Explain why this quadrilateral is not a parallelogram.

Answer:

While central tendency tells you where most of your data points lie, variability summarizes how far apart your points from each other. Data sets can have the same central tendency but different levels of variability or vice versa. Together, they give you a complete picture of your data.

Step-by-step explanation:

Answer:

$304

Step-by-step explanation:

4 Windows (each window has 1 blind and 2 panels of curtains)

1 blind = $20 * 4 = $80

1  panels curtains = $28 * 2 = $56 * 4 = $224

$80 + $224 = $304

Answer:

tanθ ≅ 0.4364

Step-by-step explanation:

This value is approximate.

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Explanation:

To find the perimeter, we simply add up the lengths of the three external sides.

The horizontal side from D to E is 16 units long since |-10-6| = 16. I subtracted the x coordinates of the points and applied absolute value. You could also count out the spaces and you should count 16 spaces from D to E.

Unfortunately, the diagonal lengths aren't as straight forward. We have two options here: The pythagorean theorem, or the distance formula.

I'll go with the distance formula.

Let's find the distance from C to D, aka the length of side CD

[tex]C = (x1,y1) = (-1,-2)\\\\D = (x2,y2) = (-10,0)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-1-(-10))^2 + (-2-0)^2}\\\\d = \sqrt{(-1+10)^2 + (-2-0)^2}\\\\d = \sqrt{(9)^2 + (-2)^2}\\\\d = \sqrt{81 + 4}\\\\d = \sqrt{85}\\\\d \approx 9.2195\\\\[/tex]

Side CD is roughly 9.2195 units long.

Repeat this idea to find the length of CE

[tex]C = (x1,y1) = (-1,-2)\\\\E = (x2,y2) = (6,0)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-1-6)^2 + (-2-0)^2}\\\\d = \sqrt{(-7)^2 + (-2)^2}\\\\d = \sqrt{49 + 4}\\\\d = \sqrt{53}\\\\d \approx 7.2801\\\\[/tex]

Side CE is roughly 7.2801 units long

The perimeter of triangle CDE is approximately...

P = DE+CD+CE

P = 16 + 9.2195 + 7.2801

P = 32.4996

This then rounds to 32.5 units. The answer is choice C.

Answer: -n+(-n-1)

Step-by-step explanation:

Expression will be -n + (-1)

Series

-4 +(-5)+(-6)+(-7)+(-8)+(-9)+(-10)+(-11)+(-12)+(-13) and so on

Here number -n has + (-n-1) being added to it

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Answer: Let the length of the hypotenuse be x

Applying the Pythagorean theorem we have :

x²=20²+48²

⇒x²=2704

⇒x=52( ∀ x >= 0 )

Step-by-step explanation:

Let assume the hypotenuse(longest side of right triangle) be x

By Pythagoras theorem

[tex] \bf \large \longrightarrow \: {c}^{2} \: = \: {a}^{2} \: + \: {b}^{2} [/tex]

Applying Pythagoras theorem

[tex] \bf \large \implies \: {x}^{2} \: = \: {20}^{2} \: + \: {48}^{2} [/tex]

[tex]\bf \large \implies \: {x}^{2} \: = \:400 \: + \: 2304[/tex]

[tex]\bf \large \implies \: {x}^{2} \: = \:2704[/tex]

[tex]\bf \large \implies \: \sqrt{x} \: = \: \sqrt{2704} [/tex]

[tex]\bf \large \implies \: \: x \: = \: 52[/tex]

Hence , the length of hypotenuse is 52.

19. 68 because 90seconds 1hr 30 mons

Answer:

make an 8 horizontal

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Answer:

TRUE

The number of multiples of a given number is finite is a false statement. The number of multiples of a given number is infinite.

Examples:

Multiples of 2 = 2,4,6,8,10,…..

Multiples of 3 = 3,6,9,12,15,18,…

Multiples of 4 = 4, 8, 12, 16, 120, 24….

∴ The number of multiples of a given number is infinite .

Answer From Gauth Math

9514 1404 393

Answer:

Step-by-step explanation:

Dilation has no effect on angle measures, so ∠A = ∠A'.

Point A is the center of dilation, so doesn't move. Any line through point A will still go through point A after dilation. Lines AD and A'D' are not distinct.

Answer:

1/6 or 16.6%

Step-by-step explanation:

There are 6 possible combinations, one of which being whole wheat with thick crust. Therefore there is a 1/6 chance.

At three meters, the difference in the decibel level if and if not connected to the speaker is 1.5 dB

The reason for arriving at the above value is as follows:

The known parameters:

The audio sensed by the microphone when connected to the speaker are;

0 meters = 60 decibels

The level of the decibel decrease by half for each additional meter;

Therefore, when the microphone is connected to the speaker, we have;

[tex]\begin{array}{|c|cc|}\mathbf{Distance \ (m)}&&\mathbf{Sound \ (dB)}\\0&&60\\1&&30\\2&&15\\3&&7.5\end{array}\right][/tex]

If the microphone is not connected to the speaker, we have;

0 meters = 30 decibels

The level of the decibel decreasing by 8 dB for every additional meter from the speaker, therefore, when the microphone is not connected to the speaker we have;

[tex]\begin{array}{|c|cc|}\mathbf{Distance \ (m)}&&\mathbf{Sound \ (dB)}\\0&&30\\1&&22\\2&&14\\3&&6\end{array}\right][/tex]

At three meters from the speaker, the difference in the decibel level when it is connected and when it is not connected to the speaker is therefore;

Decibel level at 3 meters when connected, s₁ = 7.5 dB

Decibel level at 3 meters when not connected, s₂ = 6 dB

The difference in the decibel level = s₂ - s₁ = 7.5 dB - 6 dB = 1.5 dB

The difference in the decibel level when connected to the speaker and when not connected to the speaker is 1.5 dB

Learn more about sound level here:

https://brainly.com/question/11047787

Answer:

It would cost you 9.6 dollar .

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Answer:

i have attached pic of the graph

i hope this helps you

Answer:

[tex]C. \ \ \ 86[/tex]°

Step-by-step explanation:

1. Approach

In order to solve this problem, one must first find a relationship between arc (a) and arc (c). This can be done using the congruent arcs cut congruent segments theorem. After doing so, one can then use the secants interior angle to find the precise measurement of arc (a).

2. Arc (a) and arc (c)

A secant is a line or line segment that intersects a circle in two places. The congruent segments cut congruent arcs theorem states that when two secants are congruent, meaning the part of the secant that is within the circle is congruent to another part of a secant that is within that same circle, the arcs surrounding the congruent secants are congruent. Applying this theorem to the given situation, one can state the following:

[tex]a = c[/tex]

3. Finding the degree measure of arc (a),

The secants interior angle theorem states that when two secants intersect inside of a circle, the measure of any of the angles formed is equal to half of the sum of the arcs surrounding the angles. One can apply this here by stating the following:

[tex]86=\frac{a+c}{2}[/tex]

Substitute,

[tex]86=\frac{a+c}{2}[/tex]

[tex]86=\frac{a+a}{2}[/tex]

Simplify,

[tex]86=\frac{a+a}{2}[/tex]

[tex]86=\frac{2a}{2}[/tex]

[tex]86=a[/tex]

Answer:

The correct label of the line is CD

Answer:

p = 5

Step-by-step explanation:

hopefully it is clear and understandable :)

Answer:

288 km²

Step-by-step explanation:

Surface area,

(10×10)+(9.4×10×2)

= 100+188

= 288 km²

Answer:

Step-by-step explanation:

Area = L * W

L = 1/2

Area = 5/16

5/16 = 1/2 * w    You could do this using decimals

5/16 = 0.3125

1/2 = 0.5

0.3125 = 0.5 * w

w = 0.3125/0.5

w = 0.625

w = 5/8

The other way is done by fractions

[tex]\frac{\frac{5}{16} }{\frac{1}{2} } = \frac{5}{16}*\frac{2}{1} =\frac{5}{8}[/tex]

There are a couple of notes

Answer:

The area of circle is 12.56m sq.

Answer:

hope this help you

sorry if it is mistake

9514 1404 393

Answer:

  -13/11

Step-by-step explanation:

Straightforward evaluation of the expression at x=1 gives (1 -1)/(1 -1) = 0/0, an indeterminate form. So, L'Hopital's rule applies. The ratio of derivatives is ...

  [tex]\displaystyle\lim_{x\to 1}\dfrac{n}{d}=\dfrac{n'}{d'}=\left.\dfrac{\dfrac{4}{3\sqrt[3]{4x-3}}-\dfrac{7}{2\sqrt{7x-6}}}{\dfrac{5}{2\sqrt{5x-4}}-\dfrac{2}{3\sqrt[3]{2x-1}}}\right|_{x=1}=\dfrac{4/3-7/2}{5/2-2/3}=\dfrac{8-21}{15-4}\\\\=\boxed{-\dfrac{13}{11}}[/tex]

Equate what is inside cosine with [tex]2\pi[/tex], base period and solve for x,

[tex]2\pi=\frac{\pi}{3}x[/tex]

[tex]6\pi=\pi x[/tex]

[tex]\boxed{x=6}[/tex]

Hope this helps :)

Answer:

Option A, m⁴/n²

Multiply the exponent 6 with the exponents of m and n

Answer:

θ = [tex]\frac{\pi}{4}[/tex]  

θ = [tex]\frac{7\pi}{4}[/tex]

Step-by-step explanation:

2cosθ - √2 = 0

First, add √ 2 to both sides

2cosθ - √2 = 0

          +√2  +√2

2cosθ = √2

Divide both sides by 2

2cosθ/2 = √2 / 2

cosθ = [tex]\frac{2}{\sqrt{2}}[/tex]

Use arccos to find θ

arccos([tex]\frac{2}{\sqrt{2}}[/tex]) = [tex]\frac{\pi}{4}[/tex]  and  [tex]\frac{7\pi}{4}[/tex] = θ

The three main log rules you'll encounter are

The first rule allows us to go from a log of some product, to a sum of two logs. In short, we go from product to sum. The second rule allows us to go from a quotient to a difference. Lastly, the third rule allows to go from an exponential to a product.

Here are examples of each rule being used (in the exact order they were given earlier).

----------------

Here's a slightly more complicated example where the log rules are used.

log(x^2y/z)

log(x^2y) - log(z)

log(x^2) + log(y) - log(z)

2*log(x) + log(y) - log(z)

Hopefully you can see which rules are being used for any given step. If not, then let me know and I'll go into more detail.

Answer:

m=5+t/2-s

Step-by-step explanation:

arrange like terms

2m-sm=5+t

factotise m in the first side of the equation

m(2-s)=5+t

divide both sides by (2-s)

therefore m=5+t/2-s

Answer:

6/15.

14/42.

Step-by-step explanation:

2/5 = 6/x

Cross multiply:

2x = 5*6

x = 15

Similarly:

10/30 = 14/x

10x = 30*14

x = 420/10

x = 42.

Answer:

A'(0,-8) B'(5,-7) C'(3,0) D'(2,-5)

A''(0,8) B''(-5,7) C''(-3,0) D''(-2,5)

Step-by-step explanation:

first everything is shifted down 8 units (x,y-8), so we get A'(0,-8) B'(5,-7) C'(3,0) D'(2,-5)

then you multiply by -1 A''(0,8) B''(-5,7) C''(-3,0) D''(-2,5)