can the value of y be the same for all X values in a function

Answer:

B

Step-by-step explanation:

x must be a number between 60 and 57 and those numbers are 58 or 59

60 is greater than 59, and 59 is greater than 57

Answer:

x = 59

Step-by-step explanation:

The number must be less than 60 from the first inequality and greater than 57 from the second inequality

so the integers allowed are 58,59

Answer:

  A

Step-by-step explanation:

The relevant rules of exponents are ...

  (a^b)^c = a^(bc)

  a^-b = 1/a^b

__

  [tex]\left(\dfrac{2^{-10}}{4^2}\right)^7=\dfrac{2^{(-10)(7)}}{4^{(2)(7)}}=\dfrac{2^{-70}}{4^{14}}\\\\=\boxed{\dfrac{1}{2^{70}\cdot 4^{14}}}[/tex]

Answer:

D

Step-by-step explanation:

The scale factor is the ratio of the corresponding sides, image to original, that is

scale factor = [tex]\frac{P'S'}{PS}[/tex] = [tex]\frac{6}{3}[/tex] = 2 → D

Answer:

[tex]X \sim N(200000,100000)[/tex]  

Where [tex]\mu=200000[/tex] and [tex]\sigma=10000[/tex]

From the empirical rule we know that within one deviation from the mean we have 68% of the values so then 1 deviation above the mean we will have (100-68)/2 = 16% and then the number of houses that are greater than one deviation above the mean are:

[tex] Number = 1216*0.16 = 194.56[/tex]

And the answer woud be between 194 and 195 houses

Step-by-step explanation:

Let X the random variable that represent the value of homes in Hampton VA of a population, and for this case we know the distribution for X is given by:

[tex]X \sim N(200000,100000)[/tex]  

Where [tex]\mu=200000[/tex] and [tex]\sigma=10000[/tex]

From the empirical rule we know that within one deviation from the mean we have 68% of the values so then 1 deviation above the mean we will have (100-68)/2 = 16% and then the number of houses that are greater than one deviation above the mean are:

[tex] Number = 1216*0.16 = 194.56[/tex]

And the answer woud be between 194 and 195 houses

Answer:

[tex]D[/tex]

Step-by-step explanation:

[tex]36 + 60[/tex]

[tex]12(3)+12(5)[/tex]

[tex]12(3+5)[/tex]

Answer:

12( 3+5)

Step-by-step explanation:

Answer:

a=0.000000002

b=0.95762

c=$2800

Step-by-step explanation:

Kindly check attached picture for other calculation and the Poisson Probability Distribution for the problem.

Answer:

a. The mean of the sample is M=35.

The variance of the sample is s^2=39.125.

The standard deviation of the sample is s=6.255.

b. z=-1.6

c. SEM = 2.212

Step-by-step explanation:

The mean of the sample is M=35.

The variance of the sample is s^2=39.125.

The standard deviation of the sample is s=6.255.

Sample mean

[tex]M=\dfrac{1}{8}\sum_{i=1}^{8}(27+25+32+40+43+37+35+38)\\\\\\ M=\dfrac{277}{8}=35[/tex]

Sample variance and standard deviation

[tex]s^2=\dfrac{1}{(n-1)}\sum_{i=1}^{8}(x_i-M)^2\\\\\\s^2=\dfrac{1}{7}\cdot [(27-(35))^2+(25-(35))^2+(32-(35))^2+(40-(35))^2+(43-(35))^2+(37-(35))^2+(35-(35))^2+(38-(35))^2]\\\\\\[/tex]

[tex]s^2=\dfrac{1}{7}\cdot [(58.141)+(92.641)+(6.891)+(28.891)+(70.141)+(5.64)+(0.14)+(11.39)]\\\\\ s^2=\dfrac{273.875}{7}=39.125\\\\\\s=\sqrt{39.125}=6.255[/tex]

b. If the population mean is 45, the z-score for M=35 would be:

[tex]z=\dfrac{M-\mu}{\sigma}=\dfrac{35-45}{6.255}=\dfrac{-10}{6.255}=-1.6[/tex]

c. The standard error of the mean (SEM) of this group is calculated as:

[tex]SEM=\dfrac{s}{\sqrt{n}}=\dfrac{6.255}{\sqrt{8}}=\dfrac{6.255}{2.828}=2.212[/tex]

Answer:

The probability that he ends up with a full house is 0.0083.

Step-by-step explanation:

We are given that a gambler has been dealt five cards—two aces, one king, one 3, and one 6. He discards the 3 and the 6 and is dealt two more cards.

We have to find the probability that he ends up with a full house (3 cards of one kind, 2 cards of another kind).

We know that gambler will end up with a full house in two different ways (knowing that he has given two more cards);

Only in these two situations, he will end up with a full house.

Now, there are three kings and two aces left which means at the time of drawing cards from the deck, the available cards will be 47.

So, the ways in which we can draw two kings from available three kings is given by =  [tex]\frac{^{3}C_2 }{^{47}C_2}[/tex]   {∵ one king is already there}

              =  [tex]\frac{3!}{2! \times 1!}\times \frac{2! \times 45!}{47!}[/tex]           {∵ [tex]^{n}C_r = \frac{n!}{r! \times (n-r)!}[/tex] }

              =  [tex]\frac{3}{1081}[/tex]  =  0.0028

Similarly, the ways in which one king and one ace can be drawn from available 3 kings and 2 aces is given by =  [tex]\frac{^{3}C_1 \times ^{2}C_1 }{^{47}C_2}[/tex]

                                                                   =  [tex]\frac{3!}{1! \times 2!}\times \frac{2!}{1! \times 1!} \times \frac{2! \times 45!}{47!}[/tex]

                                                                   =  [tex]\frac{6}{1081}[/tex]  =  0.0055

Now, probability that he ends up with a full house = [tex]\frac{3}{1081} + \frac{6}{1081}[/tex]

                                                                                    =  [tex]\frac{9}{1081}[/tex] = 0.0083.

Answer:

0.0083

Step-by-step explanation:

The gambler will have full house if he is dealt two kings or ace and a king.Now, there are 47 cards left in the deck and two which are aces and three are king.

The probability of these event are [tex]\frac{3C_2}{47C_2}[/tex]

and  [tex]\frac{3C_1\times 2C_1}{47C_2}[/tex]  respectively. So, the probability of a full house is given as:

[tex]\frac{3C_2}{47C_2}+\frac{3C_1\times 2C_1}{47C_2}[/tex]

=0.0083

Answer: A. 85ᴼC

Step-by-step explanation:

0 degrees Celsius is at 32 degrees Fahrenheit.

100 degrees Celsius is at 212 degrees Fahrenheit.

212 - 32 = 180

180 / 100 = 1.8

So, every degree Celsius is 1.8 degrees Fahrenheit, starting at 32 of course.

1.8 * 85 = 153

153 + 32 = 185

Answer:

The correct answer is 85°C.

Step-by-step explanation:

I use the equation 9C = 5F - 160 to solve for temperatures.

Therefore, we just insert values for each variable except for the one that we want to solve for. In this case, we are doing Fahrenheit → Celsius, so we are solving for the unknown variable of C. We are given a value for F, 185°.

Therefore, just insert these into the equation and solve for C.

[tex]9C = 5(185)-160[/tex]

[tex]9C = 925 - 160[/tex]

[tex]9C = 765[/tex]

[tex]\frac{765}{9} = 85[/tex]

C = 85°C

Answer:

23.55 or [tex]\frac{15}{2}[/tex]π

Step-by-step explanation:

The arc is 75% of the full circumference, as the cut away angle is 90º.

To find the arc length, you multiply the ratio of the whole circle that remains by the circumference: [tex]\frac{270}{360}[/tex]×π×2(5)=[tex]\frac{15}{2}[/tex]π, or 23.55 if you round pi to 3.14.

Answer:

7.85

Step-by-step explanation:

Solve this by using the formula for arc length with central angle in degrees.

Do this by identifying the formula and plugging in the given values. The formula for arc length is [tex]arc length = 2\pi r (\frac{theta}{360} )[/tex] , where the theta is represented by the central angle and r is the radius

The radius is shown on the circle is 5 and the theta (angle in degrees) is 90, represented by the tiny square in the middle.

Plug it all into the formula. Your equation should now look like this: arc length = 2 (3.14 or [tex]\pi[/tex]) (5) ([tex]\frac{90}{360}[/tex])

Solve for arc length and enter your answer as a decimal or in terms of pi

Answer: The answer is given below

Step-by-step explanation:

In statistics, a stratified sampling is a method of sampling that is gotten from a population that can be divided into subpopulations.

Based on th information provided in n the question, the 6 most populous counties and their populations are provided below

Mecklenburg County, North Carolina 969,031

Wake County, North Carolina 952,151

Guilford County, North Carolina 500,879

Forsyth County, North Carolina 358,137

Cumberland County, North Carolina 324,049

Durham County, North Carolina 279,64

Answer:

1443.3 in³ or 0.835 ft³

Step-by-step explanation:

Let's begin by listing out the given variables:

length (l) = 100 ft = 1200 in, nominal size = 4 in

From the copper tube of industry standard guide of the design and the installation of piping system, the dimension and physical characteristics of type M copper tubing of nominal size 4 inch is given as

Outer diameter (Do) = 4.125 in ⇒ ro = Do ÷ 2 = 2.0625 in, Inner diameter (Di) = 3.935 in ⇒ ri = Di ÷ 2 = 1.9675 in

calculate the volume of the pipe, we use the formula

V = π(ro² - ri²) * l

V = π(2.0625² - 1.9675²) * 1200

V = 1443.3 in³ or 0.835 ft³

Answer:

C/B

Step-by-step explanation:

Ax + By = C

Subtract Ax from each side

Ax -Ax+ By =-Ax+ C

By = -Ax +C

Divide each side by B

By/B = -A/Bx +C/B

y = -A/Bx +C/B

The y intercept is C/B

Answer:

I think it's just E.

Step-by-step explanation:

When you name triangles, you would often put a Δ and then the letters of the 3 angles. The only answer that fits that criteria is E.

The valid name for the given triangle is ΔΧΜΑ.

A triangle is a 3-sided polygon that consists of three edges and 3 vertices. The most vital asset of a triangle is that the sum of the inner angles of a triangle is identical to a hundred and eighty tiers. This belonging is called the attitude sum property of the triangle.

Learn more about triangle here https://brainly.com/question/2938476

#SPJ2

Answer:

a) s = (4-t)/(t^2+4)^2,   a(t) = (2t^3-24t)/(t^2+4)^3

b) s = 0.2ft, v = 0.12 ft/s,  a = -0.176 ft/s^2

c) t = 2s

d) slowing down for t < 2, speeding up for t > 2

e) 0.327 ft

Step-by-step explanation:

The position function of a particle is given by:

[tex]s(t)=\frac{t}{t^2+4},\ \ \ t\geq 0[/tex]   (1)

a) The velocity function is the derivative, in time, of the position function:

[tex]v(t)=\frac{ds}{dt}=\frac{(1)(t^2+4)-t(2t)}{(t^2+4)^2}=\frac{4-t^2}{(t^2+4)^2}[/tex]   (2)

The acceleration is the derivative of the velocity:

[tex]a(t)=\frac{dv}{dt}=\frac{(-2t)(t^2+4t)^2-(4-t^2)2(t^2+4)(2t)}{(t^2+4)^4}\\\\a(t)=\frac{(-2t)(t^2+4)-4t(4-t^2)}{(t^2+4)^3}=\frac{2t^3-24t}{(t^2+4)^3}[/tex] (3)

b) For t = 1 you have:

[tex]s(1)=\frac{1}{1+4}=0.2\ ft\\\\v(1)=\frac{4-1}{(1+4)^2}=0.12\frac{ft}{s}\\\\a(1)=\frac{2-24}{(1+4)^3}=-0.176\frac{ft}{s^2}[/tex]

c) The particle stops for v(t)=0. Then you equal equation (2) to zero ans solve the equation for t:

[tex]v(t)=\frac{4-t^2}{(t^2+4)^2}=0\\\\4-t^2=0\\\\t=2[/tex]

For t = 2s the particle stops.

d) The second derivative evaluated in t=2 give us the concavity of the position function.

[tex]\frac{d^2s}{dt^2}=a(2)=\frac{2(2)^3-24(2)}{(2^2+4)^3}=-0.062<0[/tex]

Then, the concavity of the position function is negative. For t=2 there is a maximum. Before t=2 the particle is slowing down and after t=2 the particle is speeding up.

e) Due to particle goes and come back. You first calculate s for t=2, then calculate for t=5.

[tex]s(2)=\frac{2}{2^2+4}=0.25\ ft[/tex]

[tex]s(5)=\frac{5}{5^2+4}=0.172\ ft[/tex]

The particle travels 0.25 in the first 2 seconds. In the following three second the particle comes back to the 0.172\ ft. Then, in the second trajectory the particle travels:

0.25 - 0.127 = 0.077 ft

The total distance is the sum of the distance of the two trajectories:

s_total = 0.25 ft + 0.077 ft = 0.327 ft

Answer:

Divide 757 by 68 so:

Step-by-step explanation:

757 / 68 = 11.9 so 757 can go into 68 11.9 times.

Hope this helps, have a good day! :)

(Brainliest would be appreciated?)

Step-by-step explanation:

please give me full question

Answer:

3/2

Step-by-step explanation:

(3/4) / (1/2) is equivalent to (3/4)*(2/1), or 6/4, or 3/2.

To divide by a fraction, invert the fraction and multiply instead.

Answer:

the answer is 1 and 1/2

Answer:

x = 0.4

Step-by-step explanation:

Let me rewrite it so it looks better:

[tex]\frac{3}{4} x=\frac{3}{10}[/tex]

The first way is to cross multiply.

30x = 12

x=0.4

The other way is to see that the two numerators are the same except for the x on the left side.

You can see the the denominators are 4 and 10.

You can create a proportion of 4 : 10 and apply it to the fractions.

You get that you have to multiply the left side by 0.4, so x = 0.4

Answer:

0.4

Step-by-step explanation:

Answer:

(A)C,D,A,B

Step-by-step explanation:

[tex]f(x) = x^2- 2x\\g(x) = x^3-1[/tex]

a)

[tex]f(-2) = (-2)^2- 2(-2)\\=4-(-4)\\=4+4\\=8$ (C)[/tex]

b)

[tex]g(-2) = (-2)^3-1\\\=-8-1\\=-9 $(D)[/tex]

c)

[tex]f(-1) = (-1)^2- 2(-1)=1+2=3\\g(3) = (3)^3-1=27-1=26\\f(-1) + g(3)=3+26\\=29$ (A)[/tex]

d) f(5) : g(2)

[tex]f(5) = (5)^2- 2(5)=25-10=15\\g(2) = (2)^3-1=8-1=7\\f(5) :g(2)=15/7$ (B)[/tex]

Answer:

0.927

Step-by-step explanation:

Hope this helps.

Answer:

I think it would just be 0.927

Step-by-step explanation:

with 0.9267, 6 is in the thousandth spot. 2 is in the hundredth spot, and 9 is in the tenth spot. Since the number behind 6 is larger than five, you'd round your number 6 in the thousandth spot to a 7. Therefore, you should have 0.927.

Answer: there is a relationship between study hours and test score. as the hours of studying increase, the test scores increase.

Answer:

C) There is a relationship between study hours and test score. As the hours of studying increase, the test scores increase.

Step-by-step explanation:

In the scatter plot, I can see that when the hours increase, so does the test scores. Thus, the answer is C

Answer:

80 shipments will be 80 * 431 = 34,480 coats.

9514 1404 393

Answer:

  |m-2.5| ≤ 0.08

  2.42 ≤ m ≤ 2.58

Step-by-step explanation:

The equation of interest is the one that says the positive difference from the ideal mass is at most 0.08 ounces:

  |m -2.5| ≤ 0.08 . . . an absolute value inequality

The solution is found by solving the equivalent compound inequality:

  -0.08 ≤ m -2.5 ≤ 0.08

  2.42 ≤ m ≤ 2.58 . . . . the range of masses

Answer:

8/3 km

Step-by-step explanation:

we can represent the given information on a table:

Kilometers        time (hours)

      2/5           ⇔         1 1/2

and since we want to know how many kilometers (x) will be paved on 10 hours:

Kilometers        time (hours)

      2/5           ⇔         1 1/2

        x             ⇔         10

The relationship these 3 numbers have can be described by using the rule of three, which is to multiply the cross quantities on the table (2/5 by 10) and then divide by the remaining amount (1 1/2):

x = [tex]\frac{2}{5}*10[/tex] ÷ [tex]1\frac{1}{2}[/tex]

x = [tex]\frac{20}{5}[/tex] ÷ [tex]1\frac{1}{2}[/tex]

we use [tex]1\frac{1}{2}=\frac{3}{2}[/tex]

x = [tex]\frac{20}{5}[/tex] ÷ [tex]\frac{3}{2}[/tex]

and we make the division:

x = [tex]\frac{20}{5}[/tex] ÷ [tex]\frac{3}{2}[/tex] = [tex]\frac{20*2}{5*3}=\frac{40}{15}[/tex]

we simplify the fraction by dividing the numerator and denominator both by 5, and we get the result:

x = [tex]\frac{8}{3}[/tex]

thus, in 10 hours the crew will pave 8/3 km. Which is about 2.66 km.

Answer:

44

Step-by-step explanation:

f(x) = 6x - 4

f(8) = 6(8) - 4

f(8) = 48 - 4

f(8)= 44

Answer:

The carts velocity= 2m/s

Step-by-step explanation:

It took Manuel 87 seconds to push a shopping cart directly to his car.

One third of 87 = 87/3 = 29

In 29 seconds the carts moved 58 meter's.

The carts velocity = distance/time

The carts velocity = 58/29

The carts velocity= 2m/s

Answer:

40

Step-by-step explanation:

let the numbers be a+b+c+d.

the average of 4 numbers is 38

; (a+b+c+d)/4 = 38

(a+b+c+d) = 152 ......equ1

the average of the first two numbers is 42

; (a+b)/2 = 42

(a+b) = 84 ...... equ2

the average of the last three numbers is 36

; (b+c+d)/3 = 36

(b+c+d) = 108 .....equ3

substitute equ3 into equ1

a + 108 = 152

a= 152 - 108

a = 44

input the value of a into equ2

44 + b = 84

b = 40

the second number is 40.

I hope this helps.

Answer:

The null and alternative hypothesis are:

[tex]H_0: \mu=47.79\\\\H_a:\mu< 47.79[/tex]

This is a left tailed test.

Step-by-step explanation:

A hypothesis test is to be performed to determine whether last​ year's mean local monthly bill for cell phone users has decreased from the 2001 mean of ​$47.79.

Then, the claim that will be expressed in the alternative hypothesis is that the monthly bill is lower than $47.79.

The null hypothesis will state that the monthly bill does not differ significantly from $47.79.

Then, the null and alternative hypothesis are:

[tex]H_0: \mu=47.79\\\\H_a:\mu< 47.79[/tex]

As we only want to test if its lower, we are interested only in the left tail of the distribution. We want to know if the test statistic is below the critical value to conclude if we have evidence for our claim. This is then a left tailed test.

Answer:

Percentage of students who tried both questions = [tex]8\%[/tex]

Percentage of students who tried at least one question = [tex]96\%[/tex]

Step-by-step explanation:

Given: 25 students take a midterm psychology exam, 15 answered the first of two bonus questions, 11 answered the second bonus question, and 1 didn't bother with either one.

To find: percentage of students who tried both questions and percentage of students who tried at least one question

Solution:

Let A denotes students who answered the first of two bonus questions and B denotes students who answered the second bonus question.

Let U denotes the universal set denoting students who take a midterm psychology exam.

[tex]n(A)=15\,,\,n(B)=11\,,\,n(U)=25[/tex]

[tex]n\left ( A'\cap B' \right )=1[/tex]

[tex]n\left ( A'\cap B' \right )=n\left ( A\cup B \right )'\\=n(U)-n\left ( A\cup B \right )\\\Rightarrow 1=25-n\left ( A\cup B \right )\\n\left ( A\cup B \right )=25-1=24[/tex]

[tex]n\left ( A\cup B \right )=n(A)+n(B)-n\left ( A\cap B \right )\\24=15+11-n\left ( A\cap B \right )\\n\left ( A\cap B \right )=15+11-24=2[/tex]

Percentage of students who tried both questions = [tex]\frac{2}{25}\times 100=8\%[/tex]

Percentage of students who tried at least one question = [tex]\frac{24}{25}\times 100=96\%[/tex]