Find the slope of the line passing through the pair of points or state that the slope is undefined. Then indicate whether the line
through the points rises, falls, is horizontal, or is vertical
(2,9) and (-2,9)

The value of g across from angle G is 5feet

According to sine rule

[tex]\frac{e}{sinE}=\frac{f}{sinF}=\frac{g}{sinG}[/tex]

Given the following

∠G = 45°

∠F = 82°

f = 7feet

Required

side g

Substitute the given values into the formula

[tex]\frac{f}{sinF}=\frac{g}{sinG}\\ \frac{7}{sin82}=\frac{g}{sin45}\\\frac{7}{0.9903}=\frac{g}{0.7071}\\7.0686=\frac{g}{0.7071}\\g=7.0686*0.7071\\g=4.998\\g\approx5ft[/tex]

Hence the value of g across from angle G is 5feet

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The length of the line segment EF ([tex]g[/tex]) is approximately 5 feet.

Let be [tex]EFG[/tex] a Triangle, whose expression derived from the Law of Sines is described below:

[tex]\frac{e}{\sin E} = \frac{f}{\sin F} = \frac{g}{\sin G}[/tex] (1)

Where:

[tex]e[/tex] - Measure of the line segment FG, in feet.

[tex]f[/tex] - Measure of the line segment EG, in feet.

[tex]g[/tex] - Measure of the line segment EF, in feet.

[tex]E[/tex] - Angle at vertex E, in sexagesimal degrees.

[tex]F[/tex] - Angle at vertex F, in sexagesimal degrees.

[tex]G[/tex] - Angle at vertex G, in sexagesimal degrees.

We can determine a missing length, by knowing the length of a neighboring side and two consecutive angles. If we know that [tex]f = 7\,ft[/tex], [tex]G = 45^{\circ}[/tex] and [tex]F = 82^{\circ}[/tex], then the measure of the line segment EF is:

[tex]g = f\cdot \left(\frac{\sin G}{\sin F} \right)[/tex] (2)

[tex]g = (7\,ft)\cdot \left(\frac{\sin 45^{\circ}}{\sin 82^{\circ}} \right)[/tex]

[tex]g\approx 4.998\,ft[/tex]

[tex]g \approx 5\,ft[/tex]

The length of the line segment EF ([tex]g[/tex]) is approximately 5 feet.

Answer:

Step-by-step explanation:

Any alteration to the x value means that the function will move right. There are no exceptions to this that  I can think of.

Answer:

56

Step-by-step explanation:

A=(3*4)+(4*(4+3+4))=56

Answer:

B is correct .trust me

Step-by-step explanation:

Answer:

Line A does not intersect line B.

Step-by-step explanation:

line A comes close, but does not touch, intersect, or overlap line A. hope this helps, please correct me if i am wrong.

Answer:

5,20,80,320

Step-by-step explanation:

a1 = 5

an = 4 an-1

Let n = 2

a2 = 4 * a1 = 4*5 = 20

Let n = 3

a3 = 4 * a2 = 4*20 = 80

Let n = 4

a4 = 4 * a3 = 4*80 = 320

Answer:

8 of the 11

Step-by-step explanation:

4+4=8 of the 11

Part of oranges usef from the orange packet used on 1st day = 4/11

Part of oranges used from the orange packet used on 2nd day = 4/11

Total part of oranges used from the orange packet

= (4/11) + (4/11)

= 8/11

So, Sipho's dad used 8 elevenths of the oranges.

Answer:

65 m

Step-by-step explanation:

u = 6 m/s

v = 20 m/s

t = 5 s

[tex]s=\frac{1}{2} (6+20)5[/tex]

[tex]s=\frac{1}{2} (26)5[/tex]

[tex]s=(13)5[/tex]

[tex]s=65[/tex]

Hey there!

1/2(6 + 20)(5)

= 1/2 (26)(5)

1/2(26) = 13

= 13(5)

= 65

Therefore, your answer is most likely: 65m

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

[tex] \begin{cases} \\ \large\bf{\green{ \implies}} \tt \: - \: \frac{1}{2} \: m \: = \: - 9 \\ \\ \large\bf{\green{ \implies}} \tt \: - \frac{1 \: m}{2} \: = \: - 9 \\ \\ \large\bf{\green{ \implies}} \tt \: - 1m \: = \: - 9 \: \times \: 2 \\ \\ \large\bf{\green{ \implies}} \tt \: - 1m \: = \: - 18 \\ \\ \large\bf{\green{ \implies}} \tt \: m \: = \: \frac{ \cancel- 18}{ \cancel - 1} \\ \\ \large\bf{\green{ \implies}} \tt \: m \: = \: \frac{18}{1} \\ \\ \large\bf{\green{ \implies}} \tt \: m \: = \: 18 \: \\ \end{cases}[/tex]

Find the intersection of the two planes. Do this by solving for z in terms of x and y ; then solve for y in terms of x ; then again for z but only in terms of x.

-4x + 2y - z = 1   ==>   z = -4x + 2y - 1

3x - 2y + 2z = 1   ==>   z = (1 - 3x + 2y)/2

==>   -4x + 2y - 1 = (1 - 3x + 2y)/2

==>   -8x + 4y - 2 = 1 - 3x + 2y

==>   -5x + 2y = 3

==>   y = (3 + 5x)/2

==>   z = -4x + 2 (3 + 5x)/2 - 1 = x + 2

So if we take x = t, the line of intersection is parameterized by

r(t) = ⟨t, (3 + 5t )/2, 2 + t⟩

Just to not have to work with fractions, scale this by a factor of 2, so that

r(t) = ⟨2t, 3 + 5t, 4 + 2t⟩

(a) The tangent vector to r(t) is parallel to this line, so you can use

v = dr/dt = d/dt ⟨2t, 3 + 5t, 4 + 2t⟩ = ⟨2, 5, 2⟩

or any scalar multiple of this.

(b) (-1, -1, 1) indeed lies in both planes. Plug in x = -1, y = 1, and z = 1 to both plane equations to see this for yourself. We already found the parameterization for the intersection,

r(t) = ⟨2t, 3 + 5t, 4 + 2t⟩

Answer:

554.7

Step-by-step explanation:

The pay=25.8*14+(25.8)*5*1.5=554.7

Answer:

Not a subspace

Step-by-step explanation:

(4,0,0) and (0,4,0) are vectors in R3 with zero or one entries being nonzero, but their sum, (4,4,0) has two nonzero entries.

Answer: sqrt 3V/pih = r

Step-by-step explanation:

3V = (pi r^2h)3

3V = pi r^2 h

3V/pih = r^2

Sqrt (3V/pi h) = r

Answer:

A. [tex]\frac{5}{13}[/tex]

Step-by-step explanation:

Hi there!

We are given right triangle PQR, with PR=5, RQ=12, and PQ=13

We want to find the value of sin(Q)

Let's first recall that sine is [tex]\frac{opposite}{hypotenuse}[/tex]

In reference to angle Q, PR is the opposite side, RQ is the adjacent side, and PQ is the hypotenuse

So that means that sin(Q) would be [tex]\frac{PR}{PQ}[/tex]

Substituting the values of PR and PQ gives sin(Q) as [tex]\frac{5}{13}[/tex], which is A

Hope this helps!

Answer:

The AP is 1, 11/2, 10, 29/2, 19, ....

Step-by-step explanation:

Let the first term be a and d be the common difference of the arithmetic progression.

ATQ, a+2d+a+6d=38, 2a+8d=38 and a+8d=37. Solving this, we will get a=1 and d=9/2. The AP is 1, 11/2, 10, 29/2, 19, ....

Answer:

Hello,

Are you still alive ?

Step-by-step explanation:

a)

c=k*b (c varies directly as b)

6=k*2 ==> k=3 ( c = 6 when b = 2.)

[tex]\boxed{c=3*b }\\[/tex]

b)

b=14 ==> c=3*14=42

c)

c=39

[tex]b=\dfrac{c}{3} =\dfrac{39}{3} =13\\[/tex]

Answer:

D) 1

Step-by-step explanation:

using the distributive property we have ax+a+bx-b-2=0. because the equation is true for all real x, ax=-bx. this means a-b-2=0 and a=-b. a-b-2=0 becomes a=b+2. then we substitute a for -b and get -b=b+2 which becomes 2b=-2 so b=-1. since a=-b, a=1

Answer:

167.64 cm

Step-by-step explanation:

I dont kno how to work it out

Answer:

11 weeks.

Step-by-step explanation:

227-106=121

121 divided by 11 = no. of weeks

Therefore it takes her 11 weeks.

Answer:

It will take 11 weeks

Step-by-step explanation:

11 times 11 is 121.

121 plus 106 is 227

which is the exact number the bike costs

Answer:

Step-by-step explanation:

Mean: sum of terms/ number of terms

4 + 2 + 3 + 1 + 1 + 5  = 16

Numbr of terms = 6

16/6 = 2.66

Answered by g a u t h m a th

Answer:

2 2/3

Step-by-step explanation:

The mean is the average of the values

The values on the graph are 4, 2, 3, 1, 1, and 5

Average is sum/number of values

4+2+3+1+1+5=16

16/6=2 2/3

Answer:

[tex] 16 {x}^{4} {y}^{6} [/tex]

Step-by-step explanation:

[tex](4 {x}^{2} {y}^{3} {)}^{2} [/tex]

➡️ [tex] {4}^{2} \times ( {x}^{2} {)}^{2} \times ( {y}^{3} {)}^{2} [/tex]

➡️ [tex] = 16 {x}^{4} {y}^{6} [/tex] ✅

Answer:

B = A/5h - b; You could use

B = (A - 5hb)/5h  This just puts everything over a common denominator.

Step-by-step explanation:

A = 5h (B + b)          Divide both sides by 5h

A/5h = B + b             Subtract b from both sides.

A/5h - b = B

9514 1404 393

Answer:

  (i) x° = 70°, y° = 20°

  (ii) ∠BAC ≈ 50.2°

  (iii) 120

  (iv) 300

Step-by-step explanation:

(i) Angle x° is congruent with the one marked 70°, as they are "alternate interior angles" with respect to the parallel north-south lines and transversal AB.

  x = 70

The angle marked y° is the supplement to the one marked 160°.

  y = 20

__

(ii) The triangle interior angle at B is x° +y° = 70° +20° = 90°, so triangle ABC is a right triangle. With respect to angle BAC, side BA is adjacent, and side BC is opposite. Then ...

  tan(∠BAC) = BC/BA = 120/100 = 1.2

  ∠BAC = arctan(1.2) ≈ 50.2°

__

(iii) The bearing of C from A is the sum of the bearing of B from A and angle BAC.

  bearing of C = 70° +50.2° = 120.2°

The three-digit bearing of C from A is 120.

__

(iv) The bearing of A from C is 180 added to the bearing of C from A:

  120 +180 = 300

The three-digit bearing of A from C is 300.

Answer:

= 4

Step-by-step explanation:

first lets find the value of x in 3x+2=5/9

3x+2=5/9

3x = [tex]\frac{5}{9}[/tex] -2

3x = [tex]\frac{3}{9}[/tex]

3x = [tex]\frac{1}{2}[/tex]

x = [tex]\frac{1}{2 * 3\\ }[/tex]

x = [tex]\frac{1}{6}[/tex]

[tex]\frac{1}{6}[/tex] can also be written as [tex]6^{-1}[/tex]

−3x+8

-3 ([tex]\frac{1}{6}[/tex]) +8

[tex]\frac{-3}{6}[/tex] +8

= 4

Answer:

y=2

Step-by-step explanation:

A horizontal line has a slope of zero so the x term is zero

y = mx+b

y = b

y must equal a constant

Step-by-step explanation:

x=72

63+45+x=180

[tex]108 + x = 180[/tex]

[tex]x = 72[/tex]

Answer:

I believe it is A

Step-by-step explanation:

Answer:

Step-by-step explanation: