Find the distance across the lake. Assume the triangles are similar.

Answer

Step-by-step explanation:

This is because the wild pigs' fertilty rate increased for the past five years,  which caused them to double each year.

Answer:

C.

–5; –135; –10,935

Step-by-step explanation:

Answer:

C. -5; -135, -10,935

Step-by-step explanation:

...............................................................................................................................................

Answer:

Ty = √k  * Tx

The orbital period of Y has to be be multiplied by √k .   or . k∧1/2

Step-by-step explanation:

The general equation:

T² = A³

is for the case of planet X

Tₓ² = Aₓ³

In the case of planet Y

Ty² = k * Aₓ³ .     and   Aₓ³ = Tₓ²

By substitution:

Ty² =  k *Tₓ²

Ty = √k  * Tx

Answer:

D: K^3/2

Step-by-step explanation:

Just took the test and this is right

Answer:

angle measurements of 35, 35, and 110°  

angle measurements of 40°, 60°, and 80°

Have a nice day! :)

Answer:

Step-by-step explanation:

Let d and r be the diameter and radius, respectively.

d² + 12² = 15²

d² = 15² - 12² = 81

d = √81 = 9

r = d÷2 = 4.5 mm

Answer:

false

Step-by-step explanation:

there is no graph...

Answer:

C

Step-by-step explanation:

(243)^(2/5)=3^2=9. C is the correct answer

It can be concluded that the equivalent value of the expression is 9.

An algebraic expression is a made up of terms both constants and variables. For example, we can write -

2x + 3y + z

5x + y

x + 8y

Given is the algebraic expression as -

[tex]$243^{\frac{2}{5} }[/tex]

The given algebraic expression is -

[tex]$243^{\frac{2}{5} }[/tex]

It is asked to find the equivalent value of this expression. We can write -

[tex]$243^{\frac{2}{5} }[/tex]

[tex]$3^{5\times \frac{2}{5} }[/tex]

3²

3 x 3

9

So, it can be concluded that the equivalent value of the expression is 9.

Therefore, it can be concluded that the equivalent value of the expression is 9.

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Answer:

Step-by-step explanation:

Hi there!

[tex]\large\boxed{log_b3b = 1.8397}[/tex]

Keep in mind the following log property:

logₓab = logₓa + logₓb

Thus:

[tex]log_{b}3b = log_{b}3 + log_{b}b\\\\[/tex]

We know the value of log_b3, and a log with the same values for the base equals 1. Thus:

[tex]log_b3b = 0.8397 + 1 = 1.8397[/tex]

Answer:

D.

Step-by-step explanation:

[7^(-8)]^(-4) =

A power raised to a power: multiply the exponents.

= 7^[(-8)*(4)]

= 7^(32)

Answer: D.

Answer:

7^32, the fourth option

Step-by-step explanation:

For the power rule, if you have a number to a power, for example [tex]x^{a}[/tex] and raise it to another power so it becomes, [tex](x^{a} )^{b}[/tex], We simplify by multiplying the powers together. So the simplified answer would be [tex]x^{(a*b)}[/tex].

Answer:

0.5

Step-by-step explanation:

k = y/x

k = 0.5/1

k = 0.5

Answer:

31.5 m

Step-by-step explanation:

Let w represent the width of the pool.

Since the length is 15 m greater than the width, it can be represented by w + 15.

Use the perimeter formula, p = 2l + 2w. Plug in the perimeter, and w + 15 as l into the formula:

p = 2l + 2w

96 = 2(w + 15) + 2w

96 = 2w + 30 + 2w

96 = 4w + 30

66 = 4w

16.5 = w

So, the width of the pool is 16.5 m. Add 15 to this to find the length:

16.5 + 15

= 31.5

The length of the pool is 31.5 m

Let the width be w

Length = w + 15

Now

Perimeter = 2(l + w)

96 = 2(w + 15 + w)

96/2 = w + 15 + w

48 = 2w + 15

48 - 15 = 2w

33 = 2w

33/2 = w

16.5 = w

Then,

Length = w + 15

Length = 16.5 + 15

Length = 31.5 m

[tex] \\ [/tex]

Answer:

Step-by-step explanation:

The zeros are located at x = 1 and x = 9. If x = 1 is a solution, then the factor is (x - 1); if x = 9 is a solution, then the factor is (x - 9). Choice A is the one you want. FOIL these out and you will get the equation for the quadratic.

Answer:

[tex]2\pi \times r = c[/tex]

[tex]\pi \times {r}^{2} = a[/tex]

A=5257.76

Step-by-step explanation:

Or use a calculator online.

Answer:

y -1 = 3/ 2( x + 3)

Step-by-step explanation:

m = (2 +4)/( 2+2)

m = 3/2

Answer:

216

Step-by-step explanation:

π=3

r=3

h=8

so,

πr²h

= 3×3²×8

= 216

Answered by GAUTHMATH

Answer: (0, 12)

Step-by-step explanation:

2x + 3y = 36

2(0) + 3y = 36

3y = 36

3/3 36\3

= 12

On edge

Answer:

a

Step-by-step explanation:

Answer:

The answer that I got is C I hope I'm right

Answer:

OAmalOHopeO

5x+4-2x là biểu thức đại số

Answer:

22 m/s

Step-by-step explanation:

Take the distance and divide by the time

1210 m/55s

22 m/s

Answer:

Step-by-step explanation:

[tex]speed = \frac{distantce}{time} \\ = \frac{1210m}{55s} \\ = 22m {s}^{ - 1} [/tex]

Answer:

X = 32, y = 16

Step-by-step explanation:

Cos 30 = (16√3) ÷ x

x = (16√3) ÷ cos 30

x = 32

Sin 30 = y ÷ 32

y = 32 sin 30

y = 16

Answer:

answer of this qn is 15in^2

Answer:

A = 21

Step-by-step explanation:

Complementary angles add to 90

x-21 + 2x-15 = 90

Combine like terms

3x -36 = 90

3x-36+36 = 90+36

3x = 126

Divide by 3

3x/3 =126/3

x = 42

We want to find ZA = x-21

A = 42-21

A = 21

If the sum of the measures of two angles is 90° they are known as complementary angles.

[tex] \bf \large \longrightarrow \: \:( x \: - \: 21) \: + \: (2x \: - \: 15) \: = \: 90 \degree[/tex]

Now , Opening brackets and simplifying

[tex] \bf \large \longrightarrow \: \: x \: - \: 21 \: + \: 2x \: - \: 15\: = \: 90 \degree[/tex]

[tex]\bf \large \longrightarrow \: \:3x \: - \: 36 \: = \: 90 \degree[/tex]

[tex]\bf \large \longrightarrow \: \:3x \: = \: 90 \: + \: 36[/tex]

[tex]\bf \large \longrightarrow \: \:3x \: = \: 126[/tex]

[tex]\bf \large \longrightarrow \: \:x \: = \: \frac{126}{3} \\ [/tex]

[tex]\bf \large \longrightarrow \: \:x \: = \: \cancel\frac{126}{3} \: \: \large \: ^{42} \\ [/tex]

[tex]\bf \large \longrightarrow \: \: x \: = \: 42[/tex]

Now , we have to find ZA .

[tex]\bf \large \implies \: \:A \: = \: 42 \: - \: 21[/tex]

[tex]\bf \large \implies \: \:A \: = \: 21[/tex]

The measure of angle ZA is 21°

Answer:

B. slope 1/4, y-intercept at ( 0, 5)

Step-by-step explanation:

slope m = change in y /chance in x = 5-4 / 0-(-4) = 1 / 4

the y-intercept is the point where the graph of the line intersects the y-axis so will have the coordinates (0 because x will be 0 if the point is on the y-axis, and y is a number) so is (0, a number)

we are given that one of the points is (x=0, y=5) so this is our y-intercept

OR

the slope intercept form equation of a line y= mx+b, where b is the y-intercept

y = (1/4)x +b, for the point (0, 5) we substitute x=0, and y=5

5 = (1/4)*0 +b

5 = b

South would be straight down (leg 1 of the triangle) and east would be right from that point (leg 2 of the triangle). Therefore, we are looking for the hypotenuse of the triangle.

Pythagorean Theorem: a^2 + b^2 = c^2

6^2 + 5^2 = c^2

36 + 25 = c^2

61 = c^2

c = sqrt(61)

c = 7.8 miles

Hope this helps!

Answer:

El problema esta incompleto, pero es facil ver que se desea estudiar el enfriamiento de la olla.

Sabemos que la ecuación de enfriamiento de Newton es:

[tex]T (t) = T_s + (T_0 - T_s)*e^{-k*t}[/tex]

Donde t es el tiempo.

[tex]T_s[/tex] es la temperatura del ambiente, en este caso es 12°C

[tex]T_0[/tex] es la temperatura inicial del objeto, en este caso 175°C

k es una constante, que es lo que usualmente se pide obtener en este tipo de problemas.

Reemplazando esos valores en nuestra ecuación obtenemos:

[tex]T(t) = 12 + (175 - 12)*e^{-k*t}\\\\T(t) = 12 + (163)*e^{-k*t}[/tex]

Ahora se nos dice:

"Luego de 10 minutos, la temperatura de la olla será de 100°C"

(estos valores no son necesariamente los del problema, son unos valores genéricos para poder mostrar como se resuelve este tipo de ejercicio)

Entonces, T(10 min) = 100°C

Reemplazando eso en nuestra ecación, obtenemos:

[tex]T(10 min) = 100 = 12 + (163)*e^{-k*10min}[/tex]

Ahora podemos despejar el valor de k resolviendo la ecuación de arriba.

[tex]100 - 12 = (163)*e^{-k*10min}\\\\88 = (163)*e^{-k*10min}\\\\88/163 = e^{{-k*10min}[/tex]

Ahora podemos recordar que:

ln(e^x) = x

Entonces aplicando el logaritmo natural a ambos lados, obtenemos:

[tex]ln(88/163) = ln(e^{-k*10min}) = -k*10min\\\\ln(88/163)/(-10 min) = k = 0.062 min^{-1}[/tex]

Así hemos encontrado el valor de k, y con exactamente el mismo método podríamos encontrar k en cualquier situación de este tipo.

A recursive relation is a relation that defines the terms in a sequence with the previous terms.

Here, the recursive relation will be:

[tex]A_n = 2*A_{n - 1} + $50[/tex]

A₁ = $150.

We know that:

Sarah has saved $150 at the moment.

She wants to double the amount that she saves each month, so the next month she needs to save 2*$150 = $300

And if she saves the $300, then her grandma will give her another $50.

Then, if the previous month Sarah saved A, then the next month she will get the double of A plus $50, which is:

2*A + $50

Then the recursive relation is just:

[tex]A_n = 2*A_{n - 1} + $50[/tex]

Where Aₙ is the amount that she saves in the n-th month, and the first term of the sequence is the initial amount that she saved, so we have:

A₁ = $150.

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The calculated measure of the angle QSR is 68 degrees

From the question, we have the following parameters that can be used in our computation:

Angle b = 136 degrees

The measure of angle QSR can be calculated using

QSR = 1/2 * Angle b

substitute the known values in the above equation, so, we have the following representation

QSR = 1/2 * 136 degrees

Evaluate

QSR = 68 degrees

Hence, the measure of angle QSR is 68 degrees

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To find the time in which all the bells ring together, we need to find the LCM of 36,40,48.

Prime factorization of 36=2×2×3×3

Prime factorization of 40=2×2×2×5

Prime factorization of 48=2×2×2×2×3

Hence, LCM of 36,40,48=2×2×2×2×3×3×5=720 seconds.

720seconds=  

60

720

​

minutes=12minutes

Hence, all the bells will ring together after 12 mi

Answer:

9pm or 12 hours from 9am.