Determine the approximate density of a high-leaded brass that has a composition of 60.5 wt% Cu, 34.5 wt% Zn, and 5.0 wt% Pb. The densities of Cu, Zn, and Pb are 8.94, 7.13 and 11.35 g/cm3, respectively.

Answer:

heterogeneous mixture

Explanation:

I'm not sure what halo halo or buko is but with mixed nuts you can see the mixture elements so that would be heterogeneous.

If you can't see the individual pieces in a mixture like ex: milk. that is a homogenous mixture.

Answer:

Explanation:B storing waste materials

Answer:

21.95 g of AgCl.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

AlCl3(aq) + 3AgNO3(aq) —> 3AgCl(s) + Al(NO3)3(aq)

Next, we shall determine the masses of AlCl3 and AgNO3 that reacted and the mass of AgCl produced from the balanced equation. This is illustrated below:

Molar mass of AlCl3 = 27 + (3×35.5) = 133.5 g/mol

Mass of AlCl3 from the balanced equation = 1 × 133.5 = 133.5 g

Molar mass of AgNO3 = 108 + 14 + (3×16) = 170 g/mol

Mass of AgNO3 from the balanced equation = 3 × 170 = 510 g

Molar mass of AgCl = 108 + 35.5 = 143.5 g/mol

Mass of AgCl from the balanced equation = 3 × 143.5 = 430.5 g

From the balanced equation above,

133.5 g of AlCl3 reacted with 510 g of AgNO3 to produce 430.5 g of AgCl.

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

133.5 g of AlCl3 reacted with 510 g of AgNO3.

Therefore,

22 g of AlCl3 will react with =

(22 × 510)/133.5 = 84.04 g of AgNO3.

Thus, we can see that it will require a higher mass (i.e 84.04 g) of AgNO3 than what was given (i.e 26 g) to react completely with 22 g of AlCl3. Therefore, AgNO3 is the limiting reactant and AlCl3 is the excess reactant.

Finally, we shall determine the mass of the solid product (AgCl) produced from the reaction.

In this case the limiting reactant will be used because, it will produce the maximum yield of the reaction since all of it is used up in the reaction.

The limiting reactant is AgNO3 and the mass of AgCl produced can be obtained as follow:

From the balanced equation above,

510 g of AgNO3 reacted to produce 430.5 g of AgCl.

Therefore, 26 g of AgNO3 will react to produce = (26 × 430.5)/510 = 21.95 g of AgCl.

Thus, the mass of the solid product (AgCl) produced is 21.95 g

Answer:

J. J. Thomson - Electrons

John Dalton - Atoms

Ernest Rutherford - Protons

James Chadwick - Neutrons

Answer:

Look at the picture :)

Answer:

[tex]0.0000708\ \text{mol/L}[/tex]

Explanation:

The nitrate concentration of the sample = [tex]4.39\ \text{mg/L}=4.39\times 10^{-3}\ \text{g/L}[/tex]

Molar mass of [tex]NO^-_3=62.0049\ \text{g/mol}[/tex]

The molar concentration is obtained when we divide the concentration by its molar mass in the approriate units.

[tex]\dfrac{4.39\times 10^{-3}}{62.0049}=0.0000708\ \text{mol/L}[/tex]

The molar concentration is [tex]0.0000708\ \text{mol/L}[/tex]

Answer:

circulatory and respiratory

Explanation:

your welcome :)

Answer:

E = 2.80×10⁻¹⁶ j

E = 5.37×10⁻¹⁷j

Explanation:

Given data:

Frequency of photon = 4.23 ×10¹⁷ Hz

Energy of photon = ?

Solution:

Formula:

E = h× f

E = 6.63×10⁻³⁴ js ×4.23 ×10¹⁷ Hz

Hz = s⁻¹

E = 28.0×10⁻¹⁷ j

E = 2.80×10⁻¹⁶ j

2)

Given data:

Frequency of photon = 8.10×10¹⁶ Hz

Energy of photon = ?

Solution:

E = h× f

E = 6.63×10⁻³⁴ js ×  8.10×10¹⁶ Hz

Hz = s⁻¹

E = 53.7×10⁻¹⁸j

E = 5.37×10⁻¹⁷j

Answer:

As opposed to this, if the arrow goes counterclockwise then the absolute configuration is S.

Explanation:

Answer:

7.09 cm³

Explanation:

From the question given above, the following data were obtained:

Density of Germanium = 5.32 g/cm³

Mass of Germanium = 37.72 g

Volume of Germanium =?

The density of a substance is simply defined as the mass of the substance per unit volume of the substance. Mathematically it is expressed as:

Density = mass / volume

Thus, with the above formula, we can obtain the volume of Germanium as shown below:

Density of Germanium = 5.32 g/cm³

Mass of Germanium = 37.72 g

Volume of Germanium =?

Density = mass /volume

5.32 = 37.72 / volume

Cross multiply

5.32 × Volume = 37.72

Divide both side by 5.32

Volume = 37.72 / 5.32

Volume of Germanium = 7.09 cm³

Here is the full question:

A chemistry graduate student was given 500 mL of a 1.60 M hydrocyanic acid (HCN) solution. Hydrocyanic acid is a weak acid with [tex]K_a = 4.9 \times 10^{-10}[/tex]. What mass of KCN should the student dissolve in the HCN solution to turn it into a buffer with pH  = 9.16?

Answer:

36.85 g

Explanation:

From the given information above:

Recall that  number of moles of HCN = mass of HCN / molar mass of HCN= mass of HCN / molar mass of HCN

Therefore;

the number of moles of HCN =  [tex]\dfrac{500 \times 1.60}{1000}[/tex]

the number of moles of HCN = [tex]\dfrac{800}{1000}[/tex]

the number of moles of HCN =  0.8

The acid dissociation constant [tex]K_a[/tex] = [tex]4.9 \times 10^{-10}[/tex]

Thus the pKa = [tex]- log (4.9 \times 10^{-10})[/tex]

pKa = 9.31

However, the pH is given as:

[tex]pH = pKa + log \bigg ( \dfrac{KCN}{HCN} \bigg )[/tex]

[tex]9,16 =9.31 + log \bigg ( \dfrac{KCN}{0.8} \bigg )[/tex]

[tex]9,16 -9.31 =log \bigg ( \dfrac{KCN}{0.8} \bigg )[/tex]

[tex]-0.15 =log \bigg ( \dfrac{KCN}{0.8} \bigg )[/tex]

KCN = 0.566 mol

The standard molar mass of KCN = 65.11 g/mol

Thus, the mass of KCN = number of moles of KCN × molar mass of KCN

the mass of KCN = 0.566 × 65.11

the mass of KCN that the student needs to dissolve in HCN is =  36.85 g

Answer:

a

Explanation:

Answer:

I got e but you might want to wait for someone else to answer it just incase...

Answer:

Magma cooling = metamorphic rock formation

Explanation:

Did you mean formation not folio?

Answer:

"It is the average mass of all phosphorus elements in nature."

Explanation:

I don't really know why, I just got it right on this quiz with this answer. Hope it helps :)

Answer:

1. How is ionization energy related to how easily an electron can be lost from an atom? The easier it is to lose an electron the smaller the amount of energy needed to remove it (smaller ionization energy). ... The amount of positive charge increases as the number of protons increase from left to right across a period.

Explanation:

Answer:

Some distortion exists somewhere in the map.

Explanation:

Any map that shows the entire world will have some distortion somewhere in the map. This is because we are transforming a spherical body to a flat rectangular dimensional surface.

Answer:

Mass = 149g

Explanation:

N3 = 3x14u = 42

H12 = 12x1u = 12

P = 1x31u = 31

O4 = 4x16u = 64

42+12+31+64 = 149g

Answer:

6.79 litres

Explanation:

Potassium dichromate is K2Cr2O7

Its molar mass = 294.18 g/mol

If,

1 mole = 294.18 g

3 mole = 3 x 294.18 g

= 882.54 g

Solubility of K2Cr2O7 is

4.9 g/100 mL at 0⁰c

13 g/100 mL at 20⁰c

102 g/100 mL at 100⁰c

No specific temperature is given so I have used 20⁰C since it is close to room temperature.

at 20⁰C:

13 g of K2Cr2O7 would dissolve in = 100 mL

So 1 g of K2Cr2O7 dissolves in = (100/13)

= 7.692

882.54 g of K2Cr2O7 dissolves in = 882.54 x 7.692

= 6788.59mL

We convert to litres

= 6.79 L

Answer:

2L

Explanation:

P1xV1=P2xV2

P1=4 atm

V1=3L

P2=6 atm

V2= ?

V2= (4 x 3)/ 6

V2=2L

The mass percent of water in nickel (II) sulfate hexahydrate is 41.129 %.

The chemical formula of nickel (II) sulfate hexahydrate is NiSO₄.6H₂O.

The mass of 1 mole of NiSO₄.6H₂O is:

[tex]mNiSO_4.6H_2O = mNi + mS + 10mO + 12mH \\= 58.69 g + 32.07 g + 10 \times 16.00 g + 12 \times 1.01 g = 262.88 g[/tex]

The mass of H₂O in 1 mole of NiSO₄.6H₂O is:

[tex]mH_2O = 6 \times (2mH + mO) = 6 \times (2 \times 1.01 g + 16.00 g) = 108.12 g[/tex]

The mass percent of H₂O in NiSO₄.6H₂O is:

[tex]\% H_2O = \frac{mH_2O}{mNiSO_4.6H_2O} \times 100 \% = \frac{108.12 g}{262.88 g} \times 100 \% = 41.129 \%[/tex]

The mass percent of water in nickel (II) sulfate hexahydrate is 41.129 %.

You can learn more about percent composition here: https://brainly.com/question/17505281

Answer:

The correct approach is "Equivalence point ".

Explanation:

ΔT for the metal = 50.5 °C

ΔT for the water = 4.5 °C

The specific heat capacity for the unknown metal : 0.466 J/g° C  

The law of conservation of energy can be applied to heat changes, i.e. the heat received/absorbed is the same as the heat released  

Q in = Q out  

Heat can be calculated using the formula:  

Q = mc∆T  

Q = heat, J  

m = mass, g  

c = specific heat, joules / g ° C  

∆T = temperature difference, ° C / K  

A 200. g piece of metal is boiled in ethanol (boiling point: 78 C), so :

m metal = 200 g

Ti metal(initial temperature of metal)=78 C

T(system temperature at equilibrium)=27.5

m water = 250 ml x 1 g/ml = 250 g

c water = 4.18 joules / g ° C  

Tiw(initial temperature of water) = 23

[tex]\tt 78-27.5=50.5^oC[/tex]

[tex]\tt 27.5-23=4.5^oC[/tex]

[tex]\tt Q~metal=Q~water\\\\200\times c\times (78-27.5)=250\times 4.18\times (27.5-23)\\\\10100\times c=4702.5\\\\c=0.466~J/g^oC[/tex]

Answer:

C Mesosphere

Explanation:

the meteors will travel through the exosphere and thermosphere without much trouble due to the lack of air in those layers but when they hit the middle layer which is the mesosphere there are enough gases to cause friction and create heat burn up in the mesosphere

(I did research on a helpful site! I hope this helps)

:)

Answer:

2 e⁻ + 4 H⁺(aq) + MnO₂(s) → Mn²⁺(aq) + 2 H₂O(l)

Explanation:

Let's write the half-reaction for the reduction of solid manganese dioxide MnO₂ to manganese ion Mn²⁺ in acidic aqueous solution.

MnO₂(s) → Mn²⁺(aq)

To balance the oxygen atoms, we will add 2 moles of water on the right side. To compensate for the hydrogen atoms added, we will add 4 hydrogen ions on the left side.

4 H⁺(aq) + MnO₂(s) → Mn²⁺(aq) + 2 H₂O(l)

Finally, we will balance the charges by adding 2 electrons on the left side.

2 e⁻ + 4 H⁺(aq) + MnO₂(s) → Mn²⁺(aq) + 2 H₂O(l)

Answer:

(a) Map view and (b) cross-section view of location results for lower and upper groups overlapping with faults. Green dashed lines, magenta dots and blue dots refer to preexisting faults, lower events and upper events, respectively. (For interpretation of the references to color in this figure legend, the reader is referred to the web version of this article.)

(a) Map view and (b) cross-section view of location results for lower and upper groups overlapping with faults. Green dashed lines, magenta dots and blue dots refer to preexisting faults, lower events and upper events, respectively. (For interpretation of the references to color in this figure legend, the reader is referred to the web version of this article.)

Answer:

covalent bond

Explanation:

Answer:

Molecules are moving the fastest and are the farthest apart in the gaseous phase.

Explanation: