Find dy /dx of x² - 2x + 5 - 6x

Answer:

x2−3x+2=x2−2x−x+2

x(x−2)−1(x−2)=(x−2)(x−1)

Now

x2−4x+3=x2−3x−x+3

x(x−3)−1(x−3)=(x−3)(x−1)

Thus, the only common factor is (x-1)

Option A

hiiiii

Answer:

Step-by-step explanation:

x2−3x+2=x2−2x−x+2

x(x−2)−1(x−2)=(x−2)(x−1)

Now

x2−4x+3=x2−3x−x+3

x(x−3)−1(x−3)=(x−3)(x−1)

Thus, the only common factor is (x-1)

Option A

hope it helps

Answer:

$17000

Step-by-step explanation:

Given

[tex]Total = 18275[/tex]

[tex]Tax = 7.5\%[/tex]

Required

The original price

This is calculated using:

[tex]Price(1 + Tax) = Total[/tex]

Make Price the subject

[tex]Price = \frac{Total}{(1 + Tax)}[/tex]

So, we have:

[tex]Price = \frac{18275}{(1 + 7.5\%)}[/tex]

[tex]Price = \frac{18275}{1.075}[/tex]

[tex]Price = 17000[/tex]

Answer:

I think its C.

Step-by-step explanation:

this that I brain farted oooo i got it

Answer:

x = 5

<AED = <AEC = 37

Step-by-step explanation:

<AEF = <AEC (Vertical angles)

6x+7=8x-3

or, 8x-6x=7+3

or, 2x=10

or, x=5

6x+7 = 37

Answered by GAUTHMATH

Answer:

x=5

AED =37

Step-by-step explanation:

The angles are vertical angles and vertical angles are equal

6x+7 = 8x-3

Subtract 6x from each side

6x+7-6x = 8x-6x-3

7 = 2x-3

Add 3 to each side

7+3 = 2x-3+3

10 =2x

Divide by 2

10/2 =2x/2

5 =x

We want the AED = 6x+7 = 6*5+7 = 30+7 = 37

Answer:

0.28386

Step-by-step explanation:

Given that :

Mean, μ = 65 miles

Standard deviation, σ = 7 miles

Probability that car travels more than 69 miles per gallon :

Recall,

Z = (x - μ) / σ ; x = 69

Z = (69 - 65) / 7 = 0.5714

The probability :

P(Z > z) = P(Z > 0.5714) = 1 - P(Z < 0.5714)

P(Z > 0.5714) = 1 - P(Z < 0.5714) = 1 - 0.71614 = 0.28386

P(Z > 0.5714) = 0.28386

Answer:

a square has 4 sides therefore the formula for perimeter of a square would be 4a where a is the number of sides. in this case, we want to know the length of each side so we divide total length (28) by number of sides which is 4 and we get 7m

Answer:

the side lengths of a square are equal. Second, know that the sum of all 4 side lengths gives us the perimeter.

Answer:

Step-by-step explanation:

Eight flapjacks

2oz of butter

3oz of sugar

4 oz of rolled oats.

Each flapjack

Butter = 2/8 = 1/4 oz

Sugar = 3/8 oz

Rolled oats = 4/8 = 1/2 oz

How many flapjacks can I make if I have

14 oz of butter,

15 oz of sugar, and

16 oz of rolled oats?

Butter

= 14 oz ÷ 1/8 oz

= 14 × 8/1

= 112 flapjack

Sugar

= 15 oz ÷ 3/8 oz

= 15 × 8/3

= 120/3

= 40 flapjacks

Rolled oats

16 oz ÷ 1/2 oz

= 16 × 2/1

= 32 flapjack

Therefore,

Considering the quantity of rolled oats available, the number of flapjacks that could be made is 32

the students took math and physics = 55

Answer:

-4

they wanted you to compute using x as 3

-2*3 + 2 = -4

Step-by-step explanation:

Answer:

x = - 2

Step-by-step explanation:

Given

[tex]\frac{x}{7}[/tex] = [tex]\frac{6}{-21}[/tex] ( cross- multiply )

- 21x = 42 ( divide both sides by - 21 )

x = - 2

Answer: B

Step-by-step explanation:

We are given that a 45-45-90 triangle has a hypotenuse of [tex]7\sqrt{2}[/tex].

In a 45-45-90 triangle, the legs are congruent. Therefore we can use the Pythagorean Theorem to solve.

[tex]a^2+a^2=(7\sqrt{2})^{2}[/tex]         [combine like terms]

[tex]2a^2=(7\sqrt{2})^2[/tex]               [square root both sides]

[tex]a\sqrt{2} =7\sqrt{2}[/tex]                 [divide both sides by root 2]

[tex]a=7[/tex]

Now, we know that a leg is length 7, which is B.                

Answer:

A

Step-by-step explanation:

Equate f(x) to 8 , that is

[tex]2^{x}[/tex] = 8 = 2³

Since bases on both sides are equal, both 2, then equate exponents

x = 3

The value of the x when the exponential function shown in the graph f(x) = 2ˣ is 8 is when x = 3, which is option A.

Here, given the graph of the function,

f(x) = 2ˣ

We have to find the value of x when f(x) = 8.

In order to find the value of x, when f(x) = 8, we have to write as,

f(x) = 8

2ˣ = 8

Now write 8 as an exponent with base 2.

2ˣ = 2³

Hence the value of x = 3

Learn more about Exponential Functions here :

https://brainly.com/question/9919887

#SPJ7

The cake has a cylindrical format, and the outside of the cake will be frosted, which means that the total surface area has to be found, and doing this, we find that she will need 298.5 square inches of frosting.

Surface area of a cylinder:  

The surface area of a cylinder of radius r and height h is given by:

[tex]S = 2\pi r^2 + 2\pi rh[/tex]

The cake is 10 inches in  diameter and 4.5 inches tall.

Radius is half the diameter, so [tex]r = \frac{10}{2} = 5[/tex].

The height is [tex]h = 4.5[/tex].

How many square inches of frosting  will she need?

This is the surface area, so:

[tex]S = 2\pi(5)^2 + 2\pi(5)(4.5) = 50\pi + 45\pi = 95\pi = 298.5[/tex]

She will need 298.5 square inches of frosting.

A similar problem can be found at https://brainly.com/question/24332238

Answer:

Step-by-step explanation:

First of all, we need the formula of a cylinder which is: 2[tex]\pi[/tex]rh + 2[tex]\pi[/tex][tex]r^{2}[/tex]

BUT also remember we are solving for one base since we do not count the bottom of the tray. That formula would look like this: 2[tex]\pi[/tex]rh + [tex]\pi[/tex][tex]r^{2}[/tex] since we are using 1 base instead of 2.

Now input the missing values into the formula and solve:

2[tex]\pi[/tex]rh + [tex]\pi[/tex][tex]r^{2}[/tex]

2[tex]\pi[/tex](5)(4.5) + [tex]\pi[/tex][tex](5^{2})[/tex]

45[tex]\pi[/tex] + 25[tex]\pi[/tex] = 70[tex]\pi[/tex]

Our Answer is 70[tex]\pi[/tex], or 219.91 [tex]in^{2}[/tex]

Answer: 56

Step-by-step explanation:

Let x be the number that is supposed to be subtracted from 61.

Given

61 - x = 5

Add both sides by x

61 - x + x = 5 + x

61 = 5 + x

Subtract 5 on both sides

61 - 5 = 5 + x - 5

x = 56

Hope this helps!! :)

Please let me know if you have any questions

Answer:

4^8

Step-by-step explanation:

If the second 4 is an exponent, as in (4^2)^4, then multiply the exponents.

(4^2)^4 = 4^(2 * 4) = 4^8

Answer:

p³ + q³ is -9

Step-by-step explanation:

[tex]{ \tt{ {(p + q)}^{3} = ( {p}^{2} + {q}^{2} + 2pq)(p + q) }} \\ { \tt{ {(p + q)}^{3} = ( {p}^{3} } + 3p {q}^{2} + 3 {p}^{2} q)} \\ { \tt{ {p}^{3} + {q}^{3} = {(p + q)}^{3} - 3pq(p + q)}} \\ { \tt{ {p}^{3} + {q}^{3} = {(3)}^{3} - 3(4)(3) }} \\ = - 9[/tex]

answer: I did it in the picture above I hope it's clear and helpful

Answer:

3

Step-by-step explanation:

Answer:

E. 7x

Step-by-step explanation:

3x plus 4x is equal to 7x because they both have the same terms and when added cannot the X of 3x and 4x cannot be joined together .

So they remain the same.

(e) 12x

(f) 12x²

(g) 12x²

(h) 1x

(I) 2x²

(J) 2x²

(K) -10x

(L) -20x

(M) 6x²

(N) 20x²

(O) -15x²

(P) -12x³

Your answers were wrong so i did all of them

Quick tip the power comes only when you multiply and not when you add

For example x + x = 2x

x × x = x²

All the answers

Must click thanks and mark brainliest

Answer:

8z - 1

Step-by-step explanation:

Given

3 + 4(2z - 1) ← multiply each term in the parenthesis by 4

= 3 + 8z - 4 ← collect like terms

= 8z - 1

Answer:

-1 + 8z

Step-by-step explanation:

First use the distributive property of multiplication (Just multiply 4 with all numbers in the parenthesis):

3 + 4(2z - 1)

3 + 8z - 4

Group like terms:

3 + 8z - 4

-1 + 8z

The answer is -1 + 8z

Hope this helped.

Answer:

Step-by-step explanation:

let's try a:

-4*4x-4*(-17) - expand the distributing terms

-16x-4*(-17) - simplify

-16x-(-68) - simplify again

-16x+68 - remove parentheses

-16x+68 does not equal to 16x-68

lets try b:

-28x+3... dont know what u mean

lets try c:

13-34 first

-21

lets try d:

0-17

-17

lets try e:

-2x+(8-8)

-2x

fortunally dont know what you mean.

Answer:

C

-1/5, -1/3,-7

Step-by-step explanation:

Answer:

the answer of the question is D

Answer: 80, 40

Step-by-step explanation: I just made an equation which went something along the lines Of 3.1x=248 , then you get 80, then 40.

Answer:

I don't understand the equation, please state it differently

Answer:

x=55

Step-by-step explanation:

Since 2 sides are the same length, their base angles much be the same.  The unmarked angle muse also be x

x+x+70 = 180  since the sum of the angles of a triangle must be 180

2x+70 = 180

2x = 180-70

2x = 110

Divide by 2

2x/2 =110/2

x=55

[tex]\huge\text{Hey there!}[/tex]

[tex]\large\textsf{x + x + 70 = 180}^\circ[/tex]

[tex]\underline{\large\text{COMBINE the LIKE TERMS}}[/tex]

[tex]\large\textsf{(x + x) + 70 = 180}^\circ[/tex]

[tex]\large\textsf{x + x = \bf 2x}[/tex]

[tex]\large\textsf{2x + 70 = 180}^\circ[/tex]

[tex]\underline{\large\text{SUBTRACT 70 to BOTH SIDES}}[/tex]

[tex]\large\textsf{2x + 70 - 70 = 180 - 70}[/tex]

[tex]\large\text{CANCEL out: 70 - 70 because that gives you 0}[/tex]

[tex]\large\text{KEEP: 180 - 70 because helps solve for the x-value}[/tex]

[tex]\large\textsf{180 - 70 = \bf 110}[/tex]

[tex]\underline{\underline{\large\text{New equation: 2x = 110}}}[/tex]

[tex]\underline{\large\text{DIVIDE 2 to BOTH SIDES}}[/tex]

[tex]\large{\mathsf{\dfrac{2x}{2}=\dfrac{110}{2}}[/tex]

[tex]\large\text{CANCEL out: } \mathsf{\dfrac{2}{2}} \large\text{ because that gives you 1}[/tex]

[tex]\large\text{KEEP: }\mathsf{\dfrac{110}{2}}\large\text{ because that gives you the answer of the x-value}[/tex]

[tex]\mathsf{x = \dfrac{110}{2}}\\\\\large\textsf{x = 110}\div\large\textsf{2}\\\\\large\textsf{x = \bf 55}^\circ[/tex]

[tex]\boxed{\boxed{\huge\text{Therefore, your answer is: \textsf{x = \bf 55}}^\circ}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:  3

Step-by-step explanation:                                                                                                          

[tex]\displaystyle\ \Large \boldsymbol{} We \ have \ a \ square\ function \\\\ f(x)=ax^2+bx+c \\\\And \ we \ know \\\\ \left[\left \[ {{f(0)=a\cdot 0+b\cdot0+c=0} \atop {f(-4)=a(-4)^2+-4b+c=-24}} \right.=>[/tex]                                                [tex]\displaystyle\ \Large \boldsymbol{} \left[ \ {{c=0} \atop {16a-4b=-24}} \right. =>\boxed{4a-b=-6} \\\\\\ and \ x_0 =-\frac{b}{2a}=1 =>\boxed{ b=-2a} \\\\\\ \left \{ {{4a-b=-6} \atop {b=-2a}} \right. =>4a+2a=-6=> a=-1 \ ; \ b=2 \\\\\\then \ b-a=2-(-1)=\boxed{3}[/tex]                                                                                    

Step-by-step explanation:

this is an example u can see and write it yourself...