Answer:
The stock in last three days has a net gain of 3.
Step-by-step explanation:
The net change of the stock is the sum of daily changes in last three days. Please notice that positive sign means means for gain, whereas negative one is for loss. Based on information given on statement, we determine the net change in the stock:
[tex]x = -\left(8 + \frac{3}{8} \right)-\left(1+\frac{5}{8} \right) + 13[/tex]
[tex]x = 3[/tex]
The stock in last three days has a net gain of 3.
A team of 5people to be selected from 7women & 6men. Find the number of different teams that could be selected if there must be more women than men in the team
Answer:i would say 2 differentt teams where there is more then women than men in the team
Step-by-step explanation:
well how i came to this answer is that the team is limited to only 5 people giving the only team where there is more women over men is this first team would be 4 women and 1 men , second team would be 3 women and 2 men anything lower then 3 make its where the team has more men than women so the only options would be 2 team where either they go with 4 women or 3 women and you can't go with more then 4 because then there would be no men in the team which is what the question asks for please go with 2 teams
if this helps please make me brainlist ?!
can you help me please.
Answer:
-86
Step-by-step explanation:
-102-
98 so the answer is -86
Find the area of the triangle
Answer:
Step-by-step explanation:11/2x(8-4)=22
Peter plays basketball. In one game, he needs to score at least 38 points to have a
season high of 1,200 points. He scores x number of 2 pointers and y number of 3
pointers and meets his goal of at least 38 points.
Using the variables given, write an inequality describing this scenario.
how to evaluate 4(x+2−5x) when x=2
Answer:
-24
Step-by-step explanation:
4(x+2−5x)
Combine like terms
4(2 -4x)
Distribute
8 -16x
Let x=2
8 - 16(2)
8 - 32
-24
how to evaluate 4(x+2−5x) when x=2
To Find :The value after evaluating Solution :We are provided that x equals 2 so have to put 2 instead of x to the desired result4(x + 2 - 5x)
Putting the value of x we get
4(2 + 2 - 5 × 2)
According to BODMAS multiplication comes first then addition
So 5 × 2 will be solved after that we will simplify 2 added with 2
4(2 + 2 - 10)
4(4 - 10)
4(-6)
- 24
Henceforth, the required answer is -24
Express this to single logarithm
[tex] \frac{1}{2} log_{2}(m) - 3 log_{2}(n) + 2 log(q) [/tex]
Answer: [tex]\log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right)[/tex]
We have something in the form log(x/y) where x = q^2*sqrt(m) and y = n^3. The log is base 2.
===========================================================
Explanation:
It seems strange how the first two logs you wrote are base 2, but the third one is not. I'll assume that you meant to say it's also base 2. Because base 2 is fundamental to computing, logs of this nature are often referred to as binary logarithms.
I'm going to use these three log rules, which apply to any base.
log(A) + log(B) = log(A*B)log(A) - log(B) = log(A/B)B*log(A) = log(A^B)From there, we can then say the following:
[tex]\frac{1}{2}\log_{2}\left(m\right)-3\log_{2}\left(n\right)+2\log_{2}\left(q\right)\\\\\log_{2}\left(m^{1/2}\right)-\log_{2}\left(n^3\right)+\log_{2}\left(q^2\right) \ \text{ .... use log rule 3}\\\\\log_{2}\left(\sqrt{m}\right)+\log_{2}\left(q^2\right)-\log_{2}\left(n^3\right)\\\\\log_{2}\left(\sqrt{m}*q^2\right)-\log_{2}\left(n^3\right) \ \text{ .... use log rule 1}\\\\\log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right) \ \text{ .... use log rule 2}[/tex]
The 12th term of the arithmetic sequence is 10.5. The 18th term of this sequence is 13.5. Find the common difference and the first term
Answer:
common difference is 0.5
first term is 5
Step-by-step explanation:
use the formula for the nth term of an ap Tn=a+(n-1)d
T12=10.5
T18=13.5
therefore come up with two equations
T12=a+(12-1)d
10.5=a+11d(1st equation)
T18=a+(18-1)d
13.5=a+17d(2nd equation)
then solve both as a simultaneous equation
a+11d=10.5
a+17d=13.5
-6d/-6=-3/-6
d=0.5
use one of the equations to find the first term
a+11(0.5)=10.5
a+5.5=10.5
a=10.5-5.5
a=5
I hope this helps
please mark as brainliest
I need help for this question!!
Part (i)
We start with five dots to make the pattern in figure 1.
In figure 2, we add on 1 dot to each arm of the X shape. So that means we've added 4 dots total going from 5 to 5+4 = 9 dots.
In figure 3, there are 9+4 = 13 dots
So the pattern is simply "add 4" to get the next term. Again, this is because we add one dot per arm.
The first three terms of this arithmetic sequence are: 5, 9, 13
Your teacher wants to know what the general nth term is
We start with a = 5 and the common difference is d = 4
T(n) = nth term
T(n) = a + d(n-1)
T(n) = 5 + 4(n-1)
T(n) = 5 + 4n - 4
T(n) = 4n + 1
Let's try it out. Say we want to plug in n = 2
T(n) = 4n + 1
T(2) = 4(2) + 1
T(2) = 8 + 1
T(2) = 9
This works because the second figure indeed has 9 dots. I'll let you confirm the other figures.
Answer: 4n + 1============================================================
Part (ii)
Your teacher wants to know how many dots occur when n = 50
T(n) = 4n + 1
T(50) = 4(50)+1
T(50) = 200 + 1
T(50) = 201
Verifying this through drawing dots is going to be a very tedious task, and I don't recommend it unless you really want to. Hopefully the verification process of T(2) = 9, and similar (for small values of n) is enough to convince you that this equation works as intended.
Answer: 201Hey plese helppppp . Question: Evaluate: b²- 4ac. if a=5, b=-2,c=-3
Answer:
64
Step-by-step explanation:
b²- 4ac
Let a=5, b=-2,c=-3
(-2)^2 - 4(5) (-3)
4 +60
64
Answer:
64
Step-by-step explanation:
(-2)^2 - 4(5)(-3)
4 - - 60
64
A sinusoidal graph has an amplitude of 9 and a midline of y = –2. Determine
the range of the graph.
Answer:
[tex]( - 11.7)[/tex]
Range 18
Step-by-step explanation:
Twice the amplitude.
PLEASE HELP ITS TIMED
If x/3=5/6,
then x=
Step-by-step explanation:
x/3 = 5/6
cross multiply
6x=15
x=2.5
Answer:
x=5/2
Step-by-step explanation:
help help help help
Answer:
abc is a triangle so ,
a is ( 9,6 )
b is ( 9,3 )
and c is ( 3,3 )
Instructions: Find the measure of the indicated angle to the nearest degree.
Answer:
A = 79°
Step-by-step explanation:
CosA = adjacent ÷ hypoteneous
A = Cos^-1(6÷32)
A. =. 79.19°
A= 79°
HELP FAST Which solution shown bellow contains an error
Answer:
B
Step-by-step explanation:
What are the values of a, b, and c in the quadratic equation 0 = 1 / 3x² – 3x – 2?
O a = 3,6 =3, c= 2
O a = 1, b =-3, c= -2
O a= 2,6 = 3, c= -2
O a = 1, b = -3, c = 2
W
Answer:
[tex]a = \frac{1}{2} \\ b = - 3 \\ c = - 2[/tex]
Step-by-step explanation:
The explanation is in the picture!
Verify that –(-x) is the same as x , for x = −4/5
Answer:
Step-by-step explanation:
-(--4,5)= -(4,5)= -4,5
Four times an angle is equal to half of its supplement. Find the measures of both angles.
Answer:
The bigger angle is 144 degrees and the smaller one is 36 degrees
Help please!
Find the inverse equation of this function
f(x) = (x + 6)^2 + 1
Thank you!!
Step-by-step explanation:
you're just going to switch x and y and then solve for y
Answer:
Hello,
Step-by-step explanation:
The problem is that the inverse function is not a function but
an union of 2 functions.
[tex]y=(x+6)^2+1\ is\ the\ orignal\ function\ f(x).\\\\Inverting\ x\ and\ y\ gives: \ x=(y+6)^2+1\\\\(y+6)^2=x-1 \ nota\ bene\ x-1\geq 0 \\(y+6)^2-(x-1)=0\\\\((y+6)-\sqrt{x-1} ) * ((y+6)+\sqrt{x-1}) =0\\\\y=-6+\sqrt{x-1}-6\ or\ y=-6-\sqrt{x-1}\\[/tex]
For the fun
,[tex]f_1(x)= (x+6)^2+1=0\ if\ x<6\\f_1^{-1}(x)=-6-\sqrt{x-1} =0\ if\ x<6\\\\f_2(x)=(x+6)^2+1=0\ if\ x \geq 6\\\\f_2^{-1}(x)=-6+\sqrt{x-1} =0\ if\ x\geq 6\\[/tex]
PLEASE HELP ASAP, will give brainliest!!!!
Answer:
3.398
Step-by-step explanation:
log(2500)=log(25)+log(100)=2+2*0.699=3.398
On a coordinate plane, a curved line labeled f of x with a minimum value of (1.9, negative 5.7) and a maximum value of (0, 2), crosses the x-axis at (negative 0.7, 0), (0.76, 0), and (2.5, 0), and crosses the y-axis at (0, 2).
Which statement is true about the graphed function?
F(x) < 0 over the intervals (-∞, -0.7) and (0.76, 2.5).
F(x) > 0 over the intervals (-∞, -0.7) and (0.76, 2.5).
F(x) < 0 over the intervals (-0.7, 0.76) and (2.5, ∞).
F(x) > 0 over the intervals (-0.7, 0.76) and (0.76, ∞
Answer:
F(x) < 0 over the intervals (-∞, -0.7) and (0.76, 2.5)
Step-by-step explanation:
The minimum value of the curve = (1.9, -5.7),
The maximum value = (0, 2)
The point the function crosses the x-axis (the x-intercept) = (-0.7, 0), (0.76, 0), and (2.5, 0)
The point the function crosses the y-axis (the y-intercept) = (0, 2)
The given points can be plotted using MS Excel, from which we have;
F(x) is less than 0 over the interval from x = -∞, to x = -0.7, and the interval from x = 0.76 to x = 2.5
The correct option is therefore, F(x) < 0 over the intervals (-∞, -0.7) and (0.76, 2.5)
Answer:
A. F(x) < 0 over the intervals (-∞, -0.7) and (0.76, 2.5).
Step-by-step explanation:
Write an equation in point-slope form of the line that passes through the given point and has the given slope.
(16,-4);m=-3/4
the vertex of this parabola is at (-2 -3). When the y value is -2, the x value is -5. What is the coefficient of the squared term in the parabolas equation.
Answer:
1/9
Step-by-step explanation:
The vertex form is
y =a(x-h)^2 +k where (h,k) is the vertex
The vertex is (-2,-3)
y =a(x--2)^2 +-3
y =a(x+2)^2 -3
Substitute the point into the equation
-2 = a(-5+2)^2 -3
-2=a(-3)^2-3
Add 3 to each side
-2+3 = a(9)
1 = 9a
1/9 =a
y =1/9(x+2)^2 -3
The coefficient of the x^2 is 1/9
Answer:
[tex]\frac{1}{9}[/tex]
Step-by-step explanation:
The equation of a parabola in vertex form is
y = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
Here (h, k ) = (- 2, - 3) , then
y = a(x + 2)² - 3
To find a substitute (- 5, - 2 ) into the equation
- 2 = a(- 5 + 3)² - 3 ( add 3 to both sides )
1 = a(- 3)² = 9a ( divide both sides by 9 )
[tex]\frac{1}{9}[/tex] = a
y = [tex]\frac{1}{9}[/tex] (x + 2)² - 3
The coefficient of the x² term is therefore [tex]\frac{1}{9}[/tex]
Find the value of x in the triangle shown below.
Answer:
x=80
Step-by-step explanation:
The base angles have to be the same since the sides are both 14
The sum of the angles of triangle is 180
50+50+x = 180
100+x= 180
x = 180-100
x= 80
What is the value of the exponential expression below?
I need help can someone help me out
Answer:
C' (-1,-2)
V' (-2,2)
N' (2,0)
Answered by GAUTHMATH
Can someone find this for me please?
Answer:
the larger one is 183
Step-by-step explanation:
[tex]x + y = 262 \\ x - y = 104 \\ y = 262 - x \\ x - (262 - x) = 104 \\ x - 262 + x = 104 \\ 2x = 104 + 262 \\ 2x = 366 \\ x = 183 \\ y = 262 - 183 \\ y = 79[/tex]
the difference between 0.48 and 2.1
Answer:
0.48 is ......
[tex]0.48 < 2.1[/tex]
geometry: follow directions below for each for each figure. show steps. circle answers. find the area of each figure!!
HELP ASAP!!!
THANK YOU SO MUCH:)))
Answer:
56 cm^2
Step-by-step explanation:
The area of a triangle is
A = 1/2 bh where b is the base and h is the height
A = 1/2 (14) (8)
A = 56 cm^2
Calculate the correlation coefficient, r, for the data below. Row chart ( (x )(y ) ) row chart ( ( -10 )( 2 ) ) row chart ( ( -8 )( -3 ) ) row chart ( ( -1 )( -15 ) ) row chart ( ( -4 )( -10 ) ) row chart ( ( -6 )( -6 ) ) row chart ( ( -7 )( -5 ) ) row chart ( ( -5 )( -8 ) ) row chart ( ( -3 )( -13 ) ) row chart ( ( -2 )( -14 ) ) row chart ( ( -9 )( -1 ) )
Answer:
The correlation coefficient is approximately -0.9949
Step-by-step explanation:
The given data is presented as follows;
[tex]\begin{array}{lcl}x&&y\\-10&&2\\-8&&-3\\-1&&-15\\-4&&-10\\-6&&-6\\-7&&-5\\-5&&-8\\-3&&-13\\-2&&-14\\-9&&-1\end{array}[/tex]
The correlation coefficient, r is given as follows;
[tex]r = \dfrac{\sum(x_i - \overline x) \cdot (y_i - \overline y)}{\sqrt{\sum (x_i- \overline x)^2\times \sum (y_i- \overline y)^2 } }[/tex]
From MS Excel, we have;
∑([tex]x_i - \overline x[/tex])·([tex]y_i - \overline y[/tex]) = -155.5
∑([tex]x_i - \overline x[/tex])² = 82.5
∑([tex]y_i - \overline y[/tex])² = 296.1
Therefore, r = -155.5/(√(82.5 × 296.1)) ≈ -0.9949
The correlation coefficient, r ≈ -0.9949
In a sequence, the first term is 8 and the common difference is -2. The 18th term
of this sequence is
1) – 34
2) - 42
3) - 26
4) 26
