking
u = sec(t ) ==> du = sec(t ) tan(t ) dt
dv = sec²(t ) dt ==> v = tan(t )
so that
[tex]\displaystyle\int\sec^3(t)\,\mathrm dt = \sec(t)\tan(t) - \int\sec(t)\tan^2(t)\,\mathrm dt \\\\ \int\sec^3(t)\,\mathrm dt = \sec(t)\tan(t) - \int\sec(t)(\sec^2(t)-1)\,\mathrm dt \\\\ \int\sec^3(t)\,\mathrm dt = \sec(t)\tan(t) - \int\sec^3(t)\,\mathrm dt + \int\sec(t)\,\mathrm dt \\\\ \int\sec^3(t)\,\mathrm dt = \frac12\sec(t)\tan(t)+\frac12\int\sec(t)\,\mathrm dt \\\\ \int\sec^3(t)\,\mathrm dt = \frac12\sec(t)\tan(t) + \frac12\ln\left|\sec(t)+\tan(t)\right| + C[/tex]
To summarize, if I denotes the original integral, we have
[tex]\displaystyle I = \frac12x^2 - \int\sqrt{x^2-1}\,\mathrm dx \\\\ I = \frac12x^2 - \int\sec(t)\tan^2(t)\,\mathrm dt \\\\ I = \frac12x^2 - \sec(t)\tan(t) + \int\sec^3(t)\,\mathrm dt \\\\ I = \frac12x^2 - \sec(t)\tan(t) + \frac12\sec(t)\tan(t) + \frac12\ln\left|\sec(t)+\tan(t)\right| + C \\\\ I = \frac12x^2 - \frac12\sec(t)\tan(t) + \frac12\ln\left|\sec(t)+\tan(t)\right| + C[/tex]
Putting everything back in terms of x, we have
sec(t ) = x
tan(t ) = √(x ² - 1)
so that
[tex]\displaystyle I = \boxed{\frac12x^2 - \frac12x\sqrt{x^2-1}+\frac12\ln\left|x+\sqrt{x^2-1}\right|+C}[/tex]
Help help help help help
Answer: 0 and 4
Step-by-step explanation:
The following are the ages (years) of 5 people in a room: 16, 25, 23, 12, 17 A person enters the room. The mean age of the 6 people is now 20. What is the age of the person who entered the room?
Answer: 27
Step-by-step explanation:
Set the age of the person who entered the room as x[tex]Mean=\frac{16 + 25 + 23 + 12 + 17 + x}{6}=20 \\16 + 25 + 23 + 12 + 17 + x=20(6)\\93+x=120\\x=120-93=27[/tex]
Answer:
27 years old
Step-by-step explanation:
There are originally 5 people in the room.
Their ages are: 16, 25, 23, 12, 17
The sum of their ages is: 93
One person enters the room. That person's age is unknown, so we call it x.
The sum of the ages of the 6 people is:
x + 93
There are 6 people in the room now, so the mean age is (total age divided by number of people):
(x + 93)/6
We are told the mean age is 20.
(x + 93)/6 = 20
x + 93 = 120
x = 27
Answer: 27 years old
I need help with question 4!!!! PLEASE HELP ME!!
Answer:
4 cm
Step-by-step explanation:
V = πr²h
or, 36π = π(3)²×h
or, 36 = 9h
or, 4 = h
So the height is 4 cm
Answered by GAUTHMATH
7. In which step does a mistake first occur?
8 + 2 + (3 X 3 -2)
Step 1: 8 +2 + (3 x 1)
Step 2: 8 +2 + 3
Step 3: 4 + 3
Step 4: 7
Answer:
17
Step-by-step explanation:
8+2+(3×3-2)=8+2+(9-2)=8+2+7=17
mistake in the first step
firstly we do × and ÷
then + and -
Solve the right triangle given that mZA = 30°, mZC = 90°, and a = 15. Round
your result to one decimal place,
Answer:23
Step-by-step explanation:
Can someone help pls
The diameter of a $1 coin is 26.5 mm. Find the area of one side of the coin. Round to the nearest hundredth.
The area of one side of the coin is 41.605 mm².
Given that, the diameter of a $1 coin is 26.5 mm.
We need to find the area of one side of the coin.
What is the area of a circle formula?The area of a circle formula is A=πr².
Now, radius=26.5/2=13.25 mm.
Area of a coin=3.14×13.25=41.605 mm².
Therefore, the area of one side of the coin is 41.605 mm².
To learn more about the area of the circle visit:
https://brainly.com/question/11952845.
#SPJ2
In the diagram, which two angles are corresponding angles with angle 12?
Answer:
∠8 and ∠16.
Step-by-step explanation:
Given the diagram we have to find the angles which are corresponding angles with ∠12. Those angles which are on the same side of traversal called corresponding angles. By definition of corresponding angles the angles which are corresponding to ∠12 are ∠8 and ∠16.
30 points please help
Find the volume of the pyramid.
76.34 ft3
458.06 ft3
916.11 ft3
305.37 ft3
Answer:
With the formula of lwh/3 the answer is 305.37
Step-by-step explanation:
l×w×h /3 =305.37
Answer:
916.11 ft³
Step-by-step explanation:
(9×6)×7.83/2×13/3
= 211.41×13/3
= 916.11 ft³
Answered by GAUTHMATH
What is the slope of a line perpendicular to a line that contains the points (-5, 4) and (-2, 4)?
Select the best answer from the choices provided.
A.
0
B.
no slope
C.
8/3
D.
-3/8
maths question please help !! thank u :)
Answer:
1350m
Step-by-step explanation:
Let the distance ran by Denise, Farah and Elaine be D, F and E meters respectively.
From the given information,
D= ⅔(E +F) -----(1)
E= ½(D +F) -----(2)
Let's get rid of the fraction so the equations are much easier to work with.
From (1):
3D= 2(E +F) (Multiply both sides by 3)
3D= 2E +2F -----(3) (Expand)
From (2):
2E= D +F -----(4)
Substitute (4) into (3):
3D= D +F +2F
3D -D= 3F
2D= 3F
Given that Farah ran 360m, F= 360.
2D= 3(360)
2D= 1080
D= 1080 ÷2
D= 540
2E= D +F
2E= 540 +360
2E= 900
E= 900 ÷2
E= 450
Total distance the 3 girls ran
= D +F +E
= 540 +360 +450
= 1350m
Alternatively, you could start by substituting F= 360 to equations (1) and (2).
The report "Digital Democracy Surveyt describes a large national survey. In a representative sample of Americans ages 14 to 18 years, 45% indicated that they usually use social media while watching
TV. Suppose that the sample size was 760.
(a) Is there convincing evidence that less than half of Americans ages 14 to 18 years usually use social media while watching TV? Use a significance level of 0.05.
State the appropriate null and alternative hypotheses.
O Hop 0.5 versus Hp > 0.5
O Moip 0.5 versus H: = 0.5
O Hp = 0.5 versus HP < 0.5
OH:P < 0.5 versus , p > 0.5
OHOD 0.5 versus H: 0.5
Find the test statistic and P-value. (Use a table or technology. Round your test statistic to two decimal places and your p-value to four decimal places.)
ZE
P-value
Answer:
H0 : p = 0.5 versus H1: P < 0.5
Test statistic = - 2.76
Pvalue = 0.0029
Step-by-step explanation:
The hypothesis :
We are to test if less Than half of the American population within the of 14 to 18 years usually use social media while watching TV :
Hence, population proportion, p = 0.5
H0: p = 0.5
H1: P < 0.5
Sample size, n = 760
Sample proportion, Phat = 45% = 0.45
The test statistic, Z :
Z = (Phat - P) / √[(P(1 - P)) /n]
Z = (0.45 - 0.5) / √[(0.5(1 - 0.5)) /760]
Z = - 0.05 / √0.0003289
Z = - 2.7568 ; Z = - 2.76 (2 decimal places)
The Pvalue :
Using technology :
Pvalue from Zscore calculator ; Pvalue = 0.0029
Decision region :
Reject H0 if Pvalue < α
α = 0.05
Since 0.0029 < 0.05 ; we reject the Null and conclude that less than half of American within age 14 to 18 years usually use social media while watching TV.
Please help and show work. 60 points
Answer:
18.
Domain: X E \{-3,2}
Y-Intercept: 1/2
X-Intercept: 3
19.
Domain: (I think it's none)
Y-Intercept: -2
X-Intercept: 2
20.
Domain: X E R\ {-3,1}
y-INTERCEPT: 2/3
x-INTERCEPT: -1
Step-by-step explanation:
First you to find the worksheet and download it
plase I need help
Answer:
a) The horizontal asymptote is y = 0
The y-intercept is (0, 9)
b) The horizontal asymptote is y = 0
The y-intercept is (0, 5)
c) The horizontal asymptote is y = 3
The y-intercept is (0, 4)
d) The horizontal asymptote is y = 3
The y-intercept is (0, 4)
e) The horizontal asymptote is y = -1
The y-intercept is (0, 7)
The x-intercept is (-3, 0)
f) The asymptote is y = 2
The y-intercept is (0, 6)
Step-by-step explanation:
a) f(x) = [tex]3^{x + 2}[/tex]
The asymptote is given as x → -∞, f(x) = [tex]3^{x + 2}[/tex] → 0
∴ The horizontal asymptote is f(x) = y = 0
The y-intercept is given when x = 0, we get;
f(x) = [tex]3^{0 + 2}[/tex] = 9
The y-intercept is f(x) = (0, 9)
b) f(x) = [tex]5^{1 - x}[/tex]
The asymptote is fx) = 0 as x → ∞
The asymptote is y = 0
Similar to question (1) above, the y-intercept is f(x) = [tex]5^{1 - 0}[/tex] = 5
The y-intercept is (0, 5)
c) f(x) = 3ˣ + 3
The asymptote is 3ˣ → 0 and f(x) → 3 as x → ∞
The asymptote is y = 3
The y-intercept is f(x) = 3⁰ + 3= 4
The y-intercept is (0, 4)
d) f(x) = 6⁻ˣ + 3
The asymptote is 6⁻ˣ → 0 and f(x) → 3 as x → ∞
The horizontal asymptote is y = 3
The y-intercept is f(x) = 6⁻⁰ + 3 = 4
The y-intercept is (0, 4)
e) f(x) = [tex]2^{x + 3}[/tex] - 1
The asymptote is [tex]2^{x + 3}[/tex] → 0 and f(x) → -1 as x → -∞
The horizontal asymptote is y = -1
The y-intercept is f(x) = [tex]2^{0 + 3}[/tex] - 1 = 7
The y-intercept is (0, 7)
When f(x) = 0, [tex]2^{x + 3}[/tex] - 1 = 0
[tex]2^{x + 3}[/tex] = 1
x + 3 = 0, x = -3
The x-intercept is (-3, 0)
f) [tex]f(x) = \left (\dfrac{1}{2} \right)^{x - 2} + 2[/tex]
The asymptote is [tex]\left (\dfrac{1}{2} \right)^{x - 2}[/tex] → 0 and f(x) → 2 as x → ∞
The asymptote is y = 2
The y-intercept is f(x) = [tex]f(0) = \left (\dfrac{1}{2} \right)^{0 - 2} + 2 = 6[/tex]
The y-intercept is (0, 6)
5(15-7y/3)+2y=-4
solve for y and plz show steps
Answer:
75 - 35y / 3 + 2y = -4
( 75 - 35y + 6y ) / 3 = -4 [ Taking LCM ]
( 75 - 29y ) / 3 = -4
75 - 29y = -12
29y = 75+12
29y = 87
y = 3
hope that helps ✌
what is the equation of the line that is parallel to the given line and passes through the point (-3,2)? no links.
Answer:
D) 4x +3y = -6
Step-by-step explanation:
paralell lines so m1 and m2 are equal
m = (3 +1 )/ (0 - 3 )
m = -4/ 3
y -2 = -4/3 (x +3)
y =-4x/3 -2
3y = -4x -6
4x +3y = -6
Select the correct answer.
Which statement best describes the solution to this system of equations?
3x + y= 17
x + 2y = 49
Ο Α.
It has no solution.
B.
It has infinite solutions.
O c.
It has a single solution: x = 15, y= 17.
OD.
It has a single solution: x = -3, y = 26.
Find y when = 22, if y varies directly as x,
and y = 39 when x = 7.
Answer:
let,
x=ky
y=39 when x=7 so,
7=39k
or, k=7/39
now, when x=22
22=7y/39
or, y=39×22/7
or, y=858/7
or, y=122.57 (rounded to the nearest hundredth)
Solve the equation.
3х - 6 = 6x - 9
Answer:
x=1
Step-by-step explanation:
3х - 6 = 6x - 9
Subtract 3x from each side
3х-3x - 6 = 6x-3x - 9
-6 = 3x-9
Add 9 to each side
-6+9 = 3x-9+9
3 =3x
Divide by 3
3/3 = 3x/3
1 =x
Answer:
3x-6=6x-9
3x-6x=-9+6
-3x=-3
-3x÷-3=-3÷-3
x=1
Un deportista de natación necesita mejorar su estilo de clavado, por lo que ha grabado con una cámara ubicada bajo el agua cada uno de sus movimientos hasta obtener el mejor clavado. Los resultados del clavado esperado fueron descritos en una ecuación de la profundidad h en función de la distancia x, a la que vuelve a emerger, donde todas las distancias están en metros, así: h(x) = 6x2+6x
Si se toma el nivel del agua de la piscina como el eje de las abscisas, determine la profundidad máxima, en metros, que alcanzó en su clavado.
ayuda es para mañana
Answer:yes
Step-by-step explanation:
Yes
GH bisects LM at K. LK = 5x+2 and LM = 64 Find x
Answer:
x = 6
Step-by-step explanation:
Since GH bisects LM at K , then
LK = [tex]\frac{1}{2}[/tex] LM , that is
5x + 2 = [tex]\frac{1}{2}[/tex] × 64 = 32 ( subtract 2 from both sides )
5x = 30 ( divide both sides by 5 )
x = 6
The value of x is 6.
Here,
GH bisects LM at K.
LK = 5x+2 and LM = 64
We have to find the value of x.
What is Bisection in line?
Bisecting a line is cutting a line exactly in half. It may also be referred to as constructing a perpendicular bisector as the line you are drawing will be at a right angle to the original line.
Now,
GH bisects LM at K.
LK + KM = LM
2 LK = LM
2 ( 5x + 2 ) = 64
5x + 2 = 32
5x = 30
x = 6
Hence, The value of x is 6.
Learn more about the Bisection of line visit:
https://brainly.in/question/10606306
#SPJ2
Please hurry I will mark you brainliest
Answer:
number of pennies = 54
Step-by-step explanation:
(4,60) ; (6, 65)
Find the slope
Slope = [tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]
[tex]=\frac{65-60}{6-4}\\\\=\frac{5}{2}[/tex]
m = 5/2 and (4,60)
Equation of the line: y - y1 = m (x -x1)
[tex]y - 60 = \frac{5}{2}(x -4)\\\\y - 60 = \frac{5}{2}x-\frac{5}{2}*4\\\\y- 60 = \frac{5}{2}x-10\\\\y =\frac{5}{2}x-10+60\\\\y=\frac{5}{2}x + 50[/tex]
x-----> determine the number of pennies and y determines the mass of pennies.
Here mass (y -value) is given as 185. We have find the corresponding x-value. So plugin y = 185 in the above equation,
[tex]185 = \frac{5}{2}x+50\\\\185-50=\frac{5}{2}x\\\\135=\frac{5}{2}x\\\\135*\frac{2}{5}=x\\\\27*2=x[/tex]
x = 54
Please hurry I will mark you brainliest
What is the value of p so that the line passing through (6, 2) and (9, p) has a slope of -1?
Answer:
-1
Step-by-step explanation:
im pretty sure its right
sry if it not good luck!!
A(x) = 7 – 4x , A(-1) =
Answer:
7-4*(-1)
7-4*(-1)7+4
7-4*(-1)7+411
Step-by-step explanation:
hope it will help u
Answer:
A(- 1) = 11
Step-by-step explanation:
Substitute x = - 1 into A(x) , that is
A(- 1) = 7 - 4(- 1) = 7 + 4 = 11
