constant of proportionality

Answer:Mark brainliest please

Answer is - 0.5

Step-by-step explanation:

The average rate of change is -0.5 which is the average rate of change from x 1 to x = 4 the answer is -0.5.

It is defined as the change in values of a dependent variable with respect to the independent variables.

As we know an average is a single number that represents the mean value for the given set of data or the closed value for each entry given in the set of data.

We have a graph of functions shown in the picture.

Estimate the average rate of change from x 1 to x = 4.

At x = 1,

y = 5

At x = 4

y = 3.5(approx)

The average rate of change = (3.5 - 5)/(4 - 1)

The average rate of change = -1.5/3

The average rate of change = -0.5

Thus, the average rate of change is -0.5 which is the average rate of change from x 1 to x = 4 the answer is -0.5.

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Answer:

Step-by-step explanation:

D

Answer:

∠J ≅ ∠V

Step-by-step explanation: I took the same test (:

Answer:

Step-by-step explanation:

210=2x3x5x7

280=2x2x2x5x7

360=2x2x2x3x3x5

Answer:

210= 2×3×5×7

280=2×2×2×5×7

360=2×2×2×3×3×5

common factors=2×2×2×3×5×7=840

uncommon factors=3

L.C.M=Common factors× uncommon factors

L.C.M=840×3

L.C.M=2520

Step-by-step explanation:

i hope it will be helpful

plzz mark as brainliest

Answer:

115

Step-by-step explanation:

Since the lines are parallel, PWX+WXR=180, WXR=65. So PWX=(180-65)=115

Answer:

a

Step-by-step explanation:

1/3 x 3/5 x 3/4 =7/12 so therefore that's what the answer isn't

la cuadra se llama 6minutos

Answer:

-26k, -26,000 ; (B)

ED2021

The residual for the house with 6 bedrooms is -26k.

Scatterplots are the plotting of set of points on a vertical axis and an horizontal axis. The shows the correlation extent between the numbers of the observed quantities.

Given is a scatterplot showing the selling price of houses with the number of bedrooms.

Equation of the line of best fit is given as,

y = 6.3x + 4.8

Residual = Actual value - Predicted value

From the scatterplot,

Actual selling price of house with 6 bedrooms = 40 × 10,000 = 400,000

Predicted selling price for 6 bedrooms = (6.3 × 6) + 4.8

                                                                 = 42.6 × 10,000

                                                                 = 426,000

Residual = 400,000 - 426,000

              = -26,000

Hence the residual is -26k.

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Answer:

hope u will understand...if u like this answer plz mark as brainlist

Answer:

[tex]\displaystyle p(x) + q(x) = \frac{2x}{(x+1)(x-1)}[/tex]

The result is indeed another rational expression.

Step-by-step explanation:

We are given the two functions:

[tex]\displaystyle p(x) = \frac{1}{x+1}\text{ and } q(x) = \frac{1}{x-1}[/tex]

And we want to perform the operation:

[tex]\displaystyle p(x) + q(x)[/tex]

And show that the result is another rational expression.

Add:

[tex]\displaystyle = \frac{1}{x+1} + \frac{1}{x-1}[/tex]

To combine the fractions, we will need a common denominator. So, we can multiply the first fraction by (x - 1) and the second by (x + 1):

[tex]\displaystyle = \frac{1}{x+1}\left(\frac{x-1}{x-1}\right) + \frac{1}{x-1}\left(\frac{x+1}{x+1}\right)[/tex]

Simplify:

[tex]=\displaystyle \frac{x-1}{(x+1)(x-1)} + \frac{x+1}{(x+1)(x-1)}[/tex]

Add:

[tex]\displaystyle = \frac{(x-1)+(x+1)}{(x+1)(x-1)}[/tex]

Simplify. Hence:

[tex]\displaystyle p(x) + q(x) = \frac{2x}{(x+1)(x-1)}[/tex]

The result is indeed another rational expression.

The probabilities we found in this exercise are.

In this exercise, probability concepts are used.

A probability is the number of desired outcomes divided by the number of total outcomes.

Total number of countries:

23 + 12 + 47 + 44 + 54 + 14 = 194

Let A = the event that a country is in Asia.

44 of the 194 countries are in Asia, thus:

[tex]P(A) = \frac{44}{194} = 0.2268[/tex]

0.2268 = 22.68% probability that a country is in Asia.

Let E = the event that a country is in Europe.

47 out of 194 countries are in Europe, thus:

[tex]P(E) = \frac{47}{194} = 0.2423[/tex]

0.2423 = 24.23% probability that a country is in Europe.

Let F = the event that a country is in Africa.

54 out of 194 countries are in Africa, thus:

[tex]P(F) = \frac{54}{194} = 0.2784[/tex]

0.2784 = 27.84% probability that a country is in Africa.

Let N = the event that a country is in North America.

23 out of 194 countries are in North America, thus:

[tex]P(N) = \frac{23}{194} = 0.1186[/tex]

0.1186 = 11.86% probability that a country is in North America.

Let O = the event that a country is in Oceania.

14 out of 194 countries are in Oceania, thus:

[tex]P(O) = \frac{14}{194} = 0.0722[/tex]

0.0722 = 7.22% probability that a country is in Oceania.

Let S = the event that a country is in South America.

12 out of 194 countries are in South America, thus:

[tex]P(S) = \frac{12}{194} = 0.0619[/tex]

0.0619 = 6.19% probability that a country is in South America.

18. What is the probability of drawing a red card in a standard deck of 52 cards?

In a standard deck of 52 cards, 26 are red, and thus:

[tex]p = \frac{26}{52} = 0.5[/tex]

0.5 = 50% probability of drawing a red card in a standard deck of 52 cards.

19. What is the probability of drawing a club in a standard deck of 52 cards?

In a standard deck of 52 cards, 13 are clubs, and thus:

[tex]p = \frac{13}{52} = 0.25[/tex]

0.25 = 25% probability of drawing a club in a standard deck of 52 cards.

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Answer:

The FitnessGram™ Pacer Test is a multistage aerobic capacity test that progressively gets more difficult as it continues. The 20 meter pacer test will begin in 30 seconds. Line up at the start. The running speed starts slowly, but gets faster each minute after you hear this signal. [beep] A single lap should be completed each time you hear this sound. [ding] Remember to run in a straight line, and run as long as possible. The second time you fail to complete a lap before the sound, your test is over.ep explanation:

Answer:

216 m²

Step-by-step explanation:

Surface area of a cube = 6a², when a = length of one side

so,

6a²

= 6×6²

= 6×36

= 216 m²

Answered by GAUTHMATH

Answer:

216 m²

Step-by-step explanation:

Answer:

5y + 6x = 40

Step-by-step explanation:

hope it is well understood?

Answer:

rhe

ehd

end

Step-by-step explanation:

jsu

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dje

ej

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With some rewriting, you get

[tex]\displaystyle \sum_{k=0}^\infty (-1)^k\frac{x^{k+2}}{4^k} = x^2 \sum_{k=0}^\infty \left(-\frac x4\right)^k[/tex]

Recall that for |x| < 1, you have

[tex]\displaystyle \frac1{1-x} = \sum_{k=0}^\infty x^k[/tex]

So as long as |-x/4| = |x/4| < 1, or |x| < 4, your series converges to

[tex]\displaystyle x^2 \sum_{k=0}^\infty \left(-\frac x4\right)^k = \frac{x^2}{1-\left(-\frac x4\right)} = \frac{x^2}{1+\frac x4} = \boxed{\frac{4x^2}{4+x}}[/tex]

Based on known expressions from Taylor series, the power series [tex]\sum \limits_{k = 0}^{\infty} (-1)^{k}\cdot \frac{x^{k+2}}{4^{k}}[/tex]Taylor series-derived formula of the rational function [tex]\frac{4\cdot x^{2}}{4+x}[/tex].

Taylor series are polynomic approximations used to estimate values both from trascendental and non-trascendental functions. It is commonly used in trigonometric, potential, logarithmic and even rational functions.

In this question we must use series properties and common Taylor series-derived formulas to infer the expression behind the given series. Now we proceed to find the expression:

[tex]\sum \limits_{k = 0}^{\infty} (-1)^{k}\cdot \frac{x^{k+2}}{4^{k}}[/tex]

[tex]x^{2}\cdot \sum\limits_{k = 0}^{\infty} \left(-\frac{x}{4} \right)^{k}[/tex]

[tex]x^{2}\cdot \left(\frac{1}{1+\frac{x}{4} } \right)[/tex]

[tex]\frac{4\cdot x^{2}}{4+x}[/tex]

Based on power and series properties and most common Taylor series- derived formulas, the power series [tex]\sum \limits_{k = 0}^{\infty} (-1)^{k}\cdot \frac{x^{k+2}}{4^{k}}[/tex] represents a Taylor series-derived formula of the rational function [tex]\frac{4\cdot x^{2}}{4+x}[/tex]. [tex]\blacksquare[/tex]

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Answer:

12.5  ≥ s >0

Step-by-step explanation:

The perimeter of a square is given by

P = 4s where s is the side length

50 ≥ 4s

Divide each side by 4

50/4 ≥ 4s/4

25/2  ≥ s

12.5  ≥ s

Answer:

2.5+2.5+45+45

=95.0m

therefore area of the square= 95.0m

45m×0.5=45.5÷95=

Step-by-step explanation:

2.5m

2.5 m tiles are required

[tex]area = 2.5 \times 45 = 192.5 \: squared \: cenimetre \\ \\ no \: of \: tiles = 0.5 \times 0.5 = 0.25 \\ 192.5 \div 0.25 = 770tiles[/tex]

Answer:

26 ft

Step-by-step explanation:

I'm guessing this is how it's done

60-40= 20

there for at this time any shadow would be 20x it's original height/length

so 6+20=26 ft

lmk if I'm correct

Taking ratios

Let the shadow length=x ft

[tex]\\ \sf\longmapsto 40:60=6:x[/tex]

[tex]\\ \sf\longmapsto \dfrac{40}{60}=\dfrac{6}{x}[/tex]

[tex]\\ \sf\longmapsto \dfrac{4}{6}=\dfrac{6}{x}[/tex]

[tex]\\ \sf\longmapsto 4x=6(6)[/tex]

[tex]\\ \sf\longmapsto 4x=36[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{36}{4}[/tex]

[tex]\\ \sf\longmapsto x=9[/tex]

Answer:

Part A: y = 25x + 30

Part B: $180

Step-by-step explanation:

for part A, 25 is the constant so that goes with the x, and you just add 30 because it is the extra fee. slope intercept form is y = mx + b

for part B you just plug 6 into the slope intercept equation

y = 25(6) + 30

y = 150 + 30

y = 180

$180

Answer:

d) you can reach a large audience with one communication

Step-by-step explanation:

common sense

Answer:

around 22, or 21.98

Step-by-step explanation:

[tex]s1 = {r}^{2} \times \pi = 9 \times 3.14 = 28.26[/tex]

[tex]s2 = 1 \times 3.14 = 3.14[/tex]

[tex]s3 = 28.26 - (3.14 \times 2) = 28.26 - 6.28 = 21.98[/tex]

Answer:

3:7

Step-by-step explanation:

i hope this helps

Answer:

a) the probability that the defective board was produced during the first hour of operation is [tex]\frac{1}{10}[/tex] or 0.1000

b) the probability that the defective board was produced during the  last hour of operation is [tex]\frac{1}{10}[/tex] or 0.1000

c) the required probability is 0.2000

Step-by-step explanation:

Given the data in the question;

During a specific ten-hour period, one defective circuit board was found.

Lets X represent the number of defective circuit boards coming out of the machine , following Poisson distribution on a particular 10-hours workday which one defective board was found.

Also let Y represent the event of producing one defective circuit board, Y is uniformly distributed over ( 0, 10 ) intervals.

f(y) = [tex]\left \{ {{\frac{1}{b-a} }\\\ }} \right _0[/tex];   ( a ≤ y ≤ b )[tex]_{elsewhere[/tex]

= [tex]\left \{ {{\frac{1}{10-0} }\\\ }} \right _0[/tex];   ( 0 ≤ y ≤ 10 )[tex]_{elsewhere[/tex]

f(y) = [tex]\left \{ {{\frac{1}{10} }\\\ }} \right _0[/tex];   ( 0 ≤ y ≤ 10 )[tex]_{elsewhere[/tex]

Now,

a) the probability that it was produced during the first hour of operation during that period;

P( Y < 1 )   =   [tex]\int\limits^1_0 {f(y)} \, dy[/tex]

we substitute

=    [tex]\int\limits^1_0 {\frac{1}{10} } \, dy[/tex]

= [tex]\frac{1}{10} [y]^1_0[/tex]

= [tex]\frac{1}{10} [ 1 - 0 ][/tex]

= [tex]\frac{1}{10}[/tex] or 0.1000

Therefore, the probability that the defective board was produced during the first hour of operation is [tex]\frac{1}{10}[/tex] or 0.1000

b) The probability that it was produced during the last hour of operation during that period.

P( Y > 9 ) =    [tex]\int\limits^{10}_9 {f(y)} \, dy[/tex]

we substitute

=    [tex]\int\limits^{10}_9 {\frac{1}{10} } \, dy[/tex]

= [tex]\frac{1}{10} [y]^{10}_9[/tex]

= [tex]\frac{1}{10} [ 10 - 9 ][/tex]

= [tex]\frac{1}{10}[/tex] or 0.1000

Therefore, the probability that the defective board was produced during the  last hour of operation is [tex]\frac{1}{10}[/tex] or 0.1000

c)

no defective circuit boards were produced during the first five hours of operation.

probability that the defective board was manufactured during the sixth hour will be;

P( 5 < Y < 6 | Y > 5 ) = P[ ( 5 < Y < 6 ) ∩ ( Y > 5 ) ] / P( Y > 5 )

= P( 5 < Y < 6 ) / P( Y > 5 )

we substitute

 [tex]= (\int\limits^{6}_5 {\frac{1}{10} } \, dy) / (\int\limits^{10}_5 {\frac{1}{10} } \, dy)[/tex]

[tex]= (\frac{1}{10} [y]^{6}_5) / (\frac{1}{10} [y]^{10}_5)[/tex]

= ( 6-5 ) / ( 10 - 5 )

= 0.2000

Therefore, the required probability is 0.2000

Answer:

12

Step-by-step explanation:

Range is the subtraction of the largest number and the smallest number.

The largest number is: 23

The smallest number is: 11

Now subtract:

23 - 11 = 12

Hope this helped.

Answer:

the lowest is 11 and the highest is 24 then subtract it you are going to have 13

Step-by-step explanation:

yo

so sorry I can't

really answer it

Answer:

"a" is the answer because 3x+2 can not be equal to zero

Step-by-step explanation:

Answer:

90 days

Step-by-step explanation:

b= number of days til  her birthday

s = number of days til summer

b+s =135

b = 2s

2s+s = 135

3s = 135

Divide by 3

3s/3 =135/3

s =45

b = 2s = 2(45) = 90

Answer:

x = 35

Step-by-step explanation:

We can use the Pythagorean theorem since this is a right triangle

a^2 + b^2 = c^2  where a and b are the legs and c is the hypotenuse

x^2 + 12^2 = (x+2)^2

FOIL

x^2+144=x^2+4x+4

Subtract x^2 from each side

144= 4x+4

Subtract 4 from each side

140 = 4x

Divide by 4

35 =x

Answer:

1.33 < 2.67 ; Fail to reject H0 at 0.05

Step-by-step explanation:

Given the data :

Men:

n1= 11

s1= 6.1

Women:

n2= 14

s2= 5.3

The hypothesis :

H0 : σ1² = σ2²

H1 : σ1² > σ2²

To calculate the test statistic ; we use th Ftest statistics ;

F statistic = Larger sample variance / Smaller sample variance

Fstatistic = s1² / s2² = 6.1² / 5.3² = 37.21/28.09 = 1.325

The F critical value at :

df numerator = n - 1 = 11 - 1 = 10

df denominator = n - 1 = 14 - 1 = 13

Using the F distribution table :

F critical = 2.671

Since

F statistic < F critical ; Fail to reject H0 at 0.05

We fail to reject the null hypothesis at significance level of H0 : s1² = s2²

For the men, we have:

For the women, we have:

The null and the alternate hypotheses are:

The numerator and the denominator degrees of freedom are calculated as:

[tex]\mathbf{df = n -1}[/tex]

So, we have:

[tex]\mathbf{df_1 = 11 -1}[/tex]

[tex]\mathbf{df_1 = 10}[/tex] ----- numerator

[tex]\mathbf{df_2 = 14 -1}[/tex]

[tex]\mathbf{df_2 = 13}[/tex] ----- denominator

The test statistic of the f test is:

[tex]\mathbf{t = \frac{s_1^2}{s_2^2}}[/tex]

So, we have:

[tex]\mathbf{t = \frac{6.1^2}{5.3^2}}[/tex]

[tex]\mathbf{t = \frac{37.21}{28.09}}[/tex]

[tex]\mathbf{t = 1.325}[/tex]

The critical values at [tex]\mathbf{t = 1.325}[/tex] and the degrees of freedom is:

[tex]\mathbf{F= 2.671}[/tex]

By comparison, 1.325 is less than 2.671.

Hence, we fail to reject the null hypothesis at H0 : s1² = s2²

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Answer:

y = 6/5x-1

Step-by-step explanation:

We have two points so we can find the slope

(-5,-7) and (5,5)

The slope is

m = ( y2-y1)/(x2-x1)

   = ( 5- -7)/( 5 - -5)

   = (5+7)/(5+5)

    = 12/10

   = 6/5

The slope intercept form of a line is

y = mx+b

y = 6/5x+b

Using the point (5,5)

5 = 6/5(5)+b

5=6+b

b=-1

y = 6/5x-1

Answer:

The third side is increasing at an approximate rate of about 0.444 meters per minute.

Step-by-step explanation:

We are given a triangle with two sides having constant lengths of 13 m and 19 m. The angle between them is increasing at a rate of 2° per minute and we want to find the rate at which the third side of the triangle is increasing when the angle is 60°.

Let the angle between the two given sides be θ and let the third side be c.

Essentially, given dθ/dt = 2°/min and θ = 60°, we want to find dc/dt.

First, convert the degrees into radians:

[tex]\displaystyle 2^\circ \cdot \frac{\pi \text{ rad}}{180^\circ} = \frac{\pi}{90}\text{ rad}[/tex]

Hence, dθ/dt = π/90.

From the Law of Cosines:

[tex]\displaystyle c^2 = a^2 + b^2 - 2ab\cos \theta[/tex]

Since a = 13 and b = 19:

[tex]\displaystyle c^2 = (13)^2 + (19)^2 - 2(13)(19)\cos \theta[/tex]

Simplify:

[tex]\displaystyle c^2 = 530 - 494\cos \theta[/tex]

Take the derivative of both sides with respect to t:

[tex]\displaystyle \frac{d}{dt}\left[c^2\right] = \frac{d}{dt}\left[ 530 - 494\cos \theta\right][/tex]

Implicitly differentiate:

[tex]\displaystyle 2c\frac{dc}{dt} = 494\sin\theta \frac{d\theta}{dt}[/tex]

We want to find dc/dt given that dθ/dt = π/90 and when θ = 60° or π/3. First, find c:

[tex]\displaystyle \begin{aligned} c &= \sqrt{530 - 494\cos \theta}\\ \\ &=\sqrt{530 -494\cos \frac{\pi}{3} \\ \\ &= \sqrt{530 - 494\left(\frac{1}{2}\right)} \\ \\&= \sqrt{283\end{aligned}[/tex]

Substitute:

[tex]\displaystyle 2\left(\sqrt{283}\right) \frac{dc}{dt} = 494\sin\left(\frac{\pi}{3}\right)\left(\frac{\pi}{90}\right)[/tex]

Solve for dc/dt:

[tex]\displaystyle \frac{dc}{dt} = \frac{494\sin \dfrac{\pi}{3} \cdot \dfrac{\pi}{90}}{2\sqrt{283}}[/tex]

Evaluate. Hence:

[tex]\displaystyle \begin{aligned} \frac{dc}{dt} &= \frac{494\left(\dfrac{\sqrt{3}}{2} \right)\cdot \dfrac{\pi}{90}}{2\sqrt{283}}\\ \\ &= \frac{\dfrac{247\sqrt{3}\pi}{90}}{2\sqrt{283}}\\ \\ &= \frac{247\sqrt{3}\pi}{180\sqrt{283}} \\ \\ &\approx 0.444\text{ m/min}\end{aligned}[/tex]

The third side is increasing at an approximate rate of about 0.444 meters per minute.

9514 1404 393

Answer:

  0.444 m/min

Step-by-step explanation:

I find this kind of question to be answered easily by a graphing calculator.

The length of the third side can be found using the law of cosines. If the angle of interest is C, the two given sides 'a' and 'b', then the third side is ...

  c = √(a² +b² -2ab·cos(C))

Since C is a function of time, its value in degrees can be written ...

  C = 60° +2t° . . . . . where t is in minutes, and t=0 is the time of interest

Using a=13, and b=19, the length of the third side is ...

  c(t) = √(13² +19² -2·13·19·cos(60° +2t°))

Most graphing calculators are able to compute a numerical value of the derivative of a function. Here, we use the Desmos calculator for that. (Angles are set to degrees.) It tells us the rate of change of side 'c' is ...

  0.443855627418 m/min ≈ 0.444 m/min

_____

Additional comment

At that time, the length of the third side is about 16.823 m.

__

c(t) reduces to √(530 -494cos(π/90·t +π/3))

Then the derivative is ...

  [tex]c'(t)=\dfrac{494\sin{\left(\dfrac{\pi}{90}t+\dfrac{\pi}{3}\right)}\cdot\dfrac{\pi}{90}}{2\sqrt{530-494\cos{\left(\dfrac{\pi}{90}t+\dfrac{\pi}{3}}}\right)}}}\\\\c'(0)=\dfrac{247\pi\sqrt{3}}{180\sqrt{283}}\approx0.443855...\ \text{m/min}[/tex]