It looks like the integral you want to find is
[tex]\displaystyle \int_C x^2y\,\mathrm dx - xy^2\,\mathrm dy[/tex]
where C is the circle x ² + y ² = 4. By Green's theorem, the line integral is equivalent to a double integral over the disk x ² + y ² ≤ 4, namely
[tex]\displaystyle \iint\limits_{x^2+y^2\le4}\frac{\partial(-xy^2)}{\partial x}-\frac{\partial(x^2y)}{\partial y}\,\mathrm dx\,\mathrm dy = -\iint\limits_{x^2+y^2\le4}(x^2+y^2)\,\mathrm dx\,\mathrm dy[/tex]
To compute the remaining integral, convert to polar coordinates. We take
x = r cos(t )
y = r sin(t )
x ² + y ² = r ²
dx dy = r dr dt
Then
[tex]\displaystyle \int_C x^2y\,\mathrm dx - xy^2\,\mathrm dy = -\int_0^{2\pi}\int_0^2 r^3\,\mathrm dr\,\mathrm dt \\\\ = -2\pi\int_0^2 r^3\,\mathrm dr \\\\ = -\frac\pi2 r^4\bigg|_{r=0}^{r=2} \\\\ = \boxed{-8\pi}[/tex]
Kevin made a business trip of 312.5 miles. He averages 60 mph for the first part of the trip and 55 mph for the second part. If the trip took a 5.5 hours how long did he travel at each rate
Answer:
Kevin travels for 2 hours at 60 mph and 3.5 hours at 55 mph
Step-by-step explanation:
Let's say that Kevin spends x hours going 60 mph and y hours going 55 mph. We can say that the sum of the two parts is 5.5, so x+y = 5.5 . Next, he goes 60 miles per hour for the first part of the trip, so for each hour he goes 60 mph, he travels 60 miles. We can then denote 60 * x as the distance traveled during the first part of his trip as he goes 60 mph for x hours. Similarly, 55 * y denotes the distance Kevin travels during the second part of his trip. His total distance is thus 60 * x + 55 * y = 312.5 miles
We have
x + y = 5.5
60 * x + 55 * y = 312.5
One way we can solve this is to solve for y in the first equation and plug that into the second. Subtracting x from both sides in the first equation, we get
y = 5.5 - x
Plugging that into the second equation, we get
60 * x + 55 * (5.5-x) = 312.5
60 * x + 55 * 5.5 - 55x = 312.5
5x +302.5 = 312.5
subtract 302.5 from both sides to isolate the x and its coefficient
5x = 10
divide both sides by 5 to solve for x
x = 2
y = 5.5 - x = 5.5 - 2 = 3.5
Therefore, Kevin travels for 2 hours at 60 mph and 3.5 hours at 55 mph
How many more barrels of gasoline than desiel were produced
Answer:
15
Step-by-step explanation:
Find the distance between the pair of points.
E(5, -3), F( - 4,9)
d =
(Simplify your answer. Type an exact answer, using radicals as needed.)
Answer:
EF = 15 units
Step-by-step explanation:
Calculate the distance using the distance formula
d = [tex]\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }[/tex]
with (x₁, y₁ ) = E (5, - 3) and (x₂, y₂ ) = F (- 4, 9)
EF = [tex]\sqrt{-4-5)^2+(9-(-3))^2}[/tex]
= [tex]\sqrt{(-9)^2+(9+3)^2}[/tex]
= [tex]\sqrt{81+12^2}[/tex]
= [tex]\sqrt{81+144}[/tex]
= [tex]\sqrt{225}[/tex]
= 15
Christopher has breakfast at a cafe and the cost of his meal is \$36.00$36.00dollar sign, 36, point, 00. Because of the service, he wants to leave a 10\%10%10, percent tip.
What is his total bill including tip?
Answer: $ 39.60
Step-by-step explanation:
36 + (36*0.10) = 39.60
Budhas 7/10
of a cake left. Two of his friends are over for dessert. Estimate how much cake
each of them, including Bud, will get.
A.1/2 of the cake
B.1/4of the cake
C.3/4of the cake
D.1 1/4of the cake
Answer:
B
Step-by-step explanation:
Two friends + Bud = 3 people
7/10 = 70%, or less than a full cake
D is more than a full cake so this cannot be the answer.
C is 3/4 which 75% for each person, but there is only 70% to begin with so this is impossible.
B is 1/4 for each person also known as 25% for each person. 25% × 3 people = 75% which is slightly over how much cake Bud has (70%).
A is 1/2 for each person, but there isn't enough cake to go around to give each person a half piece.
The soundest solution would be B. Since the problem calls for estimations, B gives about 25% to each person, totaling to 75% after 3 people. Although we only have 70%, we are only estimating. A 5% difference is a good estimate.
Solve for x.
A. 9
B. 12
C. 1
D. 7
Answer:
9
Step-by-step explanation:
use Tangent-chord formula for finding the arc knowing E
x=1/2n
4x+19=1/2n
n=8x+38
both arcs = 360
28x-2+8x+38=360
x=9
Which function has a maximum with the same maximum value as
Answer:
Step-by-step explanation:
if 10x=1/0.001 find the value of x
[tex]\\ \sf\longmapsto 10x=\dfrac{1}{0.001}[/tex]
Turn over the decimal[tex]\\ \sf\longmapsto 10x=\dfrac{1}{\dfrac{1}{1000}}[/tex]
[tex]\\ \sf\longmapsto 10x=1000[/tex]
[tex]\\ \sf\longmapsto x=\dfrac{1000}{10}[/tex]
[tex]\\ \sf\longmapsto x=100[/tex]
What statement is not true? A) a square is a rhombus C) a rhombus is a rectangle D) a square is a rectangle
B) a rhombus is a parallelogram
Answer:
A square is a retangle
Step-by-step explanation:
Because a squre is a rectangle
Luna I made the trip to the moon in . In this activity, you will determine the average speed of Luna I using division.
What is the area of a square with a side length of 32 yards?
Answer:
A=1024 yd.^2
Step-by-step explanation:
A=s^2
Substitute,
A=32^2
So,
A=1024 yd.^2
Answer:
1024 yd²
Step-by-step explanation:
Since it's a square, the side lengths will all be the same length. Due to this, you can square the given value to find the area.
A(Square) = 32² = 1024
Two complementary angles have measures of s and t. if t is less than twice s, which system of linear equations can be used to determine the measure of each angle? Please explain answer.
We want to make a system of linear equations that would allow us to find the measure of the angles (we only want to find the system, not solving it)
Here we will find that we do not have a system of linear equations, we have:
s + t = 90°
t < 2*s
Here we have two complementary angles s and t.
Remember that two angles are complementary if their sum is equal to 90°, then we can write:
s + t = 90°
We also know that "t is less than twice s"
this can be written as:
t < 2*s
Notice that the above one is not an equation, is an inequality.
Then the system that we should use to
s + t = 90°
t < 2*s
If we want to force our system to be a system of linear equations, we can write:
s + t = 90°
t = 2*s
But naturally;
s + t = 90°
t < 2*s
has more solutions than:
s + t = 90°
t = 2*s
So we should not replace the inequality with an equation.
If you want to learn more, you can read:
https://brainly.com/question/9446123
3. Find F(3).
F(x)=-x^3+4x^2-2x
Answer:
To Find F(3) you just have to replace x=3 so:
F(3)= -3^3 + 4×3^2 -2×3 = -27 +4×9 - 6 = -33 + 36 = 3
look at the image below urgent plz over 100 points
Answer: 1,526.04 yd³ (this is what i got on my calculator others may vary use any rounding you need)
VOLUME of CONE is: V= Pir² h / 3
Pi= 3.14
r= 9
h= 18
V= (3.14) x (9)² x (18)
9²= 81
3.14 x 81= 254.34 x 18= 4,578.12
4,578.12 / 3= 1,526.04 <-- answer
help please !!!!!!!!
Answer:
first choice..
first choice
Answer:
FIRST CHOISE FIRST CHOISE
Step-by-step explanation:
find the surface area of prism
Answer:
114 cm²
Step-by-step explanation:
Surface area of the rectangular prism,
2(wl+hl+hw)
=2×(3×8+3×8+3×3)
=2×(24+24+9)
=2×(57)
=114 cm²
2. mrs nepali draws rs 19800 as her monthly salary in a wholesale cosmetic shop and certain commission is given as per the monthly sales. if the sales of a month is rs 1200000 and her total income of the month including commission is rs 31800 find the rate of commission. * O 1% 4% 3% 2%
Consider the differential equation: 2y′′−13y′−7y = 0
a. Show that, for any constants A and B, the following is a solution to the above differential equation: y = Ae^(−9x)+Be^(x/3)
b. Find the values A and B that make the above general solution into a solution for the following initial value problem: 2y′′−13y′−7y = 0; y(0) = 3, y′(0) = −5
--------------------------------------------------
Just a correction, the characteristic roots of the equation are [tex]y = 7[/tex] and [tex]y = -\frac{1}{2}[/tex], thus, we should test for:
[tex]y = Ae^{7x} + Be^{-\frac{x}{2}}[/tex]
--------------------------------------------------
Question a:
First, we find the derivatives, thus:[tex]y = Ae^{7x} + Be^{-\frac{x}{2}}[/tex]
[tex]y^{\prime} = 7Ae^{-7x} - \frac{1}{2}Be^{-\frac{x}{2}}[/tex]
[tex]y^{\prime\prime} = 49Ae^{-7x} + \frac{1}{4}Be^{-\frac{x}{2}}[/tex]
Now, we replace into the equation:[tex]2y^{\prime\prime} - 13y^{\prime} - 7y = 0[/tex]
[tex]2(49Ae^{-7x} + \frac{1}{4}Be^{-\frac{x}{2}}) - 13(7Ae^{-7x} - \frac{1}{2}Be^{-\frac{x}{2}}) - 7(Ae^{7x} + Be^{-\frac{x}{2}}) = 0[/tex]
[tex]98Ae^{-7x} + \frac{1}{2}Be^{\frac{x}{2}} - 91Ae^{-7x} + \frac{13}{2}e^{-\frac{x}{2}} - 7Ae^{7x} - 7Be^{-\frac{x}{2}} = 0[/tex]
[tex]98Ae^{-7x} - 91Ae^{-7x} - 7Be^{-\frac{x}{2}} + \frac{1}{2}Be^{\frac{x}{2}} + \frac{13}{2}e^{-\frac{x}{2}} - 7Be^{-\frac{x}{2}} = 0[/tex]
[tex]0A + 0B = 0[/tex]
[tex]0 = 0[/tex], thus, we found the identity, and for each constant A and B, the following is a solution.
--------------------------------------------------
Question b:
[tex]y = Ae^{7x} + Be^{-\frac{x}{2}}[/tex]
Since [tex]y(0) = 3[/tex][tex]A + B = 3 \rightarrow B = 3 - A[/tex]
--------------------------------------------------
[tex]y^{\prime} = 7Ae^{-7x} - \frac{1}{2}Be^{-\frac{x}{2}}[/tex]
Since [tex]y^{\prime}(0) = -5[/tex][tex]7A - \frac{1}{2}B = -5[/tex]
Using [tex]B = 3 - A[/tex]
[tex]7A - \frac{3}{2} + \frac{A}{2} = -5[/tex]
[tex]\frac{14A}{2} + \frac{A}{2} = -\frac{10}{2} + \frac{3}{2}[/tex]
[tex]\frac{15A}{2} = -\frac{7}{2}[/tex]
[tex]15A = -7[/tex]
[tex]A = -\frac{7}{15}[/tex]
--------------------------------------------------
Then, B is given by:
[tex]B = 3 - A = 3 - (-\frac{7}{15}) = \frac{45}{15} + \frac{7}{15} = \frac{52}{15}[/tex]
Thus, the values are: [tex]A = -\frac{7}{15}, B = \frac{52}{15}[/tex]
A similar problem is given at https://brainly.com/question/2456414
Radicals and Exponents. Tutorial Use the properties of exponents to simplify the expression. (y 3/2 x-1/2)4 =
Can I have help I am stuck on this problem It would mean the world if u helped me and tysm!! =-)
9514 1404 393
Answer:
2^6 = 64
Step-by-step explanation:
Each hour the initial value (1) is multiplied by 2 (again). So the number of times 2 multiplies the initial value is the number of passing hours (t).
The number of cells after t hours is ...
c(t) = 1×2^t = 2^t
After 6 hours, this is
c(6) = 2^6 = 64 . . . . cells after 6 hours
_____
Additional comment
As you know, multiplication simplifies repeated addition.
x + x + x = 3x
In a similar way, exponentiation simplifies repeated multiplication.
x·x·x = x³ . . . . (written as x^3 in plain text)
In this problem, we're repeatedly multiplying by 2. After we do that t times, the initial value is multiplied by 2^t.
A rectangle’s perimeter is equal to 27 plus its width. The length of the rectangle is four times its width. What is the width of the rectangle in units?
Answer:
width: 3
Step-by-step explanation:
Given a length l and a width w, we can say that the perimeter is equal to
2 * l + 2 * w. Then, we also know that the perimeter is 27 plus its width, so
2 * l + 2 * w = 27 + w
and the length is 4 times its width, so length = 4 * width = l = 4 * w
We therefore have the two equations
2 * l + 2 * w = 27 + w
l = 4 * w
What we can do is plug 4* w for l in the first equation and solve from there. We thus have
2 * ( 4 * w) + 2 * w = 27 + w
8 * w + 2 * w = 27 + w
10 * w = 27 + w
subtract w from both sides to isolate the w and its coefficient
9 * w = 27
divide both sides by 9 to isolate w
w = 3
l = 4 * w = 12
Therefore, the width is 3 and the length is 12
Does the equation, x + y = 6 show direct variation?
Answer:
Yeah, x varies directly with (6 - y)
Step-by-step explanation:
[tex]x = 6 - y \\ x = k(6 - y) \\ x \: \alpha \: (6 - y)[/tex]
find area of a square garden having a length 45m
Answer:
A = 2025 ft^2
Step-by-step explanation:
The area of a square is given by
A = s^2 where s is the side length
A = 45^2
A = 2025 ft^2
Answer:
Step-by-step explanation:
The area of any square is s^2
s in this case is 45
Area = s^2
Area = 45 * 45
Area = 2025 m^2
Using only the digits 5, 6, 7, 8, how many different three digit numbers can beformed
Answer:
totally 16 numbers can be formed
It is hard and the condition of repeat of number should be clear if you have formula ( it is obvious to have) you can use that.
find the value of x, circles and angles
Answer:
x = 50
Step-by-step explanation:
When two secants intersect in the interior of a circle, the angles formed are the average of the arc an angle and its vertical intercept. In this case, our angle, 73, should be the average of x and 96. We can translate this to an equation and solve:
[tex]\frac{x+96}{2} = 73[/tex]
x + 96 = 146
x = 50
Find the missing side or angle.
Round to the nearest tenth.
b=15 a=30 c=29 a=[?]. Acellus plz
Answer:
∠ A ≈ 79.0°
Step-by-step explanation:
Using the Cosine rule to find the angle
cosA = [tex]\frac{b^2+c^2-a^2}{2bc}[/tex]
= [tex]\frac{15^2+29^2-30^2}{2(15)(29)}[/tex]
= [tex]\frac{225+841-900}{870}[/tex]
= [tex]\frac{166}{870}[/tex] , then
A = [tex]cos^{-1}[/tex] ([tex]\frac{166}{870}[/tex] ) ≈ 79.0° ( to the nearest tenth )
[tex]\int\limits^9_3 {\frac{1}{(x+21)\sqrt{x+22} } } \, dx[/tex]
Let y = x + 22 and dy = dx, so the integral becomes
[tex]\displaystyle \int_3^9 \frac{\mathrm dx}{(x+21)\sqrt{x+22}} = \int_{25}^{31} \frac{\mathrm dy}{(y-1)\sqrt{y}}[/tex]
Now let z = √y, so that z ² = y. Then 2z dz = dy, and the integral becomes
[tex]\displaystyle \int_3^9 \frac{\mathrm dx}{(x+21)\sqrt{x+22}} = \int_{\sqrt{25}}^{\sqrt{31}} \frac{2z}{(z^2-1)z} \\\\ = \int_5^{\sqrt{31}} \frac{2}{z^2-1}\,\mathrm dz[/tex]
Expand the integrand into partial fractions:
[tex]\dfrac{2}{z^2-1} = \dfrac1{z-1}-\dfrac1{z+1}[/tex]
Then we have
[tex]\displaystyle \int_3^9 \frac{\mathrm dx}{(x+21)\sqrt{x+22}} = \int_5^{\sqrt{31}}\left(\frac1{z-1}-\frac1{z+1}\right)\,\mathrm dz \\\\ = \left(\ln|z-1|-\ln|z+1|\right)\bigg|_5^{\sqrt{31}} \\\\ =\left[\ln\left|\frac{z-1}{z+1}\right|\right]\bigg|_5^{\sqrt{31}} \\\\ =\ln\left(\frac{\sqrt{31}-1}{\sqrt{31}+1}\right) - \ln\left(\frac{4}{6}\right) \\\\ =\ln\left(32-2\sqrt{31}\right) - \ln\left(\frac23\right) \\\\ =\boxed{\ln\left(48-3\sqrt{31}\right)}[/tex]
Gieo đồng thời hai con xúc xắc. Tìm xác suất để nhận được:Tổng số chấm là 8.
Answer:
what is this sy man i dnt get it
Step-by-step explanation:
A 12 ounce bag of rice costs $4.08. A 16-ounce bag of the same rice costs $5.76. Which bag is the better by
and by how much
Answer:
16 once is the better one.
Answer: 12-ounce bag is better by $0.02 per ounce
Concept:
When coming across questions that ask for a comparison between prices, we should make the final unit [price per object].
In finding [price per object], simply do [Total price / number of objects].
Solve:
A 12-ounce bag of rice costs $4.08
Total price / number of objects = 4.08 / 12 = $0.34 per ounce
A 16-ounce bag of rice costs $5.76
Total price / number of objects = 5.76 / 16 = $0.36 per ounce
$0.36 - $0.34 = $0.02
$0.34 < $0.36, therefore, 12-ounce bag is better by $0.02 per ounce.
Hope this helps!! :)
Please let me know if you have any questions
What’s the range of A and B and both
This is of Both
Range = Highest - Lowest data
Range = 45 - 10
Range = 35
Only A
Range = 45 - 10
Range = 35
Only B
Range = 40 - 15
Range = 25
Must click thanks and mark brainliest
