Find the 5 data points needed for a box plot of the given data set: { 8, 19, 11, 20, 2, 14, 17, 9, 15}

Give the answers in order from least to greatest.

Data Point 1:

Data Point 2:

Data Point 3:

Data Point 4:

Data Point 5:

Answers

Answer 1

Answers:

Data Point 1:    2   Data Point 2:   8.5   Data Point 3:    14   Data Point 4:    18   Data Point 5:    20  

The boxplot is shown below.

=========================================

Explanation:

What your teacher wants is the five number summary.

This consists of:

MinQ1MedianQ3Max

Given in that exact order.

The given data set is  { 8, 19, 11, 20, 2, 14, 17, 9, 15}

This sorts to  {2, 8, 9, 11, 14, 15, 17, 19, 20}

From this sorted set, we see that 2 is the smallest item. So this is the min value. This is data point 1.

The max is the largest item, which in this case is 20, so this value goes in the box for data point 5.

---------------------

Count out the number of values in the sorted set. You should count out n = 9 items.

Because n is odd, this means the median is in slot n/2 = 9/2 = 4.5 = 5

The value in the 5th slot is 14 which is the median (data point 3).

-----------------------

Once you determine the median, break the sorted set up like so

L = {2, 8, 9, 11}

U = {15, 17, 19, 20}

L is the lower set of values smaller than the median

U is the upper set of values larger than the median

The median itself is not part of set L and not part of set U either. It's ignored entirely from this point on.

From here, we find the middle values of L and U

You should find that the middle value of L is (8+9)/2 = 17/2 = 8.5 which is the value of Q1 (data point 2)

And also, the middle value of set U is (17+19)/2 = 36/2 = 18 which is the value of Q3 (data point 4)

-----------------------

To wrap everything up, we have this five number summary

Min = 2Q1 = 8.5Median = 14Q3 = 18Max = 20

These will determine the features of the boxplot as shown below.

In this case, there are no outliers.

Find The 5 Data Points Needed For A Box Plot Of The Given Data Set: { 8, 19, 11, 20, 2, 14, 17, 9, 15}Give

Related Questions

Find the length of the arc. Round your answer to the nearest tenth​

Answers

Answer:

12.6 mi

Step-by-step explanation:

Arc length = 2πr (Θ/360)

2π(12) (60/360)

= 12.6 mi

Answered by g a u t h m a t h

Express the prime number 19 as the difference of two squares? 19 =​

Answers

Answer:

The two squares are 81 and 100, and their difference is 19

Step-by-step explanation:

Hey there!

Let's take out the square of 1st ten natural numbers to find out the exact answer.

1² = 1

2² = 4

3² = 9

4² = 16

5² = 25

6² = 36

7² = 49

8² = 64

9² = 81

10² = 100

Now; You can take any of these numbers and subtract from their squares.

So, let's check 6² and 5²

36-25 = 11 which is not equal to 19

Again check for 10²-9²

100 - 81 = 19 (True value)

Therefore, 19 can be expressed as the difference of square of 10 and 9.

Hope it helps!

find the sum of the given infinite geometric series​. NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW

Answers

Answer:

320/3

Step-by-step explanation:

First find the common ratio

20/80 = 1/4

The sum of an infinite geometric series

sum = a1/ (1-r)  where a1 is the first term and r is the common ratio

         =80/ ( 1-1/4)

         = 80/(3/4)

        = 80 *4/3

      = 320/3

Calculate the minimum number of subjects needed for a research study regarding the proportion of respondents who reported a history of diabetes using the following criteria:

95% confidence, within 5 percentage points, and a previous estimate is not known.

Answers

Answer:

The minimum number of subjects needed is 385.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].

The margin of error is:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

95% confidence level

So [tex]\alpha = 0.05[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].

95% confidence, within 5 percentage points, and a previous estimate is not known.

The sample size is n for which M = 0.05. We don't know the true proportion, so we use [tex]\pi = 0.5[/tex]

Then

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

[tex]0.05 = 1.96\sqrt{\frac{0.5*0.5}{n}}[/tex]

[tex]0.05\sqrt{n} = 1.96*0.5[/tex]

[tex]\sqrt{n} = \frac{1.96*0.5}{0.05}[/tex]

[tex](\sqrt{n})^2 = (\frac{1.96*0.5}{0.05})^2[/tex]

[tex]n = 384.16[/tex]

Rounding up:

The minimum number of subjects needed is 385.

A sample of 4 different calculators is randomly selected from a group containing 14 that are defective and 34 that have no defects. What is the probability that at least one of the 4 calculators in the sample is defective

Answers

Answer:

The answer is "0.7616".

Step-by-step explanation:

Using formula:

[tex]\text{P( at least one de-fective) = 1 - P( all calculators work )}[/tex]

                                          [tex]= 1-(\frac{34}{48}\times \frac{33}{47}\times \frac{32}{46}\times \frac{31}{45})\\\\= 1-(\frac{34}{1}\times \frac{11}{47}\times \frac{1}{23}\times \frac{31}{45})\\\\=1-(\frac{11594}{48647})\\\\=\frac{48647-11594}{48647}\\\\=\frac{37051}{48647}\approx 0.7616[/tex]

A 230 pound man, a 140 pound woman, a 750 pound crate of equipment, an 80 pound bag of concrete. What percent of the total weight was concrete?
What percent of the total weight was human?

Answers

Concrete percent: 80/1200 = .0666666 = 6.7%
Human percent: 370/1200 = .308333 = 30.8 %

Solve the equation below:

5x – 11 = 19
x = 4
x = 6
x = 4.4
x = 1.6


pls answer i need help today

Answers

Answer:

x=6

Step-by-step explanation:

5x - 11 = 19

5x = 30

x = 6

20characters

5x = 19+11 5x = 30 x = 30/5 x = 6

Is the function f(x) = 1/8 ^x an exponent function? If so , identify the base , if not why not ?

Yes , the base is 1/e

yes, the base is e

No, there is no base that is a positive real number not equal to 1 raised to a variable exponent.

No, the base is the reciprocal of e, a number smaller than 1.

Answers

9514 1404 393

Answer:

  (a) Yes , the base is 1/e

Step-by-step explanation:

The variable is in the exponent, so this is an exponential function.

The base is the number that has the exponent. The base is (1/e).

Answer:

Step-by-step explanation:

bvxbvxbvxbvcvbbb cv

A silo is built in the shape of a cylinder with a cone for a roof. If the height of the
cylinder is 5 m, the radius is 2.8 m and the slant height of the cone is 6,6 m,
determine the amount of material needed to create the rounded sides and conical
roof, Round to the nearest tenth of a cubic m.

Answers

9514 1404 393

Answer:

  146.0 m²

Step-by-step explanation:

The lateral areas of the cylinder and cone are given by the formulas ...

  A = πrs . . . . cone area; radius r, slant height s

  A = 2πrh . . . . cylinder area; radius r, height h

__

The total area lateral area of the silo is ...

  A = π(2.8 m)(6.6 m) +2π(2.8 m)(5 m) = π(2.8 m)(6.6 m +2(5 m)) = 46.48π m²

  A ≈ 146.0 m² . . . area of sides and roof of silo

_____

Additional comment

The answer is requested in cubic meters. Area has units of square meters. There is nothing in this problem statement that seems to be requesting a volume, which is what would have units of cubic meters.

Solve for x. Round to the nearest tenth, if necessary.
S
540
R
2.3
X
O
Please help

Answers

Answer:

[tex]\boxed {\boxed {\sf x \approx 1.9}}[/tex]

Step-by-step explanation:

We are asked to find x, a missing side in a triangle.

This is a right triangle because there is a small square in the corner representing a 90 degree or right angle. Therefore, we can use right triangle trigonometry. The three main functions are:

sinθ= opposite/hypotenuse cosθ= adjacent/hypotenuse tanθ= opposite/adjacent

Examine the triangle. We will use angle S, measuring 54 degrees, for theta. Side QR, measuring x, is opposite angle S. Side QS, measuring 2.3, is the hypotenuse because it is opposite the right angle. Since we have the opposite and hypotenuse, we will use sine.

[tex]sin \theta = \frac {opposite}{hypotenuse}[/tex]

θ= 54opposite= x hypotenuse = 2.3

[tex]sin (54)= \frac{ x}{2.3}[/tex]

We are solving for x, so we must isolate the variable. It is being divided by 2.3 The inverse operation of division is multiplication, so we multiply both sides by 2.3

[tex]2.3* sin (54)= \frac{x}{2.3}*2.3[/tex]

[tex]2.3* sin (54)=x[/tex]

[tex]2.3*0.8090169944=x[/tex]

[tex]1.860739087 =x[/tex]

Round to the nearest tenth. The 6 in the hundredth place to the right tells us to round the 8 up to a 9.

[tex]1.9 \approx x[/tex]

x is approximately 1.9

Naomi invested $3,425 in an account that
pays 3% simple interest. what was the total
balance of the account after 15 years?

Answers

Answer:

$4,966.25

Step-by-step explanation:

3 x 15 = 45

After 15 years, Naomi would have earned a total of 45% interest rate.

3,425 x 1.45 = 4,966.25

Don't use .45 as the multiplier

3,425 x .45 = 1,541.25 <- incorrect

Answer: 4,966.25

Explanation: start by diving 3425 by .03 to get the amount of interest it is yearly giving you 102.75 and then multiply that by 15 since that’s the amount of years and get 1541.25 then add 3425 and 1541.25 together to get the final product of 4,966.25

What is a placement form from the school mean

Answers

Answer:

Placements are basically extended internships or work experience assignments

Step-by-step explanation:

You plan to charge $1 for each time a student plays, and the payout for a win is $5. According to your calculations, the probability of a win is .05. What is your expected value for this game? The expected value

Answers

Answer:

- $0.75

Step-by-step explanation:

For each game played the chance of winning is 0.05 and losing is 0.95.

If the student wins, they get $5 -$1 = $4, but they lose $1.

Expected value is:

4*0.05 - 1*0.95 = -0.75

It means you will make $0.75 per average game.

Answer:

21.8

Step-by-step explanation:

Step 1

This is a problem on finding the mean of continuous grouped data. We first find the midpoint of each interval. For example, the first interval or class is 0 - 10. The mid-point of this class will be (0 + 10)/2 = 5.

fullscreen

Step 2

We now calculate the product of mid-point and frequency for each class. Here, the number of athletes in each class is the frequency of that class. For example, for the first class 0 – 10, its frequency is 3.

fullscreen

Step 3

We can now use the formula to calculate mean. Note that t...

Write an equation that represents the line.
Use exact numbers.

Answers

Answer: y=2/3X- 4/3

Step-by-step explanation:

Slope = (4-2)/(4-1)=2/3

Y-2=2/3(x-1)

Y-2=2/3x-2/3

Y=2/3X-2/3+2

Y=2/3X-4/3

A trolley travels in one direction at an average of 20 miles per hour, then turns around and travels on the same track in the opposite direction at 20 miles per hour of the total time waveling on the trolleys 3.5 hours, how far did the trolley travel in one direction?
mi
Enter your answer in the answer box and then click Check Answer
Clear All
Help Me Solve This
an Example
Get More Help

Answers

9514 1404 393

Answer:

  35 miles

Step-by-step explanation:

The relevant relation is ...

  distance = speed × time

The total distance the trolley traveled is ...

  d = (20 mi/h) × (3.5 h) = 70 mi

The distance is the same in both directions, so the trolley traveled half this distance in one direction.

The trolley traveled 35 miles in one direction.

Determine the critical values for the confidence interval for the population standard deviation from the given values. Round your answers to three decimal places.
n = 12 and c = 0.9.

Answers

Answer:

The answer is "[tex]\chi^2_{L} = 4.575 \ and\ \chi^2_{U}= 19.675[/tex]"

Step-by-step explanation:

[tex]n=12\\\\\ c= 0.9[/tex]

Calculating the level of significance [tex](\alpha) = 1 -c[/tex]

                                                                  [tex]=1-0.9\\\\=0.1[/tex]

Calculating the degrees of freedom:

[tex]df=n-1=12-1=11[/tex]

Calculating the critical value:

Applying the Chi-Square table, the critical values for the two-tailed test with a degree of freedom  (11) for the significance level of [tex]\alpha = 0.1[/tex]:

[tex]\chi^2_{L} = 4.575 \\\\\chi^2_{U}= 19.675[/tex]

A biologist was interested in determining whether sunflower seedlings treated with and an extract from Vinca minor roots resulted in a lower average height of sunflower seedlings that the standard height of 15.7 cm. The biologist treated a random sample of 33 seedlings with the extract and subsequently measured the height of those seedlings. At the 0.01 significance level, is there evidence that the true average height of the seedlings treated with an extract from Vinca minor roots is less than 15.7 cm?

Height
15.5
15.8
15.7
15.1
15.1
15.5
15.2
15.7
15.8
15.4
16.2
15.5
16.2
15.5
15.4
16.3
14.9
15.3
15.1
16.1
15.3
15.4
15.1
15.3
14.6
15.1
15.0
15.3
15.8
15.5
14.8
15.2
14.8

a. State the null and alternative hypotheses.
b. Report the value of the test statistic. Round answer to 2 decimal places. (Either calculate or use software such as minitab)
c. Using the p-value, do you reject the null hypothesis or fail to reject the null hypothesis? Explain your decision.
d. Based on your decision in part (c), write a conclusion within the context of the problem.

Answers

Answer:

Kindly check explanation

Step-by-step explanation:

H0 : μ = 15.7

H1 : μ < 15.7

This is a one sample t test :

Test statistic = (xbar - μ) ÷ (s/√(n))

n = sample size = 33

Using calculator :

The sample mean, xbar = 15.41

The sample standard deviation, s = 0.419

Test statistic = (15.41 - 15.70) ÷ (0.419/√(33))

Test statistic = - 3.976

Using the Pvalue calculator :

Degree of freedom, df = n - 1 ; 33 - 1 = 32

Pvalue(-3.976, 32) = 0.000187

Decison region :

Reject H0 if Pvalue < α

Since Pvalue < α ; we reject H0

There is significant evidence to conclude that the true average height of the seedlings treated with an extract from Vinca minor roots is less than 15.7 cm.

Walnut High Schools Enrollment is exactly five times as large as the enrollment at walmut junior high the total enrollment for the two schools is 852 what is the enrollment at each school​

Answers

Answer:

142

Step-by-step explanation:

If the enrollment is five times as big, then that is six different things. So, take 852 and divide it by 6 to get 142. Or in other words:

852÷6=142

142x6=856

I hope this helps. Cheers^^

can yall answer it in the box like the numbers

Answers

Answer:

Hi!

Step-by-step explanation:

1234567890987654211234567890......

Step-by-step explanation:

12345678890098764321

The polygons in each pair are similar. Find the missing side length.

Answers

Let missing side be x

If both polygons are similar

[tex]\\ \sf\longmapsto \dfrac{3}{4}=\dfrac{18}{x}[/tex]

[tex]\\ \sf\longmapsto 3x=4(18)[/tex]

[tex]\\ \sf\longmapsto 3x=72[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{72}{3}[/tex]

[tex]\\ \sf\longmapsto x=24[/tex]

please help me with this

Answers

4x-4+12=20°+35°4x+8=55°4x=55°-84x=47°x=47÷4x=11.75x=12

or

4x-4=124x=12+44x=16x=16÷4x=4

please mark this answer as brainlist

Find the sequence of this term



41,40,48,38 35,--....,...​

Answers

Answer:

hxvkgyjdh ht yshysfhyys is not working properly configured form and the kids will not work with a little over again. thank you

The number N(t) of supermarkets throughout the country that are using a computerized checkout system is described by the initial-value problem

dN/dt = N(1 − 0.0008N), N(0) = 1.

Required:
Predict how many supermarkets are expected to adopt the new procedure over a long period of time?

Answers

Answer:

1250 supermarkets

Step-by-step explanation:

Given

[tex]\frac{dN}{dt} = N(1 - 0.0008N)[/tex]

[tex]N(0) = 1[/tex]

Required

Number of supermarkets over a long period of time

To do this, we simply set

[tex]\frac{dN}{dt} = 0[/tex]

So, we have:

[tex]N(1 - 0.0008N) = 0[/tex]

Split

[tex]N = 0\ or\ 1 - 0.0008N = 0[/tex]

Solve: [tex]1 - 0.0008N = 0[/tex]

Collect like terms

[tex]0.0008N = 1[/tex]

Make N the subject

[tex]N = \frac{1}{0.0008}[/tex]

[tex]N = 1250[/tex]

So:

[tex]\lim_{t \to \infty} N(t) = 1250[/tex]

Describe who is responsible for the cost and efficiency variances for direct materials, direct labor, and manufacturing overhead

Answers

Answer:

The materials price variance is usually the responsibility of the purchasing manager. The materials quantity and labor efficiency variances are usually the responsibility of production managers and supervisors.

I'm not sure how to do this

Answers

Answer:

1 and 5 sevenths of a bag

Step-by-step explanation:

2/7 males half to it takes 4/7 to make a full one multiply 4 by 3 and you get 12/7 so that makes 1 and 5/7

= 10 + 3
=13
Example 6
If f(x) = 2x + 1, g(x) = 3x - 2 and fg(x) = 5, find the value of x,​

Answers

Answer:

f(x) = 2x + 1, g(x) = 3x - 2 and fg(x) = 5

Step-by-step explanation:

A hose is left running for 240 minutes to 2 significant figures. The amount of water coming out of the hose each minute is 2.1 litres to 2 significant figures. Calculate the lower and upper bounds of the total amount of water that comes out of the hose.​

Answers

Answer:

Hello,

Step-by-step explanation:

Let say t the time the hose is left running

235 ≤ t < 245 (in min)

Let say d the amount of water coming out of the hose each minute

2.05 ≤ d < 2.15 (why d : débit in french)

235*2.05 ≤ t*d < 245*2.15

481.75 ≤ t*d < 526.75    (litres)

Answer:

Lower bound: [tex]495\; \rm L[/tex] (inclusive.)

Upper bound: [tex]505\; \rm L[/tex] (exclusive.)

Step-by-step explanation:

The amount of water from the hose is the product of time and the rate at which water comes out.

When multiplying two numbers, the product would have as many significant figures as the less accurate factor.

In this example, both factors are accurate to two significant figures. Hence, the product would also be accurate to two significant figures. That is:

[tex]240 \times 2.1 = 5.0 \times 10^{2}\; \rm L[/tex] ([tex]500\; \rm L[/tex] with only two significant figures.)

Let [tex]x[/tex] denote the amount of water in liters. For [tex]x\![/tex] to round to [tex]5.0 \times 10^{2}\; \rm L[/tex] only two significant figures are kept, [tex]495 \le x < 505[/tex]. That gives a bound on the quantity of water from the hose.

Teacher gives 2 questions to a class of 50 student. 30 students correctly answer ther first question, 25 students correctly answer the second question, 7 wongly answer both question, there are _ students correctly answer both question

Answers

Answer:

43

Step-by-step explanation:

only 7 out of the 50 got both wrong

Answer:

Step-by-step explanation:

Write the options so they are homogeneous in content. • Use answers given in previous open-ended exams to provide realistic distractors. 2. Use a Question ...


Ten samples were taken from a plating bath used in an electronics manufacturing process, and the bath pH was determined. The sample pH value are 7.91, 7.85, 6.82, 8.01, 7.46, 6.95, 7.05, 7.35, 7.25, 7.42. Manufacturing engineering believes that pH has a median value of 7.0. Do the sample data indicate that this statement is correct

Answers

Answer:

There is no sufficient evidence to support the claim.

Step-by-step explanation:

Given the data:

7.91, 7.85, 6.82, 8.01, 7.46, 6.95, 7.05, 7.35, 7.25, 7.42

Sample size, n = 10

The sample mean, xbar = ΣX/ n = 74.07 / 10 = 7.407

The sample standard deviation, s = 0.41158 ( from calculator)

The hypothesis :

H0 : μ = 7

H0 : μ ≠ 7

The test statistic :

(xbar - μ) ÷ (s/√(n))

(7.047 - 7) ÷ (0.41158/√(10))

0.047 / 0.1301530

Test statistic = 0.361

Testing the hypothesis at α = 0.05

The Pvalue ;

df = n - 1 ; 10 - 1 = 9

Two tailed test

Pvalue(0.361, 9) = 0.7263

Since the Pvalue > α ; we fail to reject the Null and conclude that there isn't sufficient evidence to support the claim.

Remy drinks 2/1/4 cups of water every 1/4/5 hours.

How many cups of water does he drink in 1 hour?

Answers

Answer:

1¼ cups

Step-by-step explanation:

2¼ ÷ 1/4/5 =

9/4 ÷ 9/5 =

9/4 x 5/9 =

5/4 = 1¼

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