Based on the percent moisture content of the dried product, the mass of dried casein produced os 852.3 kg.
What is the mass of casein in wet casein?The mass of casein in 1000 Kg of wet casein is 75% 1000 kg = 750 Kg
Mass of water 250 kg
The mass of casein is constant while the moisture content can be changed.
At 12% moisture content;
750 kg = 88%%
100 % = 100 ×750/88 = 852.27 kg
Therefore, the mass of dried casein produced os 852.3 kg.
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Linkage-style clutch control systems use a system of _______ between the clutch pedal and the clutch fork.
Linkage-style clutch control systems use a system of levers, cables, and rods between the clutch pedal and the clutch fork.
What is a clutch?A clutch can be defined as a mechanical device that is designed and developed to play the role of engaging and disengaging power transmission in the input shaft, so that the speed of input shaft can be changed as necessary.
In Mechanical engineering, linkage-style clutch control systems can use a system of levers, cables, and rods between the clutch pedal and the clutch fork.
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A 90° elbow in a horizontal pipe is used to direct water flow upward at a rate of 45 kg/s. Another identical elbow is attached to the existing elbow such that the water flow makes a U-turn as shown in the second figure. The diameter of the entire elbow is 10 cm. The elbow discharges water into the atmosphere, and thus the pressure at the exit is the local atmospheric pressure. The elevation difference between the centers of the exit and the inlet of the elbow is 50 cm. The weight of the elbow and the water in it is considered to be negligible. Take the momentum-flux correction factor to be 1.03 at both the inlet and the outlet. Take the density of water to be 1000 kg/m3.
When a liquid flows in a horizontal pipe, the force component in horizontal direction is 650 N.
What is force?The force which acts on the liquid depends upon the density of fluid, it volume and acceleration due to gravity.
Given, mass flow rate m = 45 kg/s, D1 =D2 =10cm, density ρ =1000 kg/m³ and momentum flux correction factor is K =1.03.
Using the Bernoulli's theorem, we have
P1/ρg +V1²/2g +z1 =P2/ρg +V2²/2g +z2
P1/ ρg =z2 - z1 = 0.5 m
P1 = 4.905kPa
The force in horizontal direction is
Fx = P1A1 +ρQ(V1 - V2cosθ) x K
here θ =180°
ρAV1 =m =45
1000 x π/4x (0.1)² x V1 =45
V1 = 5.732 m/s
Fx =(4.905 x π/4 x 0.1²) x 10³ + 42 x 5.732 x 2
Fx = 650N
Thus, the force component in horizontal direction is 650N.
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