Answer:
Horizontal distance, R = vo2 sin(2x45)/g
v = 285 km/h = 79.17 m/s
R = 79.172 x 1/1.6
R = 3917 m
R = 3.9 km
Tiger Woods' golf ball will travel approximately 3925.22 meters horizontally before landing back on the surface of the moon.
To find the horizontal distance traveled by the golf ball on the moon, we can use the following kinematic equation:
d =[tex](v^2 * sin(2\theta)) / g[/tex]
where:
d = horizontal distance traveled
v = initial velocity of the golf ball (converted to m/s)
θ = launch angle
g = acceleration due to gravity on the moon (1.60 m/s²)
First, we need to convert the initial velocity from km/h to m/s:
Initial velocity (v) = 285 km/h = 285 * (1000 m/km) / (3600 s/h) ≈ 79.17 m/s
Now, plug the values into the equation:
d = ([tex]79.17^2[/tex]* sin(2 * 42°)) / 1.60
Calculate the value within the parentheses first:
sin(2 * 42°) = sin(84°) ≈ 0.999
Now, calculate the horizontal distance (d):
d = [tex](79.17^2 * 0.999) / 1.60[/tex]
d ≈ 3925.22 meters
So, Tiger Woods' golf ball will travel approximately 3925.22 meters horizontally before landing back on the surface of the moon.
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Cho các máy cắt sử dụng trong công nghiệp có ký hiệu trên nhãn thiết bị: C350; B500. Hãy tính dòng điện bảo vệ ngắn mạch và dòng điện bảo vệ quá tải của từng thiết bị?
Answer:
ask in the English then I can help you
Explanation:
please mark me as brain list
A fan is turned off, and its angular speed decreases from 10.0 rad/s to 6.3 rad/s in 5.0 s. What is the magnitude of the angular acceleration of the fan?
A) 0.37 rad/s2
B) 11.6 rad/s2
C) 0.74 rad/s2
D) 0.86 rad/s2
E) 1.16 rad/s2
Answer:
chk photo
Explanation:
Length of spring is 8cm when mass is 4kg is hang on it its become 16cm what is its spring constant?
Answer:
constant is 500 N/m
Explanation:
Extension, e = (16 - 8) = 8 cm
Force, F = (4 × 10) = 40 N
from hooke's law:
[tex]F = kx \\ 40 = (k \times 0.08) \\ k = \frac{40}{0.08} \\ \\ k = 500 \: newton \: per \: metre[/tex]
Between which two points of a concave mirror should an object be placed to obtain a magnificati of -3
Answer:
When object is placed between the focus (F) and pole (P) of a concave mirror, magnified and erect image of the object is formed on the back of the mirror.
When object is placed between the centre of curvature and the principal focus of a concave mirror, magnified and inverted image is formed in front of the mirror.
Explanation:
a baseball is given an initial velocity with magnitude v at the angle beta above the surface of an incline which in turn inclined at angle teta above horizontal calculate the distance measured along incline from the launch point to where the baseball strike the incline
Explanation:
The maximum height of an object, given the initial launch angle and initial velocity is found with:h=v2isin2θi2g h = v i 2 sin 2 θ i 2 g .
why do we go to hospital
Answer:
bcz we want to have fun there lolol
Answer:
for emergency, treatment, medicines,etc.....
The timing device in an automobile’s intermittent wiper system is based on an RC time constant and utilizes a 0.500 micro F capacitor and a variable resistor. Over what range must R be made to vary to achieve time constants from 2.00 to 15.0 s?
Answer:
check 2 photos for answer
check 2 photos for answer
Sound is an example of a:
Select one:
O a. rolling waves
b. longitudinal wave
O c. traverse waves
O d. surface wave
Ez Physics question will mark brainliest.
Answer:
The answer is B. longitude wave
Calculate the kinetic energy of a mass 2kg moving with a velocity of 0.1m/s
ANSWER-:
1/2 mv²
K.E = 1/2 mv²
K.E = 0.01 J.
Hence, the kinetic energy of a body is 0.01 Joule.
!! HOPE ITS HELP U !!
Consider a concave mirror that has a focal length f. In terms of f, determine the object distances that will produce a magnification of
A. -2
B. -3
C. -4
We have that the magnification of each focal length is given respectively as
A) has [tex]u=3\frac{f}{2}[/tex]
B) has [tex]u=4\frac{f}{3}[/tex]
C) has [tex]u=5\frac{f}{4}[/tex]
From the question we are told that:
Focal Length F
Generally, the equation for Magnification is mathematically given by
[tex]M=\frac{-v}{u}[/tex]
Therefore
[tex]v=2u[/tex]
For A
[tex]M=-2[/tex]
Therefore
[tex]\frac{1}{f}=\frac{1}{u}+\frac{1}{v}[/tex]
[tex]\frac{1}{f}=\frac{1}{u}+\frac{1}{2u}[/tex]
Therefore
[tex]u=3\frac{f}{2}[/tex]
For B
[tex]M=-3[/tex]
Therefore
[tex]v=3u[/tex]
Where
[tex]\frac{1}{f}=\frac{1}{u}+\frac{1}{v}[/tex]
[tex]\frac{1}{f}=\frac{1}{u}+\frac{1}{3u}[/tex]
Therefore
[tex]u=4\frac{f}{3}[/tex]
For C
[tex]M=-4[/tex]
Therefore
[tex]v=4u[/tex]
Therefore
[tex]\frac{1}{f}=\frac{1}{u}+\frac{1}{v}[/tex]
[tex]\frac{1}{f}=\frac{1}{u}+\frac{1}{4u}[/tex]
Therefore
[tex]u=5\frac{f}{4}[/tex]
Conclusion
From the calculations above we can rightly say that the magnifications of the values above are
A has [tex]u=3\frac{f}{2}[/tex]
B has [tex]u=4\frac{f}{3}[/tex]
C has [tex]u=5\frac{f}{4}[/tex]
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a bullet is dropped from the same height when another bullet is fired horizontally they will hit the ground
Answer:
simultaneously
Time taken to reach the ground depends on the vertical component of velocity, not horizontal component of velocity.
A train starts from rest (at position zero) and moves with constant acceleration. On the first observation, its velocity is 20m/s and 80seconds later the velocity became 60m/s. At 80s calculate the position, average velocity, and the constant acceleration over the interval.(7-points)
The value of the acceleration is a = 0.5 m/s². The position at 80 s is x = 3200 m and finally the average velocity is v = 40 m/s.
Acceleration:
We can use the fallowing kinematic equation to get the acceleration at 80 s.
[tex]a=\frac{v_{f}-v_{i}}{t}[/tex]
Where:
v(i) is the initial velocity (20 m/s)v(f) is the final velocity (60 m/s)t is the interval (80 s)The, we have:
[tex]\vec{a}=\frac{60-20}{80}[/tex]
[tex]\vec{a}=0.5\: m/s^{2}[/tex]
Position:
Knowing the acceleration we can find the position using the falling equation.
[tex]\vec{x}=v_{i}t+0.5at^{2}[/tex]
[tex]\vec{x}=20*80+0.5*0.5*80^{2}[/tex]
[tex]\vec{x}=3200 m[/tex]
Average velocity:
The definition of the average velocity is:
[tex]\vec{v}=\frac{\Delta x}{t}[/tex]
[tex]\vec{v}=\frac{x_{f}-x_{i}}{t}[/tex]
[tex]\vec{v}=\frac{3200-0}{80}[/tex]
[tex]\vec{v}=40\: m/s[/tex]
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Describe the forces that act on a skydiver before
and after the parachute is opened.
I will give brainliest!!!!
Answer:
Before the parachute opens: Immediately on leaving the aircraft, the skydiver accelerates downwards due to the force of gravity. There is no air resistance acting in the upwards direction, and there is a resultant force acting downwards. The skydiver accelerates towards the ground.
Once the parachute is opened, the air resistance overwhelms the downward force of gravity. The net force and the acceleration on the falling skydiver is upward. An upward net force on a downward falling object would cause that object to slow down. The skydiver thus slows down.
I HOPE THIS WILL HELP YOU IF NOT THEN SORRYHAVE A GREAT DAY :)
Yeast are tiny fungi to make products like bread, other kinds of dough, beer, and wine. They do this by digesting sugar. A byproduct of this is the release of carbon dioxide gas which makes bread so light and fluffy. We can observe yeast through experimentation by putting them in a closed container with sugar with a ballon on top to trap any carbon dioxide released. What is a quantitative observation that could be made in this experiment?
Answer:
Compare the volume (weight) of CO2 gas produced to the weights of sugar and yeast that were used to produce the CO2. Ideally, both the yeast and sugar would be entirely consumed.
A 10 n force is applied horizontally on a box to move it 10 m across a frictionless surface. How much work was done to move the box?
Answer:
[tex]\boxed {\boxed {\sf 100 \ J}}[/tex]
Explanation:
We are asked to calculate the work done to move a box.
Work is the product of force and distance or displacement.
[tex]W= F*d[/tex]
A 10 Newton force is applied horizontally on the box. Since the surface is frictionless, there is no force of friction, and the net force is 10 Newtons. The force moves the box 10 meters.
F= 10 N d= 10 mSubstitute the values into the formula.
[tex]W= 10 \ N * 10 \ m[/tex]
Multiply.
[tex]W= 100 \ N*m[/tex]
Let's convert the units. 1 Newton meter is equal to 1 Joule, therefore our answer of 100 Newton meters is equal to 100 Joules.
[tex]W= 100 \ J[/tex]
100 Joules of work was done to move the box.
Earth’s Moon has a diameter of 3,474 km and orbits at an average distance of 384,000 km. At that distance it subtends and angle just slightly larger than half a degree in Earth’s sky. Pluto’s moon Charon has a diameter of 1,186 km and orbits at a distance of 19,600 km from the dwarf planet. Compare the appearance of Charon in Pluto’s skies with the Moon in Earth’s skies. Describe where in the sky Charon would appear as seen from various locations on Pluto.
The reason for arriving at the above solutions is as follows:
The given dimensions and distance from the Earth of the Moon are;
The diameter of the Moon, d = 3,474 km
The average distance of the Moon from the Earth, R = 384,000 km
Required:
The comparison between Charon's appearance in Pluto and the Moon's appearance on Earth Earth
Solution:
The distance of the Moon's travels in an orbit, C = 2·π·R
∴ C = 2 × π × 384,000 km
The angle subtended by the Moon, θ = d/C × 360°
∴ θ = 3,474/(2 × π × 384,000) × 360° ≈ 0.518°
Pluto's moon Charon, has the following parameters;
The diameter of the Charon, d₂ = 1,186 km
The average distance of the Charon from Pluto, R₂ = 19,600 km
Therefore, the distance of the Moon's travels in an orbit, C₂ = 2·π·R₂
∴ C₂ = 2 × π × 19,600 km
The angle subtended by the Moon, θ₂ = d₂/C₂ × 360°
∴ θ₂ = 1,186/(2 × π × 19,900) × 360° ≈ 3.415°
The angle subtended by Charon in Pluto's sky ≈ 3.415°
Charon therefore, appears 7 times larger in Pluto's skies than the Moon's appearance in Earth's skies
Required:
The appearance of Charon as seen from different locations on Pluto
Solution:
Charon is gravitationally locked to Pluto, therefore, the same side of Pluto is faced with the same side of Charon
Therefore;
Charon appears constantly overhead from the side of Pluto locked to CharonCharon appears constantly at the horizon from the poles on either side of the axis of rotation of Pluto and CharonLearn more about Pluto's moon Charon here:
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tìm thời điểm vật đạt tốc độ 25\pi cm/s lần thứ 2021
Answer:
una ufx vek cintos kavres millianto
Explanation:
vekas moriqn5o siveria il a ola ola micanese ma n8 aou ko sevyaera
what Is accuracy ............
Answer:
Accuracy is how much the consequence of an estimation adjusts to the right worth or a norm' and basically alludes to how close an estimation is to its concurred esteem
《OAmalaOHopeO》
Answer:
In a set of measurements, accuracy is closeness of the measurements to a specific value, while precision is the closeness of the measurements to each other.
Explanation:
_Hope it helps you_
Need help with this one! Thank you xoxo!
Answer:
it's electron attraction
The answer is Electron Attraction
The theory of the origin of the universe that is most popular among space scientists suggests that our universe originated how long ago
10-20 million years ago
10-20 trillion years ago,
10-20 billion years ago
10-20 thousand years ago
Answer:
10 - 20 million years ago
The question is in the photo.
Answer:
heyaa thereeee
see temperature is rising in interval of
0 to 4 minutes
8 to 10 minutes
but 8 to 10 is NOT in options
so answer is option a) 0 to 4 minutes
:))))
the treasure map gives the following directions to the buried treasure
Answer:
North
South
East
West
Explanation:
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Good evening everyone Help me i n my hw ,The wall of cinema hall are covered with sound absorbing materials. Why?Answer it ASAP.Good day
what do you mean about it
Which state of matter has properties that are responsible for your smelling
the perfume of someone across the room?
A. Gas
B. Solid
C. Liquid
D. Plasma
Answer:
Gas
Explanation:
Solid particles cannot travel far, since they are mostly attracted together.
Liquid Particles cannot travel far either, although they can flow, but they flow with respect with gravity.
Plasma... is a very hot material, it's probably cooler than the sun but it's way warmer than your average boiling water.
So which leaves gas, since we know that the properties of gases are :
Gas particles can freely travel
Gas particles are spread out
These enables it to flow around the room, and this has something to do with diffusion, but i believe it's out of topic.
So, the answer's gas!
HOPE THIS ANSWER HELPED :)Magnetic fields exist
A. Near a magnet
B. Farther away from a magnet
C. Within a magnet
D. All of the above
Answer:
Magnetic fields exist near a magnet, farther away from a magnet, and within a magnet.
So, the answer is D. All of the above.
Let me know if this helps!
A diffraction grating has 6000 lines per centimeter ruled on it. What is the angular separation (in degrees) between the second and the third orders on the same side of the central bright fringe when the grating is illuminated with a beam of light of wavelength 500 nm
Explanation:
Hope it Will help he hsuejwoamxgehanwpalasmbwfwfqoqlmdbehendalmZbgevzuxwllw. yeh we pabdvddxhspapalw. X
The angular separation (in degrees) between the second and the third orders on the same side of the central bright fringe if the wavelength is 500 nm and A diffraction grating has 6000 lines per centimeter ruled on it, is 27.29°.
What is diffraction?Waves spreading outward around obstructions are known as diffraction. Sound, electromagnetic radiation like light, X-rays, and gamma rays, as well as very small moving particles like atoms, neutrons, and electrons that exhibit wavelike qualities all exhibit diffraction.
Given:
The number of lines = 6000 per cm,
The Wavelength, λ = 500 nm = 500 × 10 ⁻⁹ m
Calculate the diffraction grating,
[tex]d = 1 / no\ of\ lines[/tex]
d = 10⁻² / 6000 m,
Calculate the second-order maxima angle and third-order maxima angle by the formula given below,
[tex]dsin\theta_1 = n_1 \lambda[/tex]
[tex]sin\theta_1 = n_1\lambda / d[/tex]
[tex]\theta _1 = sin^{-1}[2\times 500\times 10 ^{-9}/10^{-2}\times 6000][/tex]
θ₁ = sin⁻¹(0.6)
θ₁ = 36.87°
Similarly, for θ₂,
θ₂ = sin⁻¹(3 × 500 × 10 ⁻⁹ / 10⁻² × 6000)
θ₂ = sin⁻¹(0.9)
θ₂ = 64.16°
Calculate the separation as follows,
θ₂ - θ₁ = 64.16° - 36.87°
θ₂ - θ₁ = 27.29°
Therefore, the angular separation (in degrees) between the second and the third orders on the same side of the central bright fringe if the wavelength is 500 nm and A diffraction grating has 6000 lines per centimeter ruled on it, is 27.29°.
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The angle of the resultant vector is equal to
the inverse tangent of the quotient of the x-component divided by the y-component of the resultant vector
the inverse cosine of the quotient of the y-component divided by the x-component of the resultant vector.
the inverse cosine of the quotient of the x-component divided by the y-component of the resultant vector.
the inverse tangent of the quotient of the y-component divided by the x-component of the resultant vector.
The angle of the resultant vector is equal to the inverse tangent of the quotient of the y-component divided by the x-component of the resultant vector.
To find the angle of a resultant vector, the vector must be resolved into y-component and x-component.
The y-component of a vector is the product of the magnitude of the vector and the sine of the angle of the vector to the horizontal. The x-component of a vector is the product of the magnitude of the vector and the cosine of the angle of the vector to the horizontal.The angle of this resultant vector is also known as the direction of the vector.
Mathematically, the direction of a resultant vector is given as;
[tex]\theta = tan^{-1} (\frac{R_y}{R_x} )\\\\where;\\\\\theta \ is \ the \ direction \ of \ the \ resultant \ vetcor\\\\R_y \ is \ the \ magnitude \ of \ the\ vector \ resolved \ in \ y - direction\\\\R_x \ is \ the \ magnitude \ of \ the\ vector \ resolved \ in \ x - direction[/tex]
Therefore, the angle of the resultant vector is equal to the inverse tangent of the quotient of the y-component divided by the x-component of the resultant vector.
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Select the correct answer.
What is abstraction?
OA. the concept that software architecture can be separated into modules and that each module can be examined independently
OB. the process of containing information within a module, preventing any crossover or access to Irrelevant information
OC. the process of splitting a program both horizontally and vertically
OD. the process of cutting down irrelevant information so only the information that is useful for a particular purpose remains
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Answer:
OD. The process of cutting down irrelevant information so only the information that is useful for particular purpose remains
Abstraction is the process of cutting down irrelevant information so only the information that is useful for a particular purpose remains.
What is abstraction?Abstraction is the practice of removing anything from a set of core features by eliminating or deleting attributes.
One of the three core ideas of object-oriented programming is abstraction order to decrease complexity and maximize efficiency, a programmer uses abstraction to conceal all but the important facts about an object.
Abstraction is the process of cutting down irrelevant information so only the information that is useful for a particular purpose remains.
Hence option D is correct.
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A cylinder is given a push and then rolls up an inclined plane. If the origin is the starting point, sketch the position, velocity, and acceleration of the cylinder vs. time as it goes up and then down the plane.
What is tensor quantity?
Is Inertia a tensor? give reason
Answer:
A tensor is a quantity, for example a stress or a strain, which has magnitude, direction, and a plane in which it acts. Stress and strain are both tensor quantities. ... A tensor is a quantity, for example a stress or a strain, which has magnitude, direction, and a plane in which it acts.
Inertia Tensor. where I = the inertia tensor. The angular momentum of a rigid body rotating about an axis passing through the origin of the local reference frame is in fact the product of the inertia tensor of the object and the angular velocity. ... As shown in [7], the inertia tensor is symmetric.
Explanation:
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