Drag each number to the correct location on the table. Not all numbers will be used.
Jacob performed an experiment with a weighted die, numbered 1 to 6. He rolled the die 125 times and recorded the results. Complete the table below.

24
22
0.176
18
0.232
37
0.048
0.104

Drag Each Number To The Correct Location On The Table. Not All Numbers Will Be Used.Jacob Performed An

Answers

Answer 1

Answer:

Complete Table:

Result of Roll ------ Frequency ------- Experimental Probability

1 --------------------------- 22 ------------------- 0.176

2 --------------------------- 13 ------------------- 0.104

3 --------------------------- 18 ------------------- 0.144

4 --------------------------- 29 ------------------- 0.232

5 --------------------------- 37 ------------------- 0.296

6 --------------------------- 6 ------------------- 0.048

Step-by-step explanation:

Required: Complete the table

The table is divided into 3:

1. Result of Roll

2. Frequency (F)

3. Experimental Probability (P)

The relationship between (2) and (3) is:

[tex]P = \frac{F}{N}[/tex]

Where

N = Number of Rolls

N = 125

For Roll of Result = 2

Frequency = 13

The probability is calculated as thus:

[tex]P = \frac{13}{125}[/tex]

[tex]P = 0.104[/tex]

For Roll of Result = 3

Probability = 0.144

The Frequency is calculated as thus:

[tex]0.144 = \frac{F}{125}[/tex]

[tex]F = 0.144 * 125[/tex]

[tex]F = 18[/tex]

For Roll of Result = 4

Frequency = 29

The probability is calculated as thus:

[tex]P = \frac{29}{125}[/tex]

[tex]P = 0.232[/tex]

For Roll of Result = 5

Probability = 0.296

The Frequency is calculated as thus:

[tex]0.296 = \frac{F}{125}[/tex]

[tex]F = 0.296* 125[/tex]

[tex]F = 37[/tex]

For Roll of Result = 6

Frequency = 6

The probability is calculated as thus:

[tex]P = \frac{6}{125}[/tex]

[tex]P = 0.048[/tex]

For Roll of Result = 1.

To get the frequency; we subtract the sum of frequencies of roll of results 2 to 6 from the total number of rolls.

In other words:

Frequency of 1 = Total Rolls - (Frequency of 2 + Frequency of 3 + Frequency of 4 + Frequency of 5 + Frequency of 6)

Frequency of 1 = 125 - (13 + 18 + 29 + 37 +6)

Frequency of 1 = 125 - 103

Frequency of 1 = 22

The probability is calculated as thus:

[tex]P = \frac{F}{N}[/tex]

[tex]P = \frac{22}{125}[/tex]

[tex]P = 0.176[/tex]


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Answer:

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Step-by-step explanation:

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Answers

Answer:

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Answer:

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Step-by-step explanation:

Two bots 7.50 each

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Answer:

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Step-by-step explanation:

A number line going from 0 to 4. Numbers 0, 1, 2, 3, and 4 are marked on the line. Marks divide the spaces between each number into 3 equal parts. Use the drop-down menus to complete the statements. What is 4 ÷ 1 3 ? This problem asks how many groups of are in . The quotient of 4 ÷ 1 3 is .

Answers

Answer:

Use the drop-down menus to complete the statements.

What is 4 ÷  

1

3

?

This problem asks how many groups of  

1/3

are in  

4

.

The quotient of 4 ÷  

1

3

 is  

12

.

Step-by-step explanation:

The completed statements with respect to the parts on the number line are;

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A number line is a visual representation of the set of real numbers. A number line is a straight line on which each point corresponds to a number. The points on the line are evenly spaced, with the distance between two points representing the difference between the numbers.

The question asks how many groups of 1/3 are in 4, which is equivalent to dividing 4 by 1/3, which can be expressed as 4 ÷ 1/3

To divide a number by a fraction, we can multiply the number by the reciprocal of the fraction.

The reciprocal of a fraction is obtained by flipping the numerator and denominator. The reciprocal of 1/3 is 3/1 which is 3. The expression can therefore, be expressed as follows;

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The quotient of 4 ÷ (1/3) is 12, which indicates that the number of groups of 1/3 in 4 are 12

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Step-by-step explanation:

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Answers

Answer:

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Answer:

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Answers

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Let the number nickels be x and the number of quarters be y.

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Substitute x=68-y in equation (I), we get

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Substitute y=27 in equation (II), we get

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Therefore, the number of nickels are 41 and the number of quarters are 27.

To learn more about the linear system of an equations visit:

https://brainly.com/question/27664510.

#SPJ2

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Answer:

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