Answer:
6 3/4 miles
Step-by-step explanation:
We can use ratios to solve
20.25 miles x miles
------------------ = ------------
3 hours 1 hours
Using cross products
20.25 * 1 = 3x
Divide each side by 3
20.25 /3 = x
6.75 = x
Changing to a fraction
6 3/4
If the sum of the measure of two angles in a triangle is 101, then the measure
of the third angle must be
Answer:
79 degrees.
Step-by-step explanation:
It is just a rule of trigonometry that all the angles inside ANY triangle will add up to 180 degrees.
There's only 3 possible angles in a triangle, so if you know what the sum of 2 are, its easy to find the last one.
All you have to do is 180 - 101, which equals 79 degrees.
Hope this helped : )
PLEASE HELP!!!!!
Parking for 4 hours costs $10. Parking for 5 hours costs $12. Is this a proportional relationship, and if so, what is the constant of proportionality?
Answer:
Not a Proportional Relationship ; No Constant of Proportionality
Step-by-step explanation:
Consider the first example, 4 hours of parking costs $ 10. From this we can derive the ratio 4 : 10, so that hours parked : fee for parking is a common ratio among the two examples, the other being 5 : 12;
[tex]4 : 10, Simplify\\2 : 5, Take As Fraction,\\Solution; 2 / 5ths\\[/tex]
[tex]5 : 12, Simplify\\( Can't Be Simplified Further ) - Take as Fraction,\\Solution; 5 / 12ths[/tex]
Considering that the fractions when compared are not similar, ( 2 / 5, and 5 / 12 ) they don't have a proportional relationship, and thus have no constant of proportionality
Solution; Not a Proportional Relationship
What is the value of x in the diagram?
Answer:
5
Step-by-step explanation:
Given is a right angled triangle.
Therefore, by Pythagoras theorem:
[tex] {(2x + 3)}^{2} = {x}^{2} + {(2x + 2)}^{2} \\ 4 {x}^{2} + 9 + 12x = {x}^{2} + 4 {x}^{2} + 4 + 8x \\ 9 + 12x = {x}^{2} + 4 + 8x \\ {x}^{2} + 4 + 8x - 12x - 9 = 0 \\ {x}^{2} - 4x - 5 = 0 \\ ({x}^{2} - 4x + 4 )- 4 - 5 = 0 \\ {(x - 2)}^{2} - 9 = 0 \\ {( x - 2)}^{2} = 9 \\ x - 2 = \pm \: \sqrt{9} \\ x - 2 = \pm 3 \\ x = 2 \pm 3 \\ x = 2 + 3 \: \: or \: \: x = 2 - 3 \\ x = 5 \: \: or \: \: x = - 1 \\ \because \: x \: can \: not \: be \: negative \\ \therefore \: x \neq \: - 1 \\ \therefore \: x = 5[/tex]