Answer:
Explanation:
Conversion
1 foot=12 inches
1) 0.65ft=7.80 in
2) 8ft 2.5 inches = 98.5
3) 1inch is equal to 0.0833 decimal of a foot, so first convert to inches then to decimal foot
6ft 5 inches =65inches = 54.145
4)1 cm= 0.394inch
49.2cm = 19.3848inch
n a single-phase AC circuit, for a general load composed of RLC elements under sinusoidal-steady-state excitation, the average reactive power is given by
Answer:
The average reactive power is [tex]I_{rms}V_{rms} cos \phi[/tex]
Explanation:
For a single-phase AC circuit;
the peak current in the circuit is given as [tex]I_o[/tex]
the root-mean-square current is given by;
[tex]I_{rms} = \frac{I_o}{\sqrt{2}}[/tex]
the peak voltage in the circuit is given as [tex]V_o[/tex]
the root-mean-square voltage is given by;
[tex]V_{rms} = \frac{V_o}{\sqrt{2} }[/tex]
The average reactive power is given by
[tex]P_{avg} = I_{rms}V_{rms} cos \phi[/tex]
where;
[tex]cos \phi \ is \ the \ power \ factor[/tex]
Therefore, the average reactive power is [tex]I_{rms}V_{rms} cos \phi[/tex]
Select the correct statement about polar bonds and dipole moments.
a. A linear diatomic molecule AX has a dipole moment equal to the sum of the electronegativities of A -- X.
b. The dipole moment for a polyatomic molecule equals the vector sum of the individual bond moments.
c. The electrons in a polar covalent bond spend more time near the least electronegative atom in the bond.
d. A polyatomic molecule which contains one or more polar bonds always has a molecular dipole moment.
e. A dipole moment quantifies the separation of charge in a molecule using the number of lone pairs on each atom.
Answer:
e
Explanation:
The correct statement about polar bonds and dipole moments is A. A linear diatomic molecule AX has a dipole moment equal to the sum of the electronegativities of A -- X.
It should be noted that a dipole moment refers to the product of partial charge and the distance that separates the charge in the polar covalent bond.
In a dipole moment, the linear diatomic molecule AX has a dipole moment that is equal to the sum of the electronegativities of A -- X. The electrons in a polar covalent bond do not spend more time near the least electronegative atom in the bond.
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Determine the maximum slope and maximum deflection of the simply supported beam subjected the moment M0. Assu
Answer:
hello your question is incomplete attached below is the complete question
Explanation:
attached below is the detailed solution
Taking into account that EI is constant and the Beam is made out of a single uniform material which is prismatic
4.5. In a balanced 480 V three-phase system, the line current is measured to be 15 A. Find ZY and Z .
Answer:
We are to find bar Zy and bar X in this question
We have Va = 480v
IL = 15L-25⁰
When we connect Y we have
Iph = IL = 15L-25⁰
Vph = VL/√3
= 489/√3
= 277.128V
Bar Zy = Vph/Iph = 277.128/15L-25⁰
= 18.475L25⁰
For bar Z
15L-25⁰/√3
= 8.6L-25⁰
VL = 480v
480/8.6L-25⁰
= 55.14L25⁰
Please check attachment.
give 5 Examples of arithmetic sequence
Seth wants to build a wall of bricks. Which equipment will help him in the process?
OA masonry pump
OB. hacksaw
OC. mortar mixer
OD. pressurized cleaning equipment
what is the dimensions of beta
Answer:
byee byee bbbbbbbbbbbb
A steel pipe with an inside diameter of 10 in. will be used to transmit steam under a pressure of 800 psi. If the hoop stress in the pipe must be limited to 10 ksi because of a longitudinal weld in the pipe, determine the minimum satisfactory thickness for the pipe.
Answer:
The minimum satisfactory thickness for the pipe is 0.4. in
Explanation:
The computation of the minimum satisfactory thickness for the pipe is shown below:
As we know that
[tex]\sigma _h = \frac{pr}{t}[/tex]
Now for determining the thickness we have to rearrange it
[tex]t = \frac{pr}{\sigma_h}[/tex]
where,
p = pressure inside the pips
r = pipe radius
[tex]\sigma _h[/tex] = stress of the hoop
Now put the given values to the above equation
So,
[tex]t = \frac{800 \times 5}{10 \times (10)^3}[/tex]
= 0.4 in
Hence, the minimum satisfactory thickness for the pipe is 0.4. in
The same is to be considered
. Convert 350 lb* ft In Joules?
Answer:
474.536 Joules
Explanation:
Use a converter machine.
1lb = 1.355818 j
350 = 1.355818 j *350
= 474.536
A simple ideal Rankine cycle with water as the working fluid operates between the pressure limits of 3 MPa in the boiler and 30 kPa in the condenser. If the quality at the exit of the turbine cannot be less than 82 percent, what is the maximum thermal efficiency this cycle can have
The proportioning of a concrete mixture has resulted in the following SSD weights.
Material WSSD (Ib/yd^3) Other Info
Cement 739 Gs=3.15
Rock (coarse) 1550 Gs(SSD)= 2.7, % tot= 6%, % abs= 0.8%
Sand (fine) ? SSD =2.6, % tot=1.4%, % abs= 1.4%
Water 325
Air ___ % Air =7%
1. What is the volume of sand required?
a. 6.45 ft^3
b. 6.94 ft^3
c. 8.83 ft^3
d. 9.66 ft^3
2. What is the batch water weight?
a. 230 lbs
b. 245 lbs
c. 325 lbs
d. 405 lbs
Answer:
1) 8.84 ft ^3 ( c )
2) 325 Ibs
Explanation:
1) Determine the volume of sand required
Volume of sand = [ 1 - volume of cement - volume rock - volume air - volume water ] * Gs of sand -------- ( 1 )
Note : volume = [ mass / (density of water * Gs) ]
Volume of cement = [ 739 / ( 1685.55 * 3.15 ) ] = 0.139 yd^3
Volume of rock = [ 1550 / ( 1685.55 * 2.7 ) ] = 0.340 yd^3
volume of air = 0.07 yd^3
volume of water = 0.325
back to equation ( 1 )
[ 1 - 0.139 - 0.340 - 0.07 - 0.325 ] * 2.6 * 27 = 8.84 ft ^3
2) Determine Batch water weight
= 325 Ib/yd^3 * 1 yd^3
= 325 Ibs
1. Make sure the inputs are set to df = 20 and p-value of 0.05 (critical value for t will adjust automatically). Now reduce degrees of freedom to 15, then to 10, and then to 5. What happens to the critical value for t?
Answer:
It moves inwards towards the center of the distribution
Explanation:
It is given :
Number of degrees of freedom , df = 19
α = 0.05
α/2 = 0.05/2 = 0.025
Therefore, [tex]$t_{\alpha/2, df} = t_{0.025,19} = \pm 2.093$[/tex]
So critical value of t = ± 2.093
Therefore, the curve moves towards the center of the distribution.
A triangular distributed load of max intensity w = 420 N/m acts on beam A B . The beam is supported by a pin at A and member C D , which is connected by pins at C and D respectively. Determine the reaction forces at A and C . Enter your answers in Cartesian components. Assume the masses of both beam A B and member C D are negligible.
Answer:
hello your question is incomplete attached below is the missing diagram
a = 5.20 m
b = 7.80 m
c = 4.16 m
answer :
Reaction force at A :
= Fax i + Fay j
= -14836.5 i - 9139.2 j N
Reaction force at B
= Fcx i + Fcy j
= - 14836.5 i - 11869.2 j N
Explanation:
attached below is the detailed solution
Reaction force at A :
= Fax i + Fay j
= -14836.5 i - 9139.2 j N
Reaction force at B
= Fcx i + Fcy j
= - 14836.5 i - 11869.2 j N
Describe the different methods that mine-owners used to remove water from their mines in the 18th century. Explain why the mine-owners were always looking for new methods to remove this water.
2. Assume that the graphite epoxy reinforced plastic with longitudinal fibers 25% graphite fibers. The elastic modulus of the fibers is 320 GPa and that of the epoxy matrix is 110 GPa. Calculate the elastic modulus of the composite and the fraction of the load supported by the fibers.
Answer:Elastic modulus of the composite =162.5GPa; Fraction of load supported by fibres=0.4923
Explanation:
Elastic modulus of the composite s given by
Ec= XEf + (1-X)Em
where
Ef=Elastic modulus of the fibre = 320GPa
X=Cross sectonal area of fire= 25%= 0.25
Em= Epoxy matrix= 110GPa
Ec= XEf + (1-X)Em
= 0.25(320)+ (1-0.25) 110
=80+0.75x 110
=80+82.5
Elastic modulus of the composite =162.5GPa
b) Fraction of load supported by fibres is given as
Pf/Pm= Ef/Em/(Ef/Efm+ Vm/Vf)
=320/110 / ( 320/110 + 0.75/0.25)
2.9090 / (2.9090+3)
2.9090/5.9090
=0.49229≈0.4923
Fraction of load supported by fibres=0.4923
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Bridge collapses have hit the news recently with more frequency. Do some research online and state two possible reasons for these collapses. How might those employed in the Health, Safety, & Environmental Management pathway help prevent these collapses and keep us safe?
Answer:
The main reason for bridges collapses is: earthquakes (natural disasters) and construction incidents. Whenever a natural disaster occur, it makes the bridge collapse. An example is hurricanes. Hurricanes come with a great wind and that might lead to the bridge collapsing. Construction incidents means the bridge falls during construction. Those who are employed in health, safety and environmental management need to make sure that during the construction, they have examined the material and made sure it is strong. Working with economists, they should seek better understanding of the methods for minimizing the costs during the life of the bridge. In case for natural disasters, like flooding, they should make the bridge in a lever where the water won't reach the bridge. And they should have a limit for weight in the bridges because that is another reason it collapses, because the bridge does not support extra weight.
Explanation:
hope this helps
The specific gravity of gold is 19.3. Write a MATLAB function that will determine the length of one side of a cube of solid gold, in units of inches, provided the mass of the cube in kilograms. The output should display a sentence like the one shown below, with the length formatted to 2 decimal places. If the user types a negative number or zero for the mass of the cube, your program should display an error message and terminate.
Sample Input / Output (multiple scenarios):
Enter the mass of the cube [kilograms]: -3
Error: Mass must be greater than zero grams.
Enter the mass of the cube [kilograms]: 0.4
The length of one side of the cube is 1.08 inches.
Answer:
The code is written line wise with number. The code is explained by comments, which are written after % sign in bold. Note: Comments are not the part of code.
Explanation:
1. mass = input('Enter the mass of cube [kilograms]:'); %First we take mass input and save in variable m
2. if mass <= 0 %Condition for value less than or equal to 0
3. disp('Mass must be greater than zero grams');
4. end
5. if mass > 0
6. density = 19.3*1000; % Calculating Density of gold
7. Volume = mass/density; %Calculating Volume
8. Length = Volume^(1/3); %Calculating Length of edge
9. Length = Length*(39.37); %Conversion to inches
10. fprintf('The length of one side of cube is ');
11. fprintf('%.2f',Length);
12. fprintf(' inches');
13. end
Water flows steadily through a 3.28-in-diameter pipe and discharges through a 1.64-in-diameter nozzle to atmospheric pressure. The flow rate is 26.5 gpm. (a) Calculate the minimum static pressure required in the pipe to produce this flow rate. (b) Evaluate the axial force of the nozzle assembly on the pipe flange.
Answer:
A) 61.628 Ib/ft^2
B) 3.271 Ibf
Explanation:
diameter of pipe = 3.28 inches
diameter of nozzle = 1.64 inches
flow rate = 26.5 gpm =
convert the flow rate to ft^3/s
= 26.5 gpm * 0.133681 ft^3/gallons * 1 min/ 60 seconds
= 0.059 ft^3/s
next we calculate the velocity in the pipe
Q = [tex]\frac{\pi }{4} d^{2} _{1} V1[/tex]
Q = 0.059
d1 = (3.28 / 12 )
hence V1 = ( 0.059 ) / (0.0747 * 0.7854 ) = 1 .01 ft/s
velocity in the Nozzle
Q = [tex]\frac{\pi }{4} d^{2} _{2} V2[/tex]
Q = 0.059
d2 = ( 1.64 /12 )
hence V2 = ( 0.059 ) / ( 0.7854 * 0.0187 ) = 4.02 ft/s
A) To determine the Minimum static pressure we apply the Bernoulli's equation
since the pipe and the Nozzle are at the same height the equation will be modified as
[tex]\frac{P1}{w} + \frac{V^2_{1} }{2g} = \frac{P2}{w} + \frac{v_{2} ^2}{2g}[/tex]
where w = 62.4 Ib/ft^3
V1 = 1.01
V2 = 4.02
P1 = ?
P2 = 0
g = 9.81
hence P1 ( static pressure ) = 62.4 * 0.772 = 61.628 Ib/ft^2
B) evaluate the axial force of the Nozzle assembly on the pipe flange
attached below is the detailed solution
Fx( axial force ) = -0.345 + 3.616 = 3.271 Ibf
Describing if the structure is low-level or high-level abstraction. Summarizing how each structure functions individually and part of the larger system. Describing the similarities between each side-by-side structure (i.e. how is a cell similar to a transistor
Answer:
[FIRST 2 SO FAR]
Explanation:
1. The cell and the transistor would be considered to be the lowest level of abstraction. This is because they are the smallest, basic building blocks that make up these structures.
The cell makes up the parts of the body and the transistors make up the computer. The cells take in nutrients from food, converts the nutrients into energy, and carry out specialized functions. Cells move around to convert chemical energy into mechanical energy, allowing the body to move. The transistors are like switches that turn on and off electric current (by controlling the movement of electrons, either stopping or starting the current). They store and move data from one place to another, allowing the computer or device to work.
These two structures are both the smallest part that makes up the main structure. They allow the larger structure that they are contained in to function by doing small tasks/activities in the structure.
2. The Tissue and Logic Gate are a lower-level abstraction because the are composed of smaller structures.
Tissues are groups of cells that perform one or more specific functions. Tissues (enforced by the cells) can control the movement of information that is spread through the surface of the body, protect and support organs, and allow entire body movement. Logic gates are the basic building blocks of digital system that can have more than one input and only one output. These input and output functions are determined by using logic, with the gates being named And, Or, and Not.
The two structures are similar because they allow the movement of something to flow through the bigger structure, allowing the structure to function. Logic Gates control the actions of the transistors by taking in multiple inputs, then uses logic to tell the transistor to turn on or off an electric current.
Use the price-demand equation to find the values of p which meet the given condition of elasticity.
x-f(p)= 246- 8p:
Determine the values of p for which demand has elastic and inelastic elasticity.
Answer:
The values of p for which demand has elastic and inelastic elasticity is 15.38
Explanation:
given; x = f(p) = 246 - 8p
Elasticity is given by E(p) = [ -p × f'(p) ] ÷ [ f(p) ]
E(p) = [ -p × (-8) ] ÷ [ 246 - 8p ]
E(p) = 8p ÷ (246 - 8p)
to determine the values of p for which demand has elastic and inelastic elasticity.
1) for demand has elastic elasticity, E(p) > 1
8p ÷ (246 - 8p) > 1
8p > 246 - 8p
16p > 246
p > 15.38
2) for demand has inelastic elasticity, E(p) < 1
8p ÷ (246 - 8p) < 1
8p < 246 - 8p
16p < 246
p < 15.38
p > 15.38 , and p < 15.38, this is a unit elasticity
So i have to make a project about how an alien would live on saturn and the features it needs to adapt on it. The planet i was given was saturn. Can somebody help?
Explanation:
It would be impossible to live on Saturn, because the planet is made of gas. Unlike earth Saturn doesn’t have a surface.
Saturns atmosphere is made up of hydrogen and helium which combined together is about 99.5%, with ammonia making up the remaining 0.5%.
For an alien to survive on Saturn or live there he would definitely require oxygen as this is not present on the planet.
_____________ processes are actions that create physical solutions to problems.
a
Production Processes
b
Medical Processes
c
Agricultural Processes
d
Communication Process
Answer:
yes answer d is correct
Communication Process are actions that create physical solutions to problems. The correct option is d.
What is Communication Process?Human existence and organisational survival both depend on effective communication. It is a process of generating and disseminating thoughts, facts, opinions, and sentiments from one place, individual, or group to another. The Management function of Directing depends on effective communication.
The sending party, message encoding, channel selection, message receipt by the recipient, and message decoding are all aspects of the communication process.
Feedback is when the recipient communicates something back to the original sender. These procedures are actions that result in tangible fixes for issues.
Thus, the correct option is d.
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A strain gauge, diaphragm pressure transducer (accuracy: <0.1% reading) is subjected to a pres- sure differential of 10 kPa. If the output is meas- ured using a voltmeter having a resolution of 10 mV and accuracy of better than 0.1% of the reading, estimate the uncertainty in pressure at the design stage. How does this change at 100 and 1,000 kPa
Answer:
the design stage uncertainty for pressure is (√[ 25 + 0.10⁻⁴ P² ]) / 10 kPa
the change in sensitivity is 0.01 mV/kPa
Explanation:
Given that;
Differential pressure in the transducer ΔP = 10 kPa
Accuracy in the reading of diaphragm pressure transducer, α < 0.1%.
Resolution of the voltmeter, Rv = 10 mV
Now we write the expression for the design stage uncertainty
Us = √[(Us)₁² + (Us)₂²] ......................equ 1
nex we write the expression for design stage uncertainty for the voltmeter having resolution 10 mV .
(Us)₁² = ± 1/2Rv
we substitute the values
(Us)₁² = ± 1/2(10 mV) = ±5 mV
we write the expression for design stage uncertainty with respect to strain gauge.
(Us)₂ = aKtΔP
Kt is the strain gauge constant, Rs is the resolution for the voltmeter when accuracy in strain gauge is less than 0.1% .
Substitute the values.
(Us)₂ = (0.1%) (P mV / kPa) 10 kpa
= 0.01P mV
Here, P is a constant.
Substitute the values in equation 1
Us = √[(±5 mV)² + (0.01P mV)²]
= √[ 25 + 0.10⁻⁴ P² ]
Write the expression for the design stage uncertainty for pressure
Up = Us / ΔP
Substitute the values.
Up = (√[ 25 + 0.10⁻⁴ P² ]) / 10 kPa
therefore the design stage uncertainty for pressure is (√[ 25 + 0.10⁻⁴ P² ]) / 10 kPa
Write the value of the design stage uncertainty for pressure, ΔP is 100 kPa .
(Up)₁ = (√[ 25 + 0.10⁻⁴ P² ]) / 100 kPa
Write the value of the design stage uncertainty for pressure ΔP is 1000 kPa
(Up)₂ = (√[ 25 + 0.10⁻⁴ P² ]) / 1000 kPa
Write the expression for the sensitivity of the pressure transducer.
s = Rv / 1000 kPa
Substitute the values
s = 10 mV / 1000 kPa
= 0.01 mV/kPa
therefore the change in sensitivity is 0.01 mV/kPa
Determine the electric power consumption of the system for pumping. Would you recommend the use of a single large pump or several smaller pumps of the same total pumping power scattered along the pipeline
Answer:
Hello your question is incomplete attached below is the complete question
answer: 4493.24 Kw
I would recommend the use of several smaller pumps of the same total pumping power scattered along the pipeline
Explanation:
Calculate the Electric power consumption of the system for pumping using the formula below
[tex]W_{electric} = \frac{Qp}{n}[/tex] --------- ( 1 )
P = ΔP = 2166.67kPa ( calculated using : [tex]\frac{p_{0} flv^2}{2d}[/tex] )
where: [tex]p_{0}[/tex] = 950.6 kg/m^3 , f = 0.0083, v = 5.305 m/s, d = 0.6 m, l = 12 km
n = efficiency of motor pump = 74% = 0.74
Q = 1.5 m^3/s
input the given values into equation ( 1 )
[tex]W_{electric}[/tex] = 4493.24 Kw
I would recommend the use of several smaller pumps of the same total pumping power scattered along the pipeline
Type the correct answer in the box. Spell all words correctly.
Convert calories to joules.
3 calories is ____ joules
Answer:
46
Explanation:
Answer:
12.55 Joules
Explanation:
For edmentum users :)
Some wastewater has a BOD5 of 150 mg/L at 20° C. The reaction rate k at that temperature has been determined to be 0.20/day. Find BOD5 (in mg/L) at 15° C.
Answer:
The value of [tex]\mathbf{BOD_5 \ at \ 15^0 \ C \ is \simeq 130.14 \ mg/L}[/tex]
Explanation:
From the given information:
To find the BOD5 (in mg/L) at 15° C; we need to know the ultimate carbonaceous BOD and the reaction rate coefficient at 15° C.
So, to start with the calculation of the ultimate carbonaceous BOD by using the formula:
[tex]BOD_t = L_o (1-e^{-k*t})[/tex]
where;
[tex]BOD _t[/tex] = Biochemical oxygen demand at t days
[tex]L_o[/tex] = the ultimate carbonaceous
∴
[tex]150= L_o (1-e^{-0.20*5})[/tex]
[tex]L_o =\dfrac{150}{ (1-e^{-0.20*5})}[/tex]
[tex]L_o =\dfrac{150}{ (1-0.3679)}[/tex]
[tex]L_o =237.30 \ mg/L[/tex]
Thus, the ultimate carbonaceous BOD = 237.30 mg/L
For the reaction rate coefficient; we use the formula:
[tex]k_{\tau} = k_{20} \times \theta^{\tau - 20}[/tex]
where;
[tex]k_{\tau}[/tex] = rate of the reaction constant at various temperature (T) = 15
[tex]k_{20}[/tex] = rate of the reaction constant at standard laboratory = 0.20
[tex]\theta[/tex] = constant = 1.047
∴
[tex]k_{15} =0.20 \times \theta^{15 - 20}[/tex]
[tex]k_{15} =0.20 \times 1.047^{-5}[/tex]
[tex]k_{15} =0.20 \times0.7948[/tex]
[tex]k_{15} = 0.1590 / day[/tex]
Thus, at 15° C, the reaction constant (k) = 0.1590 / day
Finally, the BOD5 (in mg/L) at 15° C can be calculated by using the formula:
[tex]BOD_t = L_o (1 - e^{-k*t})[/tex]
[tex]BOD_t = 237.30 \times (1 - e^{-0.1590*5})[/tex]
[tex]BOD_t = 237.30 \times (1 -0.45158)[/tex]
[tex]BOD_t = 237.30 \times (0.54842)[/tex]
[tex]\mathbf{BOD_5 \simeq 130.14 \ mg/L}[/tex]
A pequin walks 10 feet in six second how far does the pequin wals in 45 seconds
Answer:
7.5 feet
Explanation:
45 divided by 6 is 7.5
Answer:
7.5 feet
Explanation:
45 divided by 6 is 7.5
Which statement best explains why pneumatic cylinders need to be smaller than hydraulic cylinders?
The pneumatic system only needs enough room to have an onloff switch installed in order to operate correctly.
The energy in pneumatic power systems is easily transmitted to gases, which absorb the energy of the system and lower its efficiency
The control of the hydraulic system is much more precise and therefore requires a larger cylinder.
The fluid in a hydraulic system has more mass and therefore needs more storage space.
Answer:
The energy in pneumatic power systems is easily transmitted to gases, which absorb the energy of the system and lower its efficiency.
Explanation:
I did it on edge and got it right.
Answer:
The energy in pneumatic power systems is easily transmitted to gases, which absorb the energy of the system and lower its efficiency
Thanks for points!!! :D
You have designed a bridge beam with an I of 1000 in4 and estimate a maximum deflection of 4 inches. In order to reduce the maximum deflection to 3.1 inches, you must increase I to ________ in4
Answer:
1290.32 In⁴
Explanation:
∆ = wL⁴/384EI
∆ is directly proportional to 1/I
∆1/∆2 = i2/i1
We have
∆1 = 4 inches
∆2 = 3.1 inches
i1 = 1000
i2 is unknown
So when we insert these values into the formula we have:
4/3.1 = i2/1000
From here we cross multiply
4x1000 = 3.1(i2)
4000 = 3.1(i2)
Divide through by 3.1
= 4000/3.1 = i2
= 1290.32 in⁴
i2 = 1290.32 in⁴
So, In order to reduce the maximum deflection to 3.1 inches, you must increase I to 1290.32 in⁴
A site is underlain by a 10 meter layer of saturated gravel with unit weight = 20 kN/m3. Point A is located 5 meters below the ground surface. The horizontal effective stress at point A is 30 kPa. Determine the lateral stress ratio of the soil at point A.
Answer:
The lateral stress ratio of the soil at point A is 0.3
Explanation:
given that; Unit weight = 20 kNm⁻³ at point A 5m below the ground surface,
vertical stress ([tex]V_{stress}[/tex]) = 20 kNm⁻³ × 5m ⇒ 100 kNm⁻²
vertical stress ([tex]V_{stress}[/tex]) = 100kPa
note that; Horizontal Stress ([tex]H_{stress}[/tex]) is given by k([tex]V_{stress}[/tex])
where "k" is the lateral stress ratio
[tex]H_{stress}[/tex] = k([tex]V_{stress}[/tex])
k = [tex]H_{stress}[/tex] ÷ [tex]V_{stress}[/tex]
k = 30 kPa ÷ 100 kPa
k = 0.3
