Can someone help me on any of the problems that are circled

Answer:

Step-by-step explanation:

Given:

Isolate b:

Find b:

[tex]\\ \sf\longmapsto t+\dfrac{1}{2}b=Y[/tex]

[tex]\\ \sf\longmapsto \dfrac{1}{2}b=Y-t[/tex]

[tex]\\ \sf\longmapsto \dfrac{b}{2}=Y-t[/tex]

[tex]\\ \sf\longmapsto b=2(Y-t)[/tex]

[tex]\\ \sf\longmapsto b=2Y-2t[/tex]

Answer:

0.6192

Step-by-step explanation:

Step-by-step explanation:

1/(seca-tana) - 1/cosa=1/cosa -1/(seca+tana)

There are many ways to solve this, let's take a look at a simple one

1/(seca-tana) + 1/(seca+tana) =1/cosa + 1/cosa

((seca-tana)+(seca+tana))/(sec^2a-tan^2a)=2/cosa

(seca-tana+seca+tana)/1=2*1/cosa

2seca=2seca

Answer:

1

Step-by-step explanation:

Answer:

1/ a

Step-by-step explanation:

go to desmos graphing calculator :) yea

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Answer:

m = 5 and c = -2

Step-by-step explanation:

[tex]let \: y = \sqrt{20} \times {10}^{ - 3} \times {10}^{5x} \\ be \: equation \: 1[/tex]

Now

[tex]y = \sqrt{5} ( \sqrt{20} \times {10}^{ - 3} \times {10}^{5x} ) \\ y = \sqrt{100} \times {10}^{ - 3} \times {10}^{5x} \\ y = 10 \times {10}^{ - 3} \times {10}^{5x} [/tex]

[tex]using \: rules \: of \: indices \: we \: get \\ y = {10}^{1 - 3 + 5x} \\ y = {10}^{ - 2 + 5x} \\ [/tex]

[tex]now \: take \: log \: of \: both \: sides \: and \: use \: laws \: of \: logarithm \\ we \: get \\ [/tex]

[tex] log(y) = log( {10}^{ - 2 + 5x} ) \\ log(y) = ( - 2 + 5x) log(10) \\ log(y) = - 2 + 5x \\ log(y) - 5x = - 2 \\ \\ comparing \: this \: to \: \\ log(y) - mx = c \\ \\ we \: get \: m \: = 5 \: and \: c = - 2[/tex]

Answer:

(D) 2 x 10²

Step-by-step explanation:

Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the 10. If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.

Answer:

2 × 10 ^2

Step-by-step explanation:

(d) option is correct

Answer:

4

Step-by-step explanation:

The degree is equal to the largest exponent on a variable. In this instance, it is 4.

Answer:

by observation we get to know

highest is 28

lowest is 4

hence difference = 28 - 4 = 24

brainliest plsss

Pls mark me brainliest

Answer:

30

Step-by-step explanation:

The total number of people is

5+6+4+7+5+3 = 30 people

Answer:

30

Step-by-step explanation:

pizza:5+7=12

Burger:6+5=11

Other:4+3=7

Total:12+11+7=30

Answer:

10t+2

Step-by-step explanation:

2-5t+8+5t-8

10t+2

Answer:

x = -11/2

Step-by-step explanation:

The ratios need to stay the same

5x        11

----- = -------

x-2       3

Using cross products

5x*3 = (x-2) 11

15x = 11x - 22

Subtract 11 from each side

15x-11x = -22

4x = -22

x = -22/4

x = -11/2

Answer:

5 whole number 1/2

Step-by-step explanation:

5x:(x-2)=11:3

(:)This simply means ''ratio''

5x/(x-2) = 11/3

(cross multiply)

11(x-2) = 3(5x)

11x-22 = 15x

collect like terms

15x - 11x = 22

4x = 22

x = 22/4, but it is best you put it as a Mixed number.

x = 5 whole number 2/4, which can be reduced to

x = 5 whole number 1/2

Answer:

$10.48

Step-by-step explanation:

To the nearest cent, your answer would be 10.48

sin O = 1/2 = p/h

p=1, h = 2.

by pythagoras tgeorem,

b =

[tex] \sqrt{3} [/tex]

tan0= p/b

[tex]1 \div \sqrt{3} [/tex]

9514 1404 393

Answer:

  no feasible solutions

Step-by-step explanation:

There are so many inequalities that determining the area covered by all 5 of them is problematic. Hence, we have reversed all of them in the attached graph, so any feasible solution region would remain white. Alas, there is no such region.

This system of inequalities has no feasible solution.

Answer:

[tex]c=-2[/tex]

Step-by-step explanation:

We are given the function:

[tex]f(x) = -2c + cx - x^2[/tex]

And that:

[tex]\displaystyle f^{-1} (5) = -1[/tex]

And we want to determine the value of c.

Recall that by definition of inverse functions:

[tex]\displaystyle \text{If } f(a) = b, \text{ then } f^{-1}(b) = a[/tex]

So, since f⁻¹(5) = -1, then f(-1) = 5.

Substitute:

[tex]f(-1) = 5 = -2c + c(-1) - (-1)^2[/tex]

Simplify:

[tex]5 = -2c - c - (1)[/tex]

Combine like terms:

[tex]6 = -3c[/tex]

And divide. Hence:

[tex]c = -2[/tex]

In conclusion, the value of c is -2.

Now

[tex]\\ \sf\longmapsto tan(\alpha+\beta)=\sqrt{3}[/tex]

[tex]\\ \sf\longmapsto \alpha+\beta=60\dots(1)[/tex]

And

[tex]\\ \sf\longmapsto tan(\alpha-\beta)=\dfrac{1}{\sqrt{3}}[/tex]

[tex]\\ \sf\longmapsto \alpha-\beta=30\dots(2)[/tex]

Adding both

[tex]\\ \sf\longmapsto 2\alpha=30+60=90[/tex]

[tex]\\ \sf\longmapsto sin2\alpha=sin90[/tex]

[tex]\\ \sf\longmapsto sin2\alpha=1[/tex]

Answer:

8 cm

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

So first let's write the information we got

Angle BAC = 90 degrees

Midpoint of BC = M

AC = 6cm

Am= 5cm

Also I found MC = BM, since it has a line that represents both lines are same

so to find it we have to Pythagoras theorem (A^2 + B^2 = C^2), well it is question we have the 'A value and C Value', also we need to find the value of B to find the length of MC and BM

A = 5

C = 6

so therefore to find B^2, we have to do the reverse, we don't add but subtract

C^2 - A^2 = B^2

___________________________________________________________

Moving on to Calculation

6^2 - 5^2 = B^2

36 - 25 = B^2

B^2 = 9

B = √9

B = 3

MC and BM Length =  3 cm

____________________________

Now, we know the length we again need to use Pythagoras theorem to solve this.

Since we know

A = 5

B = 3

So..

A^2 + B^2 = C^2

5^2 + 3^2 = C^2

25 - 9 = C^2

C^2 = 16

C = √16

C = 4

9514 1404 393

Answer:

Step-by-step explanation:

The GCF can be no larger than the difference between the numbers. That would be the first value you want to check to see if it is a factor of the numbers.

The difference is 10, which is a factor of both 40 and 50.

  GCF(40, 50) = 10

__

You can figure the GCF pairwise, as GCF(14, 56) = 14; then GCF(14, 63) = 7. Or, you can look at the smallest difference between any pair of numbers. Here, that is 63 -56 = 7, which is a factor of all three numbers.

  GCF(14, 56, 63) = 7

_____

Additional comment

Euclid's algorithm has you compute the remainder from division of the largest by the smallest. When that remainder is non-zero, it replaces the largest, and you repeat. When the remainder is zero, the smallest is the GCF.

For example, let's look at the GCF of 14 and 63.

  63/14 = 4 r 7

  14/7 = 2 r 0 . . . . . 7 is the divisor, so is the greatest common factor

Answer:

5/6 = v + 2/7

Step-by-step explanation:

5/6 = v + 2/7  

23/42 - v = 0

5/6 = 1/7 (7 v + 2)

Answer:

23/42 = v

Step-by-step explanation:

5/6=v+2/7

Multiply each side by the common denominator, 42

42( 5/6=v+2/7)

35 = 42v + 12

Subtract 12 from each side

35-12 = 42v

23 = 42 v

Divide each side by 42

23/42 = v

Answer:

She borrowed 4000 from bank.

Step-by-step explanation:

Let 'y' be the amount borrowed from bank. Then 10000-y is the amount borrowed from her mother-in-law.

Let x= interest amount gained by bank . Then 1080- x = interest gained by mother-in-law

I1= interest rate by bank= 9%

I2= interest rate by mother-in-law=12%

Time(T) = 1 year

Now, By Simple Interest formula:

x=PTR/100

Or, x=(y*1*9)/100

Or,100x=9y

or,9y-100x=0...........................Equation (i)

Again 1080-x= ((10000-y)*1*12)/100

Or, 108000-100x=120000-12y

Or, 12y-100x=12000.................Equation(ii)

Solving equation (i) and (ii), we get

y= 4000, which the amount borrowed from bank.

Answer:

6632.55

Step-by-step explanation:

P=A*(1+r/100)^x

P=6250*(1+2/100)^3

P=6632.55

Answer:

$6632.55

Step-by-step explanation:

→ Find the multiplier

( 100 + 2 ) ÷ 100 = 1.02

→ Multiply the investment by the multiplier to the power of years

6250 × ( 1.02 )³ = 6632.55

Answer:

Step-by-step explanation:

[tex]5*\dfrac{1}{4}=\dfrac{5}{4}\\[/tex]

Using addition,

Add (1/4) , five times

[tex]\dfrac{1}{4}+\dfrac{1}{4}+\dfrac{1}{4}+\dfrac{1}{4}+\dfrac{1}{4}=\dfrac{1+1+1+1+1}{4}\\\\=\dfrac{5}{4}[/tex]

Answer:

5/4

Step-by-step explanation:

Add 1/4 together 5 times:

1/4 + 1/4 + 1/4 + 1/4 + 1/4 = 5/4

Answer:

Parallel: AC and DB, BA and CD

Perpendicular: AC and CD, DB and CD, DB and BA, BA and AC

Neither: None

Step-by-step explanation:

Step 1: Find Slopes

Let's first find the slopes of each side of the rectangle, as that will helps us determine which sides are parallel, perpendicular, or neither.

Recall that the formula for finding the slope between two points is [tex]\frac{y_2 - y_1}{x_2-x_1}[/tex] where [tex](x_1, y_1)[/tex] and [tex](x_2,y_2)[/tex] are the coordinates of the two points. To avoid confusion, I will be taking the first point I list as [tex](x_1,y_1)[/tex] and the second point as [tex](x_2,y_2)[/tex].

Slope of [tex]BA[/tex]:

[tex]\frac{-7-(-3)}{-1-(-4)}\\=\frac{-7+3}{-1+4} \\= -\frac{4}{3}[/tex]

Slope of [tex]AC[/tex]:

[tex]\frac{-4-(-7)}{3-(-1)} \\=\frac{-4+7}{3+1} \\=\frac{3}{4}[/tex]

Slope of [tex]CD[/tex]:

[tex]\frac{0-(-4)}{0-3} \\=\frac{4}{-3} \\=-\frac{4}{3}[/tex]

Slope of [tex]DB[/tex]:

[tex]\frac{-3-0}{-4-0} \\=\frac{-3}{-4} \\=\frac{3}{4}[/tex]

Step 2: Determine which sides are parallel, perpendicular, or neither

Now that we found the slopes of the sides, we can determine which sides are parallel, perpendicular, or neither.

Recall that parallel lines have the same slope. [tex]\bf AC[/tex] and [tex]\bf DB[/tex], along with [tex]\bf BA[/tex]and [tex]\bf CD[/tex], have the same slope, so they are parallel. No other pair of sides has the same slope, so these are our only parallel pairs.

For two lines to be perpendicular, the product of their slopes must be [tex]-1[/tex]. [tex]\bf AC[/tex] and [tex]\bf CD[/tex], [tex]\bf DB[/tex] and [tex]\bf CD[/tex], [tex]\bf DB[/tex] and [tex]\bf BA[/tex], and [tex]\bf BA[/tex] and [tex]\bf AC[/tex] [tex]\bf[/tex]meet that criteria, so they are perpendicular. No other pair of sides meets the criteria, so these are our only perpendicular pairs. Hope this helps!

Answer:

p = 212

Step-by-step explanation:

p-83=129

Add 83 to each side

p-83+83=129+83

p =212

Answer:=212

Step-by-step explanation:

add 83 to both sides and then simplify

−83=129

p-83=129

p−83=129

−83+83=129+83

Answer:

Step-by-step explanation:

Answer:

B is the answer

Step-by-step explanation:

Answer:

24 and 48

Today, the son is 24 years old, and the father is 48 years old.  

Step-by-step explanation:

(x - 10) + (2x - 10) = 52

3x + 20 = 52

3x = 72

x = 24

The father is 2 times his son's age.

2x

= 2(24)

= 48

So, the son is 24 and the father is 48.

10 years ago, son was 14 and father was 38, if added, this adds up to 52, so we know our calculations are correct.

Answer:

So the son’s age is 24 and the father’s is 48. Ten years ago, they were 14 and 38, which adds up to 52.

Step-by-step explanation:

If the son’s age is x, the father’s age is 2x.

Ten years ago:

(x - 10) + (2x - 10) = 52

3x + 20 = 52

3x = 72

x = 24

2x = 48

Let one be x

ATQ

[tex]\\ \sf \longmapsto x+x-10=90[/tex]

[tex]\\ \sf \longmapsto 2x-10=90[/tex]

[tex]\\ \sf \longmapsto 2x=90+10[/tex]

[tex]\\ \sf \longmapsto 2x=100[/tex]

[tex]\\ \sf \longmapsto x=\dfrac{100}{2}[/tex]

[tex]\\ \sf \longmapsto x=50[/tex]

[tex]\\ \sf \longmapsto x-10=50-10=40[/tex]