How does the velocity of a falling object change with time? How would you describe the mathematical relationship between velocity and time of a falling object?
Answer:
Increases with time via the relationship:
velocity = acceleration * time = g * t
Explanation:
Since the object is falling under the constant acceleration due to gravity, its velocity is increasing with time. Such relationship can be described via the equation:
velocity = acceleration * time = g * t
Where the direction of the acceleration due to gravity (g) (pointing downwards) is in the same direction of that of the object's velocity.
A 2.00-m rod of negligible mass connects two very small objects at its ends. The mass of one object is 1.00 kg and the mass of the other is unknown. The center of mass of this system is on the rod a distance 1.60 m from the 1.00-kg mass object. What is the mass of the other object?A) 0.250kg B) 4.00kg C) 4.11kg D) 0.800kg E) 3.22kg
Answer:
4kgExplanation:
Step one:
given
length of rod=2m
mass of object 1 m1=1kg
let the unknown mass be x
center of mass c.m= 1.6m
hence 1kg is 1.6m from the c.m
and x is 0.4m from the c.m
Taking moment about the c.m
clockwise moment equals anticlockwise moments
1*1.6=x*0.4
1.6=0.4x
divide both sides by 0.4 we have
x=1.6/0.4
x=4kg
The mass of the other object is 4kg
A 25 kg of bananas is being pushed across the floor with a force of 37.5 N. What is the acceleration of the crate?
a. Some materials exhibit the property of superconductivity under certain conditions.
State what is meant by superconductivity and explain the required conditions for the
material to become superconducting.
Answer:
Conditions for Superconductivity
The material must be cooled below a characteristic temperature, known as its superconducting transition or critical temperature (Tc). ... The magnetic field to which the material is exposed must be below a characteristic value known as the critical magnetic field (Hc).
A 0.10 g flea, having leapt from the surface of a dog’s cranium, is observed to be moving at 1.25 m/s when it is 5.00 cm above the position from which it leapt. What was the elastic potential energy stored in its legs before its leap
Answer:
E.P.E = 1.27 x 10⁻⁴ J = 0.127 mJ
Explanation:
From Law of Conservation Energy, we know that:
Elastic Potential Energy Stored = Gain in Kinetic Energy + Gain in Gravitational Potential Energy
E.P.E = (1/2)mv² + mgh
where,
E.P.E = Elastic Potential Energy = ?
m = mass of flea = 0.1 g = 1 x 10⁻⁴ kg
v = speed = 1.25 m/s
g = 9.8 m/s²
h = height = 5 cm = 0.05 m
Therefore,
E.P.E = (1/2)(1 x 10⁻⁴ kg)(1.25 m/s)² + (1 x 10⁻⁴ kg)(9.8 m/s²)(0.05 m)
E.P.E = 0.78 x 10⁻⁴ J + 0.49 x 10⁻⁴ J
E.P.E = 1.27 x 10⁻⁴ J = 0.127 mJ
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Answer:
ALUMINUM ITS ALUMINUM BRO
Explanation:
Given a force of 56 N and an acceleration of 7 m/s2, what is the mass?
Answer:
8 kgExplanation:
The mass of an object can be found by using the formula
[tex]m = \frac{f}{a} \\ [/tex]
f is the force
a is the acceleration
From the question we have
[tex]m = \frac{56}{7} \\ [/tex]
We have the final answer as
8 kgHope this helps you
Answer:
8 kg*m/s (8 kg)
Explanation:
f= 56 N
a= 7 m/s^2
m= ?
m= 56 N / 7 m/s^2
= 8 kg*m/s
(8 kg)
Imagine that you are approaching a black hole in a spacecraft. What would you see? What would happen to you?
(please a short simple answer if possible)
Can any answer this plzz
Answer: u failed both sad welp ill try to help
Explanation:
A 15-cm-diameter CD has a mass of 25 g.A. What is the CD's moment of inertia for rotation about a perpendicular axis through its center?B. What is the CD's moment of inertia for rotation about a perpendicular axis through the edge of the disk?
Solution :
The moment of inertia for a circular disc about its centre is given by
[tex]$I=\frac{mr^2}{2}$[/tex]
Given , radius of CD, [tex]$r=\frac{d}{2}$[/tex]
[tex]$r=\frac{1.5 \times 10^{-2}}{2}$[/tex]
[tex]$=7.5 \times 10^{-2} \ m$[/tex]
A).
The moment of inertia of CD about its centre is
[tex]$I_{centre}=\frac{mr^2}{2}$[/tex]
[tex]$=\frac{25 \times 10^{-3}\times (7.5 \times 10^{-2})^2}{2}$[/tex]
[tex]$= 7\times 10^{-5} \ kg \ m^2$[/tex]
B).
The moment of inertia about parallel axis of CD with respect to its central axis is given by the parallel axis theorem,
[tex]$I_{p}=I_c + md^2$[/tex]
where, d is the distance between the parallel axis and central axis
Therefore, moment of inertia of CD about its edge is
[tex]$I_p=I_c +md^2$[/tex]
[tex]$=\frac{mr^2}{2}+mr^2$[/tex]
[tex]$=\frac{3}{2}mr^2$[/tex]
[tex]$=\frac{3(25 \times 10^{-3})\times (7.5 \times 10^{-2})^2}{2}$[/tex]
[tex]$=2.1 \times 10^{-4} \ kg \ m^2$[/tex]
(a) The CD's moment of inertia for rotation about a perpendicular axis through its center is [tex]7.031 \times 10^{-5} \ kgm^2[/tex]
(b) The CD's moment of inertia for rotation about a perpendicular axis through the edge of the disk is [tex]2.11 \times 10^{-4} \ kgm^2[/tex]
The given parameters;
diameter of the CD, d = 15 cmradius of the CD, r = 7.5 cmmass of the CD, m = 25 g = 0.025 kg(A) The CD's moment of inertia for rotation about a perpendicular axis through its center is calculated as follows;
[tex]I_c = \frac{1}{2} mr^2\\\\I_c = \frac{1}{2} \times 0.025 \times (0.075)^2\\\\I_c = 7.03 1 \times 10^{-5} \ kgm^2[/tex]
(B) The CD's moment of inertia for rotation about a perpendicular axis through the edge of the disk is calculated as;
[tex]I_p = I_c + mr^2\\\\I_p = (7.031 \times 10^{-5}) \ + \ 0.025 \times (0.075)^2\\\\I_p = 2.11 \times 10^{-4} \ kgm^2[/tex]
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Which best describes most covalent compounds? resilient brittle cold warm
Answer:
B) brittle
Explanation:
This describes most covalent compounds.
Answer:
B.)
Explanation:
The atoms can be of the same element or different elements. In each molecule, the bonds between the atoms are strong but the bonds between molecules are usually weak. This makes many solid materials with covalent bonds brittle.
A wave has a frequency of 15,500 Hz and a wavelength of 0.20 m. What is the
speed of the wave? Use the equation v=fx2.
A. 0.0000013 m/s
B. 3100 m/s
O C. 78,000 m/s
D. 0.00032 m/s
Answer:
it's B for a pe x
Explanation:
An object is thrown with a horizontal velocity of 49mt/sec and a vertical velocity of 18.8 mt/sec. How long will the object take to return to earth. Please help asap
Answer:
The object takes 3.84 seconds to return to earth.
Explanation:
Projectile Motion
It's when an object projected above the ground at a certain velocity, moves along a curved path under the action of gravity.
The initial velocity has two components, given by:
[tex]v_x=vo_x[/tex]
[tex]v_y=vo_y-gt[/tex]
Where vox is the initial component of the velocity in the horizontal direction, voy is the initial component of the velocity in the vertical direction, and t is the time.
The object reaches a maximum height and then it returns to the ground. The time it takes to reach the maximum height can be calculated when the vertical component of the velocity is zero:
[tex]vo_y-gt=0[/tex]
[tex]\displaystyle t_m=\frac{vo_y}{g}[/tex]
The initial vertical component of the velocity is 18.8 m/s, thus:
[tex]\displaystyle t_m=\frac{18.8}{9.8}=1.92~s[/tex]
The total time is double that time:
[tex]t_t=2*1.92~s=3.84~s[/tex]
The object takes 3.84 seconds to return to earth.
Why are scientists choosing to colonize Mars rather than another planet?
Scientists are choosing to colonize Mars rather than another planet out of curiosity, the potential for humans to provide more in-depth observational research than uncrewed rovers, economic interest in its resources, and the possibility that the settlement of other planets could decrease the likelihood of human extinction.
What is colonization of mars?Colonization requires the establishment of permanent habitats that have the potential for self-expansion and self-sustenance.
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What is the relationship between the focal length of a cylindrical mirror and its radius of curvature?
Answer:
Explanation:
Focal length (f) can be defined as the distance from the focal point to the centre of the surface of the mirror.
While radius of curvature (r) is the radius of the sphere of which the mirror forms a part.
Hence the relationship between the two is that the focal length is half of the length of the radius of curvature.
Mathematically,
F = r/2
A roller coaster car is traveling 1 m/s at the top of the track. At the bottom of the track, 5 seconds later, it is traveling 36 m/s. What is the average acceleration?
Answer:
Explanation:
F
Starting at (0,0) an object travels 36 meters north and then it covers 20 meters east. What is
the magnitude and direction of its displacement? (
Answer:
Explanation:
Using the pythagoras theorem, the displacement is expressed as;
d² = x²+y²
y = 36m (north)
x = 20m east
Substitute;
d² = 36²+20²
d² = 1296+400
d² = 1696
d = √1696
d = 41.18m
For the direction;
theta = tan^-1(y/x)
theta = tan^-1(36/20)
theta = tan^-1(1.8)
theta = 60.95°
Hence the magnitude is 41.18m and the direction is 60.95°
A car travels with a constant acceleration of 2.4 m/s2. Find the mass of the car if an 1850 N net force is required to produce this acceleration.
Answer:
770.83 kgExplanation:
The mass of the car can be found by using the formula
[tex]m = \frac{f}{a} \\ [/tex]
f is the force
a is the acceleration
From the question we have
[tex]m = \frac{1850}{2.4} \\ = 770.83333...[/tex]
We have the final answer as
770.83 kgHope this helps you
A motor requires 400 joules of energy to lift a 5.0 kg mass 2.0 meters. Calculate the efficiency of this motor.
Answer:
25%
Explanation:
use F=mg
then use the answer you get from that and plug it into W=Fxh
take that answer and divide it by 400 J and multiply by 100
round to sig figs
Consider a cylindrical pipe with both ends open and fundamental resonance frequency 150 Hz. If this particular pipe has a length of L, what the wavelengths of three lowest modes produced by this pipe? Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a. L,2L, 3L b. 2L, L, 2L/3 с. 2L/3, L, 2L d. L, L/2, L/3 e. 4L, 24, 4L/3 f. 4L, 4L/3, 4L/5 g. Neither of above.
Answer:
answers, the correct one is b
Explanation:
For this problem we use the fact that since the ends are open at these points we have a maximum,
fundamental L =λ/2 λ = 2L
second harmonic L = λ λ = 2L / 2
third harmonic L = 3 λ/2 λ = 2L / 3
n harmonic lam = 2L / n
with n an integer
therefore the length of the first three harmonics are: 2L, L, 2L / 3
when examining the different answers, the correct one is b
What is the force acting an object that is accelerating at 3.6 m/s/s and has a mass of 15 kg?
Answer:
54 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 15 × 3.6
We have the final answer as
54 NHope this helps you