Can someone help me please. I am struggling and I would be so happy if any of you helped me. Thank you for your help!

Answer:

2.5

Step-by-step explanation:

i had it

Answer:

D

Step-by-step explanation:

inverse just means opposite so if its shown dividing it first then adding, then the inverse is multiplying then subtracting

Answer:

The right solution is:

(a) 0.8849

(b) 12.28%

(c) 4.9935

(d) 28004

Step-by-step explanation:

Given:

Mean,

= 4.5

Standard deviation,

= 0.3

(a)

P(x > 4.14)

As we know,

⇒ [tex]z = \frac{4.14-4.5}{0.3}[/tex]

      [tex]=-1.20[/tex]

then,

⇒ [tex]P(z>-1.20) = P(z<1.20)[/tex]

                          [tex]=0.8849[/tex]

(b)

P(4.8 < x < 5.04)

= [tex]P(\frac{4.8-4.5}{0.3} < \frac{x-\mu}{\sigma} < \frac{5.04-4.5}{0.3} )[/tex]

= [tex]P(1<z<1.80)[/tex]

= [tex]P(z<1.80)-P(z<1)[/tex]

= [tex]0.9641 -0.8413[/tex]

= [tex]0.1228[/tex]

or,

= [tex]12.28[/tex] (%)

(c)

P(x > x) = 0.05

z value will be,

= 1.645

⇒ [tex]1.645 = \frac{x - 4.5}{0.3}[/tex]

         [tex]x = 4.9935[/tex]

(d)

P(x < 5.01)

⇒ [tex]z = \frac{x- \mu}{\sigma}[/tex]

      [tex]=\frac{5.01-4.5}{0.3}[/tex]

      [tex]=1.7[/tex]

P(z < 1.70) = 0.9554

⇒ [tex]n = \frac{27875}{0.9954}[/tex]

       [tex]=28004[/tex]

Answer:

search up the formula

Step-by-step explanation:

Answer:

5/6

Step-by-step explanation:

12/3 × 1/2 = 5/6

hope it helps

please mark Brainliest

Answer:

200

Step-by-step explanation:

Break down 25 = 5*5

Break down 8 = 2*2*2

They have no common factors

The least common multiple is

5*5*2*2*2 = 25*8 = 200

Answer:

200

Step-by-step explanation:

list the factors of 25: 5,5

factors of 8:2,2,2,

Answer:

2160

Step-by-step explanation:

I find that it is easier to split the sequence into smaller, more manageable sections. For numbers beyond 13, the simplest way is to split it up into place values.

Note: * is a multiplication symbol

5*1 = 5

5*8 = 40

5*27 = (5*20) + (5*7) = 100+35 = 135

5*64 = (5*60) + (5*4) = 300+20 = 320

5*125 = (5*100) + (5*20) + (5*5) = 500+100+25 = 625

5*216 = (5*200) + (5*10) + (5*6) = 1000+50+30=1080

Now you can add all of the totals up!

135+320+625+1080 = 2160

Answer:

c

Step-by-step explanation:

hope it helps!!!!!!!!!!!!!!

Answer:

Step-by-step explanation:

I am assuming i is the imaginary number:

Factor:

(3 + i)x - (4-2i) = 0.

In order for this to equal 0, x must be equal to 1-i.

I don't want to be reported to so take my word for it.

Also I plugged it into wolfram alpha so if it is wrong, blame the most powerful math equation solver available on the internet.

Using BTS he properties, find the unit's digit of the cube of each of the following numbers

Answer:

Step-by-step explanation:

4

We have a function,

[tex]f(x)=x^2-1[/tex]

and we are asked to find its inverse function.

An inverse function essentially gets you the original value that was dropped into a function.

For example,

If I put 5 into [tex]f(x)[/tex] I will get 24. Now If I take 24 and put it into the inverse function I have to get number 5 back.

The way to determine the inverse function swap the x and the [tex]f(x)[/tex], then solve for [tex]f(x)[/tex],

[tex]x=f(x)^2-1[/tex]

[tex]f(x)^2=x+1[/tex]

[tex]f(x)=\pm\sqrt{x+1}[/tex]

Of course the notation demands that the obtained function be called,

[tex]f^{-1}(x)=\pm\sqrt{x+1}[/tex]

Hope this helps :)

Answer:

Rs. 80

Step-by-step explanation:

Given that :

Purchase price = 70

Profit = 6

Discount = 5%

Let selling price = x

Selling price * (1 - discount) = (purchase price + profit)

x * (1 - 5%) = (70 + 6)

x * (1 - 0.05) = 76

x * 0.95 = 76

0.95x = 76

x = 76 / 0.95

x = 80

Hence, selling price = Rs. 80

Answer:

352

Step-by-step explanation:

I = PRT  where P is the principle, I is the interest rate, T is the time

I = 275 ( .08) ( 16)

I = 352

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Answer:

  $3277.23

Step-by-step explanation:

The future value of the CD with interest at rate r compounded semiannually for t years will be given by ...

  A = P(1 +r/2)^(2t)

where P is the principal value.

For the given rate and time, this is ...

  A = $2000(1 +0.05/2)^(2·10) = $2000(1.025^20) ≈ $3277.23

The value of the CD at maturity will be $3277.23.

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Answer:

  C. More than 1 solution

Step-by-step explanation:

Divide the second equation by 3.

  y -x = -3

Add x.

  y = x -3

This matches the first equation exactly, meaning that any solution to the first equation is also a solution to the second equation. There are an infinite number of possibilities. There is "More than 1 solution."

Answer:

hiuu ui9i io9

Step-by-step explanation:

iu9uj k

Answer:

The answer would be 28%!

Step-by-step explanation:

14/50 is 0.28. To change a decimal to a percentage, we multiply it by 100 which we can do by moving the decimal two numbers to the right.

Answer:

b) Y =5.73X +4.36

C)  =5.73225*(21)X +4.359

    124.73625

D) 163.728 = 5.73X +4.36  

     X = (163.728 - 4.36)/5.73

     X = 27.81291449

  Year would be 2027

Step-by-step explanation:

x1 y1  x2 y2

4 27.288  16 96.075

(Y2-Y1) (96.075)-(27.288)=   68.787  ΔY 68.787

(X2-X1) (16)-(4)=    12  ΔX 12

slope= 5 41/56    

B= 4 14/39    

Y =5.73X +4.36      

Markdown is the difference (at sale) between the price an item is placed at for retail sale, and the actual price the item is sold

The correct option is; B. GHC 50.00

The reason for choosing option B is as follows;

The known parameters

The percentage by which damaged items are marked down = 25% to 40%

The percentage markdown offered by the newspaper coupon = 10%

The original marked price of the item = GHC 100

Strategy:

Apply the damaged items and coupon markdown percentages to the original marked price of GHC100 sum the results to find the total markdown

Solution:

Markdown due to damage:

Given that the item is damaged, to have the lowest price, we apply the largest markdown of 40%;

40% is removed from the price to which the item marked down due to damage, as follows;

The markdown due to damage = 40/100 × GHC 100 = GHC 40

Markdown due to Coupon Holder:

The markdown the coupon holder is to get = 10% off the retail price

Given that the damage is not mentioned in the newspaper, we have;

∴ The markdown the coupon holder is to get = 10/100 × GHC 100 = GHC 10

Total markdown:

The total markdown is therefore equal to GHC 40 + GHC 10 = GHC 50

The Lowest Price of A Damaged Items marked GHC100:

The lowest price of the item = Original price - Maximum markdown

The lowest price of the item = GHC 100 - GHC 50 = GHC 50

Learn more about markdown and markup concepts here;

https://brainly.com/question/20705786

Answer:

2/23

6/23

5/23

Step-by-step explanation:

60 only want chilis

20 wants both

100 only want red lobster

50 want neither

The right solution to the given question is "[tex]\frac{2}{23}[/tex]", "[tex]\frac{6}{23}[/tex]" and "[tex]\frac{5}{23}[/tex]".

According to the question,

By putting the value of "b", we get

                [tex]a = 80-20[/tex]

                [tex]a = 60[/tex]

By putting the value of "b", we get

      [tex]20+c=120[/tex]

              [tex]c = 120-20[/tex]

              [tex]c = 100[/tex]

By putting the values of "a", "b", "c" and "d", we get    

       [tex]d = 50[/tex]

(a)

P(both Chili's and Red lobster),

= [tex]\frac{b}{a+b+c+d}[/tex]

= [tex]\frac{2}{23}[/tex]

(b)

P(only chili's),

= [tex]\frac{a}{a+b+c+d}[/tex]

= [tex]\frac{6}{23}[/tex]

(c)

P(neither),

= [tex]\frac{d}{a+b+c+d}[/tex]

= [tex]\frac{5}{23}[/tex]

Learn more about probability here:

https://brainly.com/question/24269622

Answer:

[tex]\displaystyle y' = \frac{\sqrt{y} + y}{4\sqrt{x}y \Big( y^\Big{\frac{3}{2}} + \sqrt{y} + 2y \Big) + \sqrt{x} + x}[/tex]

General Formulas and Concepts:

Calculus

Differentiation

Derivative Property [Multiplied Constant]:                                                           [tex]\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)[/tex]

Derivative Property [Addition/Subtraction]:                                                         [tex]\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)][/tex]

Basic Power Rule:

Derivative Rule [Quotient Rule]:                                                                           [tex]\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}[/tex]

Derivative Rule [Chain Rule]:                                                                                 [tex]\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)[/tex]

Implicit Differentiation

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle \frac{\sqrt{x} + 1}{\sqrt{y} + 1} = y^2[/tex]

Step 2: Differentiate

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

Book: College Calculus 10e

Answer:

Dependent event

[tex]P(Red = 2) = \frac{5}{588}[/tex]

Step-by-step explanation:

Given

[tex]Total = 49[/tex]

[tex]Red = 5[/tex]

Solving (a): Are the events dependent?

Yes, they are.

When the first red candy is selected and eaten, the total number of candies reduced to 48 and the number of red candies also reduced to 4.

So, the probability of selecting a 2nd candy is dependent on the first candy selected.

Solving (b): P(Red = 2)

This is calculated as:

[tex]P(Red = 2) = P(Red) * P(Red | Red)[/tex]

The first selection has the following probability:

[tex]P(Red) = \frac{Red}{Total}[/tex]

[tex]P(Red) = \frac{5}{49}[/tex]

The second selection has the following probability:

[tex]P(Red|Red) = \frac{Red - 1}{Total - 1}[/tex]

[tex]P(Red|Red) = \frac{5 - 1}{49 - 1}[/tex]

[tex]P(Red|Red) = \frac{4}{48}[/tex]

So, we have:

[tex]P(Red = 2) = P(Red) * P(Red | Red)[/tex]

[tex]P(Red = 2) = \frac{5}{49} * \frac{4}{48}[/tex]

Reduce fraction

[tex]P(Red = 2) = \frac{5}{49} * \frac{1}{12}[/tex]

Multiply

[tex]P(Red = 2) = \frac{5}{588}[/tex]

Answer:

b) two-sample z-test for proportions

Step-by-step explanation:

The most appropriate test to use for the research hypothesis stated above is the two sample z-test for proportions, this is because, the experiment has two independent groups (male and female) with the result of each group not affecting the result of the other. The experiment clearly stses that, it is to estimate the difference in proportion, hence, it is a test of proportions rather than mean. Also when performing, a two sample tests of proportion, the Z distribution is used.

Answer:

a) Everyone on the team talks until the entire team agrees on one decision.

Step-by-step explanation:

Option B consists of voting and not everyone would like the outcome. Option C is making an outsider the decision maker, which can't be helpful since he / she won't have as strong opinions as the team itself. Option D is just plain wrong as it defeats the purpose of team work and deciding as one team. So, I believe option A makes the most sense

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Answer:

  4a. ∠V≅∠Y

  4b. TU ≅ WX

  5. No; no applicable postulate

  6. see below

Step-by-step explanation:

a. When you use the ASA postulate, you are claiming you have shown two angles and the side between them to be congruent. Here, you're given side TV and angle T are congruent to their counterparts, sides WY and angle W. The angle at the other end of segment TV is angle V. Its counterpart is the other end of segment WY from angle W. In order to use ASA, we must show ...

  ∠V≅∠Y

__

b. When you use the SAS postulate, you are claiming you have shown two sides and the angle between them are congruent. The angle T is between sides TV and TU. The angle congruent to that, ∠W, is between sides WY and WX. Then the missing congruence that must be shown is ...

  TU ≅ WX

__

The marked congruences are for two sides and a non-included angle. There is no SSA postulate for proving congruence. (In fact, there are two different possible triangles that have the given dimensions. This can be seen in the fact that the given angle is opposite the shortest of the given sides.)

  "No, we cannot prove they are congruent because none of the five postulates or theorems can be used."

__

The first statement/reason is always the list of "given" statements.

1. ∠A≅∠D, AC≅DC . . . . given

2. . . . . vertical angles are congruent

3. . . . . ASA postulate

4. . . . . CPCTC

Answer:

C)

Step-by-step explanation:

Just see the length of the R line, A and B are almost the same large when you add them.

Answer:

Step-by-step explanation:

Given,

[tex] {25x}^{2} - \frac{1}{49} [/tex]

[tex] = {(5x)}^{2} - {( \frac{1}{7}) }^{2} [/tex]

Since,

[tex] {x}^{2} - {y}^{2} = (x + y)(x - y)[/tex]

Then,

[tex] = (5x + \frac{1}{7} )(5x - \frac{1}{7} )(ans)[/tex]