Becky Anderson must pay a lump sum of $6000 in 5 yr. If only $5000 is available to deposit right now, what annual interest rate is necessary for the money to increase to $6000 in 5 yr?

Answer:

False

Step-by-step explanation:

You first need to distribute the -4 to (x+4).

Answer:

[tex]\frac{135}{15} =\frac{15(x+2)}{15}[/tex]

[tex]9=x+2[/tex]

[tex]x=7[/tex]

OAmalOHopeO

Answer:

A movie is $4.50 and a video game is $5

Step-by-step explanation:

Create a system of equations where m is the cost of each movie and v is the cost of each video game:

2m + 5v = 34

8m + 3v = 51

Solve by elimination by multiplying the top equation by -4:

-8m - 20v = -136

8m + 3v = 51

Add these together and solve for v:

-17v = -85

v = 5

So, a video game is $5. Plug in 5 as v into one of the equations, and solve for m:

2m + 5v = 34

2m + 5(5) = 34

2m + 25 = 34

2m = 9

m = 4.5

A movie is $4.50 and a video game is $5

The question is an illustration of a function using graphs. When a function is plotted on a graph, the x-axis represents the domain, while the y-axis represents the range of the function.

The domain and the range of the given function are:

Domain: [tex](-\infty,\infty)[/tex]

Range: [tex](3,\infty)[/tex]

From the question, we have the function to be:

[tex]g(x) = 3^x + 3[/tex]

First, we plot the graph of g(x)

To do this, we first generate values for x and g(x). The table is generated as follows:

[tex]x = 0 \to g(0) = 3^0 + 3 = 4[/tex]

[tex]x = 1 \to g(1) = 3^1 + 3 = 6[/tex]

[tex]x = 2 \to g(2) = 3^2 + 3 = 12[/tex]

[tex]x = 3 \to g(3) = 3^3 + 3 = 30[/tex]

[tex]x = 4 \to g(4) = 3^4 + 3 = 84[/tex]

In a tabular form, we have the following pair of values

[tex]\begin{array}{cccccc}x & {0} & {1} & {2} & {3} & {4} \ \\ g(x) & {4} & {6} & {12} & {30} & {84} \ \end{array}[/tex]

See attachment for graph

From the attached graph of g(x), we can observe that the curve stretches through the x-axis and there are no visible endpoints.

This means that the curve starts from - infinity to +infinity

Hence, the domain is: [tex](-\infty,\infty)[/tex]

Also, from the same graph, we can observe that the curve of g(x) starts at y = 3 on the y-axis and the curve faces upward direction.

This means that the curve of g(x) is greater than 3 on the y-axis.

Hence, the range is: [tex](3,\infty)[/tex]

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Answer:

The answer is "1900"

Step-by-step explanation:

It takes 500 fewer calories per day for her to lose 1 lb of weight every week.

[tex]\to (15 \times 160)-500 =(2400)-500 =2400-500=1900[/tex]

A well formatted table of the distribution is attached below :

Answer:

0.124

0.733

0.408

Step-by-step explanation:

Using the table Given :

1.) P(AP Statistics) = 90 / 725 = 0.124

2.) P(12th grade ; Precalculus or AP Statistics) = (100 + 65) / 225 = 165 /225 = 0.733

3.) P(Algebra 11 | 11th grade) = P(Algebara11 n 11th grade) / P(11th grade) = 100 / 245 = 0.408

Answer:

x = 6

z = 60

Step-by-step explanation:

Solve for x

(6x + 84) = 120

     -  84     -84

6x = 36

6x/6 = 36/6

x = 6

Then solve for z

120 + z = 180

-120        -120

z = 60

The average weekly allowance of a 5th grade student as calculated using direct variation with the information provided by Fidelity Investment Vision Magazine is 5.367 dollars per week.

The question given is a direct variation problem:

Let:

• Average weekly allowance = [tex]a[/tex]

• Grade level = [tex]g[/tex]

If Average weekly allowance varies directly as grade level , then , then the direct variation between the variables can be expressed as :

[tex]a = k * g[/tex]

Where ,  [tex]k[/tex] = constant of proportionality

We can obtain the value of k from the given values of a and g

[tex]9.66 = k * 9\\9.66 = 9k\\k = 9.66/9[/tex]

Our equation becomes:

[tex]a = (9.66/9) * g[/tex]

[tex]a = (9.66/9) * 5\\a = 5.367[/tex] (rounded to 3 decimal places)

Hence, using proportional relationship, the average weekly allowance for a 5th grade student is [tex]5.367[/tex] per week

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Answer:

Step-by-step explanation:

one angle is 50

Answer:

18

Step-by-step explanation:

(p-1/p)² = 4²

p² + 1/p² - 2(p)(1/p) = 16

p²+1/p² -2 =16

so, p²+1/p² = 16+2

= 18

Answer:

Step-by-step explanation:

Speed = (15 mi)/hr × (1.6 km)/mi = (24 km)/hr

:::::

(4 hr) × (24 km)/hr = 96 km

Answer

its uhhhhh i dont know

Step-by-step explanation:

Answer:

in four (4) ways 4 people can be selected

square meter is the SI unit of area.

Answer:

Step-by-step explanation:

i) 18 - 2b = 5a

18 - 2b - 5a = 0

-2b -5a = -18

2b + 5a = 18

5a + 2b = 18

ii) 3a = 5b + 17

3a - 5b = 17

At this time x = 3, y = -5, c= 17

ax + by = c is equivelant to 3a -5b = 17

So another equation is:

3a - 5b = 17

Answer from Gauthmath

Step-by-step explanation:

18-2b=5a

we want to make 5a the subject so first we 5a to the left so our new equation is 5a+18-2b=0

then we move the 2b infront of the +18 so then our new equation is 5a+2b+18=0 then. we move the +18 to the other side to give 5a+2b=18

Answer:

A.

Step-by-step explanation:

π/4 radians = 45°

In a 45-45-90 degree angle, the ratio of the lengths of the sides is

1 : 1 : √2

x = y = 1/√2

x = y = √2/2

Answer: A.

Answer:

A

Step-by-step explanation:

π/4 rad is 45°

cos 45° and sin 45° are both equal to (√2 / 2)

If you're curious, cos delta = x-coordinate while sin delta = y-coordinate

80 inches in standard notation using feet and inches would be expressed as 6 ft 8 inches by converting inches into feet and inches.

The solution to the given problem is to use some standard conversion units that are:

Solution:

As mentioned above that one inch is equal to 0.8333 foot therefore

1 foot = 12 inches

then,

80 inches would be equal to

= [tex]\frac{80}{12}[/tex] ft

= [tex]\frac{20}{3}[/tex] ft

= 6ft 8 inches

= 6' 8"

Thus, 80 inches in standard notation using feet and inches would be expressed as 6 ft 8 inches by converting inches into feet and inches.

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Answer:

0.2937 ;

0.292 ;

0.275, 0.314, 0.295, 0.296, 0.276, 0.289

Step-by-step explanation:

0.275 0.319 0.314 0.280 0.288 0.314 0.295 0.296 0.317 0.276 0.274 0.289 0.295 0.276 0.275 0.296 0.311 0.289 0.283 0.312

Reordered data :

0.274, 0.275, 0.275, 0.276, 0.276, 0.280, 0.283, 0.288, 0.289, 0.289, 0.295, 0.295, 0.296, 0.296, 0.311, 0.312, 0.314, 0.314, 0.317, 0.319

The mean : ΣX / n ; n = sample size, = 20

Mean = 5.874 / 20 = 0.2937

The median : 1/2(n+1)th term

Median = 1/2(21)th term = 10.5 th term

Median = (10th + 11th) terms / 2

Median = (0.289+0.295) / 2 = 0.292

The mode = 0.275, 0.314, 0.295, 0.296, 0.276, 0.289 (values with ten highest number of occurence.)

One piece will be length x and the other piece will be 20 cm longer, so it will be x + 20 cm long.  

Added together the length of these two boards will equal 86 cm. So you can write an equation:  

x + (x + 20) = 86  

Remove the parentheses and add the two x's together to get:  

2x + 20 = 86

Subtract 20 from both sides:  

2x = 66  

Divide both sides by 2 and you have:  

x = 33  

The short piece is 33 cm and the other piece is 20 cm longer or 33 + 20 = 53 cm.

Let the width = x

The length would be 4x-27

Area = length x width

2790 = (4x-27) * x

Expand:

2790 = 4x^2 - 27x

Subtract 2790 from both sides:

4x^2 - 27x - 2790 = 0

Use the quadratic formula to solve for the positive value of x:

X = -(-27) + sqrt(-27^2 -4*4(-2790)) /(2*4)

X = 30

Now replace x with 30 in the lengths:

Width = x = 30 inches

Length = 4x -27 = 4(30) -27 = 120-27 = 93 inches

Answer:

Y= -9x+45

y = -9 X + b

-9 = -9(6) + b

-9 = -54 + b

b=45

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

I guess that is the answer

I think the given integral reads

[tex]\displaystyle \int_{-3}^3 \int_0^{9-x^2} \int_{x^2+y^2}^{9-x^2-y^2} \mathrm dz\,\mathrm dy\,\mathrm dx[/tex]

In cylindrical coordinates, we take

x ² + y ² = r ²

x = r cos(θ)

y = r sin(θ)

and leave z alone. The volume element becomes

dV = dx dy dz = r dr dθ dz

Then the integral in cylindrical coordinates is

[tex]\displaystyle \boxed{\int_0^\pi \int_0^{(\sqrt{35\cos^2(\theta)+1}-\sin(\theta))/(2\cos^2(\theta))} \int_{r^2}^{9-r^2} r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta}[/tex]

To arrive at this integral, first look at the "shadow" of the integration region in the x-y plane. It's the set

{(x, y) : -3 ≤ x ≤ 3 and 0 ≤ y ≤ 9 - x ²}

which is the area between a paraboloid and the x-axis in the upper half of the plane. So right away, you know θ will fall in the first two quadrants, so that 0 ≤ θ ≤ π.

Next, r describes the distance from the origin to the parabola y = 9 - x ². In cylindrical coordinates, this equation changes to

r sin(θ) = 9 - (r cos(θ))²

You can solve this explicitly for r as a function of θ :

r sin(θ) = 9 - r ² cos²(θ)

r ² cos²(θ) + r sin(θ) = 9

r ² + r sin(θ)/cos²(θ) = 9/cos²(θ)

(r + sin(θ)/(2 cos²(θ)))² = 9/cos²(θ) + sin²(θ)/(4 cos⁴(θ))

(r + sin(θ)/(2 cos²(θ)))² = (36 cos²(θ) + sin²(θ))/(4 cos⁴(θ))

(r + sin(θ)/(2 cos²(θ)))² = (35 cos²(θ) + 1)/(4 cos⁴(θ))

r + sin(θ)/(2 cos²(θ)) = √[(35 cos²(θ) + 1)/(4 cos⁴(θ))]

r  = √[(35 cos²(θ) + 1)/(4 cos⁴(θ))] - sin(θ)/(2 cos²(θ))

Then r ranges from 0 to this upper limit.

Lastly, the limits for z can be converted immediately since there's no underlying dependence on r or θ.

The expression above is a bit complicated, so I wonder if you are missing some square roots in the given integral... Perhaps you meant

[tex]\displaystyle \int_{-3}^3 \int_0^{\sqrt{9-x^2}} \int_{x^2+y^2}^{9-x^2-y^2} \mathrm dz\,\mathrm dy\,\mathrm dx[/tex]

or

[tex]\displaystyle \int_{-3}^3 \int_0^{\sqrt{9-x^2}} \int_{x^2+y^2}^{\sqrt{9-x^2-y^2}} \mathrm dz\,\mathrm dy\,\mathrm dx[/tex]

For either of these, the "shadow" in the x-y plane is a semicircle of radius 3, so the only difference is that the upper limit on r in either integral would be r = 3. The limits for z would essentially stay the same. So you'd have either

[tex]\displaystyle \int_0^\pi \int_0^3 \int_{r^2}^{9-r^2} r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta[/tex]

or

[tex]\displaystyle \int_0^\pi \int_0^3 \int_{r^2}^{\sqrt{9-r^2}} r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta[/tex]

Elimination method

3x +4y ≥ 0

2x +3y ≥ 1

Multiply by 2, -3

6x +8y ≥ 0

-6x +-9y ≥ -3

Add

-1y ≥ -3

y = 3

3x + 12≥ 0

3x + ≥ -12

x = -4

answer: y = 3 x = -4

Answer:

Option B. M = Log 10000

Step-by-step explanation:

From the question given above, we were told that the intensity (I) is 10000 times that of the reference earthquake (I₀).

Thus, we can obtain the magnitude (M) of the earthquake as follow:

Let the reference earthquake (I₀) = A

Then, the intensity (I) = 10000 × A

M = Log(I/I₀)

M = Log(10000A / A)

M = Log 10000

Thus, option B gives the right answer to the question.

9514 1404 393

Answer:

  (x, y') = (-13, 13)

Step-by-step explanation:

At the given value of x, f(x) = 2. Then 9f(x)-5 = 9(2) -5 = 13.

The point on the scaled, translated graph will be ...

  (x, y') = (-13, 13)

_____

The graph shows a function f(x) with a distinct feature (vertex) at (-13, 2). It also shows where that distinct feature moves to when the function is scaled and translated.

I REALLY HOPE THIS HELPS! I’m sorry if this was wrong but I really believe it’s true.

Answer:

The value of P is $6.75.

Step-by-step explanation:

In the diagram to the left, we see 6 apples, and are labeled that the price is $4.50.

If the prices are proportional, that may mean that each apple has the same price. To find the price of apples in the diagram to the right, divide the total price by 6:

4.50/6 = 0.75

So the price per apple is 0.75.

As seen on the diagram, P represents the total price of 9 apples.

Multiply the price per apple by 9:

0.75 x 9 = 6.75

So the value of P is $6.75

Answer:

Step-by-step explanation:

Assume the dish opens upwards. The cross-section through the vertex is a parabola. You know three points on the parabola: (0,0), (2,2), and (-2,2). Plug the points into y = ax² + bx + c to get a system of three equations where a=0.5, b=c=0.

Equation of parabola: y = 0.5x²

:::::

Vertex (0,0)

Focal length = 1/(4×0.5) = 0.5

Focus (0,0+0.5) = (0, 0.5)

Directrix y = 0-0.5 = -0.5

:::::

At endpoints of latus rectum, y = 0.5

x = ±√0.5 = ±√2/2

Focal width = 2×√2/2 = √2

:::::

Place antenna at focus, (9,2)

The length of YZ in the similar triangle given is calculated using Pythagoras theorem which gave us 16√3

Similar triangles are two or more triangles that have the same shape but may be different sizes. They have the same angles and corresponding sides that are proportional.

In this problem, we need to use the concept of ratio and proportions to find the length of YZ

However, we can simply use Pythagoras theorem to determine the length.

According to Pythagoras' Theorem, the square of the hypotenuse, or side opposite the right angle, in a right-angled triangle, is equal to the sum of the squares of the other two sides.

It is expressed as the equation a² + b² = c².

This is because the triangles forms a right angled triangle and we can easily apply that here.

YZ² = 16² + (16√2)²

YZ² = 768

YZ = √768

YZ = 16√3

The length or distance from point Y to WX which is the same as the length of YZ is calculated as 16√3.

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Answer:

C. 16

Step-by-step explanation:

I hope this helps :)