check the correctness of formula t=2π √m/k, dimensionally​

Answers

Answer 1

Hi there! Lets see!

m is mass, and its units are kgk is the elastic constant measured in newtons per meter (N/m), or kilograms per second squared kg/s²

Therefore:

[tex]\sqrt{\dfrac{m}{k}} =\sqrt{\dfrac{[kg]}{[\dfrac{kg}{s^2}]}} =\sqrt{\dfrac{[kg]}{[kg]}\cdot s^2} = \sqrt{[s]^2} = s[/tex]

The period is given in seconds so the formula is dimensionally​ correct.


Related Questions

Help please an observer at the North Pole sees the moon phase shown below. What Moon phase will be observed approximately one week later?

Answers

Answer:

it should be a new moon

Explanation:

HURRY
An ultrasound tech is trying to identify an object, but the screen of the machine is broken. Which statement best describes this situation?

The generated sound wave will not be able to reflect off of the object.
The sound wave will not be generated, so there will be no echoes received.
The echoes will be made but will not be able to be received by the machine.
The machine will not be able to process the received echoes into images.

Answers

Answer:

It’s b

Explanation:

Everyone else is wrong and I tried this and got it right

Answer:

the answer is b or "The sound wave will not be generated, so there will be no echoes received."

Explanation:

give a strong idea to protect , purify and the beautify of the Dal lake​

Answers

Answer:

Water in dal lake is test for any heavy metals and pollutant, sewage and drainage system are also monitored for the same.

Explanation:

Dal lake is located in Srinagar that is the state capital of Kashmir and is known for recreation and tourism purposes. The area covers about 18 km sq. and forms a part of natural wetlands. The lake is prone to pollution and has recently undergone restoration measures. To address the problems of eutrophication algae and large-scale microplankton have been removed from the water. The government of India has taken various measures to check the pollution by setting up a committee to monitor the proper use of allotted funds.

How does simple machines make work easier?

Answers

They make it so you would exert less force and make things easier to move

The simple machines can help make work easier by working quicker than the people and making other peoples jobs easier.

Explanation:

I hope this helped.

The Sputnik 1 satellite orbited Earth
(mass = 5.98 x 1024 kg) in a circle of
radius 6.96 x 106 m. What was its
period of orbit in seconds?
[?] s

Answers

Answer:

5778.1931

Explanation:

Given that:

Mass (M) = 5.98 x 10^24 kg

Radius (r) = 6.96 x 10^6 m

Gravitational constant (G) = 6.67 * 10^-11

Using the relation:

T² / R³ = 4π² / GM

Where T = period of orbit

T = 2π√(R³ /GM)

T = 2π√((6.96 x 10^6)³) /(6.67 * 10^-11) * (5.98 x 10^24)

T = 2π√((3.37153 * 10^20) / (39.866 * 10^13))

T = 2π √845715.64

T = 2π * 919.62799

T = 5778.1931

What is the minimum energy (in MeV) that is required to break a nucleus of 12C (of mass 11.99671 u) into three nuclei of 4He (of mass 4.00151 u each)?

Answers

Answer:

the minimum energy that needed to break the nucleus is  1.12608 × 10^-12 J

Explanation:

The computation of the minimum energy that needed to break the nucleus is shown below:

The Change in mass is

= 11.99671 - 3 × 4.00151

= 0.00782

The Energy = mc^2

= (0.00782 × 1.6 × 10^{-27}) × (3 × 10^8)^2

= 1.12608 × 10^-12 J

Hence, the minimum energy that needed to break the nucleus is  1.12608 × 10^-12 J

The same is to be considered

A proton moves at a speed of 850 m/s in a direction perpendicular to a magnetic field with a magnitude of 0.70 T. What is the magnitude of the magnetic force on the proton?

Answers

Answer:

The magnitude of the magnetic force on the proton is 9.532 x 10⁻¹⁷ N

Explanation:

Given;

speed of proton, v = 850 m/s

magnitude of magnetic field, B = 0.7 T

Charge of proton, q = 1.602 x 10⁻¹⁹ C

The magnitude of the magnetic force on the proton;

F = qvB

F = ( 1.602 x 10⁻¹⁹)(850)(0.7)

F = 9.532 x 10⁻¹⁷ N.

Therefore, the magnitude of the magnetic force on the proton is 9.532 x 10⁻¹⁷ N

The diagrams below show forces acting on a toy car as it moves to the right which diagram shows the toy car that will most likely accelerate to the right based on these conditions?

Answers

Answer:

Option 1.

Explanation:

To know which option is correct, let us calculate the net force in each case to know which will move to the right direction.

Option 1:

Force to the right (Fᵣ) = 8 N

Force to the left (Fₗ) = 6 N

Net force (Fₙ) =?

Fₙ = Fᵣ – Fₗ

Fₙ = 8 – 6

Fₙ = 2 N to the right

Option 2:

Force to the right (Fᵣ) = 8 N

Force to the left (Fₗ) = 10 N

Net force (Fₙ) =?

Fₙ = Fₗ – Fᵣ

Fₙ = 10 – 8

Fₙ = 2 N to the left

Option 3:

Force to the right (Fᵣ) = 10 N

Force to the left (Fₗ) = 10 N

Net force (Fₙ) =?

Fₙ = Fᵣ – Fₗ

Fₙ = 10 – 10

Fₙ = 0 (no movement)

Option 4:

Force to the right (Fᵣ) = 10 N

Force to the left (Fₗ) = 13 N

Net force (Fₙ) =?

Fₙ = Fₗ – Fᵣ

Fₙ = 13 – 10

Fₙ = 3 N to the left

From the illustrations made above, only option 1 has a net force toward the right direction. Therefore, only option 1 will have an acceleration towards the right direction.

Answer:

Option 1

Explanation:

A 1100 kg sports car accelerates from 0m/s to 32m/s in 10 seconds. What is the average power of the engine?

Answers

Answer:

The average power of the engine of the sports car is 56.32 kW

Explanation:

Given;

mass of the sports car, m = 1100 kg

initial velocity of the sports car, u = 0 m/s

final velocity of the sports car, v = 32 m/s

time of motion, t = 10 s

The kinetic energy of the car is given by;

K.E = ¹/₂m(v² - u²)

K.E = ¹/₂mv²

K.E = ¹/₂ x 1100 x 32²

K.E = 563200 J

The average power of the engine of the sports car is given by;

Pavg = Energy / time

Pavg = 563200 / 10

Pavg = 56320 W

Pavg = 56.32 kW

Therefore, the average power of the engine of the sports car is 56.32 kW

According to the Law of the Conservation of Matter, if you dissolve 25 grams of sugar into 150 grams of water, the mixture should weigh how much?

Answers

19grams becauce if u

If we increase the driving frequency in a circuit with purely resistive load, how do the amplitudes VR and IR change?

Answers

Answer:

V = I R    

expression does not depend on the frequency, so when changing this quantity does not change the voltage or the current in the circuit.

Explanation:

In a purely resistive circuit, the Ohm relation, m for which

          V = I R

We see that the previous expression does not depend on the frequency, so when changing this quantity does not change the voltage or the current in the circuit.

This does not happen in circuits with capacitors or inductors where there is an explicit dependence on frequency.

What is the kinetic energy of a 4-kg toy car moving at a velocity of 8 m/s?
O 32J
64 J
O
128 J
256 J

Answers

Answer:

128 J

Explanation:

The kinetic energy of an object can be found by using the formula

[tex]k = \frac{1}{2} m {v}^{2} \\ [/tex]

m is the mass

v is the velocity

From the question we have

[tex]k = \frac{1}{2} \times 4 \times {8}^{2} \\ = 2 \times 64[/tex]

We have the final answer as

128 J

Hope this helps you

Mass of toy the car = 4 kg

Velocity of toy the car = 8 m/s

Kinetic energy of an object is the energy that it possesses due to its motion.

Kinetic energy is directly proportional to the mass of the object and to the square of its velocity.

Formula of Kinetic energy:

[tex] \boxed{ \bf{KE = \dfrac{1}{2}mv^2}}[/tex]

KE → Kinetic energy of the Object (J)

m → Mass of the Object (kg)

v → Speed of the Object (m/s)

By substituting values in the formula, we get:

[tex] \rm \longrightarrow KE = \dfrac{1}{2} \times 4 \times 8^2 \\ \\ \rm \longrightarrow KE = \dfrac{1}{2} \times 4 \times 64\\ \\ \rm \longrightarrow KE = 2 \times 64 \\ \\ \rm \longrightarrow KE = 128 \: J[/tex]

[tex] \therefore [/tex] Kinetic energy of the toy car = 128 J

A 1235 kg whale swims horizontally at a speed of 6.4 m/s. It suddenly collides directly with a stationary seal of mass 189 kg. The seal grabs onto the whale and holds fast. What is the speed of these two sea creatures just after their collision?

Answers

Answer:

The speed of these two sea creatures just after their collision is 5.55 m/s.

Explanation:

Given;

mass of the whale, m₁ = 1235 kg

initial speed of the whale, u₁ = 6.4 m/s

mass of the seal, m₂ = 189 kg

initial speed of the seal, u₂ = 0

let their final speed after collision, = v

Apply the principle of conservation of linear momentum;

m₁u₁ + m₂u₂ = v(m₁ + m₂)

(1235 x 6.4) + (189 x 0) = v(1235 + 189)

7904 = 1424v

v = 7904 / 1424

v = 5.55 m/s

Therefore, the speed of these two sea creatures just after their collision is 5.55 m/s.

HELLPPPP PLZZZ
10. Identify Which gas law
does this graph represent.

Answers

This graph represents Boyle’s gas law because as the pressure is increasing, the volume is decreasing. Boyle’s law states that pressure and volume will have an inverse relationship (opposite or reverse) when temperature is constant, which is what’s going on here. So, as pressure goes up, volume goes down. The other relationship is as pressure goes down, volume goes up.

Write 3 paragraphs explaining conduction, convection, and radiation. The paragraph must include examples of each and explain the type of energy. It also must include conductors and insulators and various examples of each.

Answers

Answer:

Eeeeeeeeeeeeeeeeeeeeeeeeeee


What is responsible for keeping an object at rest or maintaining an object's
constant velocity?

Answers

Answer:

Inertia

Explanation:

Inertia is a force which keeps stationary objects at rest and moving objects in motion at constant velocity.

Betelgeuse - the right shoulder star of Orion - is a red giant star. Its radiation peaks in the infrared at λ = 800 nm. What is the surface temperature of the star?

Answers

Answer:

3622.5 K

Explanation:

The radiation of red giant star is 800nm.

We need to find the surface temperature of the star. Let it is T.

Using Wein's displacement law to find it as follows :

[tex]\lambda=\dfrac{C}{T}[/tex]

C is constant an T is temperature

[tex]T=\dfrac{C}{\lambda}\\\\T=\dfrac{2.898\times 10^{-3}}{800\times 10^{-9}}\\\\ T=3622.5\ K[/tex]

So, the surface temperature of the star is 3622.5 K.

When a red giant star begins to burn helium, it

Answers

the outer shell of the star are blown off with big clouds of gas and dust which is know as a nebula

ok who love lizard can we talk plz

Answers

Answer:

Meeee

Explanation:

A body can have zero average velocity but not zero average speed. Why?​

Answers

displacement can be zero so velocity is zero but the distance won’t be zero so speed won’t be zero

A projectile is fired horizontally from a height of 78.4 m at a speed of 300 m/sec. How far did it travel horizontally before hitting the ground?​

Answers

Answer:

Explanation:

Using the formula for calculating range expressed as;

R = U√2H/g

U is the speed = 300m/s

H is the maximum height = 78.4m

g is the acceleration due to gravity = 9.8m/s²

Substitute into the fromula;

R = 300√2(78.4)/9.8

R = 300 √(16)

R = 300*4

R = 1200m

Hence the projectile travelled 1200m before hitting the ground

N stands for _____________________, which is an SI unit of force.

Answers

Answer:

Newton

Explanation:

When Royce was 10 years old, he had a mass of
30 kg. By the time he was 16 years old, his mass
increased to 60 kg. How much larger is the
gravitational force between Royce and Earth at
age 16 compared to age 10?

Answers

Answer:

The gravitational force between Royce and Earth would be doubled at 16 years.

Explanation:

"Newton's law of universal gravitation states that gravitation force between two masses is proportional to the magnitude of their masses and inverse-squared of their distance".

Royce Scenario

At the age of 10 Royce's mass = 30kg

At the age of 16 Royce's mass = 60kg

From Newton's law of universal gravitation, an Increase in the mass of a body would amount to a corresponding increase in the gravitational force.

In the case of Royce, the mass double between the age of 10 and 16, so there would be an increase of the gravitation force by double.

The gravitational force at the age of 60 is doubled of the gravitational force at the age of 10. A complete solution is below.

Given:

At 10 years old,

Mass,

m = 30 kg

now,

→ [tex]Gravitational \ force (F_1) = \frac{GMm}{r^2}[/tex]

                                          [tex]= mg[/tex]

or,

→ [tex]g = \frac{GM}{r^2}[/tex]

then,

Gravitational force = 30 g

Now,

At 16 years old,

Mass,

m = 60 kg

Now,

→ [tex]\frac{F_1}{F_2} = \frac{30}{60}[/tex]

       [tex]=\frac{1}{2}[/tex]

  [tex]F_2 = 2F_1[/tex]

Thus the above response is right.

Learn more:

https://brainly.com/question/22416758

(30points pls help ASAP) How many grams of sodium would there be in 70 g of NaCl?

Answers

I believe 1.05g:))))))

27.52g grams of sodium would there be in 70 g of NaCl.

What is molecular mass ?

The molecular mass gives the total mass of the molecule, it is the sum of masses of all the atoms present in a molecule. for example in Nacl, there is one atom of Na and one atom of Cl both makes NaCl. the sum of masses of Na and Cl gives the mass of the NaCL. Molecular mass is expressed in amu. 1 amu = Avogadro's number of atom or molecule.

The Molar mass is defined as the mass of a given substance divided by the amount of a substance. its unit is g/mol.

Here I have direct method for the calculation of mass of particular atom in the molecule.

Molecular weight of the NaCl is,

(23+35.5)g=58.5g where 23= mass of Na and 35.5 mass Cl.

in this we can see that 58.5 g of Nacl contains 23 g of Na.

we can write 58.5 NaCl = 23g Na

therefore 70g of NaCl = (23÷58.5)×70 Na

70g of NaCl = 27.52g of Na

Hence 70g of NaCl contains 27.52g of sodium.

To know more about molecular mass, click :

https://brainly.com/question/18446366

#SPJ2

what is da answer please i need help

Answers

Answer:

Air and water i think

Explanation:

Cause Air =25% and water=25% so that equals 50%

the nitrogen group has 5 electrons true or false

Answers

Answer:

True

Nitrogen family elements consists of atoms having 5 electrons in their outer energy level.

Please mark me the brainliest

Hope it may helps you

A book on a 2-meter high shelf has a mass of 0.4 kg. What is its potential energy?

Answers

Answer:

[tex]\boxed {\boxed {\sf 7.84 \ Joules}}[/tex]

Explanation:

The formula for potential energy is:

[tex]PE=m*g*h[/tex]

where m is the mass, g is the gravitational acceleration, and h is the height.

The mass of the book is 0.4 kilograms. The gravitational acceleration on Earth is 9.8 m/s². The height of the book is 2 meters.

[tex]m=0.4 \ kg \\g=9.8 \ m/s^2 \\h=2\ m[/tex]

Substitute the values into the formula.

[tex]PE=(0.4 \ kg)(9.8 \ m/s^2)(2 \ m)[/tex]

Multiply the first two numbers.

0.4 kg*9.8 m/s²= 3.92 kg*m/s²If we convert the units now, the problem will be much easier later on. 1 kg*m/s² is equal to 1 Newton. So, our answer of 3.92 kg*m/s² is equal to 3.92 N

[tex]PE=(3.92 \ N )(2 \ m)[/tex]

Multiply.

3.92 N* 2 m=7.84 N*m1 Newton meter is equal to 1 Joule (this is why we converted the units). Our answer is equal to 7.84 Joules.

[tex]PE=7.84 \ J[/tex]

Answer:

7.84 is your answer ok bye

How much heat does 56 L of water need to absorb to raise its temperature from 350C to 740C?​

Answers

Answer:

300 L of water

Explanation:

(3x104 kg) (4 x 104 m)
6 x 104 s​

Answers

Answer:

77852x∧100 kgms

Explanation:

can a body have mass but no weight give reasion for your answer​

Answers

Answer:

Hey buddy, here is your answer. Hope it helps you.

Explanation:

Yes, weight of a body is not constant, it varies with the value of acceleration due to gravity, g. Weight of a body is zero, when it is taken to the centre of the earth or in the interplanetary space, where g=0. Mass is the total matter in a body, while weight is the force by which the body is attracted.

Weight is never constant while mass is. So we can have weight zero but with some mass. This will happen when an object is at the centre of earth, as g=0 at centre of earth , so weight will be 0 while mass will always be constant everywhere

Answer:

yes a body can have mass but no wt at a centre of the earth

Explanation:

this is because acceleration due to gravity decreases as we go deep into earth and becomes 0 at the centre

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