Find the radius of a circle with a circumference of 36 Inches

The vertex can be written as:

(-b/2a, b^2/(4*a) - b^2/2a + c)

For a general parabola:

y = a*x^2 + b*x + c

We can write the vertex as:

(h, k)

The x-value of the vertex is the value of the axis of symmetry.

Then we have:

h = x = -b/2a

Now we need to find the y-value of the vertex.

To do that, we just replace the variable "x" by the x-value of the vertex in our equation, so we get:

k = y = a*(-b/2a)^2 + b*(-b/2a) + c

k = b^2/(4*a) - b^2/2a + c

Then the coordinates of the vertex are:

(h, k) = (-b/2a, b^2/(4*a) - b^2/2a + c)

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Answer:

1.33

Step-by-step explanation:

62 can only be subtracted from 82 once. So 82.46-62 would be 20.46. Since you can't subtract anymore you put a decimal point. 62x3=186 and 20.46-186=1.86 and you can subtract 186-186=0.

Answer:

100.48

Step-by-step explanation:

The volume of a cylinder is given by

V = pi r^2 h where r is the radius and h is the height

V = 3.14 ( 2)^2 * 8

V = 3.14 (4)(8)

V = 100.48

Answer:

Step-by-step explanation:

10/13

Answer: 10/13

Explanation:

= 7/13 + 3/13

Its like fraction

= 10/13

Its already in lowest terms

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Answer:

Option B, parallel

Step-by-step explanation:

for the first line,

[3-(-1)]/[11-9]

= 4/2 = 2

for the second line,

(0-(-4))/(-4-(-6))

= 4/2 = 2

Both has same slope so they're parallel but it doesn't seem like they are the same line

Answer:

56 half dollars

Step-by-step explanation:

A half dollar is 1/2 of a dollar so divide 28 by 1/2

28 / 1/2

Copy dot flip

28 * 2/1

56

56 half dollars

Answer:

0

Step-by-step explanation:

The slope of the line is m=(9-9)/(-2-5)=0/-7=0

[tex] \begin{cases}\large\bf{\green{ \implies}} \tt \: \frac{6}{5} \: k \: = \: 12 \\ \\ \large\bf{\green{ \implies}} \tt \: \frac{6k}{5} \: = \: 12 \\ \\ \large\bf{\green{ \implies}} \tt \: 6k \: = \: 12 \: \times \: 5 \\ \\ \large\bf{\green{ \implies}} \tt \: 6k \: = \: 60 \\ \\ \large\bf{\green{ \implies}} \tt \: k \: = \: \cancel\frac{60}{6} \\ \\ \large\bf{\green{ \implies}} \tt \: k \: = \: 10 \end{cases}[/tex]

Answer:

k = -10

Step-by-step explanation:

In order to solve for k, we need to isolate the variable. This means we need k to be on one side of the equation by itself.

We are given:

[tex]-\frac{6}{5}k=12[/tex]

The first thing I would do is multiply both sides of the equation by 5:

[tex](5)-\frac{6}{5}k=12(5)[/tex]

This leaves us with:

[tex]-6k=60[/tex]

Now, in order to get k by itself, we need to divide by -6 on both sides:

[tex]\frac{-6k}{-6}=\frac{60}{-6}[/tex]

Therefore:

[tex]k=-10[/tex]

Answer:

4th option

Step-by-step explanation:

The relationship is linear,

putting the value of x in the right side of the equation of option 4, you'll get the value of the left side

putting, x=1

y+4=-1/2(x-1)

y=-1/2(1-1)-4

y=-4

putting, x=7

y+4=-1/2(7-1)

y=-1/2(6)-4

y=-6/2-4

y=-3-4

y=-7

9514 1404 393

Answer:

  see below

Step-by-step explanation:

  [tex]\text{A. point: }X\\\\\text{B. ray through Y: }\overrightarrow{XY}\\\\\text{C. line through Z: }\overleftrightarrow{XZ}\\\\\text{D. plane: plane } XYZ[/tex]

__

Additional comment

When you don't have the benefit of typesetting, you can refer to the geometry by name: ray XY, line XZ,

3.99-1 = 2.99 they lose 2.99 per burger

Multiply the number of people by the amount lost per burger:

2.99 x 86,047 = 257,280.53

They would lose: $257,280.53

Answer:

86043.01

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

since

cos(2x) = 1 - 2×sin²(x)

and for x near 0, sin(x) is very similar to x.

Answer:

B

Step-by-step explanation:

The function given is f(n) = n-3. Plug in n=0 and you will get an output - 3. Plug in n=2 and you will get an output - 1. Hence table B is the answer .

Answer:

spread over a wide range

cannot be evaded

Everyone can contribute

convenient

Step-by-step explanation:

Answer:

Step-by-step explanation:

(17). g(x) = x³ + 4x

f(x) = 4x + 1

( f × g )( x ) = ( x³ + 4x )( 4x + 1 ) = 4 [tex]x^{4}[/tex] + x³ + 16x² + 4x

(19). f(t) = 4t - 4

g(t) = t - 2

( 4f + 3g )( t ) = 4(4t - 4) + 3(t - 2) = 16t - 16 + 3t - 6 = 19t - 22

(21). h(t) = t + 3

g(t) = 4t + 1

h(t - 2) + g(t - 2) = ( t - 2 ) + 3 + 4( t - 2 ) + 1 = t + 4t - 2 + 3 - 8 + 1 = 5t - 6

Split up the boundary of C (which I denote ∂C throughout) into the parabolic segment from (1, 1) to (0, 0) (the part corresponding to y = x ²), and the line segment from (1, 1) to (0, 0) (the part of ∂C on the line y = x).

Parameterize these pieces respectively by

r(t) = x(t) i + y(t) j = t i + t ² j

and

s(t) = x(t) i + y(t) j = (1 - t ) i + (1 - t ) j

both with 0 ≤ t ≤ 1.

The circulation of F around ∂C is given by the line integral with respect to arc length,

[tex]\displaystyle \int_{\partial C}\mathbf F\cdot\mathbf T \,\mathrm ds[/tex]

where T denotes the tangent vector to ∂C. Split up the integral over each piece of ∂C :

• on the parabolic segment, we have

T = dr/dt = i + 2t j

• on the line segment,

T = ds/dt = -i - j

Then the circulation is

[tex]\displaystyle \int_{\partial C}\mathbf F\cdot\mathbf T\,\mathrm ds = \int_0^1 (7t^3\,\mathbf i+5t^4\,\mathbf j)\cdot(\mathbf i+2t\,\mathbf j)\,\mathrm dt + \int_0^1 (7(1-t)^2\,\mathbf i+5(1-t)^2\,\mathbf j)\cdot(-\mathbf i-\mathbf j)\,\mathrm dt \\\\ = \int_0^1 (7t^3+10t^5)\,\mathrm dt - 12 \int_0^1 (1-t)^2\,\mathrm dt =\boxed{-\frac7{12}}[/tex]

Alternatively, we can use Green's theorem to compute the circulation, as

[tex]\displaystyle\int_{\partial C}\mathbf F\cdot\mathbf T\,\mathrm ds = \iint_C\frac{\partial(5y^2)}{\partial x} - \frac{\partial(7xy)}{\partial y}\,\mathrm dx\,\mathrm dy \\\\ = -7\int_0^1\int_{x^2}^x x\,\mathrm dx \\\\ = -7\int_0^1 xy\bigg|_{y=x^2}^{y=x}\,\mathrm dx \\\\ =-7\int_0^1(x^2-x^3)\,\mathrm dx = -\frac7{12}[/tex]

The flux of F across ∂C is

[tex]\displaystyle \int_{\partial C}\mathbf F\cdot\mathbf N \,\mathrm ds[/tex]

where N is the normal vector to ∂C. While T = x'(t) i + y'(t) j, the normal vector is N = y'(t) i - x'(t) j.

• on the parabolic segment,

N = 2t i - j

• on the line segment,

N = - i + j

So the flux is

[tex]\displaystyle \int_{\partial C}\mathbf F\cdot\mathbf N\,\mathrm ds = \int_0^1 (7t^3\,\mathbf i+5t^4\,\mathbf j)\cdot(2t\,\mathbf i-\mathbf j)\,\mathrm dt + \int_0^1 (7(1-t)^2\,\mathbf i+5(1-t)^2\,\mathbf j)\cdot(-\mathbf i+\mathbf j)\,\mathrm dt \\\\ = \int_0^1 (14t^4-5t^4)\,\mathrm dt - 2 \int_0^1 (1-t)^2\,\mathrm dt =\boxed{\frac{17}{15}}[/tex]

Answer:

C

Step-by-step explanation:

Let the first term be a and the common ratio be r.

ATQ, ar^4=24 and ar^6=144, r=sqrt(6) and a=24/(sqrt(6))^2=24/36=2/3

Answer:

12/5

Step-by-step explanation:

since we are dealing with the angle at Z, we consider Z also to be the center of a circle.

then 10 is the radius of this circle.

24 is tan Z in this circle with radius 10.

tan Z in the standard circle with radius 1 is simply 1/10 of the tan Z in the circle with radius 10.

so, tan Z = 24/10 = 12/5

Step-by-step explanation:

slope of given line:

m=2

as lines are parallel so slopes will be equal:

required slope m=2

By using point slope form:

y-y1=m(x-x1)

y-5=2(x-5)

y-5=2x-10

y=2x-10+5

y=2x-5

Note:if you need to ask any question please let me know.

[tex]\\ \sf\longmapsto \left\{x|x \epsilon I,x\leqslant 3\right\}[/tex]

In listing

[tex]\\ \sf\longmapsto \left\{\dots,0,1,2,3\right\}[/tex]

Answer:

Option E, 4, 4√3

Step-by-step explanation:

s = 4

q = 4√3

Answer:

[tex]10^{-3} \times10^{k} =10^{-3} =\frac{1}{10^{3} }[/tex]

[tex]10^{-3+1+k} =10^{-3}[/tex]

[tex]10^{-2+k} =10^{-3}[/tex]

Therefore, [tex]-2+k=-3[/tex]

[tex]k=-3+2[/tex]

[tex]k=-1[/tex]

OAmalOHopeO

Recall that a ⇒ b   ⇔   ¬a ∨ b. So we can write

q ⇒ (p ∧ r )   ⇔   ¬q ∨ (p ∧ r )

Then the negation of this would be, for instance,

¬(¬q ∨ (p ∧ r ))   ⇔   ¬(¬q) ∧ ¬(p ∧ r )

…   ⇔   q ∧ (¬p ∨ ¬r )

…   ⇔   (¬p ∧ q) ∨ (q ∧ ¬r )

…   ⇔   ¬(p ∨ ¬q) ∨ (q ∧ ¬r )

…   ⇔   (p ∨ ¬q) ⇒ (q ∧ ¬r )

It's impossible to tell what kind of statement your program is expecting, but since there are 5 slots available, my money would be on q ∧ (¬p ∨ ¬r ), so long as ¬p and ¬r are options.

Answer:

Step-by-step explanation:

[tex]\boxed{\sf a(b+c)=ab+ac}[/tex]

[tex]\\ \sf\longmapsto 2396\times 78 +2396\times 22[/tex]

[tex]\\ \sf\longmapsto 2396(78+22)[/tex]

[tex]\\ \sf\longmapsto 2396(100)[/tex]

[tex]\\ \sf\longmapsto 239600[/tex]

Answer:

Step-by-step explanation:

[tex]6 \div \frac{3}{8} = 6 \times \frac{8}{3} \\ [/tex]

[tex] = \frac{6 \times 8}{3} \\ \\ = \frac{48}{3} =1 6[/tex]

Answer:

Whole number —> X

Twice the square of the number —> 2X²

X + 2X² = 10

2X²+X –10 =0

(2x + 5) ( x–2) =0

2x +5=0 —> 2x= – 5 —> x= – 5/2 = —> x= - 2.5 (rejected)

x–2=0 —> x= 2

So Ans ; X= 2 ( the number )

I hope I helped you^_^

[tex]\\ \sf\longmapsto 4x+4x+5x-7+5x+2+96=540[/tex]

[tex]\\ \sf\longmapsto 4x+4x+5x+5x-7+2+96=540[/tex]

[tex]\\ \sf\longmapsto 8x+10x-5+96=540[/tex]

[tex]\\ \sf\longmapsto 18x+91=540[/tex]

[tex]\\ \sf\longmapsto 18x=540-91=449[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{449}{18}[/tex]

[tex]\\ \sf\longmapsto x\approx2.4[/tex]

Answer:

x=25

Step-by-step explanation:

4x+5x-8+96+5x+2+4x=540

18x+90=540

18x=540-90=450

x=450/18=25