Answer:
–272.96 °C
Explanation:
From the question given above, the following data were obtained:
Initial temperature (T₁) = 27.0 °C
Initial volume (V₁) = 630 L.
Final volume (V₂) = 92.0 mL
Final temperature (T₂) =?
Next, we shall convert 27.0 °C to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
Initial temperature (T₁) = 27.0 °C
Initial temperature (T₁) = 27.0 °C + 273
Initial temperature (T₁) = 300 K
Next, we shall convert 92.0 mL to L. This can be obtained as follow:
1000 mL = 1 L
Therefore,
92 mL = 92 mL × 1 L / 1000 mL
92 mL = 0.092 L
Next, we shall determine the final temperature.
Initial temperature (T₁) = 300 K
Initial volume (V₁) = 630 L.
Final volume (V₂) = 0.092 L
Final temperature (T₂) =?
V₁ / T₁ = V₂ / T₂
630 / 300 = 0.092 / T₂
2.1 = 0.092 / T₂
Cross multiply
2.1 × T₂ = 0.092
Divide both side by 2.1
T₂ = 0.092 / 2.1
T₂ = 0.04 K
Finally, we shall convert 0.04 K to celsius temperature. This can be obtained as follow:
T(°C) = T(K) – 273
Final temperature (T₂) = 0.04 K
Final temperature (T₂) = 0.04 – 273
Final temperature (T₂) = –272.96 °C
Necesito ayuda porfavor
Answer:
thank for the points ❤️
Explanation:
pa breinlyest po
Hl Weakly dissociates in water according to the chemical equation below. H20+ Hl <-> H3O^+ + l- What is a conjugate acid-base pair in this reaction?
Answer:
https://www.clutchprep.com/chemistry/practice-problems/70217/hi-aq-h2o-l-h3o-aq-i-aq-identify-each-as-either-a-bronsted-lowry-acid-bronsted-l
Explanation:
https://www.clutchprep.com/chemistry/practice-problems/70217/hi-aq-h2o-l-h3o-aq-i-aq-identify-each-as-either-a-bronsted-lowry-acid-bronsted-l
What is the pH of a 0.235 M Ba(OH)2 solution?
Answer:
13.672
Explanation:
2 moles of OH in Ba(OH)₂
0.235 M × 2 mol OH = 0.47 M OH
pOH = -log[OH-] ; pOH = -log[0.47 M OH] ; 0.328 = pOH (consider significant figures)
14 - pOH = pH because pH + pOH = 14
14 - 0.328 = 13.672 [there are three decimal places after the OH concentration, so there should be in the answer as well - 13.672]
Element is defined as either a
Answer:
An element is an ATOM or aggregate of atoms all of which have the same number of protons. In pure form, they will also have the same number of electrons. Each element has its own unique number of protons. For example, hydrogen always has one proton, helium always has two and lithium always has three.
Explanation:
If 3.13 mol of an ideal gas has a pressure of 2.33 atm and a volume of 72.31 L, what is the temperature of the sample in degrees Celsius?
Answer:
382.49 C degree Celsius
Explanation:
Hello,
This problem deals with understanding the ideal gas law which hopes to predict how ideal gases might behave in any given condition. I listed the formula below and we are basically just going to solve for temperature by rearranging the equation as seen on the picture (there's also other rearranged ones in case you need to solve for those).
Universal gas constant R has a value of 0.0821 L * atm/(mole * K) when working with these given units so it will be part of this equation. R value changes based on what units you have.
T = PV/nR
= (2.33) (72.31) / (3.13)(0.0821)
= 655.64 K
Question is asking temperature in celsius so we employ the formula attached below:
C = K - 273.15
= 655.64-273.15
= 382.49 degree Celsius
382.49 degree Celsius is the answer!
How many moles of oxygen are required to produce 4.62 moles of carbon monoxide that is formed by direct combination of its elements?
Answer: 6.01
Explanation:
What is the volume of a 12.2 g piece of metal with a density of 9.43 g/cm??
Answer:
1.29
Explanation:
You have to find the equation which is d=m/v. d is 9.43=12.2/v. You have to solve for v which you get 1.29
1.29 [tex]cm^3[/tex] is the volume of a 12.2 g piece of metal with a density of 9.43 g/cm.
What is density?Density is the measurement of how tightly a material is packed together.
Density =Mass ÷ volume
9.43=12.2 ÷ V
V = 1.29 [tex]cm^3[/tex]
Hence, 1.29 [tex]cm^3[/tex] is the volume of a 12.2 g piece of metal with a density of 9.43 g/cm.
Learn more about density here:
brainly.com/question/16894337
#SPJ2
Water forms according to the equation below:
2H2(g) + O2(g) 2H2O(g) es001-2= -483.64 kJ
How much energy is released during the formation of 1 mol H2O(g)?
Answer:
The first blank is: -241.82 kJ
The second blank is: 483.64
Explanation:
Edge 21'
Determine the pH of 1.0 x 10-10M NaOH
pH=
Answer:
4
Explanation:
Applying,
pH = 14-pOH.................... Equation 1
But,
pOH = -log(OH⁻)
Where OH⁻ = Hydroxyl ion concentration of NaOH.
From the question,
Given: OH⁻ = (1×10⁻¹⁰) M
Substitute these values into equation 1
pH = 14-log((1×10⁻¹⁰)
pH = 14-10
pH = 4
Hence the pH of NaOH with a molarity of 1.0 x 10-10M = 4
What effect does photosynthesis have on Earth’s atmosphere?
i need help who ever helps me will get a Brainliest
Photosynthesis removes both carbon dioxide and oxygen from the atmosphere.
Photosynthesis removes carbon dioxide from the atmosphere and adds oxygen to the atmosphere.
Photosynthesis adds both carbon dioxide and oxygen to the atmosphere.
Photosynthesis removes oxygen from the atmosphere and adds carbon dioxide to the atmosphere.
PLEASE HELP I HAVE 19 MINUTES LEFT I WILL MARK BRAINLIEST
How much more acidic is a pH of 4 as compared to a pH of 6.5?
Answer:
316.227766
Explanation:
Do u believe that you are beautiful/handsome?
Yes or No?
The materials or compounds that are changed into new compounds in a chemical reaction are known as ?
Answer:
The starting substances of a chemical reaction are called the reactants, and the new substances that result are called the products.
130 cm of a gas at 20°C exerts a pressure of
750 mm Hg. Calculate its pressure if its volume
is increased to 150 cm3 at 35 °C.
Answer: The pressure is 1137.5 mm Hg its pressure if its volume is increased to 150 [tex]cm^{3}[/tex] at 35 °C
Explanation:
Given: [tex]P_{1}[/tex] = 750 mm Hg, [tex]V_{1} = 130 cm^{3}[/tex], [tex]T_{1} = 20^{o}C[/tex]
[tex]P_{2}[/tex] = ?, [tex]V_{2} = 150 cm^{3}[/tex], [tex]T_{2} = 35^{o}C[/tex]
Formula used to calculate the new pressure is as follows.
[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}[/tex]
Substitute the values into above formula as follows.
[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{750 mm Hg \times 130 cm^{3}}{20^{o}C} = \frac{P_{2} \times 150 cm^{3}}{35^{o}C}\\P_{2} = 1137.5 mm Hg[/tex]
Thus, we can conclude that the pressure is 1137.5 mm Hg its pressure if its volume is increased to 150 [tex]cm^{3}[/tex] at 35 °C.
Which of the following must have a host to replicate
A)bacteria
B)virus
C)Protozoa
D)fungi
Answer:
Virus
Explanation:
Hope this helped :)
A balloon is filled with 3.50 L of water at 24.0°C. What is the volume of the water at 307 K?
Answer:
what is the volume of the water at 307 k?
Determine the empirical formula for a compound that contains 87.5%
Si and 12.5% H.
Select one:
O
a. SiH4
b. Si3H12
c. SizH4
d. Si4H
Answer:
Solution. So, the empirical formula of the compound is NH2.
Explanation:
thank me later
Answer:
I don't know but I have to answer cause this is the step
Explanation:
which class do u read its so hard i read in only class6
I really need helpp
Answer:
option b
Explanation:
Will give brainliest
In the following acid-base reaction
H2O is the
HCl(g) + H2O(l) →H30+(aq) + Cl-(aq)
В
acid
base
conjugate
acid
CONJUGATE ACID
the acid's conjugate base because it can theoretically reform the acid by aaccepting a proton.
I hope this is correct >.<
6. (08.02 MC)
What is the molarity of a solution prepared by dissolving 10.0 grams of NaOH in enough water to make a solution with a total volume of 2.40 liters? (5 points)
O 0.104 M NaOH
O 0.201 M NaOH
0 0.361 M NaOH
O 0.412 M NaOH
Answer:0.104
Explanation:
Answer:
0.104
Explanation:
convert grams to moles “10.0 x 1/40”
divide moles by the liters 0.25/2.4
answer: 0.104
write half-reactions that show how H2O2 can act as either an oxidizing agent or a reducing agent, and describe where each of these situations occurred in your testing.
Answer:
H2O2 reduces itself to H2O and also oxidizes to O2 simultaneously thereby acting both as an oxidizing and reducing agent .
Explanation:
When
H2O2 acts as an oxidizing agent
H2O2 + 2e- 2H+---> 2H2O
Reducing agent
H2O2 --> O2 + 2e + 2H+
H2O2 reduces itself to H2O and also oxidizes to O2 simultaneously thereby acting both as an oxidizing and reducing agent .
Given 2.37 mol of calcium, how much (in g) would it weigh? Include the proper units
and significant digits.
The electron configuration can be also be represented by writing the symbol for the occupied subshell and adding a superscript to indicate the number of electrons in that subshell. For example, the electron configuration of the carbon atom having six electrons is written as
Answer: The electron configuration of carbon atom is written as 1s²,2s², 2p².
Explanation:
The electronic configuration of an atom is defined as the arrangement of electrons into the shells or orbit of an atom. The constituents of an atom are proton, neutron and electron. the nucleus of an atom, where most of its mass are concentrated, consists of neutrons and protons fused together. Electrons occupy the shells surrounding the nucleus. The shells are lettered K, L, M, N and so on. Numerically, K shell is numbered 1, L is 2 and so on. These numbers also correspond with the increase in the energy level. All the electrons in K shell for instance belong to the first energy level and they have equal energy.
There is a limit to the number of electrons that can be found in a shell. This can be obtained by a formula 2n² where "n" is the energy level number of the shell.
K: 2n² = 2 × 1² = 2
L: 2n² = 2× 2² = 8
These shells are further subdivided into subshells. There are 4 subshells, s, p, d, and f. Each subshell can hold a different number of electrons.
This electron configuration of carbon can be written as 1s² 2s² 2p² where 1s, 2s, and 2p are the occupied subshells, and the superscript "2" is the number of electrons in each of these subshells.
Physical properties such as melting point, boiling point, and solubility are all dependent on the type of interparticle forces a substance experiences. Identify the type of interparticle force that has the greatest influence on the physical properties for each substance.
Answer:
CaCl2 and KI- ionic
PCl3 and CH4-dispersion forces
NH2OH- hydrogen bonding
Explanation:
Complete question
Physical properties such as melting point, boiling point, and solubility are all dependent on the type of interparticle forces a substance experiences. Identify the type of interparticle force that has the greatest influence on the physical properties for each substance. Cl2, NH2OH, PCl3, CH4, CaCl2, KI
Solution
Calcium and Potassium are metal and they form ionic bonds with the non metal such as CaCl2 and KI
PCl3 and CH4- have dispersion forces as their structural arrangement distribute electrons around any atom and molecule.
NH2OH- hydrogen bonding - Due to the presence of H and O atoms, there exists hydrogen bond with in this molecule.
Calculate mL (4 sf) of 0.7500 M sodium hydroxide required to neutralize 35.00 mL of 0.7500 M phosphoric acid. Please input number as whole number not scientific notation
Answer:
105mL of 0.7500M of NaOH are required
Explanation:
Phosphoric acid, H₃PO₄, reacts with sodium hydroxide, NaOH, as follows:
H₃PO₄ + 3 NaOH → Na₃PO₄ + 3H₂O
Where 1 mole of phosphoric acid reacts with 3 moles of NaOH
To solve this question we must find, as first, the moles of H3PO4 that react. Using the chemical equation we can find the moles of NaOH required to neutralize this acid. And, with its concentration, we can find the volume oof NaOH required:
Moles H3PO4:
35.00mL = 0.03500L * (0.7500mol / L) = 0.2625 moles H3PO4
Moles NaOH:
0.2625 moles H3PO4 * (3mol NaOH / 1mol H3PO4) = 0.07875 moles NaOH
Volume NaOH:
0.07875 moles NaOH * (1L / 0.7500mol) = 0.105L =
105mL of 0.7500M of NaOH are requiredAn analysis of a compound shows that it consists of 36.8% nitrogen and 63.2% oxygen
Answer:
This question is incomplete, however, it is asking to calculate the empirical formula of the compound.
The empirical formula is N2O3
Explanation:
The following information about a compound was got from the question:
N = 36.8%
O = 63.2%
It can be said that the compound contains 36.8g of nitrogen (N) and 63.2g of oxygen (O).
Next, we convert each mass composition to moles by dividing by their respective molar masses.
N = 36.8g ÷ 14g/mol = 2.628mol
O = 63.2g ÷ 16g/mol = 3.95mol
Next, we divide each mole value by the smallest value (2.628mol).
N = 2.628mol ÷ 2.628 = 1
O = 3.95mol ÷ 2.628 = 1.5
We multiply each value by 2 to get a empirical ratio.
N = 2
O = 3
The ratio of N:O is 2:3, hence, the empirical formula is N2O3.
Which equation represents the total ionic equation for the reaction of HNO3 and NaOH?
OH+ + OH -> H2O
O HNO3 + NaOH → NaNO3 + H20
OH + NO3 +Na+ + OH -> Na + NO3 + H20
OH + NO3 + OH →→ NO3 + H20
Answer:
H⁺(aq) + NO₃⁻(aq) + Na⁺(aq) + OH⁻(aq) → Na⁺(aq) + NO₃⁻(aq) + H₂O(l)
Explanation:
First, we will write the molecular equation for the neutralization reaction between nitric acid and sodium hydroxide.
HNO₃(aq) + NaOH(aq) → NaNO₃(aq) + H₂O(l)
The total ionic equation includes all the ions and the molecular species.
H⁺(aq) + NO₃⁻(aq) + Na⁺(aq) + OH⁻(aq) → Na⁺(aq) + NO₃⁻(aq) + H₂O(l)
200.0g of a 3.0% NaF solution, how much distilled water do we weigh out?
197g of distilled water
194g of distilled water
140g of distilled water
170g of distilled water
Answer:
194g of distilled water.
Explanation:
Hello there!
In this case, according to the given information for this problem, it turns out possible for us to use the given mass of the solution and the percent by mass of NaF to firstly calculate the grams of this solute as shown below:
[tex]\%m=\frac{m_{solute}}{m_{solution}} *100\%\\\\m_{solute}=\frac{\%m*m_{solution}}{100\%} \\\\m_{solute}=\frac{3.0\%*200.0g}{100\%} \\\\m_{solute}=6g[/tex]
And finally, since the mass of solution is calculated by adding mass of solute and mass of solvent we obtain the mass of water (solvent) as follows:
[tex]m_w=200g-6g=194g[/tex]
Therefore, the answer is 194g of distilled water
Regards!
When 100 identical steel balls are placed on a
triple beam balance, their mass is determined to
be 1,450 grams. The mass of a single steel ball
would be closest to
Explanation:
thank you for the points
The heat of combustion per mole for acetylene, C2H2(g), is -1299.5 kJ/mol. Assuming that the combustion products are CO2(g) and H2O(l), and given that the enthalpy of formation is -393.5 kJ/mol for CO2(g) and -285.8 kJ/mol for H2O(l), find the enthalpy of formation of C2H2(g).
Answer: The heat of combustion per mole for acetylene is 227.7 kJ/mol.
Explanation:
The combustion equation of acetylene is as follows.
[tex]C_{2}H_{2} + \frac{5}{2}O_{2} \rightarrow 2CO_{2} + H_{2}O[/tex]
Formula to calculate enthalpy of formation for a reaction is as follows.
[tex]\Delta H^{o}_{rxn} = \sum \Delta H_{products} - \sum \Delta H_{reactants}\\\Delta H^{o}_{rxn} = [2\Delta H^{o}_{f}(CO_{2}) + \Delta H^{o}_{f} (H_{2}O)] - [\Delta H^{o}_{f}(C_{2}H_{2}) + \frac{5}{2} \Delta H^{o}_{f} O_{2}]\\-1299.5 = 2(-393.5) + (-285.8) - \Delta H^{o}_{f} (C_{2}H_{2})\\\Delta H^{o}_{f} (C_{2}H_{2}) = 227.7 kJ/mol[/tex]
Thus, we can conclude that heat of combustion per mole for acetylene is 227.7 kJ/mol.
