Correct Lewis structure for oxygen

Answer:

Well to start, as fragile as the eggs are, there should be a more durable material you feel me? Like maybe try something such as a rubbery product but one that isn't so tough on outside but not too soft on the inside. Basically a cushion but where is accessible for the eggs. We also dont want a material that is way to hard because it leaves no room for the eggs and its a very difficult workspace.

Explanation:

Hope this helps and good luck on your project :)

Answer:

[tex]\%Ag_2O=41.8\%[/tex]

Explanation:

Hello.

In this case, for the reaction:

[tex]2 Ag_2O(s) \rightarrow 4 Ag(s) + O_2(g)[/tex]

As 13.8 mL (0.0138 L) are collected at 27 °C and 1.00 atm, we can compute the yielded moles of oxygen via the ideal gas equation as shown below, considering that the pressure of oxygen is equal to the total pressure minus the vapor pressure of water (26.7 mmHg=0.035atm):

[tex]PV=nRT\\\\n=\frac{PV}{RT}=\frac{(1.00atm-0.035atm)*0.0138L}{0.082\frac{atm*L}{mol*K}*300K} =5.41x10^{-4}molO_2[/tex]

Next, via the 1:2 mole ratio between oxygen and silver oxide (molar mass = 231.735  g/mol) in the chemical reaction, the mass of pure silver oxide turns out:

[tex]m_{AgO_2}=5.41x10^{-4}molO_2*\frac{2molAgO_2}{1molO_2} *\frac{231.735gAgO_2}{1molAgO_2} \\\\m_{AgO_2}=0.251gAgO_2[/tex]

In such a way, the percent by mass of silver oxide in the 0.600-g sample is:

[tex]\%Ag_2O=\frac{0.251g}{0.600g}*100 \%\\\\\%Ag_2O=41.8\%[/tex]

Best regards.

There is  42.5% of Ag2O in the sample.

The equation of the reaction is;

2 Ag2O(s) -------> 4 Ag(s) + O2(g)

Volume of the oxygen gas = 13.8 mL or 0.0138 L

Temperature of gas = 27°C + 273 = 300 K

Pressure of the gas = 1 atm - 0.035atm = 0.965 atm

Gas constant = 0.082 atm LK-1mol-1

From;

PV = nRT

n = PV/RT

n = 0.965 atm × 0.0138 L/0.082 atm LK-1mol-1 × 300 K

n = 0.000541 moles

If 2 moles of Ag2O yields 1 mole of oxygen

x moles of Ag2O yields 0.000541 moles of oxygen

x = 2 moles ×  0.000541 moles/ 1 mole

x = 0.0011 moles of Ag2O

Mass of Ag2O = 0.0011 moles × 232 g/mol = 0.255 g

Mass percentage of Ag2O =  0.255 g/0.600 g × 100/1

= 42.5%

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Answer:

Standard solution

Explanation:

The correct answer would be a standard solution.

By definition, a standard solution is a solution whose concentration is known and which is often used to determine the concentration of other substances in, for example, titration. The process of using a solution of known concentration to determine the concentration of another substance is known as standardization.

Answer:

Yes, the intensity of the laser does affect the amount of current that flows through the photo tube. The more intense the light, the more electrons are expelled, and thus the higher the current.

Explanation: Hope this helps!

Yes, the intensity of the laser does affect the amount of current that flows through the photo tube.

Laser light is a form of electromagnetic radiation and should not be confused with ultrasound or other electromedical therapies.

Laser light is of an electrical and magnetic character. Laser light can change the chemical structure of cells and tissue, which visible light cannot.

Thus laser light differs significantly from visible light.

The intensity of a laser beam is the optical power per unit area, which is transmitted through the target surface to the spread direction.

The units of the optical intensity  are W/m2 or more commonly W/cm2.

Therefore ,we can conclude that laser light does effect the amount of current that flows through phototube.

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Answer:

I think Mary's and Alan's Methods are wrong. Jack is correct.  

Explanation:

(M1)(%)+(M2)(%)+(M3)(%)

You will be mulitplying the mass of Isotopes  by the percentages, (M1,2,3) are the isotopes. Then you just add the three to get the average.

There isn't any division involved.

Answer:

V2 = 50.67mL or 50.67cm^3

Explanation:

using the general gas law formula

(P1V1)/T1 = (P2V2)/T2

Where P1=760.0mmHg

P2=500.0mmHg

V1=250.0mL

V2=?

T1=27.0°C = 273+27=300K Note: constant temperature unit must be in Kelvin

T2=400k

Appling the formula

(P1V1) /T1 = (P2V2) /T2

Cross multiply

P1V1T2 =P2V2T1

Divide through by P2T1

therefore: V2= (P1V1T2) /(P2T1)

Inserting the values

V2=(760×25.0×400) /(500×300)

V2=(7600000) /(150000)

V2=50.67mL

Note: 1mL = 1 cm^3 therefore: V2= 50.67mL or 50.67cm^3

Answer: It will kind of make like a type of tough or soft dough

Explanation: If you add too much water it might be a dough that bearly tays together or is very soft, but if you add too little it will be hard to mold. The reason it forms a sort of consistency like this is because When water is added to flour and mixed, these proteins absorb water, otherwise known as hydrating. Gliadin and Glutenin then combine to form the protein called GLUTEN. ... When flour is mixed with water, the gluten swells to form a continuous network of fine strands.

Answer:

C, B, D, A

Explanation:

Dalton's model - 1803

J.J Thomson's model - 1904

Rutherford's model - 1911

Bohr's model - 1913

Answer:

oxygen has 6 valence electrons

Explanation:

it is in group 16

Answer:

Oxygen has a total of 6 valence electrons.

Explanation:

I have the class and we recently went over this.

The possible quantum numbers for 5f are :

Each orbital in an atom consists of 4 quantum numbers  

n is the principal quantum number ---> describes the size of the orbitals  

l is the angular momentum / azimuthal quantum number -> describes the shape of the orbitals.  

ml, the magnetic quantum number -> describes the orientation of orbitals in space  

ms, the electron-spin quantum number ---> describes the spin of electrons  

Value of n: positive integer  

value of l: s = 0, p = 1, d = 2, f = 3, ... (n-1)  

ml value: between -l to + l  

ms value: +1/2 or -1/2  

So the possible quantum numbers for 5f are :

Because the answer choices are not very clear, please see the composition I have described above

Answer:

Explanation:

The elements in Group 1A elements are Lithium, Sodium, Potassium, Rubidium, Caesium, and Francium(radioactive). The valence shells of the members have the electronic configuration of ns¹ where n =2,3,4,5,6,7. They are known as alkali earth metals. Their chemistry is dominated by the only electron in the outer shell of their atoms. Thus, they are powerful reducing agents because of their ability to lose this outer shell electron readily.

Thus ns' electrons in Group 1A require lesser energy for ionization in the case of elements of Group 1A; this explains why Group 1A elements are more reactive.

On the other hand, the Group 1B elements outer ns' electrons are less effectively shielded by the inner d electrons; therefore, the outer electrons in case of Group 1B feel more nuclear pull (due to positively charged protons in the nucleus) as compared to the nuclear pull in Group 1A elements. Thus electrons require more energy for ionization in the case of elements of Group 1B. This explains why Group 1B elements are less reactive than elements of Group 1A.

Answer:

the answer is a          shh /..\  yall smell that

Explanation:

Answer:

Option C. 1.60×10¯²¹ J

Explanation:

The following data were obtained from the question:

Frequency (f) = 2.40×10¹² Hz

Energy (E) =..?

We can obtain the energy of the photon of the infrared light by applying the following formula:

Energy (E) = Planck's constant (h) × frequency (f)

E = hf

Frequency (f) = 2.40×10¹² Hz

Planck's constant (h) = 6.63×10¯³⁴ Js

Energy (E) =..?

E = 6.63×10¯³⁴ × 2.40×10¹²

E = 1.60×10¯²¹ J

Thus, the energy of the photon of the infrared light which has a frequency of 2.40×10¹² Hz is 1.60×10¯²¹ J

According to the law of energy, it states that energy can never be created nor be destroyed. It can only transfer from one thing to another.

These are the various type of energy:-

We can obtain the energy of the photon of the infrared light by applying the following formula:

Energy (E) = Planck's constant (h) × frequency (f)  

[tex]E = hf[/tex]

After putting the value:-

[tex]E = 6.63 * 10^3^4 * 2.40*10^1^2[/tex]

After solving the equation, the energy is:-

E = 1.60×10¯²¹ J

Thus, the energy of the photon of the infrared light which has a frequency of 2.40×10¹² Hz is 1.60×10¯²¹J

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Answer:

a) Not acidic

b) Not acidic

Explanation:

To determine if a solution is acidic, we need to calculate the pH. If the pH < 7, the solution is acidic.

a) A solution with [H₃O⁺] = 2.5 × 10⁻⁸ M

We will use the following expression.

pH = -log [H₃O⁺] = -log 2.5 × 10⁻⁸ = 7.6

Since the pH > 7, the solution is not acidic

b ) A solution with [OH⁻] = 1.0 × 10⁻⁷M

First, we will calculate the pOH.

pOH = -log [OH⁻] = -log 1.0 × 10⁻⁷ = 7.0

Then, we will calculate the pH.

pH = 14.0 - pOH = 14.0 - 7.0 = 7.0

Since the pH is 7, the solution is not acidic.

Answer:

Sublimation

Explanation:

Answer:

sublimation

Explanation:

Sublimation is the process solid changes to gas without passing the liquid phase. An example of a substance that sublimes is napthalene.