Answer:
30
Step-by-step explanation:
Permutation equation: [tex]\frac{n!}{(n-r)!}[/tex]
n = Total number of objects, r = Number of objects selected
[tex]_6P_2=\frac{6!}{(6-2)!}=30[/tex]
A regular polygon is drawn in a circle so that each vertex is on the circle and is connected to the center by a radius.
Each of the central angles has a measure of 40°. How many sides does the polygon have?
THE
9
Answer: 90 sides
Step-by-step explanation:
Let's say the circle has a center at A and B and C are at the vertices of a polygon. Since this figure is inscribed in a circle, we can draw two radii through the vertices. Because all radii are congruent, we know segment BA is congruent to Segment CA. If a triangle has at least 2 congruent sides, we can identify the triangle as an isosceles triangle. With this we can conclude <ACB is congruent to <ABC. By the definition of congruent angles, m<ACB = M<ABC. Let's say m<ACB = x. By the Triangle Sum Theorem, 40 + x + m<ABC = 180. By substitution, 40 + x + x = 180. When we solve we get x =70. Since radii bisect interior angles we know that each interior angle of this polygon is 140 degrees. If we plug in 140 to our equation, [tex]\frac{(n-2)180}{n}[/tex] where n is the number of sides, we get n = 90. So we can conclude this polygon has 90 sides
Jenny paid 1/4 of her car loan so far she has paid 900 dollars what was the total amount of the loan.
urgent please help! will give brainliest
Answer:
The answer is A
Step-by-step explanation:
(-2,-3) (3,-4) (0,-1) (-7,3)
inverse means the opposite signs
(2,3) (-3,4) (0,1) (7,-3)
Assume 2 in every 3000 students at the local community college have to quit due to serious health issues. An insurance company offers them $12000 policy for $40a year. What is the amount the insurance company should expect to make on average on every student that pays?
The amount the insurance company should expect to make on average on every student that pays is $
Answer:
$32
Step-by-step explanation:
Multiply $40*3000 students. Subtract 2 students that might receive a $12000 policy each. Divide by 3000 students to find average payout.
Q: EXPRESS IT IN THE FORM OF LINEAR EQUATION IN ONE VARIABLE:
•The ordinate of a point is thrice its abscissa.
Answer:
y = 3x
Step-by-step explanation:
abscissa is the x coordinate
ordinate is the y coordinate
y = 3x
Helppp!!!!!
Please!!!
{ is question #1 is right?? }
{ i need help with question #2 please }
Please!!
Helppp!!!!!
Answer:
fyi b's answer has imaginary numbers in it...
Imaginary: 1 +[tex]\frac{\sqrt{2i} }{2 }[/tex]
Imaginary: 1 - [tex]\frac{\sqrt{2i} }{2 }[/tex]
Step-by-step explanation:
[tex]2x^{2} - 4x -3 = 0[/tex]
[tex]\sqrt{-4^{2} -4(2)(3)}[/tex] = [tex]\sqrt{-8}[/tex] ... the negative root will produce imaginary solutions
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Answer:
1a. -4, 3/4
1b. 1-0.71i, 1+0.71i
Step-by-step explanation:
The directions tell you to use the quadratic formula. Factoring may get you the solution somewhat more easily, but does not comply with the directions.
The quadratic formula tells you ...
[tex]\text{The solution to }ax^2+bx+c=0\text{ is given by }\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]
__
1a. a=4, b=13, c=-12
[tex]x=\dfrac{-13\pm\sqrt{13^2-4(4)(-12)}}{2(4)}=\dfrac{-13\pm\sqrt{361}}{8}=\dfrac{-13\pm19}{8}\\\\x=\left\{-4,\dfrac{3}{4}\right\}[/tex]
__
1b. After adding 3 to both sides, a=2, b=-4, c=3
[tex]x=\dfrac{-(-4)\pm\sqrt{(-4)^2-4(2)(3)}}{2(2)}=\dfrac{4\pm\sqrt{-8}}{4}=1\pm\dfrac{\sqrt{2}}{2}i\\\\x=\left\{1-\dfrac{\sqrt{2}}{2}i,1+\dfrac{\sqrt{2}}{2}i\right\}\approx\{1-0.71i,1+0.71i\}[/tex]
The stemplot below represents the number of bite-size snacks grabbed by 37 students in an activity for a statistics class.
A stemplot titled Number of snacks has values 12, 12, 13, 13, 14, 14, 15, 15, 15, 15, 16, 16, 17, 17, 17, 18, 18, 18, 18, 19, 19, 20, 20, 21, 21, 21, 21, 22, 23, 25, 25, 28, 32, 38, 42, 45.
Which of the following statements best describes the distribution?
The distribution of the number of snacks grabbed is skewed right with a center around 18 and varies from 15 to 45. There are no outliers.
The distribution of the number of snacks grabbed is symmetric with a center around 18 and varies from 12 to 45. There are possible outliers at 38, 42, and 45.
The distribution of the number of snacks grabbed is skewed left with a center around 18 and varies from 12 to 45. There are possible outliers at 38, 42, and 45.
The distribution of the number of snacks grabbed is skewed right with a center around 18 and varies from 12 to 45. There are possible outliers at 38, 42, and 45.
Answer:
The distribution of the number of snacks grabbed is skewed right with a center around 18 and varies from 12 to 45. There are possible outliers at 38, 42, and 45.
Step-by-step explanation:
First, we can see if the graph is symmetric. A symmetric graph is even on both sides of the center. As there are a lot more students that grabbed a small number of snacks, and the data is not even around the center (which is somewhere around 20 or 30 snacks). This means that the graph is not symmetric, making the second answer incorrect.
Next, we can check if the graph is skewed right or left. If the left of the graph represents a smaller amount of snacks and the right of it represents a higher number of snacks, we can see that most of the data is on the left of the graph. There are a few values to the right, but the overwhelming amount of data is on the left, making the distribution skewed to the right. This keeps the first and last answers possible
Moreover, we can find the center of the distribution. This is generally equal to the median, which is 18, so the center is around 18
After that, we can see what the values vary from. The lowest tens value is 1, and the lowest ones value in that is 2, making the lowest value 12. Similarly, the highest tens value is 4, and the highest ones value there is 5, making the range 12 to 45. This leaves the last answer, but we can check the outliers to make sure.
With the data, we can calculate the first quartile to be 15, the third quartile to be 21.5, and the interquartile range to be 21.5-15 = 6.75 . If a number is less than Q₁ - 1.5 * IQR or greater than Q₃ + 1.5 * IQR, it is a potential outlier. Applying that here, the lower bound for non-outliers is 15 - 6.5 * 1.5 = 5.25, and the upper bound if 21 + 6.5 * 1.5 = 30.75. No values are less than 5.25, but there are four values greater than 30.75 in 32, 38, 42, and 45. There are possible outliers at 38, 42, and 45, matching up with the last answer.
Can somebody help me solve this ?
Step-by-step explanation:
volume of sphere = 288
based on formula, V = 4/3πr³
288 = 4/3(3.14)r³
288 = 4.187(r³)
r³ = 288/4.187
r =
[tex] \sqrt[3]{68.78} [/tex]
r = 4.09
= 4.1
một công ty kinh doanh 1 loại sản phẩm có
- Đơn giá bán là 20.000 đồng
- Định phs là 150.000 đồng khi mức tiêu thụ nhỏ hơn 30.000 sản phẩm
- Biến phí đơn vị là 10.000 đồng
y/ cầu:
a. Hãy xác định tỷ lệ biến phí và tỷ lệ đảm phí?
b. Hãy xác định điểm hòa vốn?
c. Công ty sẽ lời hoặc lỗ tại mức tiêu thụ là 12.000 sản phẩm? 17.000 sản phẩm?
d. Độ lớn đòn bẩy kinh doanh của cty là bao nhiêu tại mwucs tiêu thục là 12.000 snar phẩm? 17.000 sản phẩm ? Nêu ý nghĩa của các con số đó
e. Nếu giá bán tăng lên 25.000 đ/sp và biến phí tăng lên 17.000 đ/sp thid điểm hòa vốn của cty sẽ như thế nào
Answer:
ask in English then I can help u
Please see the attached picture
Answer:
C.I = (0.259,1.175) -> Fail to Reject H0
Step-by-step explanation:
The Cinci Company issues $100,000, 10% bonds at 103 on October 1, 2020. The bonds are
dated January 1, 2020 and mature eight years from that date. Straight-line amortization is used.
Interest is paid annually each December 31. Compute the bond carrying value as of December
31, 2024.
According to the given values in the question:
The Amortization period is:
= [tex]8 \ years\times 12 \ months[/tex]
= [tex]96 \ months[/tex]
Number of months of Amortization is:
= [tex]3 \ months \ in \ 2020+(4 \ years\times 12 \ months)[/tex]
= [tex]3+48[/tex]
= [tex]51 \ months[/tex]
Now,
On bonds payable, the premium will be:
= [tex]Issue \ price - Face \ value[/tex]
= [tex](100000\times 103 \ percent)- 100000[/tex]
= [tex]103000-100000[/tex]
= [tex]3000[/tex] ($)
The Unamortized premium will be:
= [tex]Premium - Unamortized \ premium[/tex]
= [tex]3000-(3000\times \frac{51}{96} )[/tex]
= [tex]3000-1593.75[/tex]
= [tex]1406.25[/tex] ($)
hence,
The carrying value as of December 31, 2024 will be:
= [tex]100000+1406.25[/tex]
= [tex]101406.25[/tex] ($)
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Which behavior would best describe someone who has good communication skills with customers ? a) Following up with some customers b) Talking to customers more than listening to them c) Repeating back what the customer says d) Interrupting customers frequently
Answer:
C. repeating back what the customer says
which equation is equivalent to 8+2(x-1)=5
Answer:
8+2x-2 = 5
2x+6 =5
2x = -1
Step-by-step explanation:
8+2(x-1)=5
Distribute
8+2x-2 = 5
Combine like terms
2x+6 =5
Subtract 6
2x+6-6=5-6
2x = -1
in the given circle the radius is 9 cm what is its diameter?
Answer:
18
Step-by-step explanation:
The diameter is equal to twice the length of the radius
So if the radius is 9 then the diameter is 9 * 2 = 18
Write a situation that can be represented by 2x + 6 > 20.
Hm, interesting inequality.
If you know that it slightly simplifies to [tex]2x\gt14[/tex] then you could go about representing something in real life,
Buying shoes is always done in pairs, if u buy two pairs of shoes you bought 4 shoes. You can only ever buy an even number of shoes which is represented by [tex]2x[/tex].
So you are asking yourself how many pairs you had to buy in order to have more than 14 shoes. The answer is of course, 7 pairs means exactly 14 shoes but since you need more the answer is 8 pairs. Represented by,
[tex]x\gt7=\{8,9,10,\dots,\aleph_0\}[/tex]
assuming [tex]x\in\mathbb{N}[/tex], which is appropriate since you cannot buy negative shoe or [tex]0.43819[/tex] of a shoe pair.
However, if you cannot change the inequality at all, you can use the above paragraph but simply add, you have 3 pairs (6 shoes) of shoes that are indispensable and you want to know the minimum number of shoe pairs you need to buy so that you always have more than 20 shoes.
Notes
[tex]\aleph_0[/tex] is the number of natural numbers [tex]\mathbb{N}[/tex] there are.
[tex]\{\dots\}[/tex] is explicit set notation, ie. which values concretely satisfy the inequality.
Hope this helps :)
Answer:
= 2x > 20-6
= 2x > 14
= x > 7... then the answer includes the numbers greater than seven
seven times a number decreased by the number is -48 . Find the number.
Answer:
a = -8
Step-by-step explanation:
Let the required number be "a".
Given that, seven times a number minus the number is -48
7 × a - a = -48
7a - a = -48
6a = -48
a = (- 48) / 6
a = -8
There is a sales tax of S6 on an item that costs 888 before tax. The sales tax on a second item is $21. How much does the second item cost before tax?
Step-by-step explanation:
before Tax
Coast = 888
in 2ND Item = $21
• 888/21
= $42.28
determine if it is a function, find the domain and the range.
{(9,−3),(4,−2),(1,−1), (0,0),(1,1),(4,2),(9,3)}
Answer:
it is not function
Step-by-step explanation:
because,
first of all,what do mean function
A function is a relation in which each element of the domain corresponds to exactly one
element of the range.
based on this description
Since the domain element 1 is assigned to two different values in the range, -1 and 1, so that it is
not a function
Tenisha solved the equation below by graphing a system of equations.
log35x = log (2x+8)
Which point approximates the solution for Tenisha's system of equations?
0 (0.9, 0.8)
O (1.0, 1.4)
O (2.3, 1.1)
O (2.7, 13.3)
Answer:
Option B.)
Step-by-step explanation:
Just took the test and got 100% :]
The system of logarithmic equation is graphed and the point of intersection of the equation is log₃ ( 5x ) = log₅ ( 2x + 8 ) is A ( 1.0 , 1.4 )
What is Equation of Graph of Polynomials?Graphs behave differently at various x-intercepts. Sometimes the graph will cross over the x-axis at an intercept. Other times the graph will touch the x-axis and bounce off.
Identify the even and odd multiplicities of the polynomial functions' zeros.
Using end behavior, turning points, intercepts, and the Intermediate Value Theorem, plot the graph of a polynomial function.
The graphs cross or are tangent to the x-axis at these x-values for zeros with even multiplicities. The graphs cross or intersect the x-axis at these x-values for zeros with odd multiplicities
Given data ,
Let the solution to the logarithmic equation be represented as A
Now , the value of A is
log₃ ( 5x ) = log₅ ( 2x + 8 )
On simplifying , we get
log₃ ( 5x ) = log₁₀ ( 5x ) / log₁₀ ( 3 )
log₅ ( 2x + 8 ) = log₁₀ ( 2x + 8 ) / log₁₀ ( 5 )
Substituting the logarithmic quantities , we get
log₁₀ ( 5x ) / log₁₀ ( 3 ) = log₁₀ ( 2x + 8 ) / log₁₀ ( 5 )
On cross multiplying , we get
log₁₀ ( 5x ) / log₁₀ ( 2x + 8 ) = log₁₀ ( 3 ) / log₁₀ ( 5 )
( 5x ) / ( 2x + 8 ) = 3/5
On cross multiplying , we get
25x = 6x + 24
Subtracting 6x on both sides , we get
19x = 24
Divide by 19 on both sides , we get
x = 1.26
Therefore , the approximate values of the function on graphing is A ( 1.0 , 1.4 )
Hence , the solution of function from graphing is A ( 1.0 , 1.4 )
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State the domain and range of the following function:
{(- 3,4), (0,6), (2, - 2), (1, – 3), (6, - 7), (3, 2)}
Answer:
[tex]Domain = \{-3,0,2,1,6,3\}[/tex]
[tex]Range = \{4,6,-2,-3,-7,2\}[/tex]
Step-by-step explanation:
Given
[tex]\{(- 3,4), (0,6), (2, - 2), (1, - 3), (6, - 7), (3, 2)\}[/tex]
Required
The domain and range
A function is represented as:
[tex]Function = \{(x_1,y_1),(x_2,y_2),....(x_n,y_n)\}[/tex]
Where
[tex]x \to[/tex] domain
[tex]y \to[/tex] range
So, we have:
[tex]Domain = \{-3,0,2,1,6,3\}[/tex]
[tex]Range = \{4,6,-2,-3,-7,2\}[/tex]
P = 14.7e-0.21x, where x is the number of miles above sea level. To the nearest foot, how high
is the peak of a mountain with an atmospheric pressure of 8.743 pounds per square inch?
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Answer:
13064 feet
Step-by-step explanation:
We can rewrite the formula so that x is in feet. Equating the new formula to 8.743 PSI, we have ...
8.743 = 14.7e^(-0.21x/5280)
Dividing by 14.7 and taking natural logs, we have ...
ln(8.743/14.7) = -0.21x/5280
Multiplying by the inverse of the coefficient of x gives ...
x = 5280·ln(8.743/14.7)/-0.21 ≈ 13064.0806
The peak of the mountain is about 13,064 feet high.
The average mileage per gallon for cars built since 1940 approximates to the following curve 0.0075*t^2-.2672*t+14.8 where t is year -1940.
Answer the following questions:
What is the expected MPG in 2025?
How about 2050?
Is this a valid function?
Is there a top end to MPG?
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Answer:
46.3 in 202576.2 in 2050Step-by-step explanation:
The attached shows the predicted mileage for cars built in 2025 to be 46.3 mpg, 76.2 mpg for cars built in 2050.
__
No doubt, the function is valid over the time period used to derive it. It may or may not be valid for predicting MPG beyond that period.
Virtually any function that predicts future increases without bound will turn out to be unreliable at some point. In this universe, there are always limits to growth.
Line K is parallel to line I.
k
m
n
Which angle is congruent to 24?
21
0 22
025
Answer:
<4 = <1
Step-by-step explanation:
Judging from the picture, <1 and <4 are opposite angles. Opposite angles are always congruent. Hope this helps!
Solve x2 + 8x + 22 = 0 by completing the square.
Question 20 options:
A)
x = –4 + i√ 6 , x = –4 – i√ 6
B)
x = –4 + √ 14 , x = –4 – √ 14
C)
x = –4 + i√ 14 , x = –4 – i√ 14
D)
x = –4 + √ 6 , x = –4 – √ 6
Answer:
A)
Step-by-step explanation:
the solution of a squared equation is
x = (-b ± sqrt(b² - 4ac)) / (2a)
in our case
a = 1
b = 8
c = 22
x = (-8 ± sqrt(64 - 88))/2 = (-8 ± sqrt(-24))/2 =
= (-8 ± sqrt(4×-6))/2 = (-8 ± 2×sqrt(-6))/2 =
= -4 ± sqrt(-6) = -4 ± i×sqrt(6)
The weekly amount of money spent on maintenance and repairs by a company was observed, over a long period of time, to be approximately normally distributed with mean $440 and standard deviation $20. How much should be budgeted for weekly repairs and maintenance so that the probability the budgeted amount will be exceeded in a given week is only 0.1
Answer:
$465.6 should be budgeted.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Normally distributed with mean $440 and standard deviation $20.
This means that [tex]\mu = 440, \sigma = 20[/tex]
How much should be budgeted for weekly repairs and maintenance so that the probability the budgeted amount will be exceeded in a given week is only 0.1?
The 100 - 10 = 90th percentile should be budgeted, which is X when Z has a p-value of 0.9, so X when Z = 1.28. Then
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]1.28 = \frac{X - 440}{20}[/tex]
[tex]X - 440 = 1.28*20[/tex]
[tex]X = 465.6[/tex]
$465.6 should be budgeted.
Find the missing length indicated
Answer:
60
Step-by-step explanation:
Use similar triangles or the ratios from the right triangle altitude theorem.
x/36 = (64 + 36)/x
x² = 3600
x = 60
cubed root of 8 to the power of x
Answer:
your answer is 2
Step-by-step explanation:
I hope this help
A telephone call arrived at a switchboard at random within a one-minute interval. The switch board was fully busy for 10 seconds into this one-minute period. What is the probability that the call arrived when the switchboard was not fully busy
Answer:
50/60 = .8333= 83.33%
Step-by-step explanation:
The probability that the call arrived when the switchboard was not fully busy is 0.75.
What is Normal Distribution?A probability distribution that is symmetric about the mean is the normal distribution, sometimes referred to as the Gaussian distribution. It demonstrates that data that are close to the mean occur more frequently than data that are far from the mean. The normal distribution appears as a "bell curve" on a graph.
Given:
Here X follows uniform distribution with parameter a and b.
Where,
a = 0 and b = 1.
Then,
The density function of Y is given by:
P( 15 < Y ≤ 60)
or, P( 0.25 < Y ≤ 1)
So, P( 0.25 < Y ≤ 1) = [tex]\int\limits^{1}_{0.25}{f(y) \, dy[/tex]
= [tex][y]^1 _ {0.25}[/tex]
= (1- 0.25)
= 0.75
Hence, The probability that the call arrived when the switchboard was not fully busy is 0.75.
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find the scale factor and ratio of perimeters for a pair of similar octagons with areas 49 ft^2 and 64 ft^2
Answer:
scale factor: 1.16
perimeters: 21.84 ft and 25.36 ft
the line parallel to 5x-3y=15 and containing (5,7)
what is the equation of the line?
Answer:
3y=5x-4
Step-by-step explanation:
As the lines are parallel, the slope will be 5/3. The equation of line will be y=(5/3)*x-4/3. 3y=5x-4