Find the product.
1.(a + 3)(a - 4)
2. (x - 3)2
3. (2a – 62)(a + 462)
4.(x - 5)(x2 + 4x - 6)

Answer:

6.2

Step-by-step explanation:

You can find the median by adding up all of the numbers and dividing the result by how many numbers there are.

add them all together: 5 + 6 +5+6+9 = 31

there are five people, so divided 31 by 5

31 divided by 5 = 6.2

6.2

Step-by-step explanation:

the domain is the interval of x (input) values.

the range is the interval of y (result) values.

a) I would not guess (-3, 5). because -3 for x is at the beginning of the interval. and the end values of y (range) are -4 and 7 - not close enough to 5 to make me make a guess.

b) (2, 5) : 2 is closer to 5 end of the x interval, and 5 is closer to the 7 end of the y interval, so, this is closer correlated, and I could dare a guess.

Answer:

1) for -1 as x, k(x) would be -8

2) for -3 as x, k(x) would be -18

3) for 0 as x, k(x) would be -3

4) for 1 as x, k(x) would be 2

It follows from the definition of the derivative and basic properties of arithmetic. Let f(x) and g(x) be functions. Their derivatives, if the following limits exist, are

[tex]\displaystyle f'(x) = \lim_{h\to0}\frac{f(x+h)-f(x)}h\text{ and }g'(x)\lim_{h\to0}\frac{g(x+h)-g(x)}h[/tex]

The derivative of f(x) + g(x) is then

[tex]\displaystyle \big(f(x)+g(x)\big)' = \lim_{h\to0}\big(f(x)+g(x)\big) \\\\ \big(f(x)+g(x)\big)' = \lim_{h\to0}\frac{\big(f(x+h)+g(x+h)\big)-\big(f(x)+g(x)\big)}h \\\\ \big(f(x)+g(x)\big)' = \lim_{h\to0}\frac{\big(f(x+h)-f(x)\big)+\big(g(x+h)-g(x)\big)}h \\\\ \big(f(x)+g(x)\big)' = \lim_{h\to0}\frac{f(x+h)-f(x)}h+\lim_{h\to0}\frac{g(x+h)-g(x)}h \\\\ \big(f(x)+g(x)\big)' = f'(x) + g'(x)[/tex]

Answer:

A. The data set has an outlier

Step-by-step explanation:

The data set has an outlier because 100 is the largest number of the set.

Answer:

option b

Step-by-step explanation:

Answer:

x=0       x=8          x = -1/10

Step-by-step explanation:

- 2x(x − 8)(10x + 1) = 0

Using the zero product property

-2x =0   x-8 = 0    10x+1= 0

x= 0    x= 8             10x = -1

x=0       x=8          x = -1/10

Answer:

hello thereee

8 - 2v^2 we are suppose to facotrize...

2 ( 4 - v^2 )

2 ( 2^2 - v^2 )

apply identity a^2 - b^2

2 ( 2 + v ) ( 2- v )

done dana done.....

Answer:

7.5 Imperial Gallons = 30 Imperial Quarts

Hi there!  

»»————-　★　————-««

I believe your answer is:  

30 qt.

»»————-　★　————-««  

Here’s why:  

⸻⸻⸻⸻

7.5 * 4 = 30

7.5 gal. = 30 qt.

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

Answer:

y = -2x + 5

[tex]\frac{risex}{run} = slope =[/tex]Δy/Δx = -8/4 = -2

Step-by-step explanation:

Answer:

let R represent red hair

let G represent green eyes

from Baye's theorem:

[tex]P( \frac{R}{G} ) = \frac{P(RnG)}{P(G)} [/tex]

P(RnG) = 5

[tex]P(G) = { \sum}(green \: hair) \\ = (3 + 5 + 5) \\ = 13[/tex]

Therefore:

[tex]P( \frac{R}{G} ) = \frac{5}{13} \\ = 0.385[/tex]

The conditional relative frequency = 0.385

The conditional relative frequency will be  0.385

It is a theorem showing how to compute the conditional probability of each of a set of possible causes for a given observed outcome using knowledge about the probability of each cause and the conditional probability of each cause's outcome.

let R represent red hair

let G represent green eyes

from Baye's theorem:

[tex]P=\dfrac{R}{G}=\dfrac{P(R\cap G)}{P(G)}[/tex]

P(RnG) = 5

P(G) = ∑(Green hairs)

P(G)= 13+5+5 = 13

Therefore:

[tex]P(\dfrac{R}{G})= \dfrac{5}{13}=0.385[/tex]

The conditional relative frequency = 0.385

Hence the conditional relative frequency will be  0.385

To know more about Baye's theorem follow

https://brainly.com/question/14989160

#SPJ2

Answer:

[tex]\displaystyle \frac{\sin \theta + \sec \theta}{\sin \theta - \sec\theta} = -3[/tex]

Step-by-step explanation:

We are given that:

[tex]\displaystyle \frac{\sin \theta}{\sec \theta} = \frac{1}{2}[/tex]

And we want to find the value of:

[tex]\displaystyle \frac{\sin \theta + \sec \theta}{\sin \theta - \sec\theta}[/tex]

From the second expression, we can divide both the numerator and denominator by sec(θ). Thus:

[tex]\displaystyle = \frac{ \dfrac{\sin \theta + \sec \theta}{\sec \theta} }{ \dfrac{\sin \theta - \sec\theta}{\sec \theta} }[/tex]

Simplify:

[tex]\displaystyle = \frac{\dfrac{\sin \theta}{\sec \theta} + 1}{\dfrac{\sin\theta}{\sec\theta} - 1}[/tex]

Since we know that sin(θ) / sec(θ) = 1 / 2:

[tex]\displaystyle = \frac{\left(\dfrac{1}{2}\right)+1}{\left(\dfrac{1}{2}\right)-1}[/tex]

Evaluate:

[tex]\displaystyle = \frac{\dfrac{3}{2}}{-\dfrac{1}{2}} = -3[/tex]

Therefore:

[tex]\displaystyle \frac{\sin \theta + \sec \theta}{\sin \theta - \sec\theta} = -3[/tex]

Answer:

The original number is 82

Step-by-step explanation:

Very interesting question!

There is only 1 number that satisfies this condition between 10 and 9999 (I could have gone much further but didn't)

That number is 82

If you subtract 7 from 82 you get 75

75/5 = 15

If you subtract 5 from 82 you get 77

77 divide by 7 = 11

Here's the kicker.

11 is 4 less than 15.

Isn't that a weird coincidence? No other number (I would bet) does that.

Answer:

This is already listed in increasing order:

Given order .

We have to arrange it in increasing means lowest to highest

[tex]\\ \sf\longmapsto 780<807<870[/tex]

The listing will be

[tex]\\ \sf\longmapsto 780;807;870[/tex]

Answer:

Yo it's A

Step-by-step explanation:

An infinite sequence is one that goes on forever, in this case it's the one with the "..." at the end because that is what shows that the sequence is infinite

There are two infinite sequences, and you just have to figure out which one is an arithmetic sequence.  An arithmetic sequence is one that subtracts or adds the same number every time to the previous number.

Out of the two infinite sequence choices, it's obviously not B because you aren't subtracting or adding the same number every time

It's A because you add 122 every time and it goes on forever.

hope this helps lol

Answer:

40

Step-by-step explanation:

So square A has a side of 4, therefore its area is 16 because you square the side length.

Square B has a side of 2 times Square A's side. So Square B has sidelength 8 as 4*2 = 8.

If Square B has side length 8, it has an area of 64.

The average is found by adding the two area and then dividing by 2. So,

64 + 16 = 80

80/2 = 40

Answer:

What do you need help with

Step-by-step explanation:

Do you need help with a specific question? Or with the whole assignment?

Answer:

$0.60

Step-by-step explanation:

Find the unit rate.

[tex]\frac{Dollars}{Cookies}=\frac{9}{15}[/tex] ÷ [tex]\frac{15}{15}=\frac{0.6}{1}[/tex]

Therefore, the cost for one cookie is $0.60.

Answer:

$0.60

You need to find the unit rate. Unit rate is a ratio of 1 to another number, written like 1 : ?.

If a box of 15 cookies costs $9, and you want to find the price of one cookie, then you will need to use unit rate.

Start with the ratio of cookies to dollars.

15:9

Now, you need to find out the cost of one cookie. To do this, you will need to divide 9 by 15 (9/15) because you're trying to split 9 into 15 cookies.

But, you can't have .6 dollars, so the answer will be $0.60, or 60 cents.

Answer:

[tex]4 \sqrt{122} \sqrt{12} \\ (4 \times 2) \times ( \sqrt{12} \times \sqrt{12} ) \\ (4 \times 2) \times 12 \\ 8 \times 12 \\ 96[/tex]

Answer:

Just use a calculator and wite the square root value in it

Step-by-step explanation:

Atempt this method with all options at last u will have ur answer

Answer:

3x

Step-by-step explanation:

If Kapila's age =x.

Then Sasha's age would be =2x.

Their total age would be 3x.

Because 2x+x adds up to be 3x.

Answer:

A regular polygon all the angles, as well as all the sides, are equal.

Diego's claim is the quadrilateral with four congruent sides is always a regular polygon. He is only mentioning that the sides are equals.

He has not mentioned anything about the angles, the angles may or may not be equals.

In the case, if all the angles are equal too, then the claimed quadrilateral will be a regular polygon as shown in figure(a).

So, for this case, Diego's claim is correct while  Mai's claim is also wrong.

While if all the angles are not equal, then the claimed quadrilateral will not be a regular polygon as shown in figure(b).

In this case, Diego's claim is wrong while Mai's claim is correct.

So, overall, considering both the case together, none of them have the correct claim.

So, both are wrong.

Step-by-step explanation:

Step-by-step explanation:

x= 9

[tex] {x}^{2} + 9 \div x + 1[/tex]

[tex] {9 }^{2} + 9 \div 9 + 1[/tex]

[tex]81 + 9 \div 10[/tex]

[tex]90 \div 10[/tex]

[tex]9[/tex]

Answer:

Given, A={p,q,r}.

Now, possible subsets of A are ,{p},{q},(r) {p,q}.

(q,r) (p,r) (p,q,r)

Answer:

The answer to your question is x=48

Step-by-step explanation: If you have any questions regarding my answer, tell me in the comments and I will answer them. Have a good day.

x/4−2=x/8+4

1/4x+−2=1/8x+4

1/4x−2=1/8x+4

1/4x−2−1/8x=1/8x+4−1/8x

1/8x−2=4

1/8x−2+2=4+2

1/8x=6

8*(1/8x)=(8)*(6)

x=48

Answer:

below

Step-by-step explanation:

P (at least one defective) = 1 - P(all calculators work)

=  

1

−

(

30

46

×

29

45

×

28

44

×

27

43

)

=

1

−

1827

10879

=  

9052

10879

≈

0.832

Answer:

x = 18

y = 9

y = 9√3/√3 = 9

x = 9×2 = 18

Answer:

a2 – b2 = (a – b)(a + b)

(a + b)2 = a2 + 2ab + b2

a2 + b2 = (a + b)2 – 2ab

(a – b)2 = a2 – 2ab + b2

(a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca

(a – b – c)2 = a2 + b2 + c2 – 2ab + 2bc – 2ca

(a + b)3 = a3 + 3a2b + 3ab2 + b3 ; (a + b)3 = a3 + b3 + 3ab(a + b)

(a – b)3 = a3 – 3a2b + 3ab2 – b3 = a3 – b3 – 3ab(a – b)

a3 – b3 = (a – b)(a2 + ab + b2)

a3 + b3 = (a + b)(a2 – ab + b2)

(a + b)4 = a4 + 4a3b + 6a2b2 + 4ab3 + b4

(a – b)4 = a4 – 4a3b + 6a2b2 – 4ab3 + b4

a4 – b4 = (a – b)(a + b)(a2 + b2)

a5 – b5 = (a – b)(a4 + a3b + a2b2 + ab3 + b4

Answer:

a2 – b2 = (a – b)(a + b)

(a + b)2 = a2 + 2ab + b2

a2 + b2 = (a + b)2 – 2ab

(a – b)2 = a2 – 2ab + b2

(a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca

(a – b – c)2 = a2 + b2 + c2 – 2ab + 2bc – 2ca

(a + b)3 = a3 + 3a2b + 3ab2 + b3 ; (a + b)3 = a3 + b3 + 3ab(a + b)

(a – b)3 = a3 – 3a2b + 3ab2 – b3 = a3 – b3 – 3ab(a – b)

a3 – b3 = (a – b)(a2 + ab + b2)

a3 + b3 = (a + b)(a2 – ab + b2)

(a + b)4 = a4 + 4a3b + 6a2b2 + 4ab3 + b4

(a – b)4 = a4 – 4a3b + 6a2b2 – 4ab3 + b4

a4 – b4 = (a – b)(a + b)(a2 + b2)

a5 – b5 = (a – b)(a4 + a3b + a2b2 + ab3 + b4)