Answer:
Explanation:
Element -
It is the basic unit of matter, which cannot be broken down into substances by any way but can be combined to form new substances.
It is a pure substance.
It classifies into metals, non-metals, metalloids and noble gases.
Example - Hydrogen, Carbon, Oxygen
Compounds -
It is a combination of two or more elements.
It is a pure substance.
Through chemical reactions, they can be broken down into metals.
Example - Water, Carbon dioxide
Mixtures -
It is a combination of two or more elements or compounds or both.
The substances combined in a mixture are in a particular ratio.
Example - Chalk powder, Washing Soda
The density of water is 1 g/cm3. Brent used the following method to convert 1 g/cm3 to kg/m3. An equation is shown. The expression on the left has three terms separated by the multiplication sign. The first term is 1 g by 1 cubic cm. The second term is 1 kg by 1000 kg. The third term is 100 cm raised to the power of 3 divided by 1 m raised to the power of 3. The number on the right of the equal to sign is 1000 kg per cubic meter. (1 kg = 1,000 g and 1 m = 100 cm) What is the error in Brent's conversion method?
Answer:
The error includes;
a) The wrong denominator for the equivalent fraction of kilograms to grams
b) The use of the scale factor of length rather than the scale factor of volume for the equivalent fraction of cubic centimeters to cubic meters
c) The arrival at the correct 1000 kg/m³ rather than 0.1 g/m³ based on the expression on the left of the equation
Explanation:
The density of water = 1 g/cm³
The given equation is presented as follows;
1 g/cm³ × 1 kg/(1000 kg) × 100 cm³/(1 m³) = 1000 kg/m³
The error in the conversion method are;
a) The conversion, 1 kg/(1,000 kg) has an error, the correct conversion is (1 kg)/1,000 g)
b) The volume conversion error, 100 cm³/(1 m³), the correct volume conversion is (100 cm)³/(1 m³) = 1,000,000 cm³/(1 m³)
c) The right of the equal to sign error; using the left side expression only, the (wrong) answer is 0.1 g/m³
The correct equation is presented as follows;
1 g/cm³ × 1 kg/(1000 g) × 1,000,000 cm³/(1 m³) = 1000 kg/m³
Answer:
C. 1,000 kg should be written as 1,000 g.
Explanation:
Got it right on my test :)
Please help :)
A chocolate chip cookie recipe calls for 0.050 moles of baking soda (NaHCO3). How many grams should the chef mass out?
According to the mole concept, 4.2 g of baking soda should be weighed out.
What is mole concept?Mole is defined as the unit of amount of substance . It is the quantity measure of amount of substance of how many elementary particles are present in a given substance.
It is defined as exactly 6.022×10²³ elementary entities. The elementary entity can be a molecule, atom ion depending on the type of substance. Amount of elementary entities in a mole is called as Avogadro's number.
It is widely used in chemistry as a suitable way for expressing amounts of reactants and products.For the practical purposes, mass of one mole of compound in grams is approximately equal to mass of one molecule of compound measured in Daltons. Molar mass has units of gram per mole . In case of molecules, where molar mass in grams present in one mole of atoms is its atomic mass.
Baking soda has molar mass of 84 g /mole, thus mass is calculated using number of moles formula which is mass= molar mass×number of moles, which is mass=84×0.050=4.2 g.
Thus,4.2 g of baking soda should be weighed out by chef.
Learn more about mole concept,here:
https://brainly.com/question/12805690
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ASAP worth 15 points also
A pupil has drawn the electronic structure of fluorine and the diagram is shown below. However,
mistakes have been made. State three mistakes that have been made.
The first shell can only hold 2 electrons, but the pupil placed in 8 electrons.
The second shell can hold up to 8 electrons, but the pupil only placed in 2 electrons.
Flourine only has 9 total electrons, yet there are 10 electrons in the diagram.
Answer:
Explanation:
In the Fluorine atom there are 2 electrons in the innermost shell and 7 i the outer shell.
Complete combustion of a 0.350 g sample of a compound in a bomb calorimeter releases 14.0 kJ of heat. The bomb
calorimeter has a mass of 1.20 kg and a specific heat of 3.55 J/(g;°C).
If the initial temperature of the calorimeter is 22.5°C, what is its final temperature?
Use 0= mCOAT
Answer:
i cant understand what you wrote
Explanation:
it's a blank screen
