Find the length of the third side. If necessary, round to the nearest tenth. 5 10
Answers
Answer:
[tex]\boxed {\boxed {\sf 8.7}}[/tex]
Step-by-step explanation:
We are asked to find the length of the third side in a triangle, given the other 2 sides.
Since this is a right triangle (note the small square in the corner of the triangle representing a 90 degree /right angle), we can use the Pythagorean Theorem.
[tex]a^2 + b^2 =c^2[/tex]
In this theorem, a and b are the legs of the triangle and c is the hypotenuse.
We know that the unknown side (we can say it is a) and the side measuring 5 are the legs because they form the right angle. The side measuring 10 is the hypotenuse because it is opposite the right angle.
b= 5 c= 10Substitute the values into the formula.
[tex]a^2 + (5)^2 = (10)^2[/tex]
Solve the exponents.
(5)²= 5*5 = 25 (10)²= 10*10= 100[tex]a^2 + 25=100[/tex]
We are solving for a, so we must isolate the variable. 25 is being added to a. The inverse operation of addition is subtraction, so we subtract 25 from both sides.
[tex]a^2 +25-25=100-25[/tex]
[tex]a^2=100-25[/tex]
[tex]a^2 = 75[/tex]
a is being squared. The inverse of a square is the square root, so we take the square root of both sides.
[tex]\sqrt {a^2}= \sqrt{75}[/tex]
[tex]a= \sqrt{75}[/tex]
[tex]a= 8.660254038[/tex]
Round to the nearest tenth. The 6 in the hundredth place tells us to round the 6 up to a 7 in the tenth place.
[tex]a \approx 8.7[/tex]
The length of the third side is approximately 8.7
Using Pythagorean theorem
[tex]\boxed{\sf B^2=H^2-P^2}[/tex]
Putting values[tex]\\ \sf \longmapsto B^2=10^2-5^2[/tex]
[tex]\\ \sf \longmapsto B^2=100-25[/tex]
[tex]\\ \sf \longmapsto B^2=75[/tex]
[tex]\\ \sf \longmapsto B=\sqrt{75}[/tex]
[tex]\\ \sf \longmapsto B=\sqrt{25\times 3}[/tex]
[tex]\\ \sf \longmapsto B=5\sqrt{3}[/tex]
[tex]\\ \sf \longmapsto B=5\times 1.732[/tex]
[tex]\\ \sf \longmapsto B=8.66[/tex]
[tex]\\ \sf \longmapsto B\approx 8.7[/tex]
Related Questions
simple way to differentiate between speed and average speed.
Answers
Answer:
speed
1)the distance travelled by a body per unit time is known as speed.
2) speed is speed, or something how fast is going,
3) while velocity is speed how fast something is going in a specific direction.
average speed
1) average speed is the speed added up and divided by number of speed .
2)the average of all the instantaneous speed in a give time interval.
3) the average speed as the duration of the time interval approaches zero.
Which graph below has a midline of about -1, an amplitude of 2, and a period of 3pi
Answers
Answer:
the last one
Step-by-step explanation:
The two on the right bounce up and down around -1. Two up and two down from -1. But only the one on the bottom right takes 3 pi to come back to the same place it started.
Explanation:
[tex]\displaystyle y = 2cos\:(\frac{2}{3}x - \frac{\pi}{2}) - 1 \\ y = 2sin\:\frac{2}{3}x - 1 \\ \\ y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow -1 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{\frac{3}{4}\pi} \hookrightarrow \frac{\frac{\pi}{2}}{\frac{2}{3}} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{3\pi} \hookrightarrow \frac{2}{\frac{2}{3}}\pi \\ Amplitude \hookrightarrow 2[/tex]
OR
[tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow -1 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{3\pi} \hookrightarrow \frac{2}{\frac{2}{3}}\pi \\ Amplitude \hookrightarrow 2[/tex]
You will need the above information to help you interpret the graph. So, first off, you MUST figure the period out by using wavelengths. So, looking at where the graph hits [tex]\displaystyle [-4\frac{1}{2}\pi, -1],[/tex] from there to [tex]\displaystyle [-1\frac{1}{2}\pi, -1],[/tex] they are obviously [tex]\displaystyle 3\pi\:units[/tex] apart, telling you that the period of the graph is [tex]\displaystyle 3\pi.[/tex] Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = -1,[/tex] in which each crest is extended two units beyond the midline, hence, your amplitude. So, no matter how far the graph shifts vertically, the midline will ALWAYS follow.
*If you wanted to know the equation(s) of the graph, look above. If you have any questions on how the equation(s) came about, do not hesitate to ask.
I am delighted to assist you at any time.
Mary spent $15. If this was 20% of her earrings, how much money did she earned?
Answers
Hi, I'm happy to help!
First off, we need to arrange an equation for what is being asked. 15 is 20% of her earnings and we don't know her total earnings.
15=20%×__
We can write this percentage as
15=0.2×__
We then change the equation to do the inverse operation, which is division, this makes it easier to solve.
15÷0.2=__
Now, we solve
15÷0.2=75
She earned $75
I hope this was helpful, keep learning! :D
8. PLEASE HELP ME
Order the group of quadratic functions from widest to narrowest graph.
y= 6x2, y= -4.5x2, y= -x2
A. y= -4.5x2, y= -x2, y= 6x2
B. y= 6x2, y= -4.5x2, y= -x2
C. y= -x2, y= 6x2, y= -4.5x2
D. y= -x2, y= -4.5x2, y= 6x2
Answers
Answer:
B. y= 6x2, y= -4.5x2, y= -x2
Step-by-step explanation:
y = 6x2, y = −4.5x2, y = −x2
This should be correct )
To solve this problem you must keep on mind the following information: By definition, a quadratic function has the following form:
y=ax^{2}+bx+c
Where a is the leading coefficient.
If the leading coeficient is closer to zero, the parabola is widest,if it has a larger positive or negative value, the parabola is narrowest.
Therefore, by knowing the information above, you have that the answer is:
y=- x^{2} \\ y=-4.5 x^{2} \\ y=6 x^{2}
Add. Write your answer as a fraction in simplest form. 1 5 + 9 9
Answers
Answer:
57/5
Step-by-step explanation:
what is that supposed to be ?
1.5 + 9.9 ?
I base my answer in that assumption.
1.5 = 3/2
9.9 = 99/10
so, we need 3/2 + 99/10.
how do we do that ?
by bringing both fractions to the same denominator (bottom parts) but without changing the value of the fractions. that means we need to multiply numerator and denominator (top and bottom parts) by the same factor. and that factor is determined by what is needed to transform the denominator.
we have denominators 2 and 10. what is the smallest common multiple ?
I think it is plainly visible : 10. as 2 also cleanly divides 10.
in other examples, if you don't see that right away, the simplest approach is to just multiply both denominators (in our case 2×10 = 20) and work with that result.
so, we are trying to bring both fractions to denominators of 10 (or, as mentioned 20), so that we can easily add the fractions.
let's start with 3/2.
what multiplication do we need to do to turn 2 into 10 ?
right, by multiplying by 5.
remember, we need to do the same thing to numerator and denominator to keep the value of the fraction unchanged.
so, we do the following
3/2 × 5/5
as you can see, multiplying something by 5/5 does not change any value, as it means we are just multiply by 1. but we can use that little trick to change the appearance of the original fraction.
so,
3/2 × 5/5 = (3×5) / (2×5) = 15/10
by the way, if we had wanted to change the denominator to 20, our factor would have been 10/10, and we would have gotten 30/20.
now to 99/10.
well, the denominator is already 10, so we don't need any transformation.
but if we had not seen that and went for 20 as desired denominator, we would have had to multiply by 2/2 giving us
198/20.
so, for the final sum :
15/10 + 99/10 = 114/10 = 57/5
and in case of 1/20th :
30/20 + 198/20 = 228/20 = 114/10 = 57/5
now, should that original problem have been
1/5 + 9/9 ?
the same principles apply.
bring both fractions to the same denominator.
9/9 = 1
and that can be transformed easily into any other denominator expression - like 5/5.
and then we have
1/5 + 5/5 = 6/5
but if we had not seen that simple approach, we could have turned both into fractions with denominator 5×9 = 45.
9/45 + 45/45 = 54/45 = 6/5
Would be very happy if you helped.Don’t spam guys
Answers
[tex]\\ \sf\longmapsto 41sin\Theta=40[/tex]
[tex]\\ \sf\longmapsto sin\Theta=\dfrac{40}{41}[/tex]
Now
[tex]\boxed{\sf cos\Theta=\sqrt{1-sin^2\Theta}}[/tex]
[tex]\\ \sf\longmapsto cos\Theta=\sqrt{1-\left(\dfrac{40}{41}\right)^2}[/tex]
[tex]\\ \sf\longmapsto cos\Theta=\sqrt{1-\dfrac{1600}{1682}}[/tex]
[tex]\\ \sf\longmapsto cos\Theta=\sqrt{\dfrac{1681-1600}{1681}}[/tex]
[tex]\\ \sf\longmapsto cos\Theta=\sqrt{\dfrac{81}{1681}}[/tex]
[tex]\\ \sf\longmapsto cos\Theta=\dfrac{9}{41}[/tex]
We know
[tex]\boxed{\sf tan\Theta=\dfrac{Sin\theta}{Cos\Theta}}[/tex]
[tex]\\ \sf\longmapsto \dfrac{tan\Theta}{1-tan^2\Theta}[/tex]
[tex]\\ \sf\longmapsto \dfrac{\dfrac{sin\Theta}{cos\Theta}}{1-\dfrac{sin^2\Theta}{cos^2\Theta}}[/tex]
[tex]\\ \sf\longmapsto \dfrac{\dfrac{\left(\dfrac{40}{41}\right)}{\left(\dfrac{9}{41}\right)}}{1-\dfrac{\left(\dfrac{40}{41}\right)^2}{\left(\dfrac{9}{41}\right)^2}}[/tex]
[tex]\\ \sf\longmapsto \dfrac{\dfrac{{40}}{{9}}}{1-\dfrac{{40}^2}{{9}^2}}[/tex]
[tex]\\ \sf\longmapsto \dfrac{\dfrac{40}{9}}{\dfrac{9^2-40^2}{9^2}}[/tex]
[tex]\\ \sf\longmapsto \dfrac{\dfrac{40}{9}}{\dfrac{81-1600}{81}}[/tex]
[tex]\\ \sf\longmapsto \dfrac{\dfrac{40}{9}}{\dfrac{-1519}{81}}[/tex]
[tex]\\ \sf\longmapsto {\dfrac{40}{\cancel{9}}}\times \dfrac{\cancel{81}}{(-1519)}[/tex]
[tex]\\ \sf\longmapsto \dfrac{40\times 9}{(-1519)}[/tex]
[tex]\\ \sf\longmapsto - \dfrac{360}{1519}[/tex]
A farmer plants the same amount every day, adding up to 4 1/2 acres at the end of the year. If the year is 2/3 over, how many acres has the farmer planted
Answers
Answer:
3 acres
Step-by-step explanation:
If the farmer plants 4 1/2 acres in one full year, to figure out how much is planted if the year is 2/3 over, just do:
= [tex]\frac{2}{3}[/tex] [tex]of[/tex] [tex]4\frac{1}{2}[/tex]
= [tex]\frac{2}{3} * 4 \frac{1}{2}[/tex]
= [tex]\frac{2}{3} * \frac{9}{2}[/tex]
= [tex]3[/tex]
This means that 3 acres are planted
The number of acres that were planted by the farmer if the year is 2/3 will be 3.
What is multiplication?It is also known as the product. If the object n is given to m times then we just simply multiply them.
A farmer plants the same amount every day, adding up to 4 1/2 acres at the end of the year. If the year is 2/3 over.
Then the number of the acre will be
[tex]\rightarrow (4 +\dfrac{1}{2}) \times \dfrac{2}{3}\\\\\rightarrow \dfrac{9}{2} \times \dfrac{2}{3}\\\\\rightarrow 3[/tex]
More about the multiplication link is given below.
https://brainly.com/question/19943359
Alan borrowed $5,100 from his father to buy a car. He repaid him after 6 months with interest of 8%. Find the total amount he repaid. Round to the nearest cent.
Answers
If x is 2/3 of y and y is 3/4 of z, what is the ratio of:x? *
a) 1:2
b) 1:1
c) 2:1
d) 3:2
e) 4:3
Answers
Answer:
Answer is option C
Step-by-step explanation:
If you like my answer than please mark me brainliest thanks
U
w
R
Which angles
are adjacent?
T
S
A. RWS and UWT
B. UWT and SWR
C. UWT and TWU
D. RWS and SWT
Answers
Answer:
D. RWS and SWT
Step-by-step explanation:
Adjacent angles have a common side and a common vertex but they don't overlaps each other
The two angles that has these requirements are :
RWS and SWT
The two angles are said to be adjacent angles when they share the common vertex and side.
So , adjacent angles are :
RWS and SWTOption D is the correct answer.
Describe the test of divisibility for:
a) 6 b) 4
Answers
6 It is divisible by 2 and by 3.
4 it is divisible by 4...
The divisibility rules of 4 and 6 are completely different. In the divisibility rule of 4, if the last two digits are zeros or the number formed by the last two digits is exactly divisible by 4, then we can say that a number is divisible by 4.
HOPE ITS HELPFUL FOR U MATE
Pls help I’ll mark Brainliest!! Which mapping represents a function?
Answers
Answer:
Mapping C represents a function.
To be a function, there must be one and only one y value (output) for every input value (x value).
Mapping C matches this criteria, thus it is a function.
Let me know if this helps!
Find the five-number summary for the data. {231, 201, 221, 210, 225, 228, 212, 236, 225, 201, 216, 215, 231, 226, 206, 240}
Answers
Answer:
201, 206, 216, 228, 240
Step-by-step explanation:
jack wants to run at least 275 miles before the baseball season begins. he has already run 25 miles. he plans to run 2.5 miles each day. at this rate what is the fewest number of days he will need to reach his goal
Answers
Hey there! I'm happy to help!
We see that Jack has already run 25 miles.
25
He also wants to run 2.5 miles every day. This means we will multiply 2.5 miles by the number of days he runs. We will call the number of days x.
25+2.5x
And he needs this to equal 275.
25+2.5=275
We subtract 25 from both sides.
2.5x=250
We divide both sides by 2.5
x=100
So, Jack will need to run 100 days to meet his goal.
Have a wonderful day and keep on learning! :D
Write an exponential function that includes the following points (2,32) and (3,64)
Answers
Answer:
y=32x-32
Step-by-step explanation:
This time no algorithm or equation was needed i saw that if the equation was y=32x there would be ordered pairs (1,32) and (2,64) so to delay it by 1 on the x side just subtract the slope from the y - intercept sorry if that doesn't make sense
given m||n, find the value of x
Answers
Answer:
x = 155º
Step-by-step explanation:
y = 25° {Vertically opposite angles}
x + y = 180 {Co-interior angles are supplementary}
x + 25 = 180
Subtract 25 from both sides
x = 180 - 25
x = 155°
Jerry sold 320 tickets for the school play. He sold x adults tickets for $8 each and y child tickets for $5 each. He sold $1900 worth of tickets. Write a system of equations to model the situation.
What is the equation?
Answers
Answer:
x + y = 320
8x + 5y = 1900
Step-by-step explanation:
The equation x + y = 320 represents how 320 tickets were sold in total, from combining the adult and child tickets sold.
Since adult tickets are $8 each, the money from adult ticket sales can be represented by 8x.
The money from child ticket sales can be represented by 5y.
The equation 8x + 5y = 1900 represents how $1900 worth of tickets were sold.
So, the system of equations for the situation is:
x + y = 320
8x + 5y = 1900
Answer:
y = 220
x = 100
Step-by-step explanation:
x + y = 320
8x + 5y = 1900
x = 320 - y
8(320 - y) + 5y = 1900
2560 - 8y + 5y = 1900
2560 -3y = 1900
-2560 -2560
-------------------------
-3y = -660
----- -------
-3 -3
y = 220
x + 220 = 320
-220 -220
----------------------
x = 100
[tex]\sqrt{a} +\sqrt{b} =\sqrt{a+b}[/tex]CHO A,B THUỘC R, khẳng định sau đúng hay sai
Answers
Answer:
Hello,
Step-by-step explanation:
Le théorème est faux
since a=9 and b=16 then
[tex]\sqrt{9} +\sqrt{16} =3*4=7 \\\sqrt{9+16} =\sqrt{25} =5\\[/tex]
Use the distributive property to rewrite this expression, then simplify the new expression, if possible.
-3(y+2)
Answers
Answer:
-3y-6
Step-by-step explanation:
[tex]-3(y+2)=-3y-6[/tex]
The sum of first three terms of an arithmetic series is 21. If the sum of the first two terms is subtracted from the third term then it would be 9. find the three terms of the series. The first and last bra
Answers
Answer:
The terms are - 1, 7 and 15.
Step-by-step explanation:
Let the terms be a-d, a, a+d.
ATQ, a-d+a+a+d=21, a=7 and a+d-(a-d+a)=9. 2d-a=9, d=8. The terms are - 1, 7 and 15.
The first three terms will be : -1, 7, 15
We have sum of first three terms of an arithmetic series is 21. It is given that if the sum of the first two terms is subtracted from the third term then it would be 9.
We have to find the three terms of the series.
What is Arithmetic progression or sequence?An arithmetic progression or sequence with common difference [tex]d[/tex] is given as -
a, a + d, a + 2d, a + 3d .....
According to the question -
a + (a + d) + (a + 2d) = 21
3a + 3d = 21
3(a + d)=21
a + d = 7 (Eqn. 1)
(a + 2d) - (a + a + d) = 9
a + 2d - a - a - d = 9
d - a = 9
a = d - 9
Substituting the value of 'a' in Eqn. 1, we get -
d - 9 + d = 7
2d - 9 = 7
2d = 16
d = 8
Therefore -
a = 8 - 9
a = -1
The three terms are -
a = -1
a + d = -1 + 8 = 7
a + 2d = -1 + 2 x 8 = 15
Hence, the first three terms will be - -1, 7, 15
To solve more questions on Arithmetic Sequences and finding the terms, visit the link below -
https://brainly.com/question/20384906
#SPJ2
Two lines parallel to a third line are parallel to each other. never sometimes always
Answers
Answer:
always
Step-by-step explanation:
they would all have the same gradient & be parallel to each other!
ie. A || B , B || C
in this case, A || C ^^
Answer:
always
Step-by-step explanation:
have the same gradient & be parallel to each other
Find the perimeter of the polygon.
Answers
Answer:
80
Step-by-step explanation:
The Two-Tangent Theorem states that if two tangent segments are drawn to one circle from the same external point, then they are congruent
13+13+9+9+12+12+6+6= 80
Find the number of gallons of sulferic acid in 50 gallons of solution in a tank, if the percent of sulfuric acid is 50%.
Answers
Answer:
25 gallons of sulfuric acid
Step-by-step explanation:
Find how much sulfuric acid is in the tank by finding 50% of 50 (the total gallons of solution):
50(0.5)
= 25
So, there are 25 gallons of sulfuric acid.
if sum of two no is 21 and sum of their square is 256 find the number
i.e x+y=21
x²+y²=261
find value of x and y
Answers
Step-by-step explanation:
you're going to solve for y in the first equation and then substitute it in for the second equation and solve.
I attached a picture of my question. Please help me ( urgent)
Answers
ω in terms of m and k is expressed as [tex]\omega = \sqrt{\frac{k}{m} }[/tex]
The given expression is as follows;
[tex]T_s = 2\pi \sqrt{\frac{m}{k} } , \ \ \\\\ T_s = \frac{2\pi}{\omega}[/tex]
To find:
ω in terms of m and k;From the given expression above make ω the subject of the formula;
[tex]T_s = \frac{2\pi}{\omega} = 2\pi \sqrt{\frac{m}{k} } \\\\ \frac{2\pi}{\omega} = 2\pi \sqrt{\frac{m}{k} }\\\\ \frac{2\pi}{\omega} = \sqrt{4\pi^2\frac{m}{k} }\\\\square \ both \ sides \ of \ the \ equation;\\\\(\frac{2\pi}{\omega})^2 = 4\pi^2\frac{m}{k} \\\\\frac{4\pi^2}{\omega^2}= \frac{4\pi^2m}{k} \\\\\omega^2 4\pi^2m = k4\pi^2 \\\\divide \ both \ side \ by \ 4\pi ^2 \\\\\omega^2 m = k\\\\divide \ both \ sides \ by \ m\\\\\omega^2 = \frac{k}{m} \\\\[/tex]
[tex]take \ the \ square \ root \ of \ both \ sides \ of \ the \ equation\\\\\omega = \sqrt{\frac{k}{m} }[/tex]
Therefore, ω in terms of m and k is expressed as [tex]\omega = \sqrt{\frac{k}{m} }[/tex]
To learn more about subject of formula visit: https://brainly.com/question/15469690
find the unknown anagels in the following figure
Answers
Answer:
ABC=BCD
so, X=60'
Z= 70'
Y=50'
A sandwich shop offers a choice of 5 types of bread, 4 types of meat, and 3 types of cheese. How many different sandwiches could be made with 1 type of bread, 1 type of meat, and 1 type of cheese?
Answers
Answer:
12 type of bread 1 type of meat, 1 type of cheese and 1 type of bread.☺️☺️
Need help!
.......................
Answers
Answer:
[tex]24x^{3} \sqrt{5x} -4x^{3} \sqrt{10x}[/tex]
Step-by-step explanation:
[tex]2\sqrt{8x^{3} } (3\sqrt{10x^{4} } -x\sqrt{5x^{2} } )[/tex]
[tex]=2.2x\sqrt{2x} (3x^{2} \sqrt{10} -x^{2} \sqrt{5} )[/tex]
[tex]=4x\sqrt{2x} (3x^{2} \sqrt{10} -x^{2} \sqrt{5} )[/tex]
[tex]=12x^{3} \sqrt{2xx10} -4x^{3} \sqrt{2xx5}[/tex]
[tex]=24x^{3} \sqrt{5x} -4x^{3} \sqrt{10x}[/tex]
OAmalOHopeO
Question 16 of 17
Which of the following best describes the graph below?
A. Independent variable
0 o a
B. A relation that is a function
C. A relation that is not a function
D. Dependent variable
Answers
the following analysis shows how students of various department for 2018/2019 academic session, 10 for economics only, 150 from economics and geography. 90 from economics but not political science, 210 from geography, 120 fron political science and geography, 180 from economics. if the total of student registered for courses is 250, determine the no of students who registered for (i)political science (ii)political science and geography but not economics (iii)economics and political science but not geography
Answers
(i) The number of students who registered for political science is 150
(ii) The number of students who registered for political science and geography but not economics is 50
(iii) The number of students who registered for economics and political science but not geography is 20
The Venn diagram for the question is shown in the attachment below.
E represents Economics
G represents Geography
and P represents Political science
From the question,
10 for economics only, that is, n(E∩G'∩P') = 10
150 from economics and geography, that is n(E∩G) = 150
90 from economics but not political science, that is, n(E∩P') = 90
210 from geography, that is, n(G) = 210
120 from political science and geography, n(P∩G) = 120
180 from economics, that is, n(E) = 180
Total of student registered for courses is 250, that is, n(ξ) = 250
Now from the given information,
n(E∩G∩P') = n(E∩P') - n(E∩G'∩P') = 90 - 10 = 80
n(E∩G∩P) = n(E∩G) - n(E∩G∩P') = 150 - 80 = 70
n(E∩P∩G') = n(E) - [n(E∩G'∩P') + n(E∩G∩P') + n(E∩G∩P)]
= 180 - [10+80+70] = 180 - 160 = 20
n(P∩G∩E') = n(P∩G) - n(E∩G∩P) = 120 - 70 = 50
n(G∩E'∩P') = n(G) - [n(E∩G∩P') + n(E∩G∩P) + n(P∩G∩E')]
= 210 -[80+70+50] = 210 - 200 = 10
All of these are shown in the Venn diagram
(i) To determine the number of students who registered for political science, we will first determine n(P∩G'∩E'), that is, those who registered for political science only.
Let n(P∩G'∩E') = x
Then, using the Venn diagram, we can write that
10 + 80 + 20 + 70 + 10 + 50 + x = n(ξ) = 250
240 + x = 250
x = 250 - 240
x = 10
n(P∩G'∩E') = 10
∴ 10 registered for political science only
Now, number of students who registered for political science n(P) is
n(P) = n(E∩P∩G') + n(E∩G∩P) + n(P∩G∩E') + n(P∩G'∩E')
n(P) = 20 + 70 + 50 + 10
n(P) = 150
∴ 150 students registered for political science
(ii) For the number of students who registered for political science and geography but not economics, that is, n(P∩G∩E')
As determined above and as shown in the Venn diagram,
n(P∩G∩E') = 50
∴ 50 students registered for political science and geography but not economics
(iii) For the number of students who registered for economics and political science but not geography, that is, n(E∩P∩G')
As determine above and as shown in the Venn diagram as well
n(E∩P∩G') = 20
∴ 20 students registered for economics and political science but not geography
Hence,
(i) The number of students who registered for political science is 150
(ii) The number of students who registered for political science and geography but not economics is 50
(iii) The number of students who registered for economics and political science but not geography is 20
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