Find the area of the bolded outlined sector.

Answer:

24 hours

Step-by-step explanation:

The formula is

1/a + 1/b = 1/c  where a and b are the times alone and c is the times together

1/12 + 1/b = 1/8

Multiply by 24b to clear the fractions

24b(1/12 + 1/b = 1/8)

2b + 24 = 3b

Subtract 2b from each side

2b +24-2b = 3b-2b

24 = b

Answer: 32

No of workers = 8

No of days = 32

Now no of days = 8

Let the number of workers be x

ATQ

256/x = 8

x = 256/8

x = 32

Must click thanks and mark brainliest

Answer:

15

Step-by-step explanation:

the difference of 8 and 3 : 8-3 = 5

sum of 7 and 5 : 7+5 = 12

a quarter of that sum : 12/4 = 3

the difference from before is now multiplied by that quarter : 5 × 3 = 15

I know, you are a beginner, but you don't know basic arithmetic calculation of +, -, × , / ? really ?

Multiplication is the process of multiplying, therefore, adding a number to itself for the number of times stated. The solution of the difference of 8 and 3 is multiplied by one-quarter of the sum of 7 and 5 is 15.

Multiplication is the process of multiplying, therefore, adding a number to itself for the number of times stated. For example, 3 × 4 means 3 is added to itself 4 times, and vice versa for the other number.

The statement can be solved as shown below,

1.   The difference between 8 and 3,

     8 - 3 = 5

2.   The difference between 8 and 3 is multiplied by one-quarter of the    sum of 7 and 5,

    ​[tex](8-3) \times \dfrac{(7+5)}{4}\\\\= 5 \times \dfrac{12}{4}\\\\= 15[/tex]

Hence, the solution of the difference of 8 and 3 is multiplied by one-quarter of the sum of 7 and 5 is 15.

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Answer:

can you translate in english,would be better...

answer maybe wrong because of the language but stil....

9x(2+6x+1)

=9x(9x)

81x..

Lets do

[tex]\\ \Large\sf\longmapsto 150:450:750[/tex]

[tex] \\ \Large\sf\longmapsto \frac{150}{ \dfrac{450}{750} } \\ \\ \Large\sf\longmapsto \frac{15}{ \dfrac{45}{75} } \\ \\ \Large\sf\longmapsto \frac{3}{ \dfrac{9}{15} } \\ [/tex]

Simplified ratio is

[tex]\boxed{\LARGE{\sf \$1:\$3:\$5}}[/tex]

Answer:

1        : 3     : 5

Step-by-step explanation:

$150 : $450 : $750

Divide each by 150

$150/150 : $450/150 : $750/150

1        : 3     : 5

Answer:

the answer is B.

Step-by-step explanation:

it is not A is because if the radius is 6 then the volume will be 904.32

the answer is B.

because is the radius is 2 cm then the area I calculate with this radius is 33.4933333333 and the question want the approximate radius and out of all the numbers this one is the closest so the answer is B

Answer:

11. 40.5

12. 84

Step-by-step explanation:

Answer:

((3.55)^2+(4.12)^2+(4.41)^2)/2(3.55)*(4.12)

=358.519825

Step-by-step explanation:

I just used this website called mathpapa.com, extremely useful for algebra calculations. Here's the link if you need it

https://www.mathpapa.com/algebra-calculator.html

Answer:

180+120-250=50

........

Answer:

c is -30

Step-by-step explanation:

I. 1/a - 1/b - 1/d = 1/c

II. 1/2 - 1/3 - 1/5 = 1/c

III. (15-10-6)/30 = 1/c

IV. -1/30 = 1/c

V. so c.value is -30

==========================================================

Explanation:

"Use 3 for pi" is something I've never seen a teacher do before. Usually it's "use 3.14 for pi".

Anyway, the diameter of this cylinder is 2 inches, which cuts in half to 1 inch. This is the radius.

The height is 10 inches.

So we have r = 1 and h = 10

V = pi*r^2*h

V = 3*1^2*10

V = 30 cubic inches approximately

Answer:

V = 30

Step-by-step explanation:

1. lets find the radius

r = 1/2 diameter

2/2 = 1

r = 1

2. plug in our info into the equation!!!- using 3 for pi as said in the question

V = (pi) r^2 h

V = (3)*(1)^2*(10)

3. solve

V = 30

Step-by-step explanation:

here's the answer to your question

Answer:

[tex]g(x) \times f(x) = 3{x}^{3} -3x[/tex]

X exists for all real numbers.

Y exists for all real numbers.

Answer: g(x) = (1/2)3^-x  reflection over y axis yields (-x,y)

Answer:

60

would be right

Step-by-step explanation:

Total length of cable required is 466.18 m.

Pythagoras theorem states that In a right-angled triangle, the square of the hypotenuse side is equal to the sum of squares of the other two sides.

According to the question

A 100m mast is supported by six cables in two sets of three cables.

They are anchored to the ground at an equal distance from the mast.

The top set of three cables is attached at a point 20m below the top of the mast.

Each cable in the lower set of three cables is 60m long and is attached at a height of 30m above the ground.

One set of guy wires (1 upper and one lower have two right triangles which can solve

The lower right triangle

a = distance from the pole to guy tie point

b = 30 m

c = 60 m the lower guy wire (the hypotenuse)

Using Pythagoras theorem

[tex]a^{2} +30^{2} =60^{2}[/tex]

⇒ [tex]a^{2} = 3600 - 900[/tex]

⇒ [tex]a^{2} =2700[/tex]

⇒ [tex]a = \sqrt{2700}[/tex]

⇒ [tex]a = 51.96[/tex] m from the pole to the tie point.

The other triangle using upper guy wire as the hypotenuse (h) tied to a point on the pole 80 m from the ground (20 m from the top) and also 50m from the tie point.

Using Pythagoras theorem

[tex]h^{2} =(51.96)^{2} +80^{2}[/tex]

⇒ [tex]h^{2}=2700+6400[/tex]

⇒ [tex]h^{2}=9100[/tex]

⇒ [tex]h = \sqrt{9100}[/tex]

⇒ [tex]h = 95.39[/tex] m , the length of the upper guy wire

For one set of guy wires (1 upper & 1 lower):

= 95.39 + 60

= 155.39 m

For 3 sets of guy wires :

= 3(155.39)

= 466.18 m of wire required

Hence, total length of cable required is 466.18 m.

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The volume of the solid as shown in the task content is; 2786.2cm³.

It can be obtained from the task content that the solid given is a Cone.

On this note, the volume of the cone can be evaluated by means of the formula;

V = (1/3)π r²h where(r =22/2 = 11 and h=22).

Hence, Volume, V = (1/3) ×3.14× (11)²×22 = 2786.2cm³.

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Answer:

A) y=(1/4)x-1, 4y=x-4

B) y=-2x

Answer:

AB=44.98298

Step-by-step explanation:

Since this is  a right triangle, we can use trig functions

cos theta = adj / hyp

cos 12 = 44/AB

AB cos 12 = 44

AB = 44/ cos 12

AB=44.98298

Step-by-step explanation:

T0 = a³+4

T1 = a⁴x a¹ +4

T2= a³ + a³ + 4

T3= a⁴ + a⁴* a² + 4

T4= a⁴ + a⁴ x a¹ + 4

T5= a³ + a³ + a⁴+4

Answer:

hello,

Step-by-step explanation:

c(1)=5

c(2)=9

c(2)-c(1)=9-5=4

c(2)=9

c(3)=13

c(3)-c(2)=13-9=4

c(3)=13

c(4)=17

c(4)-c(3)=17-13=4

c(4)=17

c(5)=21

c(5)-c(4)=21-17=4

for n=1,2,...,k :

c(n+1)-c(n)=4 and c(n+1)=4*(n+1)+1=4n+5

c(1)=1

Answer:

1st option

1st graph has the centre on (-1,-2) and the distance of the circumference from the centre is 2

Answered by GAUTHMATH

====================================================

Work Shown:

Plug in x = 0

[tex]f(x) = \frac{2x-1}{3x+5}\\\\f(0) = \frac{2*0-1}{3*0+5}\\\\f(0) = \frac{0-1}{0+5}\\\\f(0) = -\frac{1}{5}\\\\[/tex]

Repeat for x = 8

[tex]f(x) = \frac{2x-1}{3x+5}\\\\f(8) = \frac{2*8-1}{3*8+5}\\\\f(8) = \frac{16-1}{24+5}\\\\f(8) = \frac{15}{29}\\\\[/tex]

Now use the average rate of change formula

[tex]m = \frac{f(b)-f(a)}{b-a}\\\\m = \frac{f(8)-f(0)}{8-0}\\\\m = \frac{15/29 - (-1/5)}{8}\\\\m = \frac{15/29 + 1/5}{8}\\\\m = \frac{(15/29)*(5/5) + (1/5)*(29/29)}{8}\\\\m = \frac{75/145 + 29/145}{8}\\\\[/tex]

[tex]m=\frac{104/145}{8}\\\\m = \frac{104}{145} \div \frac{8}{1}\\\\m = \frac{104}{145} \times \frac{1}{8}\\\\m = \frac{104*1}{145*8}\\\\m = \frac{104}{1160}\\\\m = \frac{13}{145}\\\\[/tex]

Step-by-step explanation:

The total of the number of computers he sold in 2015 is 67.

The total of the number of computers he sold in 2016 is 61.

The total of the number of computers he sold in 2017 is 71.

He sold 35 computers in Quarter 1, 24 in Quarter 2, 61 in Quarter 3, and 79 in Quarter 4.

He sold the most computers in 2017 and the least in Quarter 2.

Therefore, to find the total number of computers he sold all time, we add 67, 61, and 71 together to get 199.

Hope this helped!

Answer with Step-by-step explanation:

From the given table

(a)

In quarter 1

Computer sold in 2015=12

Computer sold in 2016=15

Computer sold in 2017=8

Total computer sold in quarter 1=12+15+8=35

In quarter 2

Computer sold in 2015=9

Computer sold in 2016=10

Computer sold in 2017=5

Total computer sold in quarter 2=9+10+5=24

In quarter 3

Computer sold in 2015=21

Computer sold in 2016=17

Computer sold in 2017=23

Total computer sold in quarter 3=21+17+23=61

In quarter 4

Computer sold in 2015=25

Computer sold in 2016=19

Computer sold in 2017=35

Total computer sold in quarter 4=25+19+35=79

In 2015

Total number of computer sold=12+9+21+25=67

In 2016

Total number of computer sold=15+10+17+19=61

In 2017

Total number of computer sold=8+5+23+35=71

(b)He sold the most computers in 2017

(c) He sold the least computers in quarter 2.

Answer:

where is the figure without figure how to find out

Answer:

5a+4a=9a

3b-7b=-4b

2ab

=9a-4b+2ab or 2ab+9a-4a

Step-by-step explanation:

Calculate liked terms

The median GPA of the  percussionists is 2.8

This question appears incomplete.

Here is the complete question :

Members of a band class were arguing over which instruments are played by the best academic students. A survey was conducted, and here are the results:

All 13 flute players had a grade point average (GPA) between 3.84 and 3.88.

There were only 3 percussionists. One had a GPA of 2.4, one had a GPA of 2.8, and one had a GPA of 3.2.

Among the saxophone players, 4 had a GPA of 3.9, and the other 5 had a GPA of 4.0.

For percussionists, the median GPA is _____.

Median can be described as the number that occurs in the middle of a set of numbers that are arranged either in ascending or descending order

Median is a measure of central tendency

Other measures of central tendency include  mean and mode.

The GPA of the 3 percussionists are 2.4, 2.8 and 3.2

This data has already been arranged in ascending order.

The number that is in the middle is 2.8

Conversely, if the GPA is arranged in descending order, it is 3.2, 2.8 and 2.4

The number that is in the middle is 2.8

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Question 10

Draw a 30-60-90 triangle template. Refer to the diagram below.

We have 1 as the short leg, 2 as the hypotenuse and sqrt(3) as the long leg.

Place the angle theta as the reference angle such that it's opposite the sqrt(3) side.

That allows tan(theta) = sqrt(3)/1 = opposite/adjacent

In other words, tan(60) = sqrt(3)/1

So theta = 60 is one solution. We add on 180 to get the other solution. So the other solution is 60+180 = 240

So tan(60) = tan(240) = sqrt(3)

======================================================

Question 11a

sin(theta) = -0.8

theta = arcsin(-0.8) or theta = 180-arcsin(-0.8)

theta = -53.1301  or theta = 180 - (-53.1301)

theta = -53.1301  or theta = 233.1301

Add 360 to the first angle to find a coterminal angle counterpart.

-53.1301 + 360 = 306.8699

So the two approximate solutions are

theta = 306.8699  or theta = 233.1301

and those round to 306.9 and 233.1 respectively.

======================================================

Question 11b

cot(theta) = 1.8

tan(theta) = 1/(1.8)

theta = arctan( 1/(1.8) )  or theta = 180+arctan( 1/(1.8) )

theta =  29.0546 or theta = 180+29.0546

theta = 29.0546 or theta = 209.0546

theta = 29.1 or theta = 209.1

Answer:

-19>t

Step-by-step explanation:

-6>t-(-13)

-6>t +(13)

Subtract 13 from each side

-6-13 > t+13-13

-19>t